Search Results

Search found 5065 results on 203 pages for 'django rss'.

Page 99/203 | < Previous Page | 95 96 97 98 99 100 101 102 103 104 105 106  | Next Page >

  • Not quite nested inlines?

    - by Lynden Shields
    Not quite sure what to call this, it's not quite nested inlines, but is probably related. I have a 3 level hierarchy of objects, A one-to-many B one-to-many C. Therefore, every C implicitly also belongs to an A. class A(models.Model): stuff = models.CharField("Stuff", max_length=50) class B(models.Model): a = models.ForeignKey(A) class C(models.Model): b = models.ForeignKey(B) I would like all C's that belong to an A to be listed on the admin page for A in an in-line. They do not have to show which B they belong to on the same page. Is this possible or is it the same problem as nested inlines anyway? If it's possible, how do I do it? I'm using django 1.3

    Read the article

  • Export Sharepoint 2007 Custom List as RSS File

    - by matt
    Here's our scenario: We've created a sharepoint 2007 calendar on our intranet site We want to run a daily job to export a subset of the events to an rss file Another job will move the rss file to our public web site We have some funny restrictions where we can't simply publish the rss feed to the public. We have to go this export route. I'm not clear on how to accomplish step 2. Ideally, we wouldn't have to write a lot of custom code to accomplish this. Thanks.

    Read the article

  • Retrieve a cross domain RSS(xml) through Javascript

    - by Ajay
    I have seen server side proxy workarounds for retrieving rss (xmls) from cross-domains. In fact this very question addressess my same problem but gives out a different solution. I have a constraint of do not use a proxy to retrieve rss feeds. And hence the Google AJAX Feed API solution also goes out of picture. Is there a client-only workaround for this problem. JSONP is the solution for requests that respond with JSON output. But here, I have RSS feeds which can respond with pure xml . How do I solve the problem.

    Read the article

  • Celery tasks not works with gevent

    - by Novarg
    When i use celery + gevent for tasks that uses subprocess module i'm getting following stacktrace: Traceback (most recent call last): File "/home/venv/admin/lib/python2.7/site-packages/celery/task/trace.py", line 228, in trace_task R = retval = fun(*args, **kwargs) File "/home/venv/admin/lib/python2.7/site-packages/celery/task/trace.py", line 415, in __protected_call__ return self.run(*args, **kwargs) File "/home/webapp/admin/webadmin/apps/loggingquarantine/tasks.py", line 107, in release_mail_task res = call_external_script(popen_obj.communicate) File "/home/webapp/admin/webadmin/apps/core/helpers.py", line 42, in call_external_script return func_to_call(*args, **kwargs) File "/usr/lib64/python2.7/subprocess.py", line 740, in communicate return self._communicate(input) File "/usr/lib64/python2.7/subprocess.py", line 1257, in _communicate stdout, stderr = self._communicate_with_poll(input) File "/usr/lib64/python2.7/subprocess.py", line 1287, in _communicate_with_poll poller = select.poll() AttributeError: 'module' object has no attribute 'poll' My manage.py looks following (doing monkeypatch there): #!/usr/bin/env python from gevent import monkey import sys import os if __name__ == "__main__": if not 'celery' in sys.argv: monkey.patch_all() os.environ.setdefault("DJANGO_SETTINGS_MODULE", "webadmin.settings") from django.core.management import execute_from_command_line sys.path.append(".") execute_from_command_line(sys.argv) Is there a reason why celery tasks act like it wasn't patched properly? p.s. strange thing that my local setup on Macos works fine while i getting such exceptions under Centos (all package versions are the same, init and config scripts too)

    Read the article

  • Using map() on a _set in a template?

