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  • Can't login to Guest Session or Standard Account?

    - by Rory
    Thanks in advance for any help. Ubuntu 12.04 Up until recently my mother has been using the Guest Session when she logs on; now, the Guest Session will not login. When I try to login to it, it bounces me back to the login screen. I then tried to login on a Standard account (Alberta) which I made prior to not being able to login to Guest, and it turns out I cannot login - it gives the "Invalid Password" error. So then I tried to change her password from my own account (Rory) which is the master account. Under the Login Options where the Password option is, it says "Account disabled" and it will not let me change this; I try to apply a password, get no error, but it just still says "Account disabled". Then I tried to delete the Alberta account altogether, but got this error: I also tried sudo userdel -r Alberta but got this error: "userdel: cannot lock /etc/shadow; try again later." I don't know what to do now. Any help appreciated.

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  • Cannot FTP without simultaneous SSH connection?

    - by Lucas
    I'm trying to set up an old box as a backup server (running 10.04.4 LTS). I intend to use 3rd party software on my PC to periodically connect to my server via FTP(S) and to mirror certain files. For some reason, all FTP connection attempts fail UNLESS I'm simultaneously connected via SSH. For example, if I use putty to test the connection to port 21, the system hangs and times out. I get: 220 Connected to LeServer USER lucas 331 Please specify the password. PASS [password] <cursor> However, when I'm simultaneously logged in (in another session) everything works: 220 Connected to LeServer USER lucas 331 Please specify the password. PASS [password] 230 Login successful. Basically, this means that my software will never be able to connect on its own, as intended. I know that the correct port is open because it works (sometimes) and nmap gives me: Starting Nmap 5.00 ( http://nmap.org ) at 2012-03-20 16:15 CDT Interesting ports on xx.xxx.xx.x: Not shown: 995 closed ports PORT STATE SERVICE 21/tcp open ftp 22/tcp open ssh 53/tcp open domain 139/tcp open netbios-ssn 445/tcp open microsoft-ds Nmap done: 1 IP address (1 host up) scanned in 0.15 seconds My only hypothesis is that this has something to do with iptables. Maybe it's allowing only established connections? I don't think that's how I set it up, but maybe? Here's my iptables rules for INPUT: lucas@rearden:~$ sudo iptables -L INPUT Chain INPUT (policy DROP) target prot opt source destination fail2ban-ssh tcp -- anywhere anywhere multiport dports ssh ufw-before-logging-input all -- anywhere anywhere ufw-before-input all -- anywhere anywhere ufw-after-input all -- anywhere anywhere ufw-after-logging-input all -- anywhere anywhere ufw-reject-input all -- anywhere anywhere ufw-track-input all -- anywhere anywhere ACCEPT tcp -- anywhere anywhere tcp dpt:ftp I'm using vsftpd. Any thoughts/resources on how I could fix this? L

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  • WCF Versioning, Naming and Endpoint URL

    - by Vinothkumar VJ
    I have a WCF Service and a Main Lib1. Say, I have a Save Profile Service. WCF gets data (with predefined data contract) from client and pass the same to the Main Class Lib1, generate response and send it back to client. WCF Method : SaveProfile(ProfileDTO profile) Current Version 1.0 ProfileDTO have the following UserName Password FirstName DOB (In string yyyy-mm-dd) CreatedDate (In string yyyy-mm-dd) Next Version (V2.0) ProfileDTO have the following UserName Password FirstName DOB (In UnixTimeStamp) CreatedDate (In UnixTimeStamp) Version 3.0 ProfileDTO have the following (With change in UserName and Password length validation) UserName Password FirstName DOB (In UnixTimeStamp) CreatedDate (In UnixTimeStamp) In simple we have DataContract and Workflow change between each version 1. How do I name the methods in WCF Service and Main Class Lib1? 2. Do I have to go with any specific pattern for ease development and maintenance? 3. Do I have to have different endpoints for different version? In the above example I have a method named “SaveProfile”. Do I have to name the methods like “SaveProfile1.0”, “SaveProfile2.0”, etc. If that is the case when there is no change between Version “3.0” and “4.0” then there will difficult in maintenance. I’m looking for a approach that will help in ease maintenance

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  • Spring Roo Database Reverse Engineer with Oracle

    - by kerry
    So you are trying to reverse engineer an Oracle database with roo? Unfortunately, due to licensing restrictions with the Oracle JDBC Drivers, this is a little difficult. There are a few blog posts and forum threads that address the problem but I figured I would post what worked for me here. First, you need to download the appropriate Oracle Drivers from Oracle. The required login, stringent password requirements, nosy registration form, and general system instability made this a pretty painful step for me. I’d also like to say that companies that have password requirements that don’t allow symbols (or any other non-standard requirement) have a special place in my heart. Having to recover my password every time I go to your site virtually guarantees I will only go there when I absolutely have to (not often). Anyways, once you have it downloaded you need to install is with maven: mvn install:install-file -Dfile=~/Downloads/ojdbc6.jar -DgroupId=com.oracle -DartifactId=ojdbc6 -Dversion=11.2.0.3 -Dpackaging=jar -DgeneratePom=true Here comes the fun part. You need to create an osgi wrapper for the driver to install it in roo. Otherwise, roo cannot see the driver. Create a new folder and put the contents of the oracle roo addon pom gist I created. Now build it with maven. You may want to change some of the artifact ids and dependencies for your particular situation. mvn package No open a roo shell and execute the following command: osgi install --url file:///Users/me/my-osgi-project/target/the-jar-it-built.jar Now run (in roo): jpa setup --provider HIBERNATE --database ORACLE dependency remove --groupId com.oracle --artifactId ojdbc14 --version 10.2.0.2 dependency add --groupId com.oracle --artifactId ojdbc6 --version 11.2.0.3 database properties set --key database.driverClassName --value oracle.jdbc.OracleDriver database properties set --key database.url --value jdbc:oracle:thin:@%YOUR_CONNECTION_INFO% database properties set --key database.username --value %YOUR_USERNAME% database properties set --key database.password --value %YOUR_PASSWORD% database reverse engineer --schema %YOUR_SCHEMA% --package ~.domain If you have any package loading exceptions when running the reverse engineer command you can uninstall the osgi bundle, set the package to optional in the osgi pom in the IncludedPackages tag (javax.some.package.*;resolution:=optional) rebuild, then reinstall in roo.

