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  • Using varible in re.match in python

    - by screwuphead
    I am trying to create an array of things to match in a description line. So I cant ignore them later on in my script. Below is a sample script that I have been working on, on the side. Basically I am trying to take a bunch of strings and match it against a bunch of other strings. AKA: asdf or asfs or wrtw in string = true continue with script if not print this. import re ignorelist = ['^test', '(.*)set'] def guess(a): for ignore in ignorelist: if re.match(ignore, a): return('LOSE!') else: return('WIN!') a = raw_input('Take a guess: ') print guess(a) Thanks

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  • converting if else statement to ternary

    - by EquinoX
    I have translated the following code using ternary. However, I knew there was something wrong with it. Can someone please point me into the right direction? ForwardA = 0; ForwardB = 0; //EX Hazard if (EXMEMRegWrite == 1) begin if (EXMEMrd != 0) if (EXMEMrd == IDEXrs) ForwardA = 2'b10; if (EXMEMrd == IDEXrt && IDEXTest == 0) ForwardB = 2'b10; end //MEM Hazard if (MEMWBRegWrite == 1) begin if (MEMWBrd != 0) begin if (!(EXMEMRegWrite == 1 && EXMEMrd != 0 && (EXMEMrd == IDEXrs))) if (MEMWBrd == IDEXrs) ForwardA = 2'b01; if (IDEXTest == 0) begin if (!(EXMEMRegWrite == 1 && EXMEMrd != 0 && (EXMEMrd == IDEXrt))) if (MEMWBrd == IDEXrt) ForwardB = 2'b01; end end end ForwardA = (MEMWBRegWrite && MEMWBrd != 0 && (!(EXMEMRegWrite == 1 && EXMEMrd != 0 && (EXMEMrd == IDEXrs))) && (MEMWBrd == IDEXrs)) ? 2'b01 : ((EXMEMRegWrite && EXMEMrd != 0 && EXMEMrd == IDEXrs) ? 2'b10 : 0); ForwardB = (IDEXTest == 0 && MEMWBRegWrite && MEMWBrd != 0 && (!(EXMEMRegWrite == 1 && EXMEMrd != 0 && (EXMEMrd == IDEXrt))) && (MEMWBrd == IDEXrs)) ? 2'b01 : ((EXMEMRegWrite && EXMEMrd != 0 && EXMEMrd == IDEXrt && IDEXTest == 0) ? 2'b10 : 0);

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  • Java: Prepare a statement without a connection

    - by r3zn1k
    I'm trying to generate some sql files in my java application. The application will not execute any sql statements, just generate a file with sql statements and save it. I'd like to use the java.sql.PreparedStatement to create my statements so that i don't have to validate every string etc. with my own methods. Is there a way to use the PreparedStatement without the calling java.sql.Connection.prepareStatement(String) function, because I don't have a java.sql.Connection?

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  • C: Convert A ? B : C into if (A) B else C

    - by tur1ng
    I was looking for a tool that can convert C code expressions for the form: a = (A) ? B : C; into the 'default' syntax with if/else statements: if (A) a = B else a = C Does someone know a tool that's capable to do such a transformation? I work with GCC 4.4.2 and create a preprocessed file with -E but do not want such structures in it.

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  • PHP the SELECT FROM WHERE col IN no working using array

    - by Sam Ram San
    I'm trying to pull some data from MySQL using an Array that was fetch from a first query. Everything's fine all the way to the implode after that, it's been a headache for me. Can someone help me? <?php $var = 'somedata'; include("config/conect.php"); $zip="SELECT * FROM table WHERE firstcol LIKE '%$var%' ORDER BY seconcol"; $results = $connetction->query($zip); while ($row = $results->fetch_array()){ $mycode[]=$row['zip']; } array_pop($mycode); $mycode = implode(', ',$mycode); //print_r ($mycode); echo '<br /><br /><br />'; $usr="SELECT * FROM reg_temp WHERE zip IN('".join("','", $mycode)."')"; $results = $asies->query($usr); while ($row = $results-> fetch_arra()) { $name = $row['name']; echo $name; } ?>

