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  • How to show all the tables from multiple databases

    - by saorabh
    How to select all the tables from multiple databases in mySql.. I am doing the following steps but not able to achive the goal. <?php $a = "SHOW DATABASES"; $da = $wpdb->get_results($a); foreach($da as $k){ echo '<pre>'; print_r ($k->Database);//prints all the available databases echo '</pre>'; $nq = "USE $k->Database";//trying to select the individual database $newda = $wpdb->get_results($nq); $alld = "SELECT * FROM $k->Database"; $td = $wpdb->get_results($alld); var_dump($td);//returns empty array } ?> Please Help me

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  • click multiple times a submit button

    - by Olga Anastasiadou
    Hi all, I encountered a problem that I can't solve. My point is to "click" my sybmit button and every time increase a counter, while this counter reach 10. For the first time it works, but this is it! My test code is below : <form name="testForm" method="post"> <?php $cnt=0; ?> <input type="submit" name="next" id="next" value="NEXT"/> <?php if(isset($_POST['next'])){ if($cnt< 10){ echo $cnt.' --> '; $cnt++; echo $cnt; } } ?> </form> Only 0 -- 1 is printed, every time... please help!! Thanks

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  • how can i strip formatting from word document using php

    - by shazia
    I want to display a word file and then extract the content and display it in a separate textarea. i want to do away with the formatting as well. this is what i get when i get the read the text file using php ??????ÿÿÿÿ???????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????Running Head: INTERNATIONAL BUSINESS International Business [Name of the writer] [Name of the institution] International Business Question 1 Increasing returns to scale (or economies of scale) in production is an indisputable phenomenon characterizing real world production, and, as such, they have long been recognized as a principal source of economic prosperity. Nonetheless, they have never played a major role in this is the code $fh = fopen($newname, 'r'); $contents => fread($fh, filesize($newname)); fclose($fh); unlink($newname); echo "<br/>"; echo $contents; how can i get rid of all these charecters. Thanks

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  • How do I change the JAVA_HOME for ant?

    - by Eugene M
    I'm doing java work on a class server where I don't have root. Whenever I try to compile using ant, it points to the wrong directory (/usr/tomcat instead of /usr/tomcat/jre ). One of the things we were told to do when setting up our user accounts was to add export JAVA_HOME=/usr/tomcat/jre to the .bashrc file. I don't know if that was supposed to take care of the problem but it doesn't seem to. So, how can I change the JAVA_HOME property for ant but only for when I run ant? EDIT: echo $JAVA_HOME points to /usr/tomcat/jre echo $JAVA_HOME\bin points to /usr/tomcat/jrebin The problem is when I normally run ant I get this error: Unable to locate tools.jar. Expected to find it in /usr/tomcat/lib/tools.jar Buildfile: build.xml compile: [javac] Compiling 1 source file to /home/ejm244/build/classes BUILD FAILED /home/ejm244/build.xml:9: Unable to find a javac compiler; com.sun.tools.javac.Main is not on the classpath. Perhaps JAVA_HOME does not point to the JDK Total time: 0 seconds

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  • How to Execute an Oracle SQL Statements with VBScript

    - by Arno Conradie
    I am trying to execute an Oracle SQL statement or Oracle Functions through Microsoft VBScript and the loop throught the result set or display the value returned by the function So far I have managed to connect to Oracle via SQLPlus*, but now I am stuck. Can anybody help? Dim output Dim WshShell, oExec, input set WshShell = CreateObject("WScript.Shell") set oEnv=WshShell.Environment("Process") cmdString = "C:\Oracle\11g\product\11.1.0\ruby\BIN\sqlplus.exe -S stradmin/stradmin@ruby select * from dual" Set oExec = WshShell.Exec(cmdString) WScript.Echo "Status" & oExec.Status Do While oExec.Status = 0 WScript.Sleep 2 Loop input = "" Do While Not oExec.StdOut.AtEndOfStream input = input & oExec.StdOut.Read(1) Loop wscript.echo input

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  • Why does get_posts() return only 5 matching posts, when it should return 9?

    - by Scott B
    global $post; $cat1=get_cat_ID('test1'); $cat2=get_cat_ID('test2'); $myrecentposts = get_posts(array('post_not_in' => get_option('sticky_posts'), 'cat' => "-$cat1,-$cat2",'showposts' => 5)); $myrecentposts2 = get_posts(array('post_not_in' => get_option('sticky_posts'), 'cat' => "-$cat1,-$cat2")); $myrecentpostscount = count($myrecentposts2); echo $myrecentpostscount; The value of the echo is 5 (the correct value should be 9). The only way I can get it to return the correct value for the post count is to change the $myrecentposts2 calculation as follows... $myrecentposts2 = get_posts(array('post_not_in' => get_option('sticky_posts'), 'cat' => "-$cat1,-$cat2",'showposts' => 999));

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  • How can I execute a PHP function in a form action?

    - by stocksy101
    I am trying to run a function from a PHP script in the form action. My code: <?php require_once ( 'username.php' ); echo ' <form name="form1" method="post" action="username()"> <p> <label> <input type="text" name="textfield" id="textfield"> </label> </p> <p> <label> <input type="submit" name="button" id="button" value="Submit"> </label> </p> </form>'; ?> I echo the form but I want the function "username" which is called from username.php to be executed. how can I do this in a simliar way to the above?

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  • Use text input as php variable

    - by Thomas Lai
    <input type="text" onkeydown="domaincheck()" /> <?php function domaincheck() { $recordexists = checkdnsrr("", "ANY"); if ($recordexists) echo "The domain name has been taken. Sorry!"; else echo "The domain name is available!"; } ?> I want my php code to process the text input and say if it's a valid domain or not. The only thing that doesn't work is linking the input to the php.

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  • foreach with an array of stdclass objects

    - by Jared Steffen
    So, what I want to do is quite simple in my mind. I have an array that consists solely of four objects. I want to create a loop that will echo an attribute of each object in the array. The only success I've had, however, is echoing every object and every property of the objects. I've never dealt with objects so this is probably the TRUE root of the problem. There's been a few revisions but the only thing I've really excelled at is creating error codes. Here is what I have: $categories = get_categories(array('child_of' => '8')); foreach ($categories as $cat) { echo $cat->name; };

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  • codeIgniter: pass parameter to a select query from previous query

    - by krike
    I'm creating a little management tool for the browser game travian. So I select all the villages from the database and I want to display some content that's unique to each of the villages. But in order to query for those unique details I need to pass the id of the village. How should I do this? this is my code (controller): function members_area() { global $site_title; $this->load->model('membership_model'); if($this->membership_model->get_villages()) { $data['rows'] = $this->membership_model->get_villages(); $id = 1;//this should be dynamic, but how? if($this->membership_model->get_tasks($id)): $data['tasks'] = $this->membership_model->get_tasks($id); endif; } $data['title'] = $site_title." | Your account"; $data['main_content'] = 'account'; $this->load->view('template', $data); } and this is the 2 functions I'm using in the model: function get_villages() { $q = $this->db->get('villages'); if($q->num_rows() > 0) { foreach ($q->result() as $row) { $data[] = $row; } return $data; } } function get_tasks($id) { $this->db->select('name'); $this->db->from('tasks'); $this->db->where('villageid', $id); $q = $this->db->get(); if($q->num_rows() > 0) { foreach ($q->result() as $task) { $data[] = $task; } return $data; } } and of course the view: <?php foreach($rows as $r) : ?> <div class="village"> <h3><?php echo $r->name; ?></h3> <ul> <?php foreach($tasks as $task): ?> <li><?php echo $task->name; ?></li> <?php endforeach; ?> </ul> <?php echo anchor('site/add_village/'.$r->id.'', '+ add new task'); ?> </div> <?php endforeach; ?> ps: please do not remove the comment in the first block of code!

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  • IE problem with javascript

    - by Syom
    i have the following simple script <input class="input" type="text" name="password" style="color: #797272;" value= "<?php if ($_POST[password] != '') {echo '';} else {echo '????????';}?>" onclick="if (this.value === this.defaultValue) { this.value=''; this.style.color='black'; this.type='password'; }" /> it works fine, but in IE7 it doesn't change the input type. this.type='password'; doesn't work could you help me? thanks

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  • mysql_fetch_array() not displaying all results

    - by user1666995
    I have a database with a calendar table (each row represents one day) with 4 years of rows (2012, 2013, 2014, 2015). I use the column name calyear for the year. I use the following code to find values for distinct years then display it: $year = mysql_query("SELECT DISTINCT calyear FROM calendar"); while($yeararray = mysql_fetch_array($year)) { echo($yeararray['calyear']."<br />"); } The problem is it only displays the years 2013, 2014, 2015 even though when I use echo(mysql_num_rows($year); it displays the value 4 which I take to mean all 4 years are there. I'm not quite sure where I'm going wrong with this.

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  • jQuery - Show field based on value of a type-hidden on refresh.

    - by Sebhael
    Hello, I'm trying to create something in jQuery and having a bit of problems with it. I'm not too adept on the framework, so I'm sure this is all wrong. Anyways, the ultimate goal is a full form that contains 3 radio buttons - depending on the value of the button, a LI is shown. I have all of that done, but my problem is coming with validation. If something fails then the page is reloaded and the div that was selected doesn't show without clicking another radio first, then back to the original. This process is basically the same as someone came up with here. Here's what I got so far. HTML <li> <label> License (radio) </label> <label for="commercial" class="checkBox"> Commercial </label> <input type="radio" name="license" value="commercial" id="commercial" class="checkBox" <?php echo set_radio('license', 'commercial'); ?> /> <label for="abandonware" class="checkBox"> Abandonware </label> <input type="radio" name="license" value="abandonware" id="abandonware" class="checkBox" <?php echo set_radio('license', 'abandonware'); ?> /> <label for="freeware" class="checkBox"> Freeware </label> <input type="radio" name="license" value="freeware" id="freeware" class="checkBox" <?php echo set_radio('license', 'freeware'); ?> /> </li> This is followed by three LI's that contain id="commercial, abandonware, and freeware" and class="licenseli" My jQuery is, as said, something from here. $('li.licenseli').hide(); $('input[name=license]:radio').change(function(){ var Type = $(this).val(); // Get value of radio $('li.licenseli').slideUp(); // Hide non-selected $('li#'+Type).slideDown(); // Show Selected }); So what I need help with is I have a hidden input that retrieves the value of the radio box from validation - I want to take this value (or the radio's if possible?) and have the original selected option's LI already visible.

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  • VBScript: how to set values from recordset to string

    - by phill
    This is probably a beginner question, but how do you set a recordset to a string variable? Here is my code: Function getOffice (strname, uname) strEmail = uname WScript.Echo "email: " & strEmail Dim objRoot : Set objRoot = GetObject("LDAP://RootDSE") Dim objDomain : Set objDomain = GetObject("LDAP://" & objRoot.Get("defaultNamingContext")) Dim cn : Set cn = CreateObject("ADODB.Connection") Dim cmd : Set cmd = CreateObject("ADODB.Command") cn.Provider = "ADsDSOObject" cn.Open "Active Directory Provider" Set cmd.ActiveConnection = cn cmd.CommandText = "SELECT physicalDeliveryOfficeName FROM '" & objDomain.ADsPath & "' WHERE mail='" & strEmail & "'" cmd.Properties("Page Size") = 1 cmd.Properties("Timeout") = 300 cmd.Properties("Searchscope") = ADS_SCOPE_SUBTREE Dim objRS : Set objRS = cmd.Execute WScript.Echo objRS.Fields(0) Set cmd = Nothing Set cn = Nothing Set objDomain = Nothing Set objRoot = Nothing Dim arStore Set getOffice = objRS.Fields(0) Set objRS = Nothing End function When I try to run the function, it throws an error "vbscript runtime error: Type mismatch" I presume this means it can't set the string variable with a recordset value. How do I fix this problem?

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  • json null error help in php

    - by bobby
    I get 'json is null' as error My php file: <?php if (isset($_REQUEST['query'])) { $query = $_REQUEST['query']; $url='https://www.googleapis.com/urlshortener/v1/'; $key='ApiKey'; $result= $url.($query).$key; $ch = curl_init($result); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,1); $resp = curl_exec($ch); curl_close($ch); echo $resp; } ?> My html: <html> <head> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ // when the user clicks the button $("button").click(function(){ $.getJSON("shortner.php?query="+$('#query').attr("value"),function(json){ $('#results').append('<p>Id : ' + json.id+ '</p>'); $('#results').append('<p>Longurl: ' + json.longurl+ '</p>'); }); }); }); </script> </head> <body> <input type="text" value="Enter a place" id="query" /><button>Get Coordinates</button> <div id="results"></div> Edited : <?php if (isset($_REQUEST['query'])) { $query = $_REQUEST['query']; $url='https://www.googleapis.com/urlshortener/v1/'; $key='Api'; $key2='?key='; $result= $url.$query.$key2.$key; $requestData= json_encode($result); echo var_dump($query); $ch = curl_init($requestData); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,1); $resp = curl_exec($ch); curl_close($ch); echo $resp; } ?>

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  • Move/copy files/folder in linux/solaris using only bash built-ins

    - by KullDox
    There was a situation when somebody moved the whole rootdir into a subdir on a remote system, thus all the system tools like cp, mv, etc didn't work anymore. We had an active session though but couldn't find a way to copy/move the files back using only bash built-ins. Do somebody know of a way to achieve this? I even thought about copy the cp or mv binary in the currentdir with while read -r; do echo $LINE; done and then redirect this to a file, but it didn't work. Guess because of all the special non printable chars in a binary file that can't be copied/displayed using echo. thanks.

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  • json jquery post request

    - by John
    <script type="text/javascript"> $(document).ready(function() { $("a").click(function() { var content = $('#content').html(); var data = {"content":content}; $.ajax({ type: "POST", dataType: "json", url: "ajax.php", data: {content:content}, success function (data) { alert('Hello!'); } }); }); }); </script> <div id="content"><?php echo $content; ?></div> ajax.php echo json_encode($_POST['content']); ?> Nothing happens... WhatI really want to achieve is to get that alert box and get the return data, but I am lost since I don't get any errors or nothing.

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  • How to concatenate multiple lines of log file into single variable in batch file?

    - by psych
    I have a log file containing a stack trace split over a number of lines. I need to read this file into a batch file and remove all of the lines breaks. As a first step, I tried this: if exist "%log_dir%\Log.log" ( for /F "tokens=*" %%a in ("%log_dir%\Log.log") do @echo %%a ) My expectation was that this would echo out each line of the log file. I was then planning to concatenate these lines together and set that value in a variable. However, this code doesn't do what I would expect. I have tried changing the value of the options for delims and tokens, but the only output I can get is the absolute path to the log file and nothing from the contents of this file. How can I set a variable to be equal to the lines of text in a file with the line breaks removed?

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  • PHP Classes: parent/child communication

    - by Fffff
    Hi all, I'm having some trouble extending Classes in PHP. Have been Googling for a while. $a = new A(); $a->one(); $a->b1(); // something like this, or... class A { public $test1; public function one() { echo "this is A-one"; $this->two(); $parent->two(); $parent->B->two(); // ...how do i do something like this (prepare it for using in instance $a)? } } class B extends A { public $test2; public function two($test) { echo "this is B-two"; } } I'm ok at procedural PHP.

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  • MySQL - Selecting the top occurring entries

    - by RC
    Hi, Should be a simple one. Database is mydb. One of the columns is mydata. What SELECT query do I need in order to select the top 3 occurring results from mydata, but sorted alphabetically? For example, if my data is this: mydata ====== kilo (x 1 occurrence) lima (x 9 occurrences) golf (x 5 occurrences) echo (x 9 occurrences) zulu (x 8 occurrences) How do I get it to return "echo, lima, zulu", which are the top three frequently occurring entries sorted alphabetically? Thanks! EDIT: Just to add, they need to be distinct entries. Thanks!

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  • query excuting problem

    - by srini-r85
    hi, i tried to execute following query in php script. $db_selected = mysql_select_db("lumiinc1_sndemo1", $con); if ($db_selected) { echo "database connected"; } else { die ("Can\'t use db : " . mysql_error()); } $sql = "INSERT INTO `markers` ( `name`, `address`, `lat`, `lng`, `id` ) SELECT `name`, `street`, `latitude`, `longitude`, `lid` FROM `location` WHERE NOT EXISTS ( SELECT * FROM `markers` WHERE `location`.`lid` = `markers`.`id` )"; $result = mysql_query($sql); if ($result) { echo "Query executed OK"; } else { die("Invalid query: " . mysql_error()); } script does not show any error.also query executed.but i didn't get my expected result.at the same i try this query in phpmyAdmin i got my expected result. i dont know the cause of this problem. plz any one find the problem . thanks

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  • problems, custum wrap (class) around PDO, doesn't work

    - by Knarf
    DB::construct(); $STH = DB::prepare('INSERT INTO users (username, password, email, activationkey) VALUES (?, UNHEX(?), ?, ?)'); var_dump($STH); $result = $STH->execute(array('test', 'nils', '[email protected]', '227a038fe9c81515b514cb152188e95c')); echo "working? <br />"; if($result == false) echo 'noooo...'; It outputs and doesn't put anything in the database. Works with a similare code with DPO just without my DB class. But I doesn't get any errors. Anyone have an idea what the problem could be? object(PDOStatement)#2 (1) { ["queryString"]=> string(87) "INSERT INTO users (username, password, email, activationkey) VALUES (?, UNHEX(?), ?, ?)" } working? <br /> noooo...

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  • php session variable

    - by Idealflip
    Hi Everyone, my session variable seems to keep dropping its array values. What could I be doing wrong? Is it my object? if(isset($_SESSION['locations'])){ $_SESSION['locations']->listItems($_POST['companyLocation']); echo "session exists"; }else{ $_SESSION['locations'] = new Location(); $_SESSION['locations']->listItems($_POST['companyLocation']); echo "session does not exist"; } class Location { function listItems($location){ $array; $array[] = $location; print_r($array); }

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  • Handling errors on php contact form

    - by topSearchDesign
    The below code is working great for handling errors for text fields in my contact form, but how do I get this same method to work for dropdown select option boxes and textareas? <input type="text" name="name" value="<?php if($errors){echo $name;} ?>" id="name" size="30" /> For example: <textarea name="message" value="<?php if($errors){echo $message;} ?>" id="message" rows="10" cols="40"></textarea> does not work.

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  • Pagination links do not work after first page

    - by TheStack
    Hello, I am trying to fix this pagination script. It seems when I click on the pagination links [1][2][3][4]or[5] , it doesn't work. It just shows the first page and when clicking on the next numbers nothing happens. I hoping someone can see something in the script that I can not see. The main page looks like this (pagination.php): <?php include_once('generate_pagination.php'); ?> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript" src="jquery_pagination.js"></script> <div id="loading" ></div> <div id="content" data-page="1"></div> <ul id="pagination"> <?php generate_pagination() ?> </ul> <br /> <br /> <a href="#" class="category" id="marketing">Marketing</a> <a href="#" class="category" id="automotive">Automotive</a> <a href="#" class="category" id="sports">Sports</a> Then, generate_pagination.php: <?php function generate_pagination($sql) { include_once('config.php'); $per_page = 3; //Calculating no of pages $result = mysql_query($sql); $count = mysql_fetch_row($result); $pages = ceil($count[0]/$per_page); //Pagination Numbers for($i=1; $i<=$pages; $i++) { echo '<li class="page_numbers" id="'.$i.'">'.$i.'</li>'; } } $ids=$_GET['ids']; generate_pagination("SELECT COUNT(*) FROM explore WHERE category='$ids'"); ?> Here is the jquery file (jquery_pagination.js): $(document).ready(function(){ //Display Loading Image function Display_Load() { $("#loading").fadeIn(900,0); $("#loading").html("<img src='bigLoader.gif' />"); } //Hide Loading Image function Hide_Load() { $("#loading").fadeOut('slow'); }; //Default Starting Page Results $("#pagination li:first").css({'color' : '#FF0084'}).css({'border' : 'none'}); Display_Load(); $("#content").load("pagination_data.php?page=1", Hide_Load()); //Pagination Click $("#pagination li").click(function(){ Display_Load(); //CSS Styles $("#pagination li") .css({'border' : 'solid #dddddd 1px'}) .css({'color' : '#0063DC'}); $(this) .css({'color' : '#FF0084'}) .css({'border' : 'none'}); //Loading Data var pageNum = this.id; $("#content").load("pagination_data.php?page=" + pageNum, function(){ Hide_Load(); $(this).attr('data-page', pageNum); }); }); // Editing below. // Sort content Marketing $("a.category").click(function() { Display_Load(); var this_id = $(this).attr('id'); $.get("pagination.php", { category: this.id }, function(data){ //Load your results into the page var pageNum = $('#content').attr('data-page'); $("#pagination").load('generate_pagination.php?category=' + pageNum +'&ids='+ this_id ); $("#content").load("filter_marketing.php?page=" + pageNum +'&id='+ this_id, Hide_Load()); }); }); }); Lastly, filter_marketing.php (when a user clicks the filter link buttons): <?php include('config.php'); $per_page = 3; if(count($_GET)>0) { if($_GET['page']!=''){ $page=$_GET['page']; } if($_GET['id']!=''){ $id=$_GET['id']; } } $page= ($_GET['page']!='') ? $_GET['page']: false; $id= ($_GET['id']!='') ? $_GET['id']: false; $start = ($page-1)*$per_page; if($page && $id){ $sql = "SELECT * FROM explore WHERE category='$id' ORDER BY category LIMIT $start,$per_page"; } else { die('Error: missing parameters. Id= '.$id.' and page= '.$page); } $result = mysql_query($sql); ?> <table width="800px"> <?php while($row = mysql_fetch_array($result)) { $msg_id=$row['id']; $message=$row['site_description']; $site_price=$row['site_price']; ?> <tr> <td><?php echo $msg_id; ?></td> <td><?php echo $message; ?></td> <td><?php echo $site_price; ?></td> </tr> <?php } ?> </table> So, if anyone sees where the problem is occurring and can help rid of the problem, that would be great, Thank you.

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