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  • How to design data storage for partitioned tagging system?

    - by Morgan Cheng
    How to design data storage for huge tagging system (like digg or delicious)? There is already discussion about it, but it is about centralized database. Since the data is supposed to grow, we'll need to partition the data into multiple shards soon or later. So, the question turns to be: How to design data storage for partitioned tagging system? The tagging system basically has 3 tables: Item (item_id, item_content) Tag (tag_id, tag_title) TagMapping(map_id, tag_id, item_id) That works fine for finding all items for given tag and finding all tags for given item, if the table is stored in one database instance. If we need to partition the data into multiple database instances, it is not that easy. For table Item, we can partition its content with its key item_id. For table Tag, we can partition its content with its key tag_id. For example, we want to partition table Tag into K databases. We can simply choose number (tag_id % K) database to store given tag. But, how to partition table TagMapping? The TagMapping table represents the many-to-many relationship. I can only image to have duplication. That is, same content of TagMappping has two copies. One is partitioned with tag_id and the other is partitioned with item_id. In scenario to find tags for given item, we use partition with tag_id. If scenario to find items for given tag, we use partition with item_id. As a result, there is data redundancy. And, the application level should keep the consistency of all tables. It looks hard. Is there any better solution to solve this many-to-many partition problem?

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  • NHibernate Native SQL multiple joins

    - by Chris
    Hi all, I"m having some problems with Nhibernate and native sql. I've got an entity with alot of collections and I am doing an SQL Fulltext search on it. So when returning 100 or so entities, I dont want all collections be lazy loaded. For this I changed my SQL query: SELECT Query.* FROM (SELECT {spr.*}, {adr.*}, {adrt.*}, {cty.*}, {com.*}, {comt.*}, spft.[Rank] AS [Rak], Row_number() OVER(ORDER BY spft.[Rank] DESC) AS rownum FROM customer spr INNER JOIN CONTAINSTABLE ( customerfulltext , computedfulltextindex , '" + parsedSearchTerm + @"' ) AS spft ON spr.customerid = spft.[Key] LEFT JOIN [Address] adr ON adr.customerid = spr.customerid INNER JOIN [AddressType] adrt ON adrt.addresstypeid = adr.addresstypeid INNER JOIN [City] cty ON cty.cityid = adr.cityid LEFT JOIN [Communication] com ON com.customerid = spr.customerid INNER JOIN [CommunicationType] comt ON comt.communicationtypeid = com.communicationtypeid) as Query ORDER BY Query.[Rank] DESC This is how I setup the query: var items = GetCurrentSession() .CreateSQLQuery(query) .AddEntity("spr", typeof(Customer)) .AddJoin("adr", "spr.addresses") .AddJoin("adrt", "adr.Type") .AddJoin("cty", "adr.City") .AddJoin("com", "spr.communicationItems") .AddJoin("comt", "com.Type") .List<Customer>(); What happens now is, that the query returns customers twice (or more), I assume this is because of the joins since for each customer address, communicationItem (e.g. phone, email), a new sql row is returned. In this case I thought I could use the DistinctRootEntityResultTransformer. var items = GetCurrentSession() .CreateSQLQuery(query) .AddEntity("spr", typeof(Customer)) .AddJoin("adr", "spr.addresses") .AddJoin("adrt", "adr.Type") .AddJoin("cty", "adr.City") .AddJoin("com", "spr.communicationItems") .AddJoin("comt", "com.Type") .SetResultTransformer(new DistinctRootEntityResultTransformer()) .List<Customer>(); Doing so an exception is thrown. This is because I try to list customers .List<Customer>() but the transformer returns only entities of the last join added. E.g. in the case above, the entity with alias "comt" is returned when doing .List() instead of .List(). If I would switch last join with the join alias "cty", then the transformer returns a list of cities only... Anyone knows how I can return a clean list of customers in this case?