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  • Rewriting a statement using LINQ(C#)

    - by Thinking
    Is it possible to write the folowing using lambda(C#) private static void GetRecordList(List<CustomerInfo> lstCustinfo) { for (int i = 1; i <= 5; i++) { if (i % 2 == 0) lstCustinfo.Add(new CustomerInfo { CountryCode = "USA", CustomerAddress = "US Address" + i.ToString(), CustomerName = "US Customer Name" + i.ToString(), ForeignAmount = i * 50 }); else lstCustinfo.Add(new CustomerInfo { CountryCode = "UK", CustomerAddress = "UK Address" + i.ToString(), CustomerName = "UK Customer Name" + i.ToString(), ForeignAmount = i * 80 }); } }

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  • wp e-commerce php modification

    - by user1015687
    Here are a few lines of code from a wordpress plugin (WP E-commerce) that calculate the price. Now what i want is that if 'cart_item' are more than 3 in quantity then the price should be (number of items * 4) else the function should work as it is listed below. Thnks for help. function calculate_subtotal($for_shipping = false) { 1047 global $wpdb; 1048 if($for_shipping == true ) { 1049 $total = 0; 1050 foreach($this->cart_items as $key => $cart_item) { 1051 if($cart_item->uses_shipping == 1) { 1052 $total += $cart_item->total_price; 1053 } 1054 } 1055 } else { 1056 $total = 0; 1057 if($this->subtotal == null) { 1058 foreach($this->cart_items as $key => $cart_item) { 1059 $total += $cart_item->total_price; 1060 } 1061 $this->subtotal = $total; 1062 } else { 1063 $total = $this->subtotal; 1064 } 1065 } 1066 return $total; 1067 }

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  • Why does this program stop running?

    - by designloper
    Hi everyone....I am developing a card making system...nothing fancy. Right got this far but program now stops running with no error when running after the first card sample i.e. " Enter 'OK' if this card is OK, otherwise enter an alternative border character: + ". Any suggestions Java Masters? //Ask user for input //makes use of print line method System.out.println("Enter name: "); //took the variables //called the object of the scanner 'cardOrder' //and use the Scanner objects method '.nextLine' //to read the next line of the input firstName = cardOrder.nextLine(); mInitial = cardOrder.nextLine(); lastName = cardOrder.nextLine(); //Print out the "Here is a sample card" + the first name, middle initial and last name System.out.println("Here is a sample card: \n\n" + firstName + mInitial + lastName + "**************" + "**************" + firstName + mInitial + lastName + "\n* *" + "\n*" + " " + firstName + mInitial + lastName + " *" + "\n* *\n" + firstName + mInitial + lastName +"**************" + "**************" + firstName + mInitial + lastName + "\n"); //Ask user is the card is OK to proceed to order query or if they want an alternative border character: + System.out.println("Enter 'OK' if this card is OK, otherwise enter an alternative border character: + "); //Check if user entered "OK" and store it in var optionA optionA = cardOrder.nextLine(); //test if (a == optionA){ System.out.println("\nHow many cards would you like? "); cardsOrdered = cardOrder.nextInt(); equals = (int) (cardPriceA * cardsOrdered); System.out.println("The price of " + cardsOrdered + " cards"+ " is £" + equals + ".\n"); System.out.println("No Discount given."); } else if(b == optionA) { //Print out the "Here is a sample card" + the first name, middle initial and last name System.out.println("Here is a sample card: \n\n" + firstName + mInitial + lastName + "++++++++++++++" + "++++++++++++++" + firstName + mInitial + lastName + "\n+ +" + "\n+" + " " + firstName + mInitial + lastName + " +" + "\n+ +\n" + firstName + mInitial + lastName +"++++++++++++++" + "++++++++++++++" + firstName + mInitial + lastName + "\n"); //Ask user is the card is OK to proceed to order query or if they want an alternative border character: + System.out.println("Enter 'OK' if this card is OK, otherwise enter an alternative border character: OK "); //Check if user entered "OK" and store it in var optionA optionA = cardOrder.nextLine(); if (a == optionA){ System.out.println("\nHow many cards would you like? "); cardsOrdered = cardOrder.nextInt(); equals = (int) (cardPriceA * cardsOrdered); System.out.println("The price of " + cardsOrdered + " cards"+ " is £" + equals + ".\n"); System.out.println("No Discount given."); } } else if (c == optionA) {//Print out the "Here is a sample card" + the first name, middle initial and last name System.out.println("Here is a sample card: \n\n" + firstName + mInitial + lastName + "**************" + "**************" + firstName + mInitial + lastName + "\n* *" + "\n*" + " " + firstName + mInitial + lastName + " *" + "\n* *\n" + firstName + mInitial + lastName +"**************" + "**************" + firstName + mInitial + lastName + "\n"); //Ask user is the card is OK to proceed to order query or if they want an alternative border character: + System.out.println("Enter 'OK' if this card is OK, otherwise enter an alternative border character: + "); //Check if user entered "OK" and store it in var optionA optionA = cardOrder.nextLine(); if (a == optionA){ System.out.println("\nHow many cards would you like? "); cardsOrdered = cardOrder.nextInt(); equals = (int) (cardPriceA * cardsOrdered); System.out.println("The price of " + cardsOrdered + " cards"+ " is £" + equals + ".\n"); System.out.println("No Discount given."); } }

