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• What is the php syntax for a REGEXP that changes "Last, First" into "Last..First"?

  - by ggg

  I need to create a php search function for names and need to change LastName, FirstName into LastName..FirstName to search the database. I don't know if this helps, but the string will originally be in the form a variable ($Client). I need the syntax for the three statements that find the string, matches, and makes the changes.

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• How does :g/^$/,/./-j (reduce multiple blank lines to a single blank) work in vim?

  - by Mert Nuhoglu

  In the article, Vim Regular Expressions, Oleg Raisky gives the following command to reduce multiple blank lines to a single blank: :g/^$/,/./-j Can someone please describe how this works? I know :g command and regular expressions. But I didn't understand what the part /,/./-j does.

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• preg_replace function to append a string to all the hyperlinks of a page

  - by KoolKabin

  hi guys, i want to append my own value to all hyperlinks in a page... e.g if there are links: <a href="abc.htm?val=1">abc 1</a> <br/> <a href="abc.htm?val=2">abc 1</a> <br/> <a href="abc.htm?val=3">abc 1</a> <br/> <a href="abc.htm?val=4">abc 1</a> <br/> I want to add next var like "type=int" to all hyperlinks output should be: <a href="abc.htm?val=1&type=int">abc 1</a> <br/> <a href="abc.htm?val=2&type=int">abc 1</a> <br/> <a href="abc.htm?val=3&type=int">abc 1</a> <br/> <a href="abc.htm?val=4&type=int">abc 1</a> <br/> I hope it can be done quite easily with preg_replace function

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• Regular Expression :match string containing only non repeating words

  - by nash

  I have this situation(Java code): 1) a string such as : "A wild adventure" should match. 2) a string with adjacent repeated words: "A wild wild adventure" shouldn't match. With this regular expression: .* \b(\w+)\b\s*\1\b.* i can match strings containing adjacent repeated words. How to reverse the situation i.e how to match strings which do not contain adjacent repeat words

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• Can a repeated piece of regular expression create multiple groups? Such as this example...

  - by Yousui

  Hi guys, I'm using RUBY 's regular expression to deal with text such as ${1:aaa|bbbb} ${233:aaa | bbbb | ccc ccccc } ${34: aaa | bbbb | cccccccc |d} ${343: aaa | bbbb | cccccccc |dddddd ddddddddd} ${3443:a aa|bbbb|cccccccc|d} ${353:aa a| b b b b | c c c c c c c c | dddddd} I want to get the trimed text between each pipe line. For example, for the first line of my upper example, I want to get the result aaa and bbbb, for the second line, I want aaa, bbbb and ccc ccccc. Now I have wrote a piece of regular expression and a piece of ruby code to test it: array = "${33:aaa|bbbb|cccccccc}".scan(/\$\{\s*(\d+)\s*:(\s*[^\|]+\s*)(?:\|(\s*[^\|]+\s*))+\}/) puts array Now my problem is the (?:\|(\s*[^\|]+\s*))+ part can't create multiple groups. I don't know how to solve this problem, because the number of text I need in each line is variable. Anyone can help? Great thanks.

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• With PHP preg_match_all, get value of href

  - by Jeremy Dicaire

  Hi, I don'T really understabd how regular expressions works even after I read this tutorial http://www.webcheatsheet.com/php/regular_expressions.php Here is what I need to find: And it should return: http://link Here is what I tried: $find = preg_match_all('/<link type="text/html" rel="alternate" href=".*',$file,$patterns2); You can laught :) Thanks in advance for your help and your time :)

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• Ruby: backslash all non-alphanumeric characters in a string

  - by HBlend

  I have a script where I need to take a user's password and then run a command line using it. I need to backslash all (could be more then one) non-alphanumeric characters in the password. I have tried several things at this point including the below but getting no where. This has to be easy, just missing it. Tried these and several others: password = password.gsub(/(\W)/, '\\1') password = password.gsub(/(\W)/, '\\\1') password = password.gsub(/(\W)/, '\\\\1')

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• Mod rewrite with multiple query strings

  - by Boris

  Hi, I'm a complete n00b when it comes to regular expressions. I need these redirects: (1) www.mysite.com/products.php?id=001&product=Product-Name&source=Source-Name should become -> www.mysite.com/Source-Name/001-Product-Name (2) www.mysite.com/stores.php?id=002&name=Store-Name should become -> www.mysite.com/002-Store-Name Any help much appreciated :)

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• [Python] OR in regular expression?