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  • Help optimizing a query with 16 subqueries

    - by Webnet
    I have indexes/primaries on all appropriate ID fields for each type. I'm wondering though how I could make this more efficient. It takes a while to load the page with only 15,000 rows and that'll quickly grow to 500k. The $whereSql variable simply has a few more parameters for the main ebay_archive_listing table. NOTE: This is all done in a single query because I have ASC/DESC sorting for each subquery value. NOTE: I've converted some of the sub queries to INNER JOIN's SELECT product_master.product_id, ( SELECT COUNT(listing_id) FROM ebay_archive_product_listing_assoc '.$listingCountJoin.' WHERE ebay_archive_product_listing_assoc.product_id = product_master.product_id) as listing_count, sku, type_id, ( SELECT AVG(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as average_bid_price, ( SELECT AVG(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.buy_it_now_price > 0 ) as average_buyout_price, ( SELECT MIN(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as lowest_bid_price, ( SELECT MAX(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as highest_bid_price, ( SELECT MIN(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as lowest_buyout_price, ( SELECT MAX(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as highest_buyout_price, round((( SELECT COUNT(ebay_archive_listing.id) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.status_id = 2 ) / ( SELECT COUNT(listing_id) FROM ebay_archive_product_listing_assoc '.$listingCountJoin.' WHERE ebay_archive_product_listing_assoc.product_id = product_master.product_id ) * 100), 1) as sold_percent FROM product_master '.$joinSql.' WHERE product_master.product_id IN ( SELECT product_id FROM ebay_archive_product_listing_assoc INNER JOIN ebay_archive_listing ON ( ebay_archive_listing.id = ebay_archive_product_listing_assoc.listing_id AND '.$whereSql.' ) )

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  • Calculating estimated data loss with Always on

    - by blakmk
    Ever wondered how calculate estimated data loss (time) for always on. The metric in the always on dashboard shows the metric quite nicely but there does seem to be a lack of documentation about where the metrics ---come from. Heres a script that calculates the data loss ( lag ) so you can set up alerts based on your DR SLA's:       WITH DR_CTE ( replica_server_name, database_name, last_commit_time) AS                 (                                 select ar.replica_server_name, database_name, rs.last_commit_time                                 from master.sys.dm_hadr_database_replica_states  rs                                 inner join master.sys.availability_replicas ar on rs.replica_id = ar.replica_id                                 inner join sys.dm_hadr_database_replica_cluster_states dcs on dcs.group_database_id = rs.group_database_id and rs.replica_id = dcs.replica_id                                 where replica_server_name != @@servername                 ) select ar.replica_server_name, dcs.database_name, rs.last_commit_time, DR_CTE.last_commit_time 'DR_commit_time', datediff(ss,  DR_CTE.last_commit_time, rs.last_commit_time) 'lag_in_seconds' from master.sys.dm_hadr_database_replica_states  rs inner join master.sys.availability_replicas ar on rs.replica_id = ar.replica_id inner join sys.dm_hadr_database_replica_cluster_states dcs on dcs.group_database_id = rs.group_database_id and rs.replica_id = dcs.replica_id inner join DR_CTE on DR_CTE.database_name = dcs.database_name where ar.replica_server_name = @@servername order by lag_in_seconds desc

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  • Booting Ubuntu EFI on Macbook Pro Apple Bootmanager

    - by user279771
    Following: http://www.rodsbooks.com/ubuntu-efi/ and https://help.ubuntu.com/community/UEFIBooting#Detect_.28U.29EFI_firmware_processor_architecture I have ubuntu booting on my macbook pro with both refined and the native apple loader working, however, I would like to get the "Improving the Boot Method" (i believe it is called the kernel efi stub loader) working with the Apple Boot manager (the article only explains for refined), but have found no articles explaining this. Can anyone help with this? Below is what I have: What I have is the following: /dev/sda apple partitions /boot ext3 (root) ext3 swap side notes: From what I understand, I should have had my boot partition as fat32/hfs+... I can always switch it or copy the kernel to the apple EFI partition. (I tried creating /boot as an hfs+ partition during installation but was unable. Even after installing hfsprogs, although I was able to create an hfs+ partition in gparted I couldn't use the partition as /boot in ubiquity).