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  • With (or similar) statement in JQuery

    - by Salman A
    Very simple question: I want to optimize the following jQuery code with maximum readability, optimal performance and minimum fuss (fuss = declaring new variables etc): $(".addthis_toolbox").append('<a class="addthis_button_delicious"></a>'); $(".addthis_toolbox").append('<a class="addthis_button_facebook"></a>'); $(".addthis_toolbox").append('<a class="addthis_button_google"></a>'); $(".addthis_toolbox").append('<a class="addthis_button_reddit"></a>'); . . .

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  • Invalid Active Record Statement Rails 2.3.16

    - by Ranzit
    I am using rails 2.3.16 ruby 1.8.7 For the following line of code I ma getting error as follows: Code: ForeignScheduledItem.find(:all, :conditions => { :foreign_scheduled_item => { :scheduled_items => { :subscription_id => params[:subscription_id] } } }, :joins => :scheduled_item).each { |i| @subscriptions.push(Subscription.find_by_id(i.subscription_id)) } Error: ActiveRecord::StatementInvalid (ActiveRecord::StatementInvalid): Can u please help in this regard.

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  • Cannot we use break statement in a lambda(C#3.0)

    - by Newbie
    Consider this List<int> intList = new List<int> { 1, 2, 3, 4, 5, 6 }; int j = 0; intList.ForEach(i => { if (i.Equals(1)) { j = i; break; } } ); Throwing error: No enclosing loop out of which to break or continue But the below works foreach(int i in intList) { j = i; break; } Why so. Am I making any mistake. Thanks

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  • foreach statement (get string values)

    - by nhoyti
    Can someone please help me out? My code for splitting the strings is working however, i still need to use the splitted string my page. How can i achieve this? Here's my current code private void SplitStrings() { List<string> listvalues = new List<string>(); listvalues = (List<string>)Session["mylist"]; string[] strvalues = listvalues.ToArray(); if (listvalues != null) { foreach (string strElement in listvalues) { string[] prods = strElement.ToString().Split("|".ToCharArray()); string prodName = prods[0].ToString(); Response.Write(prodName); } } } link text how can i replace the response.write with any label or literal? when i tried to use a literal on the code it displays one single string not all of the strings that's been splitted. any ideas?