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  • Unable to install mysql in ubuntu

    - by Anand
    I purged my existing mysql-server from ubuntu and re-installed the same. This was due there was an upgrade from my ubuntu and I was unable to start my sql-server. After cleaned up and taking backup of my data , I re-insalled mysql. During installaion I received following message popup. Unable to set password for the MySQL "root" user An error occurred while setting the password for the MySQL administrative user. This may have happened because the account already has a password, or because of a communication problem with the MySQL server. You should check the account's password after the package installation. Please read the /usr/share/doc/mysql-server-5.5/README.Debian file for more information. ¦ ¦ After the installation was failed, following error were received. 121109 20:36:18 InnoDB: Initializing buffer pool, size = 128.0M 121109 20:36:18 InnoDB: Completed initialization of buffer pool 121109 20:36:18 InnoDB: highest supported file format is Barracuda. 121109 20:36:18 InnoDB: Waiting for the background threads to start 121109 20:36:19 InnoDB: 1.1.8 started; log sequence number 2395841 ERROR: 130 Incorrect file format 'user' 121109 20:36:19 [ERROR] Aborting 121109 20:36:19 InnoDB: Starting shutdown... 121109 20:36:20 InnoDB: Shutdown completed; log sequence number 2395841 121109 20:36:20 [Note] /usr/sbin/mysqld: Shutdown complete start: Job failed to start invoke-rc.d: initscript mysql, action "start" failed. dpkg: error processing mysql-server-5.5 (--configure): subprocess installed post-installation script returned error exit status 1 dpkg: dependency problems prevent configuration of mysql-server: mysql-server depends on mysql-server-5.5; however: Package mysql-server-5.5 is not configured yet. dpkg: error processing mysql-server (--configure): dependency problems - leaving unconfigured No apport report written because the error message indicates its a followup error from a previous failure. Errors were encountered while processing: mysql-server-5.5 mysql-server E: Sub-process /usr/bin/dpkg returned an error code (1)

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  • Help with setting up AIM account

    - by Aaron
    Can anyone help me configure my AIM account? I have Oneiric and I want to set up my AIM account with what I believe is a chat client (the envelope icon on the top right). It is called Empathy. \n I tried to do this using Broadcast Account. It let me choose what account (Jabber, Pidgin, Aim, etc...). Once I entered my password for my AIM account, I got a pop-up asking for the master password for my Keyring. I didn't know what that was at the time so I closed that window after trying to enter my account password. Keyring apparently asks for a master password and it holds any keys you want to remember in the future. It gave me an error so I couldn't set up my AIM account completely. Now I'm trying to get back to that screen but I can only set up a Twitter or Facebook. Thanks, Aaron P.S. Can anyone tell me how to break the message up so it doesn't appear all on one line? I tried 'coding' a \n...seemed to work.

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  • Samba issue with sharing directories on NTFS/FAT32

    - by Microkernel
    I have some strange problems with Samba server. I am using samba Version 3.5.4 on Ubuntu 10.10. I have two Windows XP machines, one on VirtualBox on Ubuntu and another office laptop. Windows machine on VirtualBox has no issues in accessing the shared folders, but the laptop is not able to access all the shared content. The issue faced on laptop is the following. Shared folders on ext3 drives have no issues in accessing, but the contents shared on NTFS and FAT32 drives (mounted ones) are not accessible. When I try to open the shared folder, it asks for user name and password, but doesn't accept when I provide it. (Even if I provide admin login details). I changed workgroup value to the domain_name in office laptop, but still the problem persists. Here is the smdb.conf I am using: [global] workgroup = XXX.XXX.ORG server string = %h server (Samba, Ubuntu) map to guest = Bad User obey pam restrictions = Yes pam password change = Yes passwd program = /usr/bin/passwd %u passwd chat = *Enter\snew\s*\spassword:* %n\n *Retype\snew\s*\spassword:* %n\n *password\supdated\ssuccessfully* . unix password sync = Yes syslog = 0 log file = /var/log/samba/log.%m max log size = 1000 dns proxy = No usershare allow guests = Yes panic action = /usr/share/samba/panic-action %d guest ok = Yes [homes] comment = Home Directories [printers] comment = All Printers path = /var/spool/samba read only = No create mask = 0700 printable = Yes browseable = No [print$] comment = Samba server's CD-ROM path = /cdrom force user = nobody force group = nobody locking = No Workgroup was defined as "HOMENET" before, changed it to domain name on the office laptop thinking it was the problem, but for no avail.

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  • Mapping XFCE4/xRDP sessions to users

    - by garrilla
    I have Ubuntu 13.10 with Xubuntu Desktop - XFCE4. I'm trying to use XDRP to allow MS Windows users to login to the machine with their own user. I've been a lot around the houses with this! I've find two half-way solutions, but can't get them to work as I'd like... 1) in /etc/xrdp/xrdp.ini I set the port to -1 [xrdp1] name=sesman-Xvnc lib=libvnc.so username=ask password=ask ip=127.0.0.1 port=-1 each time any user logs on they get a new session - they can never go back to their original session 2) in /etc/xrdp/xrdp.ini I set the port to 5912 (e.g) [xrdp1] name=sesman-Xvnc lib=libvnc.so username=ask password=ask ip=127.0.0.1 port=5912 each time any user logs on they always log on to the same session irrespective of their logon details ??) I found a mid-way solution, to create a lot of sessions by adding adding additional options in the xrdp.ini e.g. [xrdp8] name=Bob's Logon lib=libvnc.so username=ask password=ask ip=127.0.0.1 port=5913 [xrdp9] name=Jill's Logon lib=libvnc.so username=ask password=ask ip=127.0.0.1 port=5914 and so on, but he problem with this is that Jill can still log into Bob's remote session ??? Is it possible to to do what I'm trying to do? Maybe I have to use different tools?

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  • Oracle Linux Tips and Tricks: Using SSH