  - by www.yegorov-p.ru

  Hello. I have text file with several thousands lines. I want to parse this file into database and decided to write a regexp. Here's part of file: blablabla checked=12 unchecked=1 blablabla unchecked=13 blablabla checked=14 As a result, I would like to get something like (12,1) (0,13) (14,0) Is it possible?

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• replacing text within quotes until next quote

  - by Jordan Trainor

  String input = "helloj\"iojgeio\r\ngsk\\"jopri\"gj\r\negjoijisgoe\"joijsofeij\"\"\"ojgsoij\""; This is my current code that works but iv added some code that has to run before this which makes some '"' split onto another line thus making the code below obsolute unless under certain cirumstances the '"' is not put onto the next line. firstQuote = input.IndexOf("\""); lastQuote = input.LastIndexOf("\""); input = input.Substring(0, firstQuote) + "<span>quote" + input.Substring(firstQuote + 1, lastQuote - (firstQuote + 1) + "quote</span>" + input.Substring(lastQuote + 1, lines.Length - (lastQuote + 1); How could I change the input string from input = "helloj\"iojgeio\r\ngsk\\"jopri\"gj\r\negjoijisgoe\"joijsofeij\"\"\"ojgsoij\""; to input = "helloj(<span>quoteiojgeio\r\ngsk\\"jopriquote</span>gj\r\negjoijisgoe<span>quotejoijsofeijquote</span>quote<span>quote</span>ojgsoij<span>quote</span>";

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• Perl equivalent of PHP's preg_callback

  - by Joseph

  Do we have a preg_callback equivalent in Perl ? Lets say I want to match something and replace it with the return value of the function that is called with the matched thing.

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• Why regular experssion's "non-capturing" group is not working

  - by Jim Horng

  as my snippet below, the non-capturing group "(?:aaa)" should be ignored in matching result, so the result should be "_bbb" only. however, I get "aaa_bbb" in matching result only when I specify group(2) does it show "_bbb". import re string1 = "aaa_bbb" print(re.match(r"(?:aaa)(_bbb)", string1).group()) >>> aaa_bbb

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• How to use regular expressions to pull a substring? (screen scraping)

  - by Diego

  Hey guys, i'm really trying to understand regular expressions while scraping a site, i've been using it in my code enough to pull the following, but am stuck here. I need to quickly grab this: http://www.example.com/online/store/TitleDetail?detail&sku=123456789 from this: ('<a href="javascript:if(handleDoubleClick(this.id)){window.location=\'http://www.example.com/online/store/TitleDetail?detail&sku=123456789\';}" id="getTitleDetails_123456789">\r\n\t\t\t \tcheck store inventory\r\n\t\t\t </a>', 1) This is where I got confused. any ideas?

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• Easiest way to convert a URL to a hyperlink in a C# string?

  - by nbirkes

  I am consuming the Twitter API and want to convert all URLs to hyperlinks. What is the most effective way you've come up with to do this? from string myString = "This is my tweet check it out http://tinyurl.com/blah"; to This is my tweet check it out <a href="http://tinyurl.com/blah">http://tinyurl.com/>blah</a>

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• How to use PHP preg_replace regular expression to find and replace text