    - by Stuart Grimshaw
    I have two models like this: class KPI(models.Model): """KPI model to hold the basic info on a Key Performance Indicator""" title = models.CharField(blank=False, max_length=100) description = models.TextField(blank=True) target = models.FloatField(blank=False, null=False) group = models.ForeignKey(KpiGroup) subGroup = models.ForeignKey(KpiSubGroup, null=True) unit = models.TextField(blank=True) owner = models.ForeignKey(User) bt_measure = models.BooleanField(default=False) class KpiHistory(models.Model): """A historical log of previous KPI values.""" kpi = models.ForeignKey(KPI) measure = models.FloatField(blank=False, null=False) kpi_date = models.DateField() and I'm using RGraph to display the stats on internal wallboards, the handy thing is Python lists get output in a format that Javascript sees as an array, so by mapping all the values into a list like this: def f(x): return float(x.measure) stats = map(f, KpiHistory.objects.filter(kpi=1) then in the template I can simply use {{ stats }} and the RGraph code sees it as an array which is exactly what I want. [87.0, 87.5, 88.5, 90] So my question is this, is there any way I can achieve the same effect using Django's _set functionality to keep the amount of data I'm passing into the template, up until now I've been passing in a single KPI object to be graphed but now I want to pass in a whole bunch so is there anything I can do with _set {{ kpi.kpihistory_set }} dumps the whole model out, but I just want the measure field. I can't see any of the built in template methods that will let me pull out just the single field I want. How have other people handled this situation?

    Read the article

  • Setting encoding in Grails controller's render method

    - by Philippe
    Hello, I'm trying to build an RSS feed using Grails and Rome. In my controller's rss action, my last command is : render(text: getFeed("rss_2.0"), contentType:"application/rss+xml", encoding:"ISO-8859-1 ") However, when I navigate to my feed's URL, the header is : <?xml version="1.0" encoding="UTF-8"?> <rss xmlns:dc="http://purl.org/dc/elements/1.1/" version="2.0"> ... Does anyone have a clue about WHY the encoding is UTF-8 when I set it to ISO-8859-1 in the render method ??? Thanks for your help !

    Read the article

  • What happens after a packet is captured?

    - by Rayne
    Hi all, I've been reading about what happens after packets are captured by NICs, and the more I read, the more I'm confused. Firstly, I've read that traditionally, after a packet is captured by the NIC, it gets copied to a block of memory in the kernel space, then to the user space for whatever application that then works on the packet data. Then I read about DMA, where the NIC directly copies the packet into memory, bypassing the CPU. So is the NIC - kernel memory - User space memory flow still valid? Also, do most NIC (e.g. Myricom) use DMA to improve packet capture rates? Secondly, does RSS (Receive Side Scaling) work similarly in both Windows and Linux systems? I can only find detailed explanations on how RSS works in MSDN articles, where they talk about how RSS (and MSI-X) works on Windows Server 2008. But the same concept of RSS and MSI-X should still apply for linux systems, right? Thank you. Regards, Rayne

    Read the article

  • Question on SyndicationItem - ASP.NET

    - by bobsmith123
    I am trying to understand how to use SyndicationItem to display feed which is RSS 2.0 or Atom compliant. What property of SyndicationItem gives me the entire description of the post. It appears that there is a Summary property but per MSDN, it gives only the Summary. Also I have noticed that in my RSS feed reader, some RSS feeds show only a few lines of description and I have to click and go to the website for the full post. But in some feeds, I can see the full post within the Feed Reader. Can someone explain how all this comes together? PS: My web page lets user enter a RSS feed address and I need to validate if the feed exists. If it does, I need to grab the last x items and show the feed's title and full description