    - by Robert Chase
    Out of all of the utilities available to systems administrators ssh is probably the most useful of them all. Not only does it allow you to log into systems securely, but it can also be used to copy files, tunnel IP traffic and run remote commands on distant servers. It’s truly the Swiss army knife of systems administration. Secure Shell, also known as ssh, was developed in 1995 by Tau Ylonen after the University of Technology in Finland suffered a password sniffing attack. Back then it was common to use tools like rcp, rsh, ftp and telnet to connect to systems and move files across the network. The main problem with these tools is they provide no security and transmitted data in plain text including sensitive login credentials. SSH provides this security by encrypting all traffic transmitted over the wire to protect from password sniffing attacks. One of the more common use cases involving SSH is found when using scp. Secure Copy (scp) transmits data between hosts using SSH and allows you to easily copy all types of files. The syntax for the scp command is: scp /pathlocal/filenamelocal remoteuser@remotehost:/pathremote/filenameremote In the following simple example, I move a file named myfile from the system test1 to the system test2. I am prompted to provide valid user credentials for the remote host before the transfer will proceed.  If I were only using ftp, this information would be unencrypted as it went across the wire.  However, because scp uses SSH, my user credentials and the file and its contents are confidential and remain secure throughout the transfer.  [user1@test1 ~]# scp /home/user1/myfile user1@test2:/home/user1user1@test2's password: myfile                                    100%    0     0.0KB/s   00:00 You can also use ssh to send network traffic and utilize the encryption built into ssh to protect traffic over the wire. This is known as an ssh tunnel. In order to utilize this feature, the server that you intend to connect to (the remote system) must have TCP forwarding enabled within the sshd configuraton. To enable TCP forwarding on the remote system, make sure AllowTCPForwarding is set to yes and enabled in the /etc/ssh/sshd_conf file: AllowTcpForwarding yes Once you have this configured, you can connect to the server and setup a local port which you can direct traffic to that will go over the secure tunnel. The following command will setup a tunnel on port 8989 on your local system. You can then redirect a web browser to use this local port, allowing the traffic to go through the encrypted tunnel to the remote system. It is important to select a local port that is not being used by a service and is not restricted by firewall rules.  In the following example the -D specifies a local dynamic application level port forwarding and the -N specifies not to execute a remote command.   ssh –D 8989 [email protected] -N You can also forward specific ports on both the local and remote host. The following example will setup a port forward on port 8080 and forward it to port 80 on the remote machine. ssh -L 8080:farwebserver.com:80 [email protected] You can even run remote commands via ssh which is quite useful for scripting or remote system administration tasks. The following example shows how to  log in remotely and execute the command ls –la in the home directory of the machine. Because ssh encrypts the traffic, the login credentials and output of the command are completely protected while they travel over the wire. [rchase@test1 ~]$ ssh rchase@test2 'ls -la'rchase@test2's password: total 24drwx------  2 rchase rchase 4096 Sep  6 15:17 .drwxr-xr-x. 3 root   root   4096 Sep  6 15:16 ..-rw-------  1 rchase rchase   12 Sep  6 15:17 .bash_history-rw-r--r--  1 rchase rchase   18 Dec 20  2012 .bash_logout-rw-r--r--  1 rchase rchase  176 Dec 20  2012 .bash_profile-rw-r--r--  1 rchase rchase  124 Dec 20  2012 .bashrc You can execute any command contained in the quotations marks as long as you have permission with the user account that you are using to log in. This can be very powerful and useful for collecting information for reports, remote controlling systems and performing systems administration tasks using shell scripts. To make your shell scripts even more useful and to automate logins you can use ssh keys for running commands remotely and securely without the need to enter a password. You can accomplish this with key based authentication. The first step in setting up key based authentication is to generate a public key for the system that you wish to log in from. In the following example you are generating a ssh key on a test system. In case you are wondering, this key was generated on a test VM that was destroyed after this article. [rchase@test1 .ssh]$ ssh-keygen -t rsaGenerating public/private rsa key pair.Enter file in which to save the key (/home/rchase/.ssh/id_rsa): Enter passphrase (empty for no passphrase): Enter same passphrase again: Your identification has been saved in /home/rchase/.ssh/id_rsa.Your public key has been saved in /home/rchase/.ssh/id_rsa.pub.The key fingerprint is:7a:8e:86:ef:59:70:ef:43:b7:ee:33:03:6e:6f:69:e8 rchase@test1The key's randomart image is:+--[ RSA 2048]----+|                 ||  . .            ||   o .           ||    . o o        ||   o o oS+       ||  +   o.= =      ||   o ..o.+ =     ||    . .+. =      ||     ...Eo       |+-----------------+ Now that you have the key generated on the local system you should to copy it to the target server into a temporary location. The user’s home directory is fine for this. [rchase@test1 .ssh]$ scp id_rsa.pub rchase@test2:/home/rchaserchase@test2's password: id_rsa.pub                  Now that the file has been copied to the server, you need to append it to the authorized_keys file. This should be appended to the end of the file in the event that there are other authorized keys on the system. [rchase@test2 ~]$ cat id_rsa.pub >> .ssh/authorized_keys Once the process is complete you are ready to login. Since you are using key based authentication you are not prompted for a password when logging into the system.   [rchase@test1 ~]$ ssh test2Last login: Fri Sep  6 17:42:02 2013 from test1 This makes it much easier to run remote commands. Here’s an example of the remote command from earlier. With no password it’s almost as if the command ran locally. [rchase@test1 ~]$ ssh test2 'ls -la'total 32drwx------  3 rchase rchase 4096 Sep  6 17:40 .drwxr-xr-x. 3 root   root   4096 Sep  6 15:16 ..-rw-------  1 rchase rchase   12 Sep  6 15:17 .bash_history-rw-r--r--  1 rchase rchase   18 Dec 20  2012 .bash_logout-rw-r--r--  1 rchase rchase  176 Dec 20  2012 .bash_profile-rw-r--r--  1 rchase rchase  124 Dec 20  2012 .bashrc As a security consideration it's important to note the permissions of .ssh and the authorized_keys file.  .ssh should be 700 and authorized_keys should be set to 600.  This prevents unauthorized access to ssh keys from other users on the system.   An even easier way to move keys back and forth is to use ssh-copy-id. Instead of copying the file and appending it manually to the authorized_keys file, ssh-copy-id does both steps at once for you.  Here’s an example of moving the same key using ssh-copy-id.The –i in the example is so that we can specify the path to the id file, which in this case is /home/rchase/.ssh/id_rsa.pub [rchase@test1]$ ssh-copy-id -i /home/rchase/.ssh/id_rsa.pub rchase@test2 One of the last tips that I will cover is the ssh config file. By using the ssh config file you can setup host aliases to make logins to hosts with odd ports or long hostnames much easier and simpler to remember. Here’s an example entry in our .ssh/config file. Host dev1 Hostname somereallylonghostname.somereallylongdomain.com Port 28372 User somereallylongusername12345678 Let’s compare the login process between the two. Which would you want to type and remember? ssh somereallylongusername12345678@ somereallylonghostname.somereallylongdomain.com –p 28372 ssh dev1 I hope you find these tips useful.  There are a number of tools used by system administrators to streamline processes and simplify workflows and whether you are new to Linux or a longtime user, I'm sure you will agree that SSH offers useful features that can be used every day.  Send me your comments and let us know the ways you  use SSH with Linux.  If you have other tools you would like to see covered in a similar post, send in your suggestions.

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  • How do I mount a CIFS share via FSTAB and give full RW to Guest

    - by Kendor
    I want to create a Public folder that has full RW access. The problem with my configuration is that Windows users have no issues as guests (they can RW and Delete), my Ubuntu client can't do the same. We can only write and read, but not create or delete. Here is the my smb.conf from my server: [global] workgroup = WORKGROUP netbios name = FILESERVER server string = TurnKey FileServer os level = 20 security = user map to guest = Bad Password passdb backend = tdbsam null passwords = yes admin users = root encrypt passwords = true obey pam restrictions = yes pam password change = yes unix password sync = yes passwd program = /usr/bin/passwd %u passwd chat = *Enter\snew\s*\spassword:* %n\n *Retype\snew\s*\spassword:* %n\n *password\supdated\ssuccessfully* . add user script = /usr/sbin/useradd -m '%u' -g users -G users delete user script = /usr/sbin/userdel -r '%u' add group script = /usr/sbin/groupadd '%g' delete group script = /usr/sbin/groupdel '%g' add user to group script = /usr/sbin/usermod -G '%g' '%u' guest account = nobody syslog = 0 log file = /var/log/samba/samba.log max log size = 1000 wins support = yes dns proxy = no socket options = TCP_NODELAY panic action = /usr/share/samba/panic-action %d [homes] comment = Home Directory browseable = no read only = no valid users = %S [storage] create mask = 0777 directory mask = 0777 browseable = yes comment = Public Share writeable = yes public = yes path = /srv/storage The following FSTAB entry doesn't yield full R/W access to the share. //192.168.0.5/storage /media/myname/TK-Public/ cifs rw 0 0 This doesn't work either //192.168.0.5/storage /media/myname/TK-Public/ cifs rw,guest,iocharset=utf8,file_mode=0777,dir_mode=0777,noperm 0 0 Using the following location in Nemo/Nautilus w/o the Share being mounted does work: smb://192.168.0.5/storage/ Extra info. I just noticed that if I copy a file to the share after mounting, my Ubuntu client immediately make "nobody" be the owner, and the group "no group" has read and write, with everyone else as read-only. What am I doing wrong?