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  • Unexpected '{' with IF statement

    - by user1926208
    this is my code to move all the files in a directory to another directory which are 1 hour old or more. <?php $srcDir = 'code'; $destDir = 'code/old'; if (file_exists($destDir)) { if (is_dir($destDir)) { if (is_writable($destDir)) { if ($handle = opendir($srcDir)) { while (false !== ($file = readdir($handle))) { if (is_file($srcDir . '/' . $file)) { if(date("U",filectime($srcDir . '/' . $file) >= time() - 3600) { rename($srcDir . '/' . $file, $destDir . '/' . $file); } } } closedir($handle); } else { echo "$srcDir could not be opened.\n"; } } else { echo "$destDir is not writable!\n"; } } else { echo "$destDir is not a directory!\n"; } } else { echo "$destDir does not exist\n"; } ?> and I am getting this error: Parse error: syntax error, unexpected '{' in /home/tcity/public_html/myDir/movefiles.php on line 11

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  • Else without if

    - by user2808951
    I'm trying to write a code for my computer programming class for a project due Monday, and I'm pretty new to Java, but I'm trying to write a program that will first determine if a number the user inputs is even or odd and then determine if the number is prime or not. I'm not sure if I did the algorithm right or not, so if anyone has any corrections on the program to my algorithm or anything else please say so, but my real issue is that the program is refusing to compile. Every time I try, it says it's having an else without if problem. Here's a link to my command box: http://s1341.photobucket.com/user/Emi_Nightshade/media/Capture_zps45f9a2ea.png.html Here's my code: import java.io.*; import java.util.*; public class Lesson9p1_ThuotteEmily { public static void main(String args[]) { Scanner kbReader0=new Scanner(System.in); System.out.print("\n\nPlease enter an integer. An integer is whole number, and it can be either negative or positive. Please enter your number: "); long num=kbReader0.nextLong(); if(num%2==0) //if and else with braces { System.out.println("Your integer " + num + " is even."); } else { System.out.println("Your integer " + num + " is odd."); } Scanner kbReader1=new Scanner(System.in); System.out.print("\n\nWould you like to know if your number is prime? Please enter yes or no: "); String yn=kbReader1.nextLine(); if(yn.equals.IgnoreCase("Yes")) { System.out.println("Okay. Give me a moment."); { if(num%2==0) { System.out.println("Your number isn't prime."); } else if(num==2) { System.out.println("Your number is 2, which is the only even prime number in existence. Cool, right?"); } for(int i=3;i*i<=n;i+=2) { if(n%1==0) { System.out.println("Your number isn't prime."); } } else { System.out.println("Your number is prime!"); } } } if(yn.equals.IgnoreCase("No")) { System.out.println("Okay."); } } } If anyone could help me out with this and also any problems I may have made elsewhere in the program, I'd be very grateful! Thanks.

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  • PHP - if == not working for 0 or ""

    - by user2933212
    I am checking the validation of the request with an if query, if ($request_userid == $userid) { ... } Thats working as expected. But further testing has shown, that if $request_userid or $userid is 0 or "", then the condition is true and the script runs the if query but it shouldn't. I am currently solving it with: if ($userid == "" ) { exit ("exit"); } But I don't think that this is the right way? Can you explain why it doesn’t work with the if query and what would be the correct way to check it?

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  • html - selection range - getting the range + starting node + ending node + distance

    - by sugar
    From my previous question for selecting specific html text, I have gone through this link to understand range in html string. Actually I am confused here very much. My question is as follows. For selecting a specific text on html page. We need to follow this steps. assumed html <h4 id="entry1196"><a href="http://radar.oreilly.com/archives/2007/03/call_for_a_blog_1.html" class="external">Call for a Blogger's Code of Conduct</a></h4> <p>Tim O'Reilly calls for a Blogger Code of Conduct. His proposals are:</p> <ol> <li>Take responsibility not just for your own words, but for the comments you allow on your blog.</li> <li>Label your tolerance level for abusive comments.</li> <li>Consider eliminating anonymous comments.</li> </ol> java script to make selection by range var range = document.createRange(); // create range var startPar = [the p node]; // starting parameter var endLi = [the second li node]; // ending parameter range.setStart(startPar,13); // distance from starting parameter. range.setEnd(endLi,17); // distance from ending parameter range.select(); // this statement will make selection I want to do this in invert way. I mean, assume that selection is done by user on browser (safari). My question is that How can we get starting node ( as we have 'the p node' here ) & ending node ( as we have 'the second li node' here ) and the range as well (as we have 13,17 here) ? Please help me. Thanks in advance for sharing your great knowledge. Sagar

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