    Read the article

  • XML Parsing Error: junk after document element

    - by Jake
    I am using the following script to generate a RSS feed for my site: <?php class RSS { public function RSS() { $root = $_SERVER['DOCUMENT_ROOT']; require_once ("../connect.php"); } public function GetFeed() { return $this->getDetails() . $this->getItems(); } private function dbConnect() { DEFINE ('LINK', mysql_connect (DB_HOST, DB_USER, DB_PASSWORD)); } private function getDetails() { $detailsTable = "rss_feed_details"; $this->dbConnect($detailsTable); $query = "SELECT * FROM ". $detailsTable ." WHERE feed_category = ''"; $result = mysql_db_query (DB_NAME, $query, LINK); while($row = mysql_fetch_array($result)) { $details = '<?xml version="1.0" encoding="ISO-8859-1" ?> <rss version="2.0"> <channel> <title>'. $row['title'] .'</title> <link>'. $row['link'] .'</link> <description>'. $row['description'] .'</description> <language>'. $row['language'] .'</language> <image> <title>'. $row['image_title'] .'</title> <url>'. $row['image_url'] .'</url> <link>'. $row['image_link'] .'</link> <width>'. $row['image_width'] .'</width> <height>'. $row['image_height'] .'</height> </image>'; } return $details; } private function getItems() { $itemsTable = "rss_posts"; $this->dbConnect($itemsTable); $query = "SELECT * FROM ". $itemsTable ." ORDER BY id DESC"; $result = mysql_db_query (DB_NAME, $query, LINK); $items = ''; while($row = mysql_fetch_array($result)) { $items .= '<item> <title>'. $row["title"] .'</title> <link>'. $row["link"] .'</link> <description><![CDATA['.$row["readable_date"]."<br /><br />".$row["description"]."<br /><br />".']]></description> </item>'; } $items .= '</channel> </rss>'; return $items; } } ?> The baffling thing is, the script works perfectly fine on my localhost but gives the following error on my remote server: XML Parsing Error: junk after document element Location: http://mysite.com/rss/main/ Line Number 2, Column 1:<b>Parse error</b>: syntax error, unexpected T_STRING in <b>/home/studentw/public_html/rss/global-reach/rssClass.php</b> on line <b>1</b><br /> ^ Can someone please tell me what's wrong?

    Read the article

  • Help me please, javascript place problem or another thing??

    - by ilkdrl
    <%@ Page Language="C#" AutoEventWireup="true" CodeFile="Urunler.aspx.cs" Inherits="Urunler" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <meta http-equiv="content-language" content="en" /> <link href="rss/example_ticker.css" rel="stylesheet" type="text/css" /> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js" type="text/javascript"></script> <script src="rss/jquery.zrssfeed.min.js" type="text/javascript"></script> <script src="rss/jquery.vticker.js" type="text/javascript"></script> <title></title> <script type="text/javascript" src="lightbox/js/prototype.js"></script> <script type="text/javascript" src="lightbox/js/scriptaculous.js?load=effects,builder"></script> <script type="text/javascript" src="lightbox/js/lightbox.js"></script> <link rel="stylesheet" href="lightbox/css/lightbox.css" type="text/css" media="screen" /> <style type="text/css"> ........... ........... ........... <td style="background-color: #808080"> <script type="text/javascript"> $(document).ready(function () { $('#ticker1').rssfeed('http://www.xxxxxxx.com/map.asp').ajaxStop(function () { $('#ticker1 div.rssBody').vTicker({ showItems: 3 }); }); }); </script> <div id="ticker1" > </div> Hi, i have two scripts.lightbox and rss. lightbox script works very well in mywebform1 but rss feed dont work.I didnot solve that?Help me please. PS: on the other hand, my another webpage(mywebform2) in same website has only rss feed and works very well.

    Read the article

  • java.io.FileNotFoundException for valid URL

    - by Alexei
    Hello. I use library rome.dev.java.net to fetch RSS. Code is URL feedUrl = new URL("http://planet.rubyonrails.ru/xml/rss"); SyndFeedInput input = new SyndFeedInput(); SyndFeed feed = input.build(new XmlReader(feedUrl)); You can check that http://planet.rubyonrails.ru/xml/rss is valid URL and the page is shown in browser. But I get exception from my application java.io.FileNotFoundException: http://planet.rubyonrails.ru/xml/rss at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1311) at com.sun.syndication.io.XmlReader.<init>(XmlReader.java:237) at com.sun.syndication.io.XmlReader.<init>(XmlReader.java:213) at rssdaemonapp.ValidatorThread.run(ValidatorThread.java:32) at java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:886) at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:908) at java.lang.Thread.run(Thread.java:619) I don't use any proxy. I get this exception on my PC and on the production server and only for this URL, other URLs are working.

    Read the article

  • What is this XML Parse Error?