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  • Python Web Applications: What is the way and the method to handle Registrations, Login-Logouts and Cookies? [on hold]

    - by Phil
    I am working on a simple Python web application for learning purposes. I have chosen a very minimalistic and simple framework. I have done a significant amount of research but I couldn't find a source clearly explaining what I need, which is as follows: I would like to learn more about: User registration User Log-ins User Log-outs User auto-logins I have successfully handled items 1 and 3 due to their simple nature. However, I am confused with item 2 (log-ins) and item 4 (auto-logins). When a user enters username and password, and after hashing with salts and matching it in the DB; What information should I store in the cookies in order to keep the user logged in during the session? Do I keep username+password but encrypt them? Both or just password? Do I keep username and a generated key matching their password? If I want the user to be able to auto-login (when they leave and come back to the web page), what information then is kept in the cookies? I don't want to use modules or libraries that handle these things automatically. I want to learn basics and why something is the way it is. I would also like to point out that I do not mind reading anything you might offer on the topic that explains hows and whys. Possibly with algorithm diagrams to show the process. Some information: I know about setting headers, cookies, encryption (up to some level, obviously not an expert!), request objects, SQLAlchemy etc. I don't want any data kept in a single web application server's store. I want multiple app-servers to be handle a user, and whatever needs to be kept on the server to be done with a Postgres/MySQL via SQLAlchemy (I think, this is called stateless?) Thank you.

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  • Samba issue with sharing directories on NTFS/FAT32 (Mounted Drives) ???

    - by Microkernel
    Hi guys, I have some strange problems with Samba server. I am using samba Version 3.5.4 on Ubuntu 10.10. I have two windows-xp machines, one on VirtualBox on Ubuntu and another office laptop. Windows machine on VBox has no issues in accessing the shared folders, but the laptop is not able to access all the shared content. The issue faced on laptop is = Shared folders on Ext3 drives have no issues in accessing, but the contents shared on NTFS and FAT32 drives (mounted ones) are not accessible. When I try to open the shared folder, it asks for user name and password, but doesn't accept when I provide it. (even if I provide admin login details!!!). I changed workgroup value to the domain_name in office laptop, but still the problem persists... Here is the smdb.conf I am using... [global] workgroup = XXX.XXX.ORG server string = %h server (Samba, Ubuntu) map to guest = Bad User obey pam restrictions = Yes pam password change = Yes passwd program = /usr/bin/passwd %u passwd chat = *Enter\snew\s*\spassword:* %n\n *Retype\snew\s*\spassword:* %n\n *password\supdated\ssuccessfully* . unix password sync = Yes syslog = 0 log file = /var/log/samba/log.%m max log size = 1000 dns proxy = No usershare allow guests = Yes panic action = /usr/share/samba/panic-action %d guest ok = Yes [homes] comment = Home Directories [printers] comment = All Printers path = /var/spool/samba read only = No create mask = 0700 printable = Yes browseable = No [print$] comment = Samba server's CD-ROM path = /cdrom force user = nobody force group = nobody locking = No Workgroup Was defined as "HOMENET" before, changed it to domain name on the office laptop thinking it was the problem, but for no avail Thanks in advance Regards, Microkernel

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  • htaccess and htpasswd trouble

    - by hjpotter92
    This is the first time that I have ever tried working with .htpasswd and .htaccess files, so please point out my childish works. I have my apache document root set to /www/ on my debian server. Inside it, there's a folder named Logs/ which I want to restrict access using a htpasswd. I created my htpasswd file using the shell's htpasswd command. And this is the result: > user:<encoded password here> > hjp:<encoded password here> > hjpotter92:<encoded password here> I put this file named .htaccess inside /www/. The Logs/ has following htaccess file in it: > AuthName "Restricted Area" > AuthType Basic > AuthUserFile /www/.htpasswd > AuthGroupFile /dev/null > require valid-user This was again created using an online tool(I forgot its name/link, and can't search the browser-history now). The problem, as it might've already struck you is that I am experiencing no change on my Logs folder access. The folder is still accessible to everyone. I am running apache as root user(if that matters/helps). Please help/guide me. I've tried reading some htaccess guides and have followed some of older SO questions, but still haven't figured out a way to restrict access to Logs folder with a password.

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  • Windows recv method usage

    - by vandamon taigi
    I'm making a multiplayer game and I have an issue with the recv function ( or the send one , not sure ). Server side code : char* UserName = new char[256]; ZeroMemory(UserName,256); recv(sConnect,UserName,256,0); // works char* Password = new char[256]; ZeroMemory(Password,256); recv(sConnect,Password,256,0); // works users[ ++usercount ] = new Client(UserName,Password,sConnect); if( users[usercount] ->GetLogInSuccesful() ) send(sConnect,"0x0001",6,0); // debugging shows it gets here and sends the data. Client side code : send(server->getsConnect(),User,256,0); // works send(server->getsConnect(),Pass,256,0); // works char* Response = new char[6]; ZeroMemory(Response,6); recv(server->getsConnect(),Response,6,0); // gets stuck here. Any ideea why does it get stuck on that recv ? I also tried by making response [256] or such.

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  • Can I set up samba so it automatically allows all the local usernames and passwords?

    - by dialer
    I have set up samba like this (this is the complete smb.conf): [global] log file = /var/log/samba/log log level = 2 security = user [homes] browsable = false read only = no valid users = %S I'd like to enable every user on server to access their home directories, but for some unknown reason only my 'administrator' account can do so. (I have done that with ftp before, but now smb is also needed). When I try to smbclient -L localhost -U [user], I get NT_STATUS_LOGON_FAILURE, except with the administrator (which is the user created during the ubuntu installation, not root). The samba log file says NT_STATUS_NO_SUCH_USER: [2012/04/04 20:26:02.081454, 2] smbd/reply.c:554(reply_special) netbios connect: name1=LOCALHOST 0x20 name2=DIALER-X 0x0 [2012/04/04 20:26:02.081733, 2] smbd/reply.c:565(reply_special) netbios connect: local=localhost remote=dialer-x, name type = 0 [2012/04/04 20:26:02.087200, 2] auth/auth.c:314(check_ntlm_password) check_ntlm_password: Authentication for user [public] - [public] FAILED with error NT_STATUS_NO_SUCH_USER I suspect that I have to manually create samba users, but the man pages state that If the client has passed a username/password pair and that username/password pair is validated by the UNIX system's password programs, the connection is made as that username. To me that sounds like as long as the provided username/password is a valid login on the server, it should work. Am I missing something totally obvious? I don't want / can't afford to manually update the samba users and passwords to match the server's. 11.10