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  • Ubuntu confuses my partitions

    - by Diego
    I have 3 relevant partitions split between 2 disks, sda2: Windows 1 partition sda3: Ubuntu partition sdb1: Data partition I was using pysdm to add a label to my partitions and somehow I seem to have screwed up my installation. Now, every time I access the Data partition mounted in /media/Data I see the files in my Windows partition, and viceversa. I've tried unmounting and remounting correctly to no avail, it seems that wherever I mount sda2, if I access that folder I get the files in sdb1, and viceversa. Anyone know what may have happened and how to solve this? Update: This is the result of blkid: /dev/sda1: LABEL="System Reserved" UUID="C62603F02603E073" TYPE="ntfs" /dev/sda2: LABEL="Windows" UUID="00A6D498A6D49010" TYPE="ntfs" /dev/sda5: UUID="033cac3b-6f77-4f09-a629-495dc866866a" TYPE="ext4" /dev/sdb1: LABEL="Data" UUID="BCD83AE3D83A9B98" TYPE="ntfs" These are the contents of my ftsab file: UUID=033cac3b-6f77-4f09-a629-495dc866866a / ext4 errors=remount-ro,user_xattr 0 1 /dev/sda1 /media/Boot_old ntfs defaults 0 0 /dev/sda2 /media/Windows ntfs defaults 0 0 /dev/sdb1 /media/Data ntfs nls=iso8859-1,ro,users,umask=000 0 0

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  • How can I install Ubuntu Saucy Server with BTRFS?

    - by Walter Souto
    So, a week ago I installed the latest beta version of Ubuntu Saucy Server in a MacMini using BTRFS as only partition to mount "/" on it (I know it's not recommended to do this, but it's not the point here) with no problems et al. Everything went just "naturally"... Now with the released image of 13.10 server, I just can't get any BTRFS partition done from installer. I'm getting a "Can't create filesystem" error whenever I try to create any BTRFS partition, like the 13.10 server final installer can't handle format BTRFS partitions... Am I doing something wrong? Or it's a bug in the installer? Is there anything that I can do to workaround this and get my BTRFS partition set on installation, or I'll need to work this after the installation. I can just leave some space left and create a btrfs partition later on, with Saucy already installed and proceed to use to LXC (which is my solo purpose to have btrfs), but anyway, why installer can't do btrfs anymore?

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  • Using LINQ to XML, how can I join two sets of data based on ordinal position?

    - by Donald Hughes
    Using LINQ to XML, how can I join two sets of data based on ordinal position? <document> <set1> <value>A</value> <value>B</value> <value>C</value> </set1> <set2> <value>1</value> <value>2</value> <value>3</value> </set2> </document> Based on the above fragment, I would like to join the two sets together such that "A" and "1" are in the same record, "B" and "2" are in the same record, and "C" and "3" are in the same record.

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  • How to get query result even if JOIN hasn't found any results?

    - by user1734651
    I want select data for user, and join another info from other table that related to the user. The problem is that this extra data not always exist for any user, just for few. How can I write a query that will return NULL for not found data, instead just return null for the whole query? SELECT a.*, b.* FROM user AS a LEFT JOIN extra AS b ON (a.userid = b.userid) WHERE a.userid = {$userid} LIMIT 1 When extra data found for the user, I get the resource as expected. If not, I get NULL for the whole query. Bottom line, I don't care if "extra" exist for the user or not, if yes - select it as well, if not - ignore that.