    - by Jake
    I am using the following script to generate a RSS feed for my site: <?php class RSS { public function RSS() { $root = $_SERVER['DOCUMENT_ROOT']; require_once ("../connect.php"); } public function GetFeed() { return $this->getDetails() . $this->getItems(); } private function dbConnect() { DEFINE ('LINK', mysql_connect (DB_HOST, DB_USER, DB_PASSWORD)); } private function getDetails() { $detailsTable = "rss_feed_details"; $this->dbConnect($detailsTable); $query = "SELECT * FROM ". $detailsTable ." WHERE feed_category = ''"; $result = mysql_db_query (DB_NAME, $query, LINK); while($row = mysql_fetch_array($result)) { $details = '<?xml version="1.0" encoding="ISO-8859-1" ?> <rss version="2.0"> <channel> <title>'. $row['title'] .'</title> <link>'. $row['link'] .'</link> <description>'. $row['description'] .'</description> <language>'. $row['language'] .'</language> <image> <title>'. $row['image_title'] .'</title> <url>'. $row['image_url'] .'</url> <link>'. $row['image_link'] .'</link> <width>'. $row['image_width'] .'</width> <height>'. $row['image_height'] .'</height> </image>'; } return $details; } private function getItems() { $itemsTable = "rss_posts"; $this->dbConnect($itemsTable); $query = "SELECT * FROM ". $itemsTable ." ORDER BY id DESC"; $result = mysql_db_query (DB_NAME, $query, LINK); $items = ''; while($row = mysql_fetch_array($result)) { $items .= '<item> <title>'. $row["title"] .'</title> <link>'. $row["link"] .'</link> <description><![CDATA['.$row["readable_date"]."<br /><br />".$row["description"]."<br /><br />".']]></description> </item>'; } $items .= '</channel> </rss>'; return $items; } } ?> The baffling thing is, the script works perfectly fine on my localhost but gives the following error on my remote server: XML Parsing Error: junk after document element Location: http://mysite.com/rss/main/ Line Number 2, Column 1:<b>Parse error</b>: syntax error, unexpected T_STRING in <b>/home/studentw/public_html/rss/global-reach/rssClass.php</b> on line <b>1</b><br /> ^

    Read the article

  • What's the best way to run Drupal and Django sites behind the same Varnish server?

    - by Alexis Bellido
    I have a high traffic website running with Drupal and Apache, five web servers behind a Varnish server load balancing. Let's say this site is example.com. I'm using five backends and a director like this in my default.vcl: director balancer round-robin { { .backend = web1; } { .backend = web2; } { .backend = web3; } { .backend = web4; } { .backend = web5; } } Now I'm working on a new Django project that will be a new section of this site running on example.com/new-section. After checking the documentation I found I can do something like this: sub vcl_recv { if (req.url ~ "^/new-section/") { set req.backend = newbackend; } else { set req.backend = default; } } That is, using a different backend for a subdirectory /new-section under the same domain. My question is, how do I make something like this work with my director and load balancing setup? I'm probably going to run two or more web servers (backends) with my new Django project, each one with a mix of Gunicorn, Nginx, and a few Python packages, and would like to put all of those in their own Varnish director to load balance. Is it possible to do use the above approach to decide which director to use?, like this: sub vcl_recv { if (req.url ~ "^/new-section/") { set req.director = newdirector; } else { set req.director = balancer; } } All suggestions welcome. Thanks!

    Read the article

  • Scrapy - Follow RSS links

    - by Tupak Goliam
    Hello, I was wondering if anyone ever tried to extract/follow RSS links using SgmlLinkExtractor/CrawlSpider. I can't get it to work... I am using the following rule: rules = ( Rule(SgmlLinkExtractor(tags=('link',), attrs=False), follow=True, callback='parse_article'), ) (having in mind that rss links are located in the link tag). I am not sure how to tell SgmlLinkExtractor to extract the text() of the link and not to search the attributes ... Any help is welcome, Thanks in advance

    Read the article

  • Media RSS and Zend

    - by user303774
    Hi, I have a Magento application running atop Zend framework. I like to generate Media RSS feed in Zend (In orded to feed the Cooliris application). Does anyone know if Zend framework supports Media RSS feed? (I didn't find anything in http://framework.zend.com/manual/1.10/en/zend.feed.html, but maybe I dint look in the right place?) Tx, Sty

    Read the article

  • Twitter rss feed 401 - unauthorisation

    - by RenegadeAndy
    Hey. I have a public twitter account and this is the rss feed for it: http://twitter.com/statuses/friends_timeline/150784631.rss The problem is, im getting an http 401 whenever im trying to access it. Can anybody explain how to stop this - and get it to work either with authentication or without! Cheers

    Read the article

  • Go for Zend framework or Django for a modular web application?