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  • MySQL can only log in as root, even after creating new users with their own database

    - by ionFish
    Problem: I just set up a Debian Wheezy installation for testing, and installed the LAMP packages and PMA. I can log in as root with my pre-defined password, create/edit/delete both databases and users. The problem comes when I create a new user 'something', set a password for it, and grant it all privileges on a table 'something' (same as the username). Upon connecting, it denies access to the user. Details: Host: localhost using MySQL 5.5.24-8 Creating user: CREATE USER 'something'@'%' IDENTIFIED BY '***';GRANT USAGE ON *.* TO 'something'@'%' IDENTIFIED BY '***' WITH MAX_QUERIES_PER_HOUR 0 MAX_CONNECTIONS_PER_HOUR 0 MAX_UPDATES_PER_HOUR 0 MAX_USER_CONNECTIONS 0;CREATE DATABASE IF NOT EXISTSsomething;GRANT ALL PRIVILEGES ONsomething.* TO 'something'@'%'; Checking privileges: GRANT USAGE ON *.* TO 'something'@'%' IDENTIFIED BY PASSWORD '*92F9DAF5F5129554509489FDB6A433510223C799'; Result: Access denied for user 'something'@'localhost' (using password: YES) More Info: I use this same exact procedure for the Squeeze distribution, and it works perfectly. Is there a chance it's because of Wheezy, or something else? I need to continue using Wheezy because of the updated packages (for this test server -- the others work fine), so 'just use Squeeze' is not an option. Note: I HAVE tried flush privileges; to no avail.

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  • What should a Java/SOA developer be able to do?

    - by Regular Joe
    Hello community. I got assigned the task to list the activities a Java Developer should be able to perform and create an estimate about the time it would take. I've came up with the following: S = Small complexity M = Medium complexity H = High complexity 1d = 1 day Create JDBC CRUD backend ( S=1d, M=5d, H=10d ) Create JSP/Servlet frontend for a CRUD app ( S=1d, M=10d, H=20d ) Create Swing desktop frontend ( S=1d, M=15d, H=30d) Create ORM based CRUD ... Create Webapp fronend with webframework ... This is thought for a Java "enterprise" developer. The other profile I have is SOA Developer, but I could not pass beyond: Create webservice ( S=.5d, M=2d, H=7d ) Q.- What other activities should a Java Developer be able to do? Q.- What activities should a SOA Developer be able to do? Please, help me with this, I know this is in the limit of the kind of questions that could be asked here, but I really need a little push on this, and I don't want to go to Yahoo Answers for this.

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  • Asp.Net Login control (Visual Web Dev)

    - by craig
    This is the code when you take the Login control from the toolbox. <%@ Page Language="C#" AutoEventWireup="true" CodeFile="Default.aspx.cs" Inherits="_Default" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title></title> </head> <body> <form id="form1" runat="server"> <div> <asp:Login ID="Login1" runat="server" onauthenticate="Login1_Authenticate" BackColor="#F7F7DE" BorderColor="#CCCC99" BorderStyle="Solid" BorderWidth="1px" Font-Names="Verdana" Font-Size="10pt"> <LayoutTemplate> <table border="0" cellpadding="1" cellspacing="0" style="border-collapse:collapse;"> <tr> <td> <table border="0" cellpadding="0"> <tr> <td align="center" colspan="2"> Log In</td> </tr> <tr> <td align="right"> <asp:Label ID="UserNameLabel" runat="server" AssociatedControlID="UserName">User Name:</asp:Label> </td> <td> <asp:TextBox ID="UserName" runat="server" ></asp:TextBox> <asp:RequiredFieldValidator ID="UserNameRequired" runat="server" ControlToValidate="UserName" ErrorMessage="User Name is required." ToolTip="User Name is required." ValidationGroup="Login1">*</asp:RequiredFieldValidator> </td> </tr> <tr> <td align="right"> <asp:Label ID="PasswordLabel" runat="server" AssociatedControlID="Password">Password:</asp:Label> </td> <td> <asp:TextBox ID="Password" runat="server" TextMode="Password"></asp:TextBox> <asp:RequiredFieldValidator ID="PasswordRequired" runat="server" ControlToValidate="Password" ErrorMessage="Password is required." ToolTip="Password is required." ValidationGroup="Login1">*</asp:RequiredFieldValidator> </td> </tr> <tr> <td colspan="2"> <asp:CheckBox ID="RememberMe" runat="server" Text="Remember me next time." /> </td> </tr> <tr> <td align="center" colspan="2" style="color:Red;"> <asp:Literal ID="FailureText" runat="server" EnableViewState="False"></asp:Literal> </td> </tr> <tr> <td align="right" colspan="2"> <asp:Button ID="LoginButton" runat="server" CommandName="Login" Text="Log In" ValidationGroup="Login1" onclick="LoginButton_Click" /> </td> </tr> </table> </td> </tr> </table> </LayoutTemplate> <TitleTextStyle BackColor="#6B696B" Font-Bold="True" ForeColor="#FFFFFF" /> </asp:Login> </div> </form> </body> </html> Part of my aspx.cs protected void LoginButton_Click(object sender, EventArgs e) { String sUserName = UserName.Text; String sPassword = Password.Text; Error 1 The name 'UserName' does not exist in the current context Error 2 The name 'Password' does not exist in the current context Error 3 'ASP.default_aspx' does not contain a definition for 'Login1_Authenticate' and no extension method 'Login1_Authenticate' accepting a first argument of type 'ASP.default_aspx' could be found (are you missing a using directive or an assembly reference?) What am I doing wrong?

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  • My PHP login no longer works