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  • Implement Tree/Details With Taskflow Regions Using EJB

    - by Deepak Siddappa
    This article describes on Display Tree/Details using taskflow regions.Use Case DescriptionLet us take scenario where we need to display Tree/Details, left region contains category hierarchy with items listed in a tree structure (ex:- Region-Countries-Locations-Departments in tree format) and right region contains the Employees list.In detail, Here User may drills down through categories using a tree until Employees are listed. Clicking the tree node name displays Employee list in the adjacent pane related to particular tree node. Implementation StepsThe script for creating the tables and inserting the data required for this application CreateSchema.sql Lets create a Java EE Web Application with Entities based on Regions, Countries, Locations, Departments and Employees table. Create a Stateless Session Bean and data control for the Stateless Session Bean. Add the below code to the session bean and expose the method in local/remote interface and generate a data control for that.Note:- Here in the below code "em" is a EntityManager. public List<Employees> empFilteredByTreeNode(String treeNodeType, String paramValue) { String queryString = null; try { if (treeNodeType == "null") { queryString = "select * from Employees emp ORDER BY emp.employee_id ASC"; } else if (Pattern.matches("[a-zA-Z]+[_]+[a-zA-Z]+[_]+[[0-9]+]+", treeNodeType)) { queryString = "select * from employees emp INNER JOIN departments dept\n" + "ON emp.department_id = dept.department_id JOIN locations loc\n" + "ON dept.location_id = loc.location_id JOIN countries cont\n" + "ON loc.country_id = cont.country_id JOIN regions reg\n" + "ON cont.region_id = reg.region_id and reg.region_name = '" + paramValue + "' ORDER BY emp.employee_id ASC"; } else if (treeNodeType.contains("regionsFindAll_bc_countriesList_1")) { queryString = "select * from employees emp INNER JOIN departments dept \n" + "ON emp.department_id = dept.department_id JOIN locations loc \n" + "ON dept.location_id = loc.location_id JOIN countries cont \n" + "ON loc.country_id = cont.country_id and cont.country_name = '" + paramValue + "' ORDER BY emp.employee_id ASC"; } else if (treeNodeType.contains("regionsFindAll_bc_locationsList_1")) { queryString = "select * from employees emp INNER JOIN departments dept ON emp.department_id = dept.department_id JOIN locations loc ON dept.location_id = loc.location_id and loc.city = '" + paramValue + "' ORDER BY emp.employee_id ASC"; } else if (treeNodeType.trim().contains("regionsFindAll_bc_departmentsList_1")) { queryString = "select * from Employees emp INNER JOIN Departments dept ON emp.DEPARTMENT_ID = dept.DEPARTMENT_ID and dept.DEPARTMENT_NAME = '" + paramValue + "'"; } } catch (NullPointerException e) { System.out.println(e.getMessage()); } return em.createNativeQuery(queryString, Employees.class).getResultList(); } In the ViewController project, create two ADF taskflow with page Fragments and name them as FirstTaskflow and SecondTaskflow respectively. Open FirstTaskflow,from component palette drop view(Page Fragment) name it as TreeList.jsff. Open SeconfTaskflow, from component palette drop view(Page Fragment) name it as EmpList.jsff and create two paramters in its overview parameters tab as shown in below image. Open TreeList.jsff , from data control palette drop regionsFindAll->Tree as ADF Tree. In Edit Tree Binding dialog, for Tree Level Rules select the display attributes as follows:-model.Regions - regionNamemodel.Countries - countryNamemodel.Locations - citymodel.Departments - departmentName In structure panel, click on af:Tree - t1 and select selectionListener with edit property. Create a "TreeBean" managed bean with scope as "session" as shown in below Image. Create new method as getTreeNodeSelectedValue and click ok. Open TreeBean managed bean and add the below code: private String treeNodeType; private String paramValue; public void getTreeNodeSelectedValue(SelectionEvent selectionEvent) { RichTree tree = (RichTree)selectionEvent.getSource(); RowKeySet addedSet = selectionEvent.getAddedSet(); Iterator i = addedSet.iterator(); TreeModel model = (TreeModel)tree.getValue(); model.setRowKey(i.next()); JUCtrlHierNodeBinding node = (JUCtrlHierNodeBinding)tree.getRowData(); //oracle.jbo.Row Row rw = node.getRow(); Object selectedTreeNode = node.getAttribute(0); Object treeListType = node.getBindings(); String treeNodeType = treeListType.toString(); this.setParamValue(selectedTreeNode.toString()); this.setTreeNodeType(treeNodeType); } public void setTreeNodeType(String treeNodeType) { this.treeNodeType = treeNodeType; } public String getTreeNodeType() { return treeNodeType; } public void setParamValue(String paramValue) { this.paramValue = paramValue; } public String getParamValue() { return paramValue; }<br /> Open EmpList.jsff , from data control palette drop empFilteredByTreeNode->Employees->Table as ADF Read-only Table. After selecting the  Employees result set, in Edit Action Binding dialog window pass the pageFlowScope parameters as shown in below Image. In empList.jsff page, click Binding tab and click on Create Executable binding and select Invoke action and follow as shown in below image. Edit executeEmpFiltered invoke action properties and set the Refresh to ifNeeded, So when ever the page needs the method will be executed. Create Main.jspx page with page template as Oracle Three Column Layout. Drop FirstTaskflow as Region in start facet and drop SecondTaskflow as Region in center facet, Edit task Flow Binding dialog window pass the Input Paramters as shown in below Image. Run the Main.jspx, tree will be displayed in left region and emp details will displyaed on the right region. Click on the Americas in tree node, all emp related to the Americas related will be displayed. Click on Americas->United States of America->South San Francisco->Accounting, only employee belongs to the Accounting department will be displayed.