  - by Roger

  I wrote this PHP code to make some substitutions: function cambio($txt){ $from=array( '/\+\>([^\+\>]+)\<\+/', //finds +>text<+ '/\%([^\%]+)\%/', //finds %text% ); $to=array( '<span class="P">\1</span>', '<span>\1</span>', ); return preg_replace($from,$to,$txt); } echo cambio('The fruit I most like is: +> %apple% %banna% %orange% <+.'); Resulting into this: The fruit I most like is: <span class="P"> <span>apple</span> <span>banna</span> <span>orange</span> </span>. however I needed to identify the fruit's span tags, like this: The fruit I most like is: <span class="P"> <span class="a">apple</span> <span class="b">banna</span> <span class="c">coco</span> </span>. I'd buy a fruit to whom discover a regular expression to accomplish this :-)

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• parse youtube video id using preg_match

  - by Webbo

  Hi, I am attempting to parse the video ID of a youtube URL using preg_match. I found a regular expression on this site that appears to work; (?<=v=)[a-zA-Z0-9-]+(?=&)|(?<=[0-9]/)[^&\n]+|(?<=v=)[^&\n]+ As shown in this pic; http://i.imgur.com/SQJW2.jpg My PHP is as follows, but it doesn't work (gives Unknown modifier '[' error)... <? $subject = "http://www.youtube.com/watch?v=z_AbfPXTKms&NR=1"; preg_match("(?<=v=)[a-zA-Z0-9-]+(?=&)|(?<=[0-9]/)[^&\n]+|(?<=v=)[^&\n]+", $subject, $matches); print "<pre>"; print_r($matches); print "</pre>"; ?> Cheers

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• jquery sortable with regexp

  - by Chris Lively

  I am trying to figure out the right regexp to match on list item id's. For example: <ul id="MyList" class="connectedSortable"> <li id="id=1-32">Item 1</li> <li id="id=2_23">Item 2</li> <li id="id=3">Item 3</li> <li id="id=4">Item 4</li> <li id="id=5">Item 5</li> <li id="id=6">Item 6</li> </ul> On the serialize method, I want it to pull everything after the equal sign (=) $(function () { $("#MyList, #OtherList").sortable({ connectWith: '.connectedSortable', update: function () { $("#MyListOrder").val($("#MyList").sortable('serialize', { regexp: '/(.+)[=](.+)/)' })); } }).disableSelection(); }); I tried the above, but that didn't quite work. My regexp expression is wrong and I don't know what it should be. Ideas?

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• Dreamweaver regular expression substitution followed by number

  - by mark

  Hi. I'm using Dreamweaver to update copyright dates across my site. I want to preserve the existing spacing (or lack thereof) between years. Examples: © 2002-2008 should update to © 2002-2009 © 2003 - 2008 should update to © 2003 - 2009 This is the regular expression I'm using to accomplish this in Dreamweaver's find & replace function Find: ©\s*(\d{4}\s*-\s*)\d{3}[^9] Replace: © $1 2009 Here's the PROBLEM: This expression works, but has that that extra space between the hyphen and 2009. If I write the replace expression without the space, as © $12009 then dreamweaver looks for the 12,009th substitution in the find expression, and, not finding one, prints $12009. Any ideas?

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• Regexp look-behind to match internet speeds

  - by Sandman

  So the user may search for "10 mbit" after which I want to capture the "10" so I can use it in a speed-search rather than a string-search. This isn't a problem, the below regexp does this fine: if (preg_match("/(\d+)\smbit/", $string)){ ... } But, the user may search for something like "10/10 mbit" or "10-100 mbit". I don't want to match those with the above regexp - they should be handled in another fashion. So I would like a regexp that matches "10 mbit" if the number is all-numeric as a whole word (i.e. contained by whitespace, newline or lineend/linestart) Using lookbehind, I did this: if (preg_match("#(?<!/)(\d+)\s+mbit#i", $string)){ Just to catch those that doesn't have "/" before them, but this matched true for this string: "10/10 mbit" so I'm obviously doing something wrong here, but what?

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• How to export the matches only in a pattern search in vim?