    - by Matt Clayton
    This page worked like a charm for years... enter the correspondng user id and password and you would be redirected to your directory. Now suddenly, all attempts to log in - valid or otherwise - result in the page remaining static... no message, no redirect, nothing. Nothing in the code has changed, it just plain doesn't work anymore. Could this be the result of some kind of change on the server side? Yeah, I know it's not super secure, but it was good enough for our purposes. I'm certainly open to better suggestions. I just need it to work... and keep working. Please be gentle! I know almost nothing of programming. Here is the page code: <meta http-equiv="Content-Type" content="text/html;charset=utf-8" > <link href="ilium.css" rel="stylesheet" media="screen"> <title>Ilium: Client Login</title> </head> <body bgcolor="#bfbfcc" background="img/loginbg.gif"> <?php /* init vars */ $userExists = false; $userIndex = -1; $authenicated = false; /*********************************************** * edit this to add new users/password * * - add user/pass/directory to the array * * below: must be in same array index to work * ***********************************************/ $user = array('foo', 'bar'); $pass = array('foo', 'bar'); $directory = array('foo', 'bar'); // run user/pass check if data passed if (isset($username) && isset($password)) { // check if user name exists for ($i = 0; $i < count($user); $i++) { if ($user[$i] == $username) { $userExists = true; $userIndex = $i; break; } } // so user exists, now test password if ($userExists) { $message = $message . "Username Valid<br>\n"; if ($pass[$userIndex] == $password) { $authenicated = true; $link = "/incoming/clients050203/" . $directory[$userIndex] . "/"; $message = $message . "Password Valid - Redirecting to your folder...<br>\n"; } else { $message = $message . "Incorrect Password<br>\n"; } } else { $message = $message . "Incorrect User Name<br>\n"; } } ?> <?php // user has been authenicated - move them to the correct directory if ($authenicated) { echo "<META HTTP-EQUIV=Refresh CONTENT=\"0; URL=" . $link . "\">"; } ?> <img src="img/spacer.gif" alt="" width="1" height="112" border="0"> <form action="login.php" method="post"> <table width="496"> <tr> <td width="100"></td> <td colspan="4" width="469"><img src="img/please.gif" alt="" width="469" height="19" border="0"></td> </tr> <tr> <td width="100"><img src="img/spacer.gif" alt="" width="100" height="1" border="0"></td> <td width="227"> <img src="img/spacer.gif" alt="" width="227" height="1" border="0"><br> </td> <td align="right" valign="top" width="84"><input type="text" name="username" size="12"><br></td> <td width="43"><img src="img/spacer.gif" alt="" width="43" height="1" border="0"><br> <br> </td> <td align="right" valign="top" width="109"><input type="password" name="password" size="16"> <p><br> </p> </td> </tr> <tr> <td width="100"></td> <td valign="top" width="227"><div class="messages"><?=$message?></div></td> <td width="84"><br> </td> <td width="43"><br> </td> <td align="right" width="109"><input type="image" src="img/enter.gif" ALT="enter"><br> <br> <br> <br> <br> </td> </tr> </table> </form> </body> </html>

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  • What should a Java/SOA developer be able to do?

    - by Regular Joe
    I got assigned the task to list the activities a Java Developer should be able to perform and create an estimate about the time it would take. I've came up with the following: Create JDBC CRUD backend ( S=1d, M=5d, H=10d ) Create JSP/Servlet frontend for a CRUD app ( S=1d, M=10d, H=20d ) Create Swing desktop frontend ( S=1d, M=15d, H=30d) Create ORM based CRUD etc. Create Webapp fronend with webframework etc Where.. S = Small complexity M = Medium complexity H = High complexity 1d = 1 day This is thought for a Java "enterprise" developer. The other profile I have is SOA Developer, but I could not pass beyond: Create webservice ( S=.5d, M=2d, H=7d ) Q.- What other activities should a Java Developer be able to do? Q.- What activities should a SOA Developer be able to do? Please, help me with this, I know this is in the limit of the kind of questions that could be asked here, but I really need a little push on this, and I don't want to go to Yahoo Answers for this.

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  • How can my CGI program access non-browseable files?

    - by Zerobu
    I was wondering if it was possible to read a text file that was located in a directory called "/home/user/files" I wanted to read it from my cgi-bin which is located in /home/user/cgi-bi/ Below is my code, #!/usr/bin/perl use strict; use CGI; #Virtual Directory #Steffan Harris eval { use constant PASSWORD => 'perl'; use constant UPLOAD_DIR => '/home/sharris2/files'; sub mapToFile { print chdir UPLOAD_DIR; } #This function will list all files in a directory. sub listDirectoryFiles { chdir UPLOAD_DIR; my @files = <*>; mapToFile; print<<LIST; <h2>Current Files</h2> <ul> LIST if(!$files[0]) { print" </ul>\n<em>No files in directory</em>"; } foreach(@files) { print" <li>$_</li>"; } print " </ul>\n"; } #This function generates a 404 Not Found error sub generate404 { print<<RESPONSE; Status: 404 Not Found Content-Type: text/html <html> <head><title>404 Not Found</title></head> <body> <p> <h1>404 - Not Found</h1> </p> The requested URL <b>$ENV{"HTTP_HOST"}$ENV{"REQUEST_URI"}</b> was not found on the server. </body> </html> RESPONSE exit; } #This function checks the path info to see if it matches a file in the UPLOAD_DIR directory, If it does not, then it returns a 404 error sub checkExsistence { if($ENV{"PATH_INFO"}) { chdir UPLOAD_DIR; my @files = <*>; if(!$files[0] and $ENV{"PATH_INFO"} eq "/") { return; } foreach(@files) { if($ENV{"PATH_INFO"} eq "/".$_ || $ENV{"PATH_INFO"} eq "/") { print "yes"; return; } } generate404; } } sub checkPassword { my ($password, $cgi); $cgi = new CGI; $password = $cgi->param('passwd'); unless($password eq PASSWORD) { print<<RESPONSE; Status: 200 OK Content-Type: text/html <html> <head> <title>Incorrect Password</title> </head> <body> <h1>Invalid password entered.</h1> <h3><a href="/~sharris2/cgi-bin/files/">Go Back</a></h3> </body> RESPONSE exit; } } sub upLoadFile { checkPassword; my ($uploadfile, $cgi); $cgi = new CGI; $uploadfile = $cgi->upload('uploadfile'); chdir UPLOAD_DIR; $uploadfile or die "Did not receive a file to upload"; open my $FILE, '>', UPLOAD_DIR."/$uploadfile" or die "$!"; while(<$uploadfile>) { print $FILE $_; } } #Start of main part of program my $cgi = new CGI; if(!$ENV{"PATH_INFO"}) { print $cgi->redirect('/~sharris2/cgi-bin/files/'); } checkExsistence; if($ENV{"REQUEST_METHOD"} eq "POST") { upLoadFile; } print <<"HEADERS"; Status: 200 OK Content-Type: text/html HEADERS print <<"HTML"; <html> <head> <title>Virtual Directory</title> </head> <body> HTML listDirectoryFiles; print<<HTML; <h2>Upload a new file</h2> <form method = "POST" enctype = "multipart/form-data" action = "/~sharris2/cgi-bin/files/" /> File:<input type = "file" name="uploadfile"/> <p>Password: <input type = "password" name ="passwd"/></p> <p><input type = "submit" value= "Submit File" /></p> </form> </body> </html> HTML };

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  • layout is not included in all pages in asp.net mvc4 application