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  • Demantra Partitioning and the First PK Column

    - by user702295
      We have found that it is necessary in Demantra to have an index that matches the partition key, although it does not have to be the PK.  It is ok   to create a new index instead of changing the PK.   For example, if my PK on SALES_DATA is (ITEM_ID, LOCATION_ID, SALES_DATE) and I decide partition by SALES_DATE, then I should add an index starting   with the partition key like this: (SALES_DATE, ITEM_ID, LOCATION_ID).   * Note that the first column of the new index matches the partition key.   It might also be helpful to create a 2nd index with the other PK columns reversed (SALES_DATE, LOCATION_ID, ITEM_ID). Again, the first column   matches the partition key.

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  • Netbook partitioning scheme suggestions

    - by David B
    I got a new Asus EEE PC 1015PEM with 2GB RAM and a 250GB HD. After playing with the netbook edition a little, I would like to install the desktop edition I'm used to. In addition to ubunto partition(s), I would like to have one separate partition for data (documents, music, etc.), so I could try other OSs in the future without losing the data. What partition scheme would you recommend? I usually like to let the installation do it by itself, but when I try to that I can only use the entire disk, so I don't get the desired data partition. I wish there was a way to see the recommended default partitioning scheme, then just tweak it a bit to fit your needs (instead of building one from scratch). So, how would you recommend I partition my HD? Please be specific since I never manually partitioned before. Thanks!

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  • Unable to start GRUB2 on Triple boot Macbook Pro with OS X Lion, Windows 7 and Ubuntu

    - by Shravan
    I installed Windows 7 using Bootcamp. Then I created a partition from the empty space in the Windows partition and another 4GB partition for the linux swap using GParted. I installed Ubuntu 12.04 LTS in the the newly created partition from the Windows partition. Now GRUB2 does not load and I can only see the blinking cursor on the top right when selecting "Windows HD" from the 'option' key at the start up. OS X works fine but nothing else. Could someone please help me fix this? I am attaching the boot-info from the boot-repair tool. http://paste.ubuntu.com/1040169/

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  • SQL query: how to translate IN() into a JOIN?

    - by tangens
    I have a lot of SQL queries like this: SELECT o.Id, o.attrib1, o.attrib2 FROM table1 o WHERE o.Id IN ( SELECT DISTINCT Id FROM table1, table2, table3 WHERE ... ) These queries have to run on different database engines (MySql, Oracle, DB2, MS-Sql, Hypersonic), so I can only use common SQL syntax. Here I read, that with MySql the IN statement isn't optimized and it's really slow, so I want to switch this into a JOIN. I tried: SELECT o.Id, o.attrib1, o.attrib2 FROM table1 o, table2, table3 WHERE ... But this does not take into account the DISTINCT keyword. Question: How do I get rid of the duplicate rows using the JOIN approach?

