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• feedparser fails during script run, but can't reproduce in interactive python console

  - by Rhubarb

  It's failing with this when I run eclipse or when I run my script in iPython: 'ascii' codec can't decode byte 0xe2 in position 32: ordinal not in range(128) I don't know why, but when I simply execute the feedparse.parse(url) statement using the same url, there is no error thrown. This is stumping me big time. The code is as simple as: try: d = feedparser.parse(url) except Exception, e: logging.error('Error while retrieving feed.') logging.error(e) logging.error(formatExceptionInfo(None)) logging.error(formatExceptionInfo1()) Here is the stack trace: d = feedparser.parse(url) File "C:\Python26\lib\site-packages\feedparser.py", line 2623, in parse feedparser.feed(data) File "C:\Python26\lib\site-packages\feedparser.py", line 1441, in feed sgmllib.SGMLParser.feed(self, data) File "C:\Python26\lib\sgmllib.py", line 104, in feed self.goahead(0) File "C:\Python26\lib\sgmllib.py", line 143, in goahead k = self.parse_endtag(i) File "C:\Python26\lib\sgmllib.py", line 320, in parse_endtag self.finish_endtag(tag) File "C:\Python26\lib\sgmllib.py", line 360, in finish_endtag self.unknown_endtag(tag) File "C:\Python26\lib\site-packages\feedparser.py", line 476, in unknown_endtag method() File "C:\Python26\lib\site-packages\feedparser.py", line 1318, in _end_content value = self.popContent('content') File "C:\Python26\lib\site-packages\feedparser.py", line 700, in popContent value = self.pop(tag) File "C:\Python26\lib\site-packages\feedparser.py", line 641, in pop output = _resolveRelativeURIs(output, self.baseuri, self.encoding) File "C:\Python26\lib\site-packages\feedparser.py", line 1594, in _resolveRelativeURIs p.feed(htmlSource) File "C:\Python26\lib\site-packages\feedparser.py", line 1441, in feed sgmllib.SGMLParser.feed(self, data) File "C:\Python26\lib\sgmllib.py", line 104, in feed self.goahead(0) File "C:\Python26\lib\sgmllib.py", line 138, in goahead k = self.parse_starttag(i) File "C:\Python26\lib\sgmllib.py", line 296, in parse_starttag self.finish_starttag(tag, attrs) File "C:\Python26\lib\sgmllib.py", line 338, in finish_starttag self.unknown_starttag(tag, attrs) File "C:\Python26\lib\site-packages\feedparser.py", line 1588, in unknown_starttag attrs = [(key, ((tag, key) in self.relative_uris) and self.resolveURI(value) or value) for key, value in attrs] File "C:\Python26\lib\site-packages\feedparser.py", line 1584, in resolveURI return _urljoin(self.baseuri, uri) File "C:\Python26\lib\site-packages\feedparser.py", line 286, in _urljoin return urlparse.urljoin(base, uri) File "C:\Python26\lib\urlparse.py", line 215, in urljoin params, query, fragment)) File "C:\Python26\lib\urlparse.py", line 184, in urlunparse return urlunsplit((scheme, netloc, url, query, fragment)) File "C:\Python26\lib\urlparse.py", line 192, in urlunsplit url = scheme + ':' + url File "C:\Python26\lib\encodings\cp1252.py", line 15, in decode return codecs.charmap_decode(input,errors,decoding_table)

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• How to draw line inside a scatter plot