    - by Ahmed
    I am developing an asp.net mvc4 application with Bootstrap 3 and i've _Layout.cshtml in "Shared" folder , in Views, i've two pages, "Index and "Register" and i've included Layout in both of these Views but It seems that Layout is included in only "Index and not in "Register" View. Following are my Index and Register Views @{ ViewBag.Title = "Index"; Layout = "~/Views/Shared/_Layout.cshtml"; } <h2 align="center" class="bg-info">Login</h2> <form class="form-horizontal" role="form"> <div class="form-group"> <label for="inputEmail3" class="col-sm-2 control-label"><strong>UserName : </strong></label> <div class="col-sm-10"> <input type="email" class="form-control" id="inputEmail3" placeholder="UserName"> </div> </div> <div class="form-group"> <label for="inputPassword3" class="col-sm-2 control-label"><strong>Password</strong></label> <div class="col-sm-10"> <input type="password" class="form-control" id="inputPassword3" placeholder="Password"> </div> </div> <div class="form-group"> <div class="col-sm-offset-2 col-sm-10"> <div class="checkbox"> <label> <input type="checkbox"> Remember me </label> </div> </div> </div> <div class="form-group"> <div class="col-sm-offset-2 col-sm-10"> <button type="submit" class="btn btn-primary">Sign in</button> </div> </div> <h2 align="center" class="bg-info">SignIn With Other Services</h2> </form> <form class="form-horizontal" role="form" method="post" action="/Home/FacebookLogin"> <div class="form-group"> <div class="col-sm-offset-2 col-sm-10"> <button type="submit" class="btn btn-primary">SignIn with Facebook</button> </div> </div> </form> <h2 align="center" class="bg-info">Don't Have an Account?</h2> <form class="form-horizontal" role="form" method="post" action="/Home/Register"> <div class="form-group"> <div class="col-sm-offset-2 col-sm-10"> <button type="submit" class="btn btn-primary">Register</button> </div> </div> </form> ![@{ ViewBag.Title = "Register"; Layout = "~/Views/Shared/_Layout.cshtml"; } <h2 align="center" class="bg-info">Register</h2> <form class="form-horizontal" role="form"> <div class="form-group"> <label for="inputEmail3" class="col-sm-2 control-label"><strong>UserName : </strong></label> <div class="col-sm-10"> <input type="email" class="form-control" id="uname" name="uname" placeholder="UserName"> <input type="button" class="btn btn-primary" id="check" value="Check Availability" > <h4 class="bg-warning"></h4> </div> </div> <div class="form-group"> <label for="inputPassword3" class="col-sm-2 control-label"><strong>Password</strong></label> <div class="col-sm-10"> <input type="password" class="form-control" id="upass" name="upass" placeholder="Password"> </div> </div> <div class="form-group"> <label for="inputPassword3" class="col-sm-2 control-label"><strong>Retype Password</strong></label> <div class="col-sm-10"> <input type="password" class="form-control" id="retype" placeholder="Password"> </div> </div> <div class="form-group"> <div class="col-sm-offset-2 col-sm-10"> <button type="submit" class="btn btn-primary">Register</button> </div> </div> </form>]

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  • question on find value in array

    - by davit-datuashvili
    i have seen a few days ago such problem there is given two array find elements which are common of these array one of the solution was sort big array and then use binary search algorithm and also there is another algorithm- brute-force algorithm for (int i=0;i<array1.length;i++){ for (int j=0;j<array2.length;j++){ if (array1[i]==array2[j]){ //code here } } it's complexity is O(array1.length*array2.length); and i am interested the first method's complexity is also same yes? because we should sort array first and then use search method binary search algorithm's complexity is log_2(n) so it means that total time will be array.length*log_2(n) and about sort? please explain me which is better

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  • struts2-json-plugin not retrieving json data from action class for Struts-JQuery-Plugin grid

    - by thebravedave
    Hello, Im having an issue getting json working with the struts-jquery-plugin-2.1.0 I have included the struts2-json-plugin-2.1.8.1 in my classpath as well. Im sure that I have my struts-jquery-plugin configured correctly because the grid loads, but doesnt load the data its supposed to get from the action class that has been json'ized. The documentation with the json plugin and the struts-jquery plugin leaves ALOT of gaps that I cant even find with examples/tutorials, so I come to the community at stackoverflow. My action class has a property called gridModel thats a List with a basic POJO called Customer. Customer is a pojo with one property, id. I have a factory that supplies the populated List to the actions List property which i mentioned called gridModel. Heres how i set up my struts.xml file: <constant name="struts.devMode" value="true"/> <constant name="struts.objectFactory" value="guice"/> <package name="org.webhop.ywdc" namespace="/" extends="struts-default,json-default"> <result-types> <result-type name="json" class="com.googlecode.jsonplugin.JSONResult"> </result-type> </result-types> <action name="login" class="org.webhop.ywdc.LoginAction" > <result type="json"></result> <result name="success" type="dispatcher">/pages/uiTags/Success.jsp</result> <result name="error" type="redirect">/pages/uiTags/Login.jsp</result> <interceptor-ref name="cookie"> <param name="cookiesName">JSESSIONID</param> </interceptor-ref> </action> <action name="logout" class="org.webhop.ywdc.LogoutAction" > <result name="success" type="redirect">/pages/uiTags/Login.jsp</result> </action> </package> In the struts.xml file i set the and in my action i listed in the action configuration. Heres my jsp page that the action loads: <%@ taglib prefix="s" uri="/struts-tags" % <%@ taglib prefix="sj" uri="/struts-jquery-tags"% <%@ taglib prefix="sjg" uri="/struts-jquery-grid-tags"% <%@ page language="java" contentType="text/html" import="java.util.*"% Welcome, you have logged in! <s:url id="remoteurl" action="login"/> <sjg:grid id="gridtable" caption="Customer Examples" dataType="json" href="%{remoteurl}" pager="false" gridModel="gridModel" > <sjg:gridColumn name="id" key="true" index="id" title="ID" formatter="integer" sortable="false"/> </sjg:grid> Welcome, you have logged in. <br /> <b>Session Time: </b><%=new Date(session.getLastAccessedTime())%> <h2>Password:<s:property value="password"/></h2> <h2>userId:<s:property value="userId"/></h2> <br /> <a href="<%= request.getContextPath() %>/logout.action">Logout</a><br /><br /> ID: <s:property value="id"/> session id: <s:property value="JSESSIONID"/> </body> Im not really sure how to tell what json the json plugin is creating from the action class. If i did know how i could tell if it wasnt formed properly. As far as I know if I specificy in my action configuration in struts.xml, that the grid, which is set to read json and knows to look for "gridModel" will then automatically load the json to the grid, but its not. Heres my action class: public class LoginAction extends ActionSupport { public String JSESSIONID; public int id; private String userId; private String password; public Members member; public List<Customer> gridModel; public String execute() { Cookie cookie = new Cookie("ywdcsid", password); cookie.setMaxAge(3600); HttpServletResponse response = ServletActionContext.getResponse(); response.addCookie(cookie); HttpServletRequest request = ServletActionContext.getRequest(); Cookie[] ckey = request.getCookies(); for(Cookie c: ckey) { System.out.println(c.getName() + "/cookie_name + " + c.getValue() + "/cookie_value"); } Map requestParameters = ActionContext.getContext().getParameters();//getParameters(); String[] testString = (String[])requestParameters.get("password"); String passwordString = testString[0]; String[] usernameArray = (String[])requestParameters.get("userId"); String usernameString = usernameArray[0]; Injector injector = Guice.createInjector(new GuiceModule()); HibernateConnection connection = injector.getInstance(HibernateConnection.class); AuthenticationServices currentService = injector.getInstance(AuthenticationServices.class); currentService.setConnection(connection); currentService.setInjector(injector); member = currentService.getMemberByUsernamePassword(usernameString, passwordString); userId = member.getUsername(); password = member.getPassword(); CustomerFactory customerFactory = new CustomerFactory(); gridModel = customerFactory.getCustomers(); if(member == null) { return ERROR; } else { id = member.getId(); Map session = ActionContext.getContext().getSession(); session.put(usernameString, member); return SUCCESS; } } public String logout() throws Exception { Map session = ActionContext.getContext().getSession(); session.remove("logged-in"); return SUCCESS; } public List<Customer> getGridModel() { return gridModel; } public void setGridModel(List<Customer> gridModel) { this.gridModel = gridModel; } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } public String getUserId() { return userId; } public void setUserId(String userId) { this.userId = userId; } public String getJSESSIONID() { return JSESSIONID; } public void setJSESSIONID(String jsessionid) { JSESSIONID = jsessionid; } } Please help me with this problem. You will make my week, as this is a major bottleneck for me :( thanks so much, thebravedave