    - by dr. squid
    I am using both Zend framework and Django, and they both have they strengths and weakness, but they are both good framworks in their own way. I do want to create a highly modular web application, like this example: modules: Admin cms articles sections ... ... ... I also want all modules to be self contained with all confid and template files. I have been looking into a way to solve this is zend the last days, but adding one omer level to the module setup doesn't feel right. I am sure this could be done, but should I? I have also included Doctrine to my zend application that could give me even more problems in my module setup! When we are talking about Django this is easy to implement (Easy as in concept, not in implementation time or whatever) and a great way to create web apps. But one of the downsides of Django is the web hosing part. There are some web hosts offering Django support, but not that many.. So then I guess the question is what have the most value; rapid modular development versus hosting options! Well, comments are welcome! Thanks

    Read the article

  • Django: How can I identify the calling view from a template?

    - by bryan
    Short version: Is there a simple, built-in way to identify the calling view in a Django template, without passing extra context variables? Long (original) version: One of my Django apps has several different views, each with its own named URL pattern, that all render the same template. There's a very small amount of template code that needs to change depending on the called view, too small to be worth the overhead of setting up separate templates for each view, so ideally I need to find a way to identify the calling view in the template. I've tried setting up the views to pass in extra context variables (e.g. "view_name") to identify the calling view, and I've also tried using {% ifequal request.path "/some/path/" %} comparisons, but neither of these solutions seems particularly elegant. Is there a better way to identify the calling view from the template? Is there a way to access to the view's name, or the name of the URL pattern? Update 1: Regarding the comment that this is simply a case of me misunderstanding MVC, I understand MVC, but Django's not really an MVC framework. I believe the way my app is set up is consistent with Django's take on MVC: the views describe which data is presented, and the templates describe how the data is presented. It just happens that I have a number of views that prepare different data, but that all use the same template because the data is presented the same way for all the views. I'm just looking for a simple way to identify the calling view from the template, if this exists. Update 2: Thanks for all the answers. I think the question is being overthought -- as mentioned in my original question, I've already considered and tried all of the suggested solutions -- so I've distilled it down to a "short version" now at the top of the question. And right now it seems that if someone were to simply post "No", it'd be the most correct answer :) Update 3: Carl Meyer posted "No" :) Thanks again, everyone.

    Read the article

  • What's the next steps for moving from appengine to full django?

    - by tomcritchlow
    Hey guys, I'm super new to programming and I've been using appengine to help me learn python and general coding. I'm getting better quickly and I'm loving it all the way :) Appengine was awesome for allowing me to just dive into writing my app and getting something live that works (see http://www.7bks.com/). But I'm realising that the longer I continue to learn on appengine the more I'm constraining myself and locking myself into a single system. I'd like to move to developing on full django (since django looks super cool!). What are my next steps? To give you a feel for my level of knowledge: I'm not a unix user I'm not familiar with command line controls (I still use appengine/python completely via the appengine SDK) I've never programmed in anything other than python, anywhere other than appengine I know the word SQL, but don't know what MySQL is really or how to use it. So, specifically: What are the skills I need to learn to get up and running with full django/python? If I'm going to host somewhere else I suppose I'll need to learn some sysadmin type skills (maybe even unix?). Is there anywhere that offers easy hosting (like appengine) but that supports django? I hear such great things about heroku I'm considering switching to RoR and going there I appreciate that I'm likely not quite ready to move away from appengine just yet but I'm a fiercely passionate learner (http://www.7bks.com/blog/179001) and would love it if I knew all the steps I needed to learn so I could set about learning them. At the moment, I don't even know what the steps are I need to learn! Thank you very much. Sorry this isn't a specific programming question but I've looked around and haven't found a good how-to for someone of my level of experience and I think others would appreciate a good roadmap for the things we need to learn to get up and running. Thanks, Tom PS - if anyone is in London and fancies showing me the ropes in person that would be super awesome :)

    Read the article

  • How to manage feeds with subclassed object in Django 1.2?