  - by ruffy

  I can't believe that this is so complicated but I tried and googled for a while now. I just want to analyse my scatter plot with a few graphical features. For starters, I want to add simply a line. So, I have a few (4) points and like in this plot [1] I want to add a line to it. http://en.wikipedia.org/wiki/File:ROC_space-2.png [1] Now, this won't work. And frankly, the documentation-examples-gallery combo and content of matplotlib is a bad source for information. My code is based upon a simple scatter plot from the gallery: # definitions for the axes left, width = 0.1, 0.85 #0.65 bottom, height = 0.1, 0.85 #0.65 bottom_h = left_h = left+width+0.02 rect_scatter = [left, bottom, width, height] # start with a rectangular Figure fig = plt.figure(1, figsize=(8,8)) axScatter = plt.axes(rect_scatter) # the scatter plot: p1 = axScatter.scatter(x[0], y[0], c='blue', s = 70) p2 = axScatter.scatter(x[1], y[1], c='green', s = 70) p3 = axScatter.scatter(x[2], y[2], c='red', s = 70) p4 = axScatter.scatter(x[3], y[3], c='yellow', s = 70) p5 = axScatter.plot([1,2,3], "r--") plt.legend([p1, p2, p3, p4, p5], [names[0], names[1], names[2], names[3], "Random guess"], loc = 2) # now determine nice limits by hand: binwidth = 0.25 xymax = np.max( [np.max(np.fabs(x)), np.max(np.fabs(y))] ) lim = ( int(xymax/binwidth) + 1) * binwidth axScatter.set_xlim( (-lim, lim) ) axScatter.set_ylim( (-lim, lim) ) xText = axScatter.set_xlabel('FPR / Specificity') yText = axScatter.set_ylabel('TPR / Sensitivity') bins = np.arange(-lim, lim + binwidth, binwidth) plt.show() Everything works, except the p5 which is a line. Now how is this supposed to work? What's good practice here?

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• Line Text with Nav Bar in HTML

  - by Eric

  I have a navbar right under the title to the site, but I want to be line up the first and last items in the navbar with the beginning and end of the Title. I don't have a live preview, but I attached an image. I can get it to line up in one browser, but when I open it in the other, its off again. Is there an easy way to line the text up so it works for everything? thank you HTML: <body onload="play()"> <div class="heading">UPRISING</div> <div class="container_12"> <div id="topnav" align="center"> <ul id="list-nav"> <li><a href="home.html">HOME</a></li> <li><a href="about.html">ABOUT</a></li> <li><a href="trailer.html">TRAILER</a></li> <li><a href="stills.html">STILLS</a></li> <li><a href="news.html">NEWS</a></li> <li><a href="contact.html">CONTACT</a></li> <!-- <li><a href="distribution.html">DISTRIBUTION</a></li> --> </ul> </div> <!-- START OF CONTAINER --> <div class="trailer"> <img id="imgHolder" /> </div> </div> <!-- END OF CONTAINER 12 --> CSS: #topnav li { margin-right: 110px; } #topnav li:nth-last-child(1) { margin-right: 0px; }

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• How to embed multiple jQuery line of code in custom HtmlHelpers ASP.NET MVC

  - by embarus

  I 've tried to create my own HTML Helper which work fine for my need but I can't embed many lines of jQuery code in my extension HtmlHelpers class. I've tried @ literal for jQuery code I doesn't work or I need to escape every line of code that I thing I not good for multiple line of code. I don't know if there is another way to achieve this problem like << Therefore, I need to include jQuery plugin file and put implement script after HTML tag. I find it would be convenience if I could put every in HTML helper and put a single line of code in aspx page for example <%= Html.ParentChildSelectList(string parentName, string childName, IEnumerable parentViewData, IEnumerable childViewData, int parentSize, in childSize) % The following code is the way that I used now. the .aspx page Category model.CategoryID)% , new { size = 10 })% model.SubcategoryID,"subcategory") % model.SubcategoryID)% , new { size = 10 })% <script type="text/javascript"> jQuery.sarapadchang.parentChildSelectList( { parentId : "CategoryID" , childId : "SubcategoryID", actionName : "GetSubcategoryList", controllerName : "Json" } ); </script> I put in head tag to include ParentChildSelectList.js the following code for ParentChildSelectList.js (function($) { $.sarapadchang = { parentChildSelectList: function(options) { // $("#CategoryID option").click(function() $("#" + options.parentId).find("option").click(function() { $("#" + options.childId).empty(); //clear data $("#" + options.childId).append('<option>loading...</option>'); $.post("/" + options.controllerName + "/" + options.actionName + "/" + $(this).attr('value'), "", function(data) { var html = ""; $.each(data, function(index, entry) { html += '<option value="' + entry['Value'] + '">' + entry['Text'] + '</option>'; } ); $("#" + options.childId).empty() $("#" + options.childId).append(html); }, "json"); //end getJson }); })(jQuery); To illustrate you, I've attached simple solution, please follow this link. http://www.thaileaguefc.net/ParentChildSelectList.rar Please accept my apologies if my English is difficult to understand. I am looking forward to hearing from you. Your faithfully, Theeranit

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• Using perl to split a line that may contain whitespace

  - by Tommy Fisk

  Okay, so I'm using perl to read in a file that contains some general configuration data. This data is organized into headers based on what they mean. An example follows: [vars] # This is how we define a variable! $var = 10; $str = "Hello thar!"; # This section contains flags which can be used to modify module behavior # All modules read this file and if they understand any of the flags, use them [flags] Verbose = true; # Notice the errant whitespace! [path] WinPath = default; # Keyword which loads the standard PATH as defined by the operating system. Append with additonal values. LinuxPath = default; Goal: Using the first line as an example "$var = 10;", I'd like to use the split function in perl to create an array that contains the characters "$var" and "10" as elements. Using another line as an example: Verbose = true; # Should become [Verbose, true] aka no whitespace is present This is needed because I will be outputting these values to a new file (which a different piece of C++ code will read) to instantiate dictionary objects. Just to give you a little taste of what it might look like (just making it up as I go along): define new dictionary name: [flags] # Start defining keys => values new key name: Verbose new value val: 10 # End dictionary Oh, and here is the code I currently have along with what it is doing (incorrectly): sub makeref($) { my @line = (split (/=/)); # Produces ["Verbose", " true"]; }

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• invalid argument IE7 javascript line number changes

  - by Lauren

  This is the test page: http://www.onebagoneearth.com/ OBOEKindBag (spaces between the pagename and domain because I don't want the URL indexed as such) If you click on one of the thumbnails, or on the main image, you see a popup window, and if you enter a quantity and then click "add to cart" here, in IE7 (and IE6, but I'm not focusing on that as much), you see an invalid argument error with Code:0. The line # changes depending on which item you add to cart! The URL also changes because it depends on this line of javascript: var cartUrl = "/app/site/backend/additemtocart.nl?c=659197&n=2&buyid=" + zbuyid + "&qty=" + zqty + "&" + strOptionId + "=" + zitmId . The strOptionId variable, which contains the bag color type (ie. this changes for the different types of bags, like Kind bags, regular OBOE bags), and the zitmID variable which contains the particular bag color that you've selected (ie. Black), are what change, and also what seem to affect the line number that the invalid argument occurs on. The error definitely doesn't occur in Chrome 4, IE 8, or FF 3.5. Ideas?

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• XSLT line counter - is it that hard?

  - by Mr AH

  I have cheated every time I've needed to do a line count in XSLT by using JScript, but in this case I can't do that. I simply want to write out a line counter throughout an output file. This basic example has a simple solution: <xsl:for-each select="Records/Record"> <xsl:value-of select="position()"/> </xsl:for-each> Output would be: 1 2 3 4 etc... But what if the structure is more complex with nested foreach's : <xsl:for-each select="Records/Record"> <xsl:value-of select="position()"/> <xsl:for-each select="Records/Record"> <xsl:value-of select="position()"/> </xsl:for-each> </xsl:for-each> Here, the inner foreach would just reset the counter (so you get 1, 1, 2, 3, 2, 1, 2, 3, 1, 2 etc). Does anyone know how I can output the position in the file (ie. a line count)?

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• PHP/Javascript: Need help removing line break from code

  - by Josh K

  I am trying to get names from a .txt file. I am using file('filename.txt') but if i use a php for loop to try and trim the names, it comes out on multiple lines: This is the actual line that prints the javascript (NOTE: I am going to be putting these names into a select box, if you can fix the problem at hand the rest of the code should work so unless you a big problem with it you don't need to comment) <?php for($i=1; $i < 27; $i++){ echo "selbox.options[selbox.options.length] = new Option('".lines[$i]."','".$lines[$i]."');\n"; } ?> Heres how it comes out on the browser: selbox.options[selbox.options.length] = new Option('Djamal ABDOUN ','First1 Last1 '); selbox.options[selbox.options.length] = new Option('Chadli AMRI ','First2 Last2 '); I need those to be on one line so i dont get a unterminated string literal js error Any ideas on what i can do here? EDIT: Oh i should probably mention, the $lines var is initiated like this: $lines = file('filename.txt'); and inside that file i have formatted like this First1 Last1 First2 Last2 First3 Last3 etc. and i hit delete after each Last name until the next first name is touching, then hit enter to put it on a new line (Editor is notepad++)

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• how to achieve this single line css format....

  - by metal-gear-solid

  I tried many formats but this is best to find classes and IDs easily without using "Find". but it is good if width of editor is wide. I use this tool to format my css in single line http://www.newmediacampaigns.com/files/posts/css-formatting/clean.php #wrapper {width:800px; margin:0 auto;} #header {height:100px; position:relative;} #feature .post {width:490px; float:left;} #feature .link {width:195px; display:inline; margin:0 10px 0 0;float:right;border-bottom:1px solid red} #footer {clear:both; font-size:93%; float:none;} I need like this. see selector #feature .link i need if any selector has more than 3 properties then it should go at next line like in this example.because i work in cms where width of textbox where i write cssis not much wide. Is there any tool/software can format CSS like this. or after getting single line format can we this formatting for big lines. in automated way #wrapper {width:800px; margin:0 auto;} #header {height:100px; position:relative;} #feature .post {width:490px; float:left;} #feature .link {width:195px; display:inline; margin:0 10px 0 0; float:right;bottom:1px solid red} #footer {clear:both; font-size:93%; float:none;}

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• Executing system command in php, differs in using broswer and in using command line

  - by Amit

  Hi, I have to execute a Linux "more" command in php from a particular offset, format the result and display the result in Browser. My Code for the above is : <html> <head> <META HTTP-EQUIV=REFRESH CONTENT=10> <META HTTP-EQUIV=PRAGMA CONTENT=NO-CACHE> <title>Runtime Access log</title> </head> <body> <?php $moreCommand = "more +3693 /var/log/apache2/access_log | grep -v -e '.jpg' -e '.jpeg' -e '.css' -e '.js' -e '.bmp' -e '.ico'| wc -l"; exec($moreCommand, $accessDisplay); echo "<br/>No of lines are : $accessDisplay[0] <br/>"; ?> The output at the browser is :: No of lines are : 3428 (This is wrong) While executing the same command using command line gives a different output. My code snippet for the same is : <?php $moreCommand = "more +3693 /var/log/apache2/access_log | grep -v -e '.jpg' -e '.jpeg' -e '.css' -e '.js' -e '.bmp' -e '.ico'| wc -l"; exec($moreCommand, $accessDisplay); echo "No of lines are : $accessDisplay[0] \n"; ? The output at the command line is :: No of lines are : 279 (This is correct) While executing the same command directly in command line, gives me output as 279. I am unable to understand why the output of the same command is wrong in the browser. Its actually giving the word count of lines, ignoring the offset parameter. Please help !! Thanks, Amit

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• how to create static line in coreplot

  - by Rémi Bédard-Couture

  I am trying to make my control lines static so instead of being displayed as part of the graph(the control lines are moving with the graph), they would be displayed like an axis the app can only scroll horizontally i'm talking about the two red line and the green line(which i put over the x axis) this is how i do my lines: // Center line CPTScatterPlot *centerLinePlot = [[CPTScatterPlot alloc] init]; centerLinePlot.identifier = kCenterLine; CPTMutableLineStyle *lineStyle = [CPTMutableLineStyle lineStyle]; lineStyle.lineWidth = 2.0; lineStyle.lineColor = [CPTColor greenColor]; centerLinePlot.dataLineStyle = lineStyle; centerLinePlot.dataSource = self; [graph addPlot:centerLinePlot]; but maybe it has something to do with the displayed range: ////////ajuste la portion a voir if(data.Resultats.count>10) { plotSpace.xRange = [CPTPlotRange plotRangeWithLocation:CPTDecimalFromDouble(data.Resultats.count - 10) length:CPTDecimalFromDouble(10)]; } plotSpace.yRange = [CPTPlotRange plotRangeWithLocation:CPTDecimalFromDouble(RangeMin) length:CPTDecimalFromDouble(RangeMax-RangeMin)]; // Adjust visible ranges so plot symbols along the edges are not clipped CPTMutablePlotRange *xRange = [plotSpace.xRange mutableCopy]; CPTMutablePlotRange *yRange = [plotSpace.yRange mutableCopy]; //place l'axe x sur la ligne de controle pour voir les WorkOrders x.orthogonalCoordinateDecimal = CPTDecimalFromDouble(center); //x.orthogonalCoordinateDecimal = yRange.location; //y.orthogonalCoordinateDecimal = xRange.location; //x.visibleRange = xRange; //y.visibleRange = yRange; //x.gridLinesRange = yRange; //y.gridLinesRange = xRange; [xRange expandRangeByFactor:CPTDecimalFromDouble(1.15)];//1.05 [yRange expandRangeByFactor:CPTDecimalFromDouble(1.15)]; plotSpace.xRange = xRange; plotSpace.yRange = yRange;

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• Problems with multi-line comments jquery

  - by c0mrade

  Hello, I'm making a image website with a bunch of images on the website, and below every image there is possibility of commenting the image and after that comments gets displayed without page loading and the comment content, the problem is when I have long comments which break the current line they don't get displayed since my comment box css overflow is hidden. Here is example : This is a comment - This is displayed properly This is a comment This is a comment This is a comment - this is not displayed properly since it break line. Here is the jQuery code for this : $.ajax({ type: "POST", url: "<?=base_url()?>imagesform/post_comment", data: datas, success: function () { $("#image-comments-" + image_id).attr("class", "comments"); $("#image-comments-" + image_id).append("<li id=\"new_append_" + image_id+ "\">" + $("#image").find(".comment").val() + "</li>").children(':last').height($('.comments li:last').height()).hide().slideDown(500, function () { var bodyHeight = $('html').height(); $('.addComment').fadeOut(300, function () { $('html').height(bodyHeight); }); }); alert($("#image").find(".comment").val()); } }); Here the $("#image").find(".comment").val() is the value of the text-area in which comment is inputted, when I alert it the whole multi line input is there put its not being appended to the li properly, that is part when I get confused, any suggestions why only part of the inputted string is appended?

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• Use Sony HDR line of camcorders as webcam?

  - by mjmarsh

  I have a Sony HDR-XR200 HD camcorder. I'd like to see if I can use it as a webcam as well. It only has USB and HDMI outputs (no DV/firewire). Is there any way to make such a device function as a webcam on Windows Vista? Almost all camcorder-to-webcam software seems to work with DV inputs.

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• Need help with yum,python and php in CentOS. (I made a complete mess!)

  - by pek

  a while back I wanted to install some plugins for Trac but it required python 2.5 I tried installing it (I don't remember how) and the only thing I managed was to have two versions of python (2.4 and 2.5). Trac still uses the old version but the console uses 2.5 (python -V = Python 2.5.2). Anyway, the problem is not python, the problem is yum (which uses python). I am trying to upgrade my PHP version from 5.1.x to 5.2.x. I tried following this tutorial but when I reach the step with yum I get this error: >[root@XXX]# yum update Loading "installonlyn" plugin Setting up Update Process Setting up repositories Reading repository metadata in from local files Traceback (most recent call last): File "/usr/bin/yum", line 29, in ? yummain.main(sys.argv[1:]) File "/usr/share/yum-cli/yummain.py", line 94, in main result, resultmsgs = base.doCommands() File "/usr/share/yum-cli/cli.py", line 381, in doCommands return self.yum_cli_commands[self.basecmd].doCommand(self, self.basecmd, self.extcmds) File "/usr/share/yum-cli/yumcommands.py", line 150, in doCommand return base.updatePkgs(extcmds) File "/usr/share/yum-cli/cli.py", line 672, in updatePkgs self.doRepoSetup() File "/usr/share/yum-cli/cli.py", line 109, in doRepoSetup self.doSackSetup(thisrepo=thisrepo) File "/usr/lib/python2.4/site-packages/yum/__init__.py", line 338, in doSackSetup self.repos.populateSack(which=repos) File "/usr/lib/python2.4/site-packages/yum/repos.py", line 200, in populateSack sack.populate(repo, with, callback, cacheonly) File "/usr/lib/python2.4/site-packages/yum/yumRepo.py", line 91, in populate dobj = repo.cacheHandler.getPrimary(xml, csum) File "/usr/lib/python2.4/site-packages/yum/sqlitecache.py", line 100, in getPrimary return self._getbase(location, checksum, 'primary') File "/usr/lib/python2.4/site-packages/yum/sqlitecache.py", line 86, in _getbase (db, dbchecksum) = self.getDatabase(location, metadatatype) File "/usr/lib/python2.4/site-packages/yum/sqlitecache.py", line 82, in getDatabase db = self.makeSqliteCacheFile(filename,cachetype) File "/usr/lib/python2.4/site-packages/yum/sqlitecache.py", line 245, in makeSqliteCacheFile self.createTablesPrimary(db) File "/usr/lib/python2.4/site-packages/yum/sqlitecache.py", line 165, in createTablesPrimary cur.execute(q) File "/usr/lib/python2.4/site-packages/sqlite/main.py", line 244, in execute self.rs = self.con.db.execute(SQL) _sqlite.DatabaseError: near "release": syntax error Any help? Thank you. Update OK, so I've managed to update yum hoping it would solve my problems but now I get a slightly different version of the same error: [root@XXX]# yum -y update Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * addons: mirror.skiplink.com * base: www.gtlib.gatech.edu * epel: mirrors.tummy.com * extras: yum.singlehop.com * updates: centos-distro.cavecreek.net (process:30840): GLib-CRITICAL **: g_timer_stop: assertion `timer != NULL' failed (process:30840): GLib-CRITICAL **: g_timer_destroy: assertion `timer != NULL' failed Traceback (most recent call last): File "/usr/bin/yum", line 29, in ? yummain.user_main(sys.argv[1:], exit_code=True) File "/usr/share/yum-cli/yummain.py", line 309, in user_main errcode = main(args) File "/usr/share/yum-cli/yummain.py", line 178, in main result, resultmsgs = base.doCommands() File "/usr/share/yum-cli/cli.py", line 345, in doCommands self._getTs(needTsRemove) File "/usr/lib/python2.4/site-packages/yum/depsolve.py", line 101, in _getTs self._getTsInfo(remove_only) File "/usr/lib/python2.4/site-packages/yum/depsolve.py", line 112, in _getTsInfo pkgSack = self.pkgSack File "/usr/lib/python2.4/site-packages/yum/__init__.py", line 661, in <lambda> pkgSack = property(fget=lambda self: self._getSacks(), File "/usr/lib/python2.4/site-packages/yum/__init__.py", line 501, in _getSacks self.repos.populateSack(which=repos) File "/usr/lib/python2.4/site-packages/yum/repos.py", line 260, in populateSack sack.populate(repo, mdtype, callback, cacheonly) File "/usr/lib/python2.4/site-packages/yum/yumRepo.py", line 190, in populate dobj = repo_cache_function(xml, csum) File "/usr/lib/python2.4/site-packages/sqlitecachec.py", line 42, in getPrimary self.repoid)) TypeError: Can not create packages table: near "release": syntax error I'm guessing that this "release" thing has something to do with a repository, but I didn't find anything... I went to the sqlitecachec.py at line 42 which writes (line numbers added for convenience): 39: return self.open_database(_sqlitecache.update_primary(location, 40: checksum, 41: self.callback, 42: self.repoid)) Update 2 I think I found the problem. This post suggests that the problem is sqlite and not yum. The version of sqlite I have installed is 3.6.10 but I have no idea which version does python 2.4 uses. ld.so.config contains the following: include ld.so.conf.d/*.conf /usr/local/lib In folder /usr/local/lib I find a symbolic link named libsqlite3.so that points to libsqlite3.so.0.8.6 WHAT IS HAPPENING??????? :S

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• Command line DVD to ISO ripper

  - by RandomInsano

  I have an old XBOX with XBMC installed and I want to rip my dvd collection to my home server as ISO files so that I can watch them over the network. My server is headless (no monitor), so I need the software to run on Solaris, Linux or OpenBSD without X11 running. Does such a magical tool exist? I've seen vobcopy, but does that only work on VOBs? Since XBMC supports DVD menus and everything as though it was a straight disc, I'd rather have my backup work exactly as it does without needing my DVD.

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• Access denied when starting SQL Server Express from command line

  - by Brettski

  Windows 7 computer running SQL Server Express 2008 (sp1). When I try to run net start mssql$sqlexpress I receive an error: System error 5 has occurred. Access is denied The SQL service is running under "Network Service" account The service starts fine if I use the services window. Could somebody help me figure out why I am receiving this error?

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• How to grep a line start with "*" using grep

  - by michael

  Hi, How can I use 'grep' to get lines start with '* ' in my file? I tried grep "" myfile I tried grep " " myfile but returns all the lines of my file. Thank you.

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• Word2007 - Preventing mid-item line breaks in a list in a table

  - by Dan

  It's not programming, but it's the paperwork you have to fill out ot get things to program. When you have a list with an item that's two lines long, and text above pushes it down such that a page break should fall between the two lines, Word pushes the item down so that both lines are on the following page - this is called Widow/Orphan Control and is an option on the Paragraph menu. When the list is inside of a table cell, however, this feature doesn't seem to work - which is what I'm looking to work around. Word doesn't push the item down automatically, so it breaks across two pages, as seen here: Solutions that have been tried: Playing with the options on the Paragraph tab: doesn't seem to do anything Changing the margins or text: this is a template and will need to always work Any ideas?

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• How to delete Chrome temp data (history, cookies, cache) using command line

  - by Dio Phung

  On Windows 7, I tried running this script but still cannot clear Chrome temp data. Can someone figure out what's wrong with the script? Where do Chrome store history and cache ? Thanks ECHO -------------------------------------- ECHO **** Clearing Chrome cache taskkill /F /IM "chrome.exe">nul 2>&1 set ChromeDataDir=C:\Users\%USERNAME%\AppData\Local\Google\Chrome\User Data\Default set ChromeCache=%ChromeDataDir%\Cache>nul 2>&1 del /q /s /f "%ChromeCache%\*.*">nul 2>&1 del /q /f "%ChromeDataDir%\*Cookies*.*">nul 2>&1 del /q /f "%ChromeDataDir%\*History*.*">nul 2>&1 set ChromeDataDir=C:\Users\%USERNAME%\Local Settings\Application Data\Google\Chrome\User Data\Default set ChromeCache=%ChromeDataDir%\Cache>nul 2>&1 del /q /s /f "%ChromeCache%\*.*">nul 2>&1 del /q /f "%ChromeDataDir%\*Cookies*.*">nul 2>&1 del /q /f "%ChromeDataDir%\*History*.*">nul 2>&1 ECHO **** Clearing Chrome cache DONE

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• Command-line access to remote MySQL server

  - by Jerry Krinock

  I administer a website on a remote, shared host. My web host offers MySQL, and I am able to access this from my Mac OS X computer using a GUI program, Sequel Pro. That works great. But I want to script some queries, and Sequel Pro is not scriptable. What should I do? I've read about tunneling to mysql via SSH. I have shell access to the server, with an SSH key on my Mac, so ssh [email protected] -p 7978 gets me in. Should tunneling the MySQL port 3306 work? Like this? ssh [email protected] -L 3306:127.0.0.1:3306 (It "times out" after a minute.) Do I need to install mysql on my Mac?

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• Unable to understand a line in Google CodePreview's README

  - by Masi

  The README is in Google's codepreview which uses Google-appengine. To run the app locally (e.g. for testing), download the Google App Engine SDK from http://code.google.com/appengine/downloads.html. You can then run the server using make serve I run make serve in my terminal after moving Google-appengine.app to my Application -folder in OS X Leopard. I get make: *** No rule to make target `serve'. Stop. How can you run the make serve to run the server for Google AppEngine?

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• Permission denied when copying on a fileshare in Finder, but copying via command line works

  - by smokris

  I'm trying to copy files on a SMB fileshare. When I attempt to copy the files in Finder, I get the following error: The operation can’t be completed because you don’t have permission to access some of the items. Copying via Terminal.app (using a simple cp command) works just fine. Permissions on the folders (as seen from the computer attached to the fileshare) are as follows: Source: dr-xr-x--- 2 smokris staff 16384 Oct 13 10:55 . dr-xr-x---@ 61 smokris staff 16384 Oct 13 10:56 .. -r--r----- 1 smokris staff 53970 Oct 13 10:55 ._IMG_3823.JPG -r--r-----@ 1 smokris staff 3135600 Oct 13 10:55 IMG_3823.JPG Destination: drwxrwx--- 2 smokris staff 16384 Apr 9 10:17 . drwxrwx--- 3 smokris staff 16384 Apr 9 10:15 .. Any ideas?

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• How can I detect upload success/failure in a scripted command-line SFTP session

  - by pkpk

  how can I detect success/failure sftp Batch script on Windows OS? I use %errorlevel% to detect success/failure, sometime the %errorlevel% be returned by 0, but that session is fail and the file is not upload to the server. my script is below how can I detect sftp uploaded correctly? THX so much @echo off (echo cd %4 echo put %2 echo exit)>sftpScript.txt sftp -b sftpScript.txt %3 set result=%errorlevel% if result EQU 0 ( del sftpScript.txt del %2 ) else ( del sftpScript.txt ) exit %result%

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• FTP an entire folder via the command line

  - by Chris Southam

  I'm looking so migrate some websites to a new server. I have SSH access to the current one but only FTP access to the new one. How can I via Centos and SSH copy entire folders to the new server via FTP? I can log into the new server via the built in FTP client on Centos but I'm not sure of the commands after this. I need to move the httpdocs folder from the old to the public_html folder of the new server. I'd love to do this server to server as it'll be a lot quicker than download - upload via my broadband connection. Yours, Chris

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• Run bash script with command line arguments

  - by Trey Parkman

  I want to do /usr/bin/bash myscript.sh -args which, as it stands, runs the script but doesn't pass the args to it. I realize that the conventional syntax is simply ./myscript.sh -args but I'm curious as to what I need to do in order to call the script from bash explicitly.

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