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  • Hibernate Exception, what wrong ? [[Exception in thread "main" org.hibernate.InvalidMappingException

    - by user195970
    I use netbean 6.7.1 to write "hello world" witch hibernate, but I get some errors, plz help me, thank you very much. my exception init: deps-module-jar: deps-ear-jar: deps-jar: Copying 1 file to F:\Documents and Settings\My Dropbox\DropboxNetBeanProjects\loginspring\build\web\WEB-INF\classes compile-single: run-main: Oct 25, 2009 2:44:05 AM org.hibernate.cfg.Environment <clinit> INFO: Hibernate 3.2.5 Oct 25, 2009 2:44:05 AM org.hibernate.cfg.Environment <clinit> INFO: hibernate.properties not found Oct 25, 2009 2:44:05 AM org.hibernate.cfg.Environment buildBytecodeProvider INFO: Bytecode provider name : cglib Oct 25, 2009 2:44:05 AM org.hibernate.cfg.Environment <clinit> INFO: using JDK 1.4 java.sql.Timestamp handling Oct 25, 2009 2:44:05 AM org.hibernate.cfg.Configuration configure INFO: configuring from resource: /hibernate.cfg.xml Oct 25, 2009 2:44:05 AM org.hibernate.cfg.Configuration getConfigurationInputStream INFO: Configuration resource: /hibernate.cfg.xml Oct 25, 2009 2:44:06 AM org.hibernate.cfg.Configuration addResource INFO: Reading mappings from resource : hibernate/Tbluser.hbm.xml Oct 25, 2009 2:44:06 AM org.hibernate.util.XMLHelper$ErrorLogger error SEVERE: Error parsing XML: XML InputStream(1) Document is invalid: no grammar found. Oct 25, 2009 2:44:06 AM org.hibernate.util.XMLHelper$ErrorLogger error SEVERE: Error parsing XML: XML InputStream(1) Document root element "hibernate-mapping", must match DOCTYPE root "null". Exception in thread "main" org.hibernate.InvalidMappingException: Could not parse mapping document from resource hibernate/Tbluser.hbm.xml at org.hibernate.cfg.Configuration.addResource(Configuration.java:569) at org.hibernate.cfg.Configuration.parseMappingElement(Configuration.java:1587) at org.hibernate.cfg.Configuration.parseSessionFactory(Configuration.java:1555) at org.hibernate.cfg.Configuration.doConfigure(Configuration.java:1534) at org.hibernate.cfg.Configuration.doConfigure(Configuration.java:1508) at org.hibernate.cfg.Configuration.configure(Configuration.java:1428) at org.hibernate.cfg.Configuration.configure(Configuration.java:1414) at hibernate.CreateTest.main(CreateTest.java:22) Caused by: org.hibernate.InvalidMappingException: Could not parse mapping document from invalid mapping at org.hibernate.cfg.Configuration.addInputStream(Configuration.java:502) at org.hibernate.cfg.Configuration.addResource(Configuration.java:566) ... 7 more Caused by: org.xml.sax.SAXParseException: Document is invalid: no grammar found. at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(ErrorHandlerWrapper.java:195) at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.error(ErrorHandlerWrapper.java:131) at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(XMLErrorReporter.java:384) at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(XMLErrorReporter.java:318) at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.scanStartElement(XMLNSDocumentScannerImpl.java:250) at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl$NSContentDriver.scanRootElementHook(XMLNSDocumentScannerImpl.java:626) at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl$FragmentContentDriver.next(XMLDocumentFragmentScannerImpl.java:3095) at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl$PrologDriver.next(XMLDocumentScannerImpl.java:921) at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(XMLDocumentScannerImpl.java:648) at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.next(XMLNSDocumentScannerImpl.java:140) at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(XMLDocumentFragmentScannerImpl.java:510) at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:807) at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:737) at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(XMLParser.java:107) at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.parse(AbstractSAXParser.java:1205) at com.sun.org.apache.xerces.internal.jaxp.SAXParserImpl$JAXPSAXParser.parse(SAXParserImpl.java:522) at org.dom4j.io.SAXReader.read(SAXReader.java:465) at org.hibernate.cfg.Configuration.addInputStream(Configuration.java:499) ... 8 more Java Result: 1 BUILD SUCCESSFUL (total time: 1 second) hibernate.cfg.xml <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd"> <hibernate-configuration> <session-factory> <property name="hibernate.dialect">org.hibernate.dialect.MySQLDialect</property> <property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property> <property name="hibernate.connection.url">jdbc:mysql://localhost:3306/hibernate</property> <property name="hibernate.connection.username">root</property> </session-factory> </hibernate-configuration> Tbluser.hbm.xml <?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <!-- Generated Oct 25, 2009 2:37:30 AM by Hibernate Tools 3.2.1.GA --> <hibernate-mapping> <class name="hibernate.Tbluser" table="tbluser" catalog="hibernate"> <id name="userId" type="java.lang.Integer"> <column name="userID" /> <generator class="identity" /> </id> <property name="username" type="string"> <column name="username" length="50" /> </property> <property name="password" type="string"> <column name="password" length="50" /> </property> <property name="email" type="string"> <column name="email" length="50" /> </property> <property name="phone" type="string"> <column name="phone" length="50" /> </property> <property name="groupId" type="java.lang.Integer"> <column name="groupID" /> </property> </class> </hibernate-mapping> Tbluser.java package hibernate; // Generated Oct 25, 2009 2:37:30 AM by Hibernate Tools 3.2.1.GA /** * Tbluser generated by hbm2java */ public class Tbluser implements java.io.Serializable { private Integer userId; private String username; private String password; private String email; private String phone; private Integer groupId; public Tbluser() { } public Tbluser(String username, String password, String email, String phone, Integer groupId) { this.username = username; this.password = password; this.email = email; this.phone = phone; this.groupId = groupId; } public Integer getUserId() { return this.userId; } public void setUserId(Integer userId) { this.userId = userId; } public String getUsername() { return this.username; } public void setUsername(String username) { this.username = username; } public String getPassword() { return this.password; } public void setPassword(String password) { this.password = password; } public String getEmail() { return this.email; } public void setEmail(String email) { this.email = email; } public String getPhone() { return this.phone; } public void setPhone(String phone) { this.phone = phone; } public Integer getGroupId() { return this.groupId; } public void setGroupId(Integer groupId) { this.groupId = groupId; } }

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