    - by Matteo
    Hi, I'm trying to generate a feed rss from a model like this one, selecting all the Entry objects: from django.db import models from django.contrib.sites.models import Site from django.contrib.auth.models import User from imagekit.models import ImageModel import datetime class Entry(ImageModel): date_pub = models.DateTimeField(default=datetime.datetime.now) author = models.ForeignKey(User) via = models.URLField(blank=True) comments_allowed = models.BooleanField(default=True) icon = models.ImageField(upload_to='icon/',blank=True) class IKOptions: spec_module = 'journal.icon_specs' cache_dir = 'icon/resized' image_field = 'icon' class Post(Entry): title = models.CharField(max_length=200) description = models.TextField() slug = models.SlugField(unique=True) def __unicode__(self): return self.title class Photo(Entry): alt = models.CharField(max_length=200) description = models.TextField(blank=True) original = models.ImageField(upload_to='photo/') class IKOptions: spec_module = 'journal.photo_specs' cache_dir = 'photo/resized' image_field = 'original' def __unicode__(self): return self.alt class Quote(Entry): blockquote = models.TextField() cite = models.TextField(blank=True) def __unicode__(self): return self.blockquote When I use the render_to_response in my views I simply call: def get_journal_entries(request): entries = Entry.objects.all().order_by('-date_pub') return render_to_response('journal/entries.html', {'entries':entries}) And then I use a conditional template to render the right snippets of html: {% extends "base.html" %} {% block main %} <hr> {% for entry in entries %} {% if entry.post %}[...]{% endif %}[...] But I cannot do the same with the Feed Framework in django 1.2... Any suggestion, please?

    Read the article

  • How can I get sessions to work if I'm using Google App Engine + Django 1.1?

    - by user341642
    Is there a way for me to get sessions working? I know Django has built in session management, and GAE has some tools for it if you're using their watered down version of Django 0.96, but is there a way to get sessions to work if you're trying to use GAE w/ Django 1.1 (i.e. use_library() call). I assume using a db-backed session doesn't work, and a file system backed one won't work b/c we don't have access to the filesystem if we deploy to the Google production servers. This kinda worked (as in didn't crap out) when I used SessionMiddleware backed by a local-memory backed cache and a non-persistent cache (i.e. setting SESSION_ENGINE to django.contrib.sessions.backends.cache). But the session never seems to persist in this case, no matter how I set the timeouts. A new session key is generated on every page reload. Maybe this is b/c the GAE assumes complete statelessness with each request and blows away my local cache? Apologies in advance, I'm pretty new to Python. Any suggestions would be greatly appreciated.

    Read the article

  • Fix: Outlook 2010 Update Progress

    - by wisecarver
    Hey hey hey…Microsoft Office was released today on MSDN! What I’m posting here is not intended as a complaint. The updates to Office are awesome! I did however run into a few problems upgrading today. First of all, if you going to install the 64bit Office 2010 please note that you can’t install the 64bit Office 2010 if you are trying to install on a machine that is running 32bit Office 2007. You will need to uninstall your 32bit Office 2007 or install the 32bit Office 2010 instead of the 64bit version...(read more)

    Read the article

  • Self hosted Netvibes alternative [on hold]

    - by Jens
    I am looking for a self-hosted alternative to part of the Netvibes functionality. It should act as feed reader, show my mail inbox, a list of bookmarks and maybe the weather forecast. I wish to move away from Netvibes since I don't care to share my browsing habit, and certainly not my mail password, with another person or company. I am certainly willing to invest some time in setup, maybe up to writing a plugin for a solution that does not fulfill all my requirements. Dou you have suggestions on where to look?

    Read the article

< Previous Page | 95 96 97 98 99 100 101 102 103 104 105 106  | Next Page >