  - by Mert Nuhoglu

  Is there a way to grab and export the match part only in a pattern search without changing the current file? For example, from a file containing: 57","0","37","","http://www.thisamericanlife.org/Radio_Episode.aspx?episode=175" 58","0","37","","http://www.thisamericanlife.org/Radio_Episode.aspx?episode=170" I want to export a new file containing: http://www.thisamericanlife.org/Radio_Episode.aspx?episode=175 http://www.thisamericanlife.org/Radio_Episode.aspx?episode=170 I can do this by using substitution like this: :s/.\{-}\(http:\/\/.\{-}\)".\{-}/\1/g :%w>>data But the substitution command changes the current file. Is there a way to do this without changing the current file?

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• Use Regular expression with fileinput

  - by chrissygormley

  Hello, I am trying to replace a variable stored in another file using regular expression. The code I have tried is: r = re.compile(r"self\.uid\s*=\s*('\w{12})'") for line in fileinput.input(['file.py'], inplace=True): print line.replace(r.match(line), sys.argv[1]), The format of the variable in the file is: self.uid = '027FC8EBC2D1' I am trying to pass in a parameter in this format and use regular expression to verify that the sys.argv[1] is correct format and to find the variable stored in this file and replace it with the new variable. Can anyone help. Thanks for the help.

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• Regular expression to retrieve everything before first slash

  - by alex

  I need a regular expression to basically get the first part of a string, before the first slash (). For example in the following: C:\MyFolder\MyFile.zip The part I need is "C:" Another example: somebucketname\MyFolder\MyFile.zip I would need "somebucketname" I also need a regular expression to retrieve the "right hand" part of it, so everything after the first slash (excluding the slash.) For example somebucketname\MyFolder\MyFile.zip would return MyFolder\MyFile.zip.

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• Remove newlines and spaces

  - by Cosmin

  How can I remove newline between <table> .... </table> and add \n after each ex: <table border="0" cellspacing="0" cellpadding="0" width="450" class="descriptiontable"><tr> <td width="50%" valign="top"> <span class="displayb">Model Procesor:</span> Intel Celeron<br><span class="displayb">Frecventa procesor (MHz):</span> 2660<br><span class="displayb">Placa Video:</span> Intel Extreme Graphics 2<br><span class="displayb">Retea integrata:</span> 10/100Mbps, RJ-45<br><span class="displayb">Chipset:</span> Intel 845G<br> </td> <td width="50%" valign="top"> <span class="displayb">Capacitate RAM (MB):</span> 512<br><span class="displayb">Tip RAM:</span> DDR<br> </td> </tr></table> and become : <table border="0" cellspacing="0" cellpadding="0" width="450" class="descriptiontable"><tr><td width="50%" valign="top"><span class="displayb">Model Procesor:</span> Intel Celeron<br><span class="displayb">Frecventa procesor (MHz):</span> 2660<br><span class="displayb">Placa Video:</span> Intel Extreme Graphics 2<br><span class="displayb">Retea integrata:</span> 10/100Mbps, RJ-45<br><span class="displayb">Chipset:</span> Intel 845G<br></td><td width="50%" valign="top"><span class="displayb">Capacitate RAM (MB):</span> 512<br><span class="displayb">Tip RAM:</span> DDR<br></td></tr></table>\n s.

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• Regular expression to match any table tag

  - by keeg

  I'm trying to write a regular expression to see if a string contains any of the typical table tags: <table></table> <td></td> <th></th> <tr></tr> <thead></thead> <tfoot></tfoot> <tbody></tbody> Along with tags that may contain other attributes e.g: <table border="1"> I've come up with this so far, however, it matches <br /> tag and I'm not sure why: /<\/?[table|td|th|tr|tfoot|thead|tbody]{1,}>?/ http://www.rexfiddle.net/20Xtqka

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• How do I write this URL in Django?

  - by alex

  (r'^/(?P<the_param>[a-zA-z0-9_-]+)/$','myproject.myapp.views.myview'), How can I change this so that "the_param" accepts a URL(encoded) as a parameter? So, I want to pass a URL to it. mydomain.com/http%3A//google.com

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