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  • how to copy char * into a string and vice-versa

    - by user295030
    If i pass a char * into a function. I want to then take that char * convert it to a std::string and once I get my result convert it back to char * from a std::string to show the result. I don't know how to do this for conversion ( I am not talking const char * but just char *) I am not sure how to manipulate the value of the pointer I send in. so steps i need to do take in a char * convert it into a string. take the result of that string and put it back in the form of a char * return the result such that the value should be available outside the function and not get destroyed. If possible can i see how it could be done via reference vs a pointer (whose address I pass in by value however I can still modify the value that pointer is pointing to. so even though the copy of the pointer address in the function gets destroyed i still see the changed value outside. thanks!

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  • More elegant way to parse inline variables in strings

    - by Tom
    Currently I have this: function parse_string($string, $variables){ extract($variables); return eval('return "'. addcslashes($string, '"') .'";'); } So I can input this string: 'Hi {$name}, my name is {$own_name}' Together with this array: array('name' => 'John', 'own_name' => 'Tom') And get this back: 'Hi John, my name is Tom'   I've never liked this eval() approach but it works and it's fast (faster than regex at least). Question: Is there a more elegant way to do this (faster than using regex) in PHP5?

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  • String Compression using Lempel-Ziv

    - by roybot
    Im looking for a way of compressing a given string using the Lempel-Ziv Algorithm. Preferably there would only be a set of two functions, encoder and decoder. The encoder takes the string and returns an integer. The decoder takes the integer and returns the original string. Time complexity is not important. How would you implement this?

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  • Why, in Ruby, does Array("foo\nbar") == ["foo\n", "bar"]?

    - by Tyson
    In Ruby 1.8.7, Array("hello\nhello") gives you ["hello\n", "hello"]. This does two things that I don't expect: It splits the string on newlines. I'd expect it simply to give me an array with the string I pass in as its single element without modifying the data I pass in. Even if you accept that it's reasonable to split a string when passing it to Array, why does it retain the newline character when "foo\nbar".split does not? Additionally: >> Array.[] "foo\nbar" => ["foo\nbar"] >> Array.[] *"foo\nbar" => ["foo\n", "bar"]

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  • insert text in the middle of string in flex 3

    - by m6azeez
    hello all, can you please help me with this issue the String class does not have insert method it has only replace :( . what I need is: - if I have string "I stackoverflow" - I need to insert "love " at index 2 to have "I love stackoverflow" so what I need is insertAt(index, String) thanks

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  • Format the output of a string

    - by prince23
    hi here string strScore="2"; or string strScore="2.45656" now here i am checking the condition if it is double value = double.Parse(strScore); strScore = value.ToString("##.##"); 2.45656 like this then i am showing the output as 2.45 if the input is string strScore="2"; then the ouput is shown as "2" but now i need to show the output has 2.00 how can i format the code like this based on the condition

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  • Python elegant inverse function of int(string,base)

    - by random guy
    python allows conversions from string to integer using any base in the range [2,36] using: int(string,base) im looking for an elegant inverse function that takes an integer and a base and returns a string for example >>> str_base(224,15) 'ee' i have the following solution: def digit_to_char(digit): if digit < 10: return chr(ord('0') + digit) else: return chr(ord('a') + digit - 10) def str_base(number,base): if number < 0: return '-' + str_base(-number,base) else: (d,m) = divmod(number,base) if d: return str_base(d,base) + digit_to_char(m) else: return digit_to_char(m) note: digit_to_char() works for bases <= 169 arbitrarily using ascii characters after 'z' as digits for bases above 36 is there a python builtin, library function, or a more elegant inverse function of int(string,base) ?

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  • How do I not include part of a regular expression

    - by Axilus
    I'm pretty new to using regexes and I can figure out how I would go about extracted a specific number from a string. Suppose the string was any amount of whitespace or random text and somewhere within it is this, "Value: $1000.00." In order to retrieve that value I am currently using this: string value = Convert.ToString(Regex.Match(BodyContent, @"Value:[ \t]*\$?\d*(\.[0-9]{2})?", RegexOptions.Singleline)); So the variable 'value' now has, "Value: $1000.00" stored in it. My question is, using Regex is there a way to use 'Value:' to find the number value but only store the actual number value (i.e. 1000.00) in the 'value' variable?

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  • How to split this string in c#?

    - by melaos
    hi i'm really not used to the split string method in c# and i was wondering how come there's no split by more than one char function? and my attempt to try to split this string below using regex has just ended up in frustration. anybody can help me? basically i want to split the string below down to aa**aa**bb**dd^__^a2a**a2a**b2b**dd^__^ into aa**aa**bb**dd a2a**a2a**b2b**dd and then later into aa aa bb dd a2a a2a b2b dd thanks!

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  • Retain Delimiters when Splitting String

    - by JoeC
    Edit: OK, I can't read, thanks to Col. Shrapnel for the help. If anyone comes here looking for the same thing to be answered... print_r(preg_split('/([\!|\?|\.|\!\?])/', $string, null, PREG_SPLIT_DELIM_CAPTURE)); Is there any way to split a string on a set of delimiters, and retain the position and character(s) of the delimiter after the split? For example, using delimiters of ! ? . !? turning this: $string = 'Hello. A question? How strange! Maybe even surreal!? Who knows.'; into this array('Hello', '.', 'A question', '?', 'How strange', '!', 'Maybe even surreal', '!?', 'Who knows', '.'); Currently I'm trying to use print_r(preg_split('/([\!|\?|\.|\!\?])/', $string)); to capture the delimiters as a subpattern, but I'm not having much luck.

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  • Filtering python string through external program

    - by Peter
    What's the cleanest way of filtering a Python string through an external program? In particular, how do you write the following function? def filter_through(s, ext_cmd): # Filters string s through ext_cmd, and returns the result. # Example usage: # filter a multiline string through tac to reverse the order. filter_through("one\ntwo\nthree\n", "tac") # => returns "three\ntwo\none\n" Note: the example is only that - I realize there are much better ways of reversing lines in python.

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  • String date time format

    - by Phil
    Hi i am using the vimeo API and i want to convert the string to a short date formate {0:d} or {0:dd/mm/yyyy}. This is my code but doesnt seem to be working for me. select new VimeoVideo { Date = String.Format("{0:d}",(item.Element("upload_date").Value)), }; return Vids.ToList(); } public class VimeoVideo { public string Date { get; set; } } Any help would be much appreciated Thanks

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  • Convert string from getline into a number

    - by haskellguy
    I am trying to create a 2D array with vectors. I have a file that has for each line a set of numbers. So what I did I implemented a split function that every time I have a new number (separated by \t) it splits that and add it to the vector vector<double> &split(const string &s, char delim, vector<double> &elems) { stringstream ss(s); string item; while (getline(ss, item, delim)) { cout << item << endl; double number = atof(item.c_str()); cout << number; elems.push_back(number); } return elems; } vector<double> split(const string &s, char delim) { vector<double> elems; split(s, delim, elems); return elems; } After that I simply iterate through it. int main() { ifstream file("./data/file.txt"); string row; vector< vector<double> > matrix; int line_count = -1; while (getline(file, row)) { line_count++; if (line_count <= 4) continue; vector<double> cols = split(row, '\t'); matrix.push_back(cols); } ... } Now my issues is in this bit here: while (getline(ss, item, delim)) { cout << item << endl; double number = atof(item.c_str()); cout << number; Where item.c_str() is converted to a 0. Shouldn't that be still a string having the same value as item? It works on a separate example if I do straight from string to c_string, but when I use this getline I end up in this error situation, hints?

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  • Python: replace urls with title names from a string

    - by Hellnar
    Hello I would like to remove urls from a string replace them with their titles of the original contents. For example: mystring = "Ah I like this site: http://www.stackoverflow.com. Also I must say I like http://www.digg.com" sanitize(mystring) # it becomes "Ah I like this site: Stack Overflow. Also I must say I like Digg - The Latest News Headlines, Videos and Images" For replacing url to the title, I have written this snipplet: #get_title: string -> string def get_title(url): """Returns the title of the input URL""" output = BeautifulSoup.BeautifulSoup(urllib.urlopen(url)) return output.title.string

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  • ruby parametrized regular expression

    - by astropanic
    I have a string like "{some|words|are|here}" or "{another|set|of|words}" So in general the string consists of an opening curly bracket,words delimited by a pipe and a closing curly bracket. What is the most efficient way to get the selected word of that string ? I would like do something like this: @my_string = "{this|is|a|test|case}" @my_string.get_column(0) # => "this" @my_string.get_column(2) # => "is" @my_string.get_column(4) # => "case" What should the method get_column contain ?

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  • Scala : cleanest way to recursively parse files checking for multiple strings

    - by fred basset
    Hi All, I want to write a Scala script to recursively process all files in a directory. For each file I'd like to see if there are any cases where a string occurs at line X and line X - 2. If a case like that occurs I'd like to stop processing that file, and add that filename to a map of filenames to occurrence counts. I just started learning Scala today, I've got the file recurse code working, and need some help with the string searching, here's what I have so far: import java.io.File import scala.io.Source val s1= "CmdNum = 506" val s2 = "Data = [0000,]" def processFile(f: File) { val lines = scala.io.Source.fromFile(f).getLines.toArray for (i = 0 to lines.length - 1) { // want to do string searches here, see if line contains s1 and line two lines above also contains s1 //println(lines(i)) } } def recursiveListFiles(f: File): Array[File] = { val these = f.listFiles if (these != null) { for (i = 0 to these.length - 1) { if (these(i).isFile) { processFile(these(i)) } } these ++ these.filter(_.isDirectory).flatMap(recursiveListFiles) } else { Array[File]() } } println(recursiveListFiles(new File(args(0))))

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  • Good way to parse query string

    - by m.edmondson
    I have a String that contains the following: ?workarea=London+&+Home+Counties+Ltd&sub=fs&&&FASh*5 which resembles a URI query string. What is the best way to parse the elements of this string (workarea and sub) without messing about with string manipulation? If I use HttpUtility.ParseQueryString is gets stuck as both elements include &. However if I encode the whole thing first I lose the seperations of the elements. Ideally the output would be: workarea = London & Home Counties Ltd sub = fs&&&FASh*5

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  • mathing string in python

    - by nani
    Write two functions, called countSubStringMatch and countSubStringMatchRecursive that take two arguments, a key string and a target string. These functions iteratively and recursively count the number of instances of the key in the target string. You should complete definitions forthe remaining problems, we are going to explore other substring matching ideas. These problems can be solved with either an iterative function or a recursive one. You are welcome to use either approach, though you may find iterative approaches more intuitive in these cases of matching linear structures

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  • how to find if groovy args contains a particular string

    - by groovynoob
    println args println args.size() println args.each{arg-> println arg} println args.class if (args.contains("Hello")) println "Found Hello" when ran give following error: [hello, somethingelse] 2 hello somethingelse [hello, somethingelse] class [Ljava.lang.String; Caught: groovy.lang.MissingMethodException: No signature of method: [Ljava.lang. String;.contains() is applicable for argument types: (java.lang.String) values: [Hello] why can I not do contains?

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  • Split string into sentences based on periods

    - by rookie
    Hi all, I have written this piece of code that splits a string and stores it in a string array:- String[] sSentence = sResult.split("[a-z]\.\s+"); However, I've added the [a-z] because I wanted to deal with some of the abbreviation problem. But then my result shows up as so:- Furthermore when Everett tried to instruct them in basic mathematics they proved unresponsiv I see that I loose the pattern specified in the split function. Its okay for me to loose the period, but loosing the last letter of the word disturbs its meaning. Could some one help me with this and in addition also could someone help me with dealing with abbreviations? Like because I split the string based on periods, I do not want to loose the abbreviations. Thanks in advance

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  • Why are argument substitutions not replaced during rescanning?

    - by James McNellis
    Consider the following macro definitions and invocation: #define x x[0] #define y(arg) arg y(x) This invocation expands to x[0] (tested on Visual C++ 2010, g++ 4.1, mcpp 2.7.2, and Wave). Why? Specifically, why does it not expand to x[0][0]? During macro replacement, A parameter in the replacement list...is replaced by the corresponding argument after all macros contained therein have been expanded. Before being substituted, each argument’s preprocessing tokens are completely macro replaced (C++03 §16.3.1/1). Evaluating the macro invocation, we take the following steps: The function-like macro y is invoked with x as the argument for its arg parameter The x in the argument is macro-replaced to become x[0] The arg in the replacement list is replaced by the macro-replaced value of the argument, x[0] The replacement list after substitution of all the parameters is x[0]. After all parameters in the replacement list have been substituted, the resulting preprocessing token sequence is rescanned...for more macro names to replace (C++03 §16.3.4/1). If the name of the macro being replaced is found during this scan of the replacement list...it is not replaced. Further, if any nested replacements encounter the name of the macro being replaced, it is not replaced (C++03 §16.3.4/2). The replacement list x[0] is rescanned (note that the name of the macro being replaced is y): x is identified as an object-like macro invocation x is replaced by x[0] Replacement stops at this point because of the rule in §16.3.4/2 preventing recursion. The replacement list after rescanning is x[0][0]. I have clearly misinterpreted something since all of the preprocessors I've tested say I am wrong. In addition, this example is a piece of a larger example in the C++0x FCD (at §16.3.5/5) and it too says that the expected replacement is x[0]. Why is x not replaced during rescanning? C99 and C++0x effectively have the same wording as C++03 in the quoted sections.

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