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  • MySQL searching using many 'like' operators: is there a better way?

    - by DrAgonmoray
    I have a page that gets all rows from a table in a database, then displays the rows in an HTML table. That works great, but now I want to implement a 'search' feature. There is a searchbox, and search-terms are separated by a space. I am going to make it search three fields for the search terms, 'make' 'model' and 'type.' These three fields are VARCHAR(30). Currently if I wanted to search using 3 terms (say 'cool' 'abc' and '123') my query would look something like this. SELECT * FROM table WHERE make LIKE '%cool%' OR make LIKE '%abc%' OR make LIKE '%123%' OR model LIKE '%cool%' OR model LIKE '%abc%' OR model LIKE '%123%' OR type LIKE '%cool%' OR type LIKE '%abc%' OR type LIKE '%123%' That looks really bad, and it will get even worse if there are more search terms or more fields to search. My question to you: is there a better way to search? If so, what?

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  • Address Book Authentication

    - by Gus E
    I just upgraded to Ubuntu 14.04.1 and run Gnome Shell. I am consistently getting a pop up window prompting me for my Gmail address book authentication. The window pops up the moment I type something into gnome shell after hitting the super key. I'm assuming that Ubuntu wants to search my address book for people to include in the search. I have opened up the settings and deleted my account from the online accounts section and rebooted, nothing seems to stop the popup. Where is it getting my email address from? Most importantly, how to I stop this super annoying popup from appearing?

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  • Writing a spell checker similar to "did you mean"

    - by user888734
    I'm hoping to write a spellchecker for search queries in a web application - not unlike Google's "Did you mean?" The algorithm will be loosely based on this: http://catalog.ldc.upenn.edu/LDC2006T13 In short, it generates correction candidates and scores them on how often they appear (along with adjacent words in the search query) in an enormous dataset of known n-grams - Google Web 1T - which contains well over 1 billion 5-grams. I'm not using the Web 1T dataset, but building my n-gram sets from my own documents - about 200k docs, and I'm estimating tens or hundreds of millions of n-grams will be generated. This kind of process is pushing the limits of my understanding of basic computing performance - can I simply load my n-grams into memory in a hashtable or dictionary when the app starts? Is the only limiting factor the amount of memory on the machine? Or am I barking up the wrong tree? Perhaps putting all my n-grams in a graph database with some sort of tree query optimisation? Could that ever be fast enough?

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  • What factors help in getting a site indexed by Google fast?

    - by ekaj
    What should I do to get a site indexed on Google, fast? Taking example of Super User I just did a quick Google for a question that was 20 minutes old, to look for an answer, and it was already on Google Search - how is this possible? I glanced over this article which seems to suggest that SU has added RSS feeds (which SU has, but when I opened the feed the article says last posted 6 minutes ago, but when Googled it is 11 hours old) - which leads me to think (Based on that article, I don't know much about search indexing but I am reading at the moment) that most of this indexing is done thanks to the sitemap. is there anything else I am unaware of that helps SU questions get on Google so fast?

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  • How can I make my Google Maps api v3 address search bar work by hitting the enter button on the keyboard?

    - by Gavin
    I'm developing a webpage and I would just like to make something more user friendly. I have a functional Google Maps api v3 and an address search bar. Currently, I have to use the mouse to select search to initialize the geocoding function. How can I make the map return a placemark by hitting the enter button on my keyboard? I just want to make it as user-friendly as possible. Here is the javascript and div, respectively, I created for the address bar: var geocoder; function initialize() { geocoder = new google.maps.Geocoder (); function codeAddress () { var address = document.getElementById ("address").value; geocoder.geocode ( { 'address': address}, function(results, status) { if (status == google.maps.GeocoderStatus.OK) { map.setCenter(results [0].geometry.location); marker.setPosition(results [0].geometry.location); map.setZoom(14); } else { alert("Geocode was not successful for the following reason: " + status); } }); } <div id="geocoder"> <input id="address" type="textbox" value=""> <input type="button" value="Search" onclick="codeAddress()"> </div> Thank you in advance for your help

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  • How to find the insertion point in an array using binary search?

    - by ????
    The basic idea of binary search in an array is simple, but it might return an "approximate" index if the search fails to find the exact item. (we might sometimes get back an index for which the value is larger or smaller than the searched value). For looking for the exact insertion point, it seems that after we got the approximate location, we might need to "scan" to left or right for the exact insertion location, so that, say, in Ruby, we can do arr.insert(exact_index, value) I have the following solution, but the handling for the part when begin_index >= end_index is a bit messy. I wonder if a more elegant solution can be used? (this solution doesn't care to scan for multiple matches if an exact match is found, so the index returned for an exact match may point to any index that correspond to the value... but I think if they are all integers, we can always search for a - 1 after we know an exact match is found, to find the left boundary, or search for a + 1 for the right boundary.) My solution: DEBUGGING = true def binary_search_helper(arr, a, begin_index, end_index) middle_index = (begin_index + end_index) / 2 puts "a = #{a}, arr[middle_index] = #{arr[middle_index]}, " + "begin_index = #{begin_index}, end_index = #{end_index}, " + "middle_index = #{middle_index}" if DEBUGGING if arr[middle_index] == a return middle_index elsif begin_index >= end_index index = [begin_index, end_index].min return index if a < arr[index] && index >= 0 #careful because -1 means end of array index = [begin_index, end_index].max return index if a < arr[index] && index >= 0 return index + 1 elsif a > arr[middle_index] return binary_search_helper(arr, a, middle_index + 1, end_index) else return binary_search_helper(arr, a, begin_index, middle_index - 1) end end # for [1,3,5,7,9], searching for 6 will return index for 7 for insertion # if exact match is found, then return that index def binary_search(arr, a) puts "\nSearching for #{a} in #{arr}" if DEBUGGING return 0 if arr.empty? result = binary_search_helper(arr, a, 0, arr.length - 1) puts "the result is #{result}, the index for value #{arr[result].inspect}" if DEBUGGING return result end arr = [1,3,5,7,9] b = 6 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9,11] b = 6 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9] b = 60 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9,11] b = 60 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9] b = -60 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9,11] b = -60 arr.insert(binary_search(arr, b), b) p arr arr = [1] b = -60 arr.insert(binary_search(arr, b), b) p arr arr = [1] b = 60 arr.insert(binary_search(arr, b), b) p arr arr = [] b = 60 arr.insert(binary_search(arr, b), b) p arr and result: Searching for 6 in [1, 3, 5, 7, 9] a = 6, arr[middle_index] = 5, begin_index = 0, end_index = 4, middle_index = 2 a = 6, arr[middle_index] = 7, begin_index = 3, end_index = 4, middle_index = 3 a = 6, arr[middle_index] = 5, begin_index = 3, end_index = 2, middle_index = 2 the result is 3, the index for value 7 [1, 3, 5, 6, 7, 9] Searching for 6 in [1, 3, 5, 7, 9, 11] a = 6, arr[middle_index] = 5, begin_index = 0, end_index = 5, middle_index = 2 a = 6, arr[middle_index] = 9, begin_index = 3, end_index = 5, middle_index = 4 a = 6, arr[middle_index] = 7, begin_index = 3, end_index = 3, middle_index = 3 the result is 3, the index for value 7 [1, 3, 5, 6, 7, 9, 11] Searching for 60 in [1, 3, 5, 7, 9] a = 60, arr[middle_index] = 5, begin_index = 0, end_index = 4, middle_index = 2 a = 60, arr[middle_index] = 7, begin_index = 3, end_index = 4, middle_index = 3 a = 60, arr[middle_index] = 9, begin_index = 4, end_index = 4, middle_index = 4 the result is 5, the index for value nil [1, 3, 5, 7, 9, 60] Searching for 60 in [1, 3, 5, 7, 9, 11] a = 60, arr[middle_index] = 5, begin_index = 0, end_index = 5, middle_index = 2 a = 60, arr[middle_index] = 9, begin_index = 3, end_index = 5, middle_index = 4 a = 60, arr[middle_index] = 11, begin_index = 5, end_index = 5, middle_index = 5 the result is 6, the index for value nil [1, 3, 5, 7, 9, 11, 60] Searching for -60 in [1, 3, 5, 7, 9] a = -60, arr[middle_index] = 5, begin_index = 0, end_index = 4, middle_index = 2 a = -60, arr[middle_index] = 1, begin_index = 0, end_index = 1, middle_index = 0 a = -60, arr[middle_index] = 9, begin_index = 0, end_index = -1, middle_index = -1 the result is 0, the index for value 1 [-60, 1, 3, 5, 7, 9] Searching for -60 in [1, 3, 5, 7, 9, 11] a = -60, arr[middle_index] = 5, begin_index = 0, end_index = 5, middle_index = 2 a = -60, arr[middle_index] = 1, begin_index = 0, end_index = 1, middle_index = 0 a = -60, arr[middle_index] = 11, begin_index = 0, end_index = -1, middle_index = -1 the result is 0, the index for value 1 [-60, 1, 3, 5, 7, 9, 11] Searching for -60 in [1] a = -60, arr[middle_index] = 1, begin_index = 0, end_index = 0, middle_index = 0 the result is 0, the index for value 1 [-60, 1] Searching for 60 in [1] a = 60, arr[middle_index] = 1, begin_index = 0, end_index = 0, middle_index = 0 the result is 1, the index for value nil [1, 60] Searching for 60 in [] [60]

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  • Mysql optimization question - How to apply AND logic in search and limit on results in one query?

    - by sandeepan-nath
    This is a little long but I have provided all the database structures and queries so that you can run it immediately and help me. Run the following queries:- CREATE TABLE IF NOT EXISTS `Tutor_Details` ( `id_tutor` int(10) NOT NULL auto_increment, `firstname` varchar(100) NOT NULL default '', `surname` varchar(155) NOT NULL default '', PRIMARY KEY (`id_tutor`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=41 ; INSERT INTO `Tutor_Details` (`id_tutor`,`firstname`, `surname`) VALUES (1, 'Sandeepan', 'Nath'), (2, 'Bob', 'Cratchit'); CREATE TABLE IF NOT EXISTS `Classes` ( `id_class` int(10) unsigned NOT NULL auto_increment, `id_tutor` int(10) unsigned NOT NULL default '0', `class_name` varchar(255) default NULL, PRIMARY KEY (`id_class`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=229 ; INSERT INTO `Classes` (`id_class`,`class_name`, `id_tutor`) VALUES (1, 'My Class', 1), (2, 'Sandeepan Class', 2); CREATE TABLE IF NOT EXISTS `Tags` ( `id_tag` int(10) unsigned NOT NULL auto_increment, `tag` varchar(255) default NULL, PRIMARY KEY (`id_tag`), UNIQUE KEY `tag` (`tag`), KEY `id_tag` (`id_tag`), KEY `tag_2` (`tag`), KEY `tag_3` (`tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=18 ; INSERT INTO `Tags` (`id_tag`, `tag`) VALUES (1, 'Bob'), (6, 'Class'), (2, 'Cratchit'), (4, 'Nath'), (3, 'Sandeepan'), (5, 'My'); CREATE TABLE IF NOT EXISTS `Tutors_Tag_Relations` ( `id_tag` int(10) unsigned NOT NULL default '0', `id_tutor` int(10) default NULL, KEY `Tutors_Tag_Relations` (`id_tag`), KEY `id_tutor` (`id_tutor`), KEY `id_tag` (`id_tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `Tutors_Tag_Relations` (`id_tag`, `id_tutor`) VALUES (3, 1), (4, 1), (1, 2), (2, 2); CREATE TABLE IF NOT EXISTS `Class_Tag_Relations` ( `id_tag` int(10) unsigned NOT NULL default '0', `id_class` int(10) default NULL, `id_tutor` int(10) NOT NULL, KEY `Class_Tag_Relations` (`id_tag`), KEY `id_class` (`id_class`), KEY `id_tag` (`id_tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `Class_Tag_Relations` (`id_tag`, `id_class`, `id_tutor`) VALUES (5, 1, 1), (6, 1, 1), (3, 2, 2), (6, 2, 2); Following is about the tables:- There are tutors who create classes. Tutor_Details - Stores tutors Classes - Stores classes created by tutors And for searching we are using a tags based approach. All the keywords are stored in tags table (while classes/tutors are created) and tag relations are entered in Tutor_Tag_Relations and Class_Tag_Relations tables (for tutors and classes respectively)like this:- Tags - id_tag tag (this is a a unique field) Tutors_Tag_Relations - Stores tag relations while the tutors are created. Class_Tag_Relations - Stores tag relations while any tutor creates a class In the present data in database, tutor "Sandeepan Nath" has has created class "My Class" and "Bob Cratchit" has created "Sandeepan Class". 3.Requirement The requirement is to return tutor records from Tutor_Details table such that all the search terms (AND logic) are present in the union of these two sets - 1. Tutor_Details table 2. classes created by a tutor in Classes table) Example search and expected results:- Search Term Result "Sandeepan Class" Tutor Sandeepan Nath's record from Tutor Details table "Class" Both the tutors from ... Most importantly, there should be only one mysql query and a LIMIT applicable on the number of results. Following is a working query which I have so far written (It just applies OR logic of search key words instead of the desired AND logic). SELECT td . * FROM Tutor_Details AS td LEFT JOIN Tutors_Tag_Relations AS ttagrels ON td.id_tutor = ttagrels.id_tutor LEFT JOIN Classes AS wc ON td.id_tutor = wc.id_tutor INNER JOIN Class_Tag_Relations AS wtagrels ON td.id_tutor = wtagrels.id_tutor LEFT JOIN Tags AS t ON t.id_tag = ttagrels.id_tag OR t.id_tag = wtagrels.id_tag WHERE t.tag LIKE '%Sandeepan%' OR t.tag LIKE '%Nath%' GROUP BY td.id_tutor LIMIT 20 Please help me with anything you can. Thanks

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  • save the transient instance before flushing

    - by eugenn
    Exception: object references an unsaved transient instance - save the transient instance before flushing: Child How to reproduce issue: 1. Hibernate is load the entity "Parent". The property "child" is null 2. The "Parent" is rendered on the screen and after that the "child" property is auto instantiated. So I have the following graph: Parent.child != null Parent.child.childId = null Parent.child.childKey = "" Parent.child.childName = "" Question: How I could to force the Hibernate to ignore updating or inserting Child entity WHEN childId = null? If childId != null I would like just create relation. <hibernate-mapping> <class name="com.test.Parent" entity-name="ParentObject" table="parent" dynamic-insert="false" dynamic-update="true" optimistic-lock="version"> <id name="rowId" type="long"> <column name="RowID" /> <generator class="native" /> </id> <version name="versionSequence" type="integer" unsaved-value="null" generated="never" insert="false"> <column name="VersionSequence" /> </version> <many-to-one name="child" entity-name="Child" fetch="select" optimistic-lock="true" embed-xml="false" update="true" insert="false"> <column name="ChildID" /> </many-to-one> <property name="dateCreated" type="timestamp"> <column name="DateCreated" length="0" /> </property> <property name="dateUpdated" type="timestamp" update="false"> <column name="DateUpdated" length="0" /> </property> </class> </hibernate-mapping> <hibernate-mapping> <class name="com.Child" entity-name="Child" table="Child" dynamic-insert="false" dynamic-update="true" optimistic-lock="version"> <id name="childId" type="long" > <column name="ChildID" /> <generator class="native" /> </id> <version name="versionSequence" type="integer" insert="false" generated="never" > <column name="VersionSequence" /> </version> <property name="childKey" type="string" > <column name="ChildKey" length="20" /> </property> <property name="childName" type="string" > <column name="ChildName" length="30" /> </property> <property name="childNumber" type="string" > <column name="ChildNumber" /> </property> <property name="dateCreated" type="timestamp"> <column name="DateCreated" /> </property> <property name="dateUpdated" type="timestamp" update="false"> <column name="DateUpdated" /> </property> </class> </hibernate-mapping>

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  • JPA @Version behaviour

    - by Albert Kam
    Hello, im using JPA2 with Hibernate 3.6.x I have made a simple testing on the @Version. Let's say we have 2 entities, Entity Team has a List of Player Entities, bidirectional relationship, lazy fetchtype, cascade-type All Both entities have @Version And here are the scenarios : Whenever a modification is made to one of the team/player entity, the team/player's version will be increased when flushed/commited (version on the modified record is increased). Adding a new player entity to team's collection using persist, the entity the team's version will be assigned after persist (adding a new entity, that new entity will got it's version). Whenever an addition/modification/removal is made to one of the player entity, the team's version will be increased when flushed/commited. (add/modify/remove child record, parent's version got increased also) I can understand the number 1 and 2, but the number 3, i dont understand, why the team's version got increased ? And that makes me think of other questions : What if i got Parent <- child <- granchildren relation ship. Will an addition or modification on the grandchildren increase the version of child and parent ? In scenario number 2, how can i get the version on the team before it's commited, like perhaps by using flush ? Is it a recommended way to get the parent's version after we do something to the child[s] ? Here's a code sample from my experiment, proving that when ReceivingGoodDetail is the owning side, and the version got increased in the ReceivingGood after flushing. Sorry that this use other entities, but ReceivingGood is like the Team, ReceivingGoodDetail is like the Player. 1 ReceivingGood/Team, many ReceivingGoodDetail/Player. /* Hibernate: select receivingg0_.id as id9_14_, receivingg0_.creationDate as creation2_9_14_, .. too long Hibernate: select product0_.id as id0_4_, product0_.creationDate as creation2_0_4_, .. too long before persisting the new detail, version of header is : 14 persisting the detail 1c9f81e1-8a49-4189-83f5-4484508e71a7 printing the size of the header : Hibernate: select details0_.receivinggood_id as receivi13_9_8_, details0_.id as id8_, details0_.id as id10_7_, .. too long 7 after persisting the new detail, version of header is : 14 Hibernate: insert into ReceivingGoodDetail (creationDate, modificationDate, usercreate_id, usermodify_id, version, buyQuantity, buyUnit, internalQuantity, internalUnit, product_id, receivinggood_id, supplierLotNumber, id) values (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?) Hibernate: update ReceivingGood set creationDate=?, modificationDate=?, usercreate_id=?, usermodify_id=?, version=?, purchaseorder_id=?, supplier_id=?, transactionDate=?, transactionNumber=?, transactionType=?, transactionYearMonth=?, warehouse_id=? where id=? and version=? after flushing, version of header is now : 15 */ public void addDetailWithoutTouchingCollection() { String headerId = "3b373f6a-9cd1-4c9c-9d46-240de37f6b0f"; ReceivingGood receivingGood = em.find(ReceivingGood.class, headerId); // create a new detail ReceivingGoodDetail receivingGoodDetailCumi = new ReceivingGoodDetail(); receivingGoodDetailCumi.setBuyUnit("Drum"); receivingGoodDetailCumi.setBuyQuantity(1L); receivingGoodDetailCumi.setInternalUnit("Liter"); receivingGoodDetailCumi.setInternalQuantity(10L); receivingGoodDetailCumi.setProduct(getProduct("b3e83b2c-d27b-4572-bf8d-ac32f6de5eaa")); receivingGoodDetailCumi.setSupplierLotNumber("Supplier Lot 1"); decorateEntity(receivingGoodDetailCumi, getUser("3978fee3-9690-4377-84bd-9fb05928a6fc")); receivingGoodDetailCumi.setReceivingGood(receivingGood); System.out.println("before persisting the new detail, version of header is : " + receivingGood.getVersion()); // persist it System.out.println("persisting the detail " + receivingGoodDetailCumi.getId()); em.persist(receivingGoodDetailCumi); System.out.println("printing the size of the header : "); System.out.println(receivingGood.getDetails().size()); System.out.println("after persisting the new detail, version of header is : " + receivingGood.getVersion()); em.flush(); System.out.println("after flushing, version of header is now : " + receivingGood.getVersion()); }

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  • Search files blazing fast