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  • Does CakePHP treat all INT fields as ID's for join tables?

    - by Jonnie
    I am trying to save a User, their Profile, and some tags and my join table that links the profile and the tags keeps getting messed up. The profile model is called Instructor, the tag model is called Subject. The Instructor has a phone number and a zip code and for some reason CakePHP thinks these are the fields it should use when creating entries in my join table. My Join table always comes out as: id | instructor_id | subject_id | 1 | 90210 | 1 | // thinks that the zip code is an instructor_id 2 | 1112223333 | 1 | // thinks that the phone number is an instructor_id 3 | 1 | 1 | // thinks that user_id is an instructor_id 4 | 1 | 1 | // the actual instructor_id, this one's correct 5 | 90210 | 2 | 6 | 1112223333 | 2 | 3 | 1 | 2 | 4 | 1 | 2 | My Models: class Instructor extends AppModel { var $name = 'Instructor'; var $belongsTo = array('User', 'State'); var $hasAndBelongsToMany = array( 'Subject' = array( 'className' = 'Subject', 'joinTable' = 'instructors_subjects', 'foreignKey' = 'instructor_id', 'associationForeignKey' = 'subject_id', 'unique' = true, 'conditions' = '', 'fields' = '', 'order' = '', 'limit' = '', 'offset' = '', 'finderQuery' = '', 'deleteQuery' = '', 'insertQuery' = '' ) ); } class Subject extends AppModel { var $name = 'Subject'; var $hasAndBelongsToMany = array( 'Instructor' = array( 'className' = 'Instructor', 'joinTable' = 'instructors_subjects', 'foreignKey' = 'subject_id', 'associationForeignKey' = 'instructor_id', 'unique' = true, 'conditions' = '', 'fields' = '', 'order' = '', 'limit' = '', 'offset' = '', 'finderQuery' = '', 'deleteQuery' = '', 'insertQuery' = '' ) ); } My Model Associations: User hasOne Instructor Instructor belongsTo User Instructor hasAndBelongsToMany Subject Subject hasAndBelongsToMany Instructor My form data looks like: Array ( [User] = Array ( [username] = MrInstructor [password] = cddb06c93c72f34eb9408610529a34645c29c55d [group_id] = 2 ) [Instructor] = Array ( [name] = Jimmy Bob [email] = [email protected] [phone] = 1112223333 [city] = Beverly Hills [zip_code] = 90210 [states] = 5 [website] = www.jimmybobbaseballschool.com [description] = Jimmy Bob is an instructor. [user_id] = 1 [id] = 1 ) [Subject] = Array ( [name] = hitting, pitching ) ) My function for processing the form looks like: function instructor_register() { $this-set('groups', $this-User-Group-find('list')); $this-set('states', $this-User-Instructor-State-find('list')); if (!empty($this-data)) { // Set the group to Instructor $this-data['User']['group_id'] = 2; // Save the user data $user = $this-User-save($this-data, true, array( 'username', 'password', 'group_id' )); // If the user was saved, save the instructor's info if (!empty($user)) { $this-data['Instructor']['user_id'] = $this-User-id; $instructor = $this-User-Instructor-save($this-data, true, array( 'user_id', 'name', 'email', 'phone', 'city', 'zip_code', 'state_id', 'website', 'description' )); // If the instructor was saved, save the rest if(!empty($instructor)) { $instructorId = $this-User-Instructor-id; $this-data['Instructor']['id'] = $instructorId; // Save each subject seperately $subjects = explode(",", $this-data['Subject']['name']); foreach ($subjects as $_subject) { // Get the correct subject format $_subject = strtolower(trim($_subject)); $this-User-Instructor-Subject-create($this-data); $this-User-Instructor-Subject-set(array( 'name' = $_subject )); $this-User-Instructor-Subject-save(); echo ''; print_r($this-data); echo ''; } } } } }

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  • I can not install Ubuntu 14.04 due to some problem?

    - by user285643
    I have installed Window 8.1 on my HP laptop.Now I want to install Ubuntu 14.04,I try to use "Wubi" but when I use it, after installation on window, when my computer restart i have a message "No root file system is defined" I have read some thread here and i got some solution. One of them are "I must format my partition again, using ext4 format and mount on it". I did it by using Gparted in Try Ubuntu mode, but I got another message "/dev/sda contains GPT signatures,indicating that it has a GPT table. However, it does not have a valid fake msdos partition table,as it should. Perhaps it was corrupted--possibly by a program that does not understand GPT partition table. Or perhaps you deleted the GPT table, and are now using msdos partition table. Is this a GPT partition table?"

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  • how to add column in SQL Query that incl. LEFT OUTER JOIN

    - by radbyx
    I have this Query: SELECT p.ProductName, dt.MaxTimeStamp, p.Responsible FROM Product p LEFT JOIN (SELECT ProductID, MAX(TimeStamp) AS MaxTimeStamp FROM StateLog WHERE State = 0 GROUP BY ProductID, Status) dt ON p.ProductID = dt.ProductID ORDER BY p.ProductName; It works like it should, but now I need to SELECT "State" out too. The tricky part is, that I only want the lastest "TimeStamp" where "State" was false. But now I also need the "State" for the lastest "TimeStamp". I tried this: SELECT p.ProductName, dt.State, dt.MaxTimeStamp, p.Responsible FROM Product p LEFT JOIN (SELECT ProductID, MAX(TimeStamp) AS MaxTimeStamp, State FROM StateLog WHERE State = 0 GROUP BY ProductID, Status) dt ON p.ProductID =dt.ProductID ORDER BY p.ProductName; But it didn't work, because it gave me the "State" for the lastest "TimeStamp". So I hope there is some clever heads out there that can help me. I'm guessing that this is either very simple or very hard to solve.

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  • [Seamless Handover of WiFi] Can we program to automatically join the WiFi with the most strongest si

    - by Dobby
    Hi all, I am making a iphone program, I wish that: it can sense and display the current signals of wifi, with strength, - as I checked, this cannot be done by official SDK, but there were some private library that can handle. 2. i wish it can always automatically join the best wifi with the most highest strength ( assume that all wifi APs have no password, and all are not remembered into the used-list inside iphone), which is something like "seamless handover"... I just guess that, there should be some APIs to let the system join one designated wifi signal from the list, and wish someone could help me. I would like to appreciate a lot : ) Thanks a lot!

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  • Does INNER JOIN performance depends on order of tables?

    - by Kartic
    A question suddenly came to my mind while I was tuning one stored procedure. Let me ask it - I have two tables, table1 and table2. table1 contains huge data and table2 contains less data. Is there performance-wise any difference between these two queries(I am changing order of the tables)? Query1: SELECT t1.col1, t2.col2 FROM table1 t1 INNER JOIN table2 t2 ON t1.col1=t2.col2 Query2: SELECT t1.col1, t2.col2 FROM table2 t2 INNER JOIN table1 t1 ON t1.col1=t2.col2 We are using Microsoft SQL server 2005.

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  • Need help migrating from Wubi

    - by neilh
    I know this question has been asked, but I am looking for specific help with my partition selection. I want to migrate my install from wubi to be a dual boot. When I installed it I choose a small, partition, around 30GB. I am following these instructions: https://help.ubuntu.com/community/MigrateWubi I see sda4 matches that size, but has mount point as '/host', am I okay to use this one? EDIT: Here is a screenshot of my partitions. http://i.imgur.com/ozPe0.png My windows partition is actually not there, that is down as sdb1, so safely out of the way? I can confirm sda4 is the location of the 'virtual partition' and is an otherwise, unused 26GB partition. It's also where I would like to migrate to a full install to.

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  • Split a string and join it back together in a different order?

    - by Xaisoft
    What is the most concise, yet readable way to split a string and put join it back together in a different order. For example, I want to split the following string: 10-20-30-4000-50000 and I would do this via: string[] tokens = original.Split('-'); and now I want to put it back together in this order: 30-20-10-4000-50000 I know I can use Join to put it back together in it's original form, but I don't want that. The only thing I can think of right now is: string modified = string.Format("{0}{1}{2}{3}{4}",tokens[2],tokens[1],tokens[0],tokens[3], tokens[4]); I realized that if I do: string modified = string.Format("{2}{1}{0}{3}{4}", tokens); it does not keep the dashes which is what I want so is to do that, should I just do: string modified = string.Format("{2}-{1}-{0}-{3}-{4}", tokens);

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  • how to join on varchar(32) and binary(16) columns in sybase?

    - by Paul Sanwald
    I want to join two tables on a UUID. table A's UUID is represented as varchar(32). table B's UUID is represented as binary(16). what's the best way to join a varchar to a binary column? I've tried using some sybase functions for this, but I'm getting different results and unsure of why: select hextobigint('0x000036ca4c4c11d88b8dcd1344cdb512') 3948051912944290701 select convert(bigint,0x000036ca4c4c11d88b8dcd1344cdb512) -2877434794219274240 what am I missing about convert and hextobigint? I must be misundstanding at least one of these functions. thanks for your help!

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  • How to add new partition to RAID-1 array on Redhat FC10?

    - by Peter Scott
    I have a RH FC10 system with RAID 1 partitions, here is mdadm.conf: # mdadm.conf written out by anaconda DEVICE partitions MAILADDR root ARRAY /dev/md1 level=raid1 num-devices=2 metadata=0.90 UUID=9588bfe1:ddfd5858:1067c814:ac499922 ARRAY /dev/md3 level=raid1 num-devices=2 metadata=0.90 UUID=3895ca46:c1526588:d48acd7e:c153aa83 ARRAY /dev/md4 level=raid1 num-devices=2 metadata=0.90 UUID=ebd4920f:b46c1f18:2eced24a:a21ca861 ARRAY /dev/md2 level=raid1 num-devices=2 metadata=0.90 UUID=048e8198:5d6d9682:d3a1e5c3:d475ad80 ARRAY /dev/md0 level=raid1 num-devices=2 metadata=0.90 UUID=d89ec2de:079d4be5:e00ee8f5:fcb19188 I want to carve off 500MB from md4 to make a new partition (for an AFS cache). I haven't touched mdadm or any other disk partitioning tools in years. md4 is 50GB and less than 10% used. What's the easiest way of doing this?

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  • How to remove a partition on a USB drive?

    - by Nathan Long
    I got a free promotional USB stick that I want to format for my own purposes. When I inserted it, it automatically opened a browser and launched a web site. I have since disabled autoplay on this computer so that nothing launches when the stick is inserted. But it still shows up as two separate drives, and one of them is a "CD Drive" that I can't format. How can a USB stick contain a "CD Drive?" And more to the point, how can I remove this partition using Windows XP or Ubuntu? Update I previously asked for an XP solution, but finding none, I have tried Ubuntu, also without success. Gparted doesn't see the "CD" portion as a device at all, and from bash, any chmod changes I try tell me that the file system is read-only. Any ideas?

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  • Is there a registry key change that will by-pass the Windows Domain Join Welcome page?

    - by user1256194
    I'm scripting some Windows Server 2008 R2 builds using Power Shell. Some software needs to be installed after the server has joined the domain. Since I want to automate everything, I'm looking to by-pass the domain controllers Welcome page using a registry hack script. I work for a large company and the Active Directory people are unwilling to change group policy. I figure if it's a registry key I can script the change, install the software, replace the key and reboot as the final step. Is there a registry key change that will by-pass the Domain Join Welcome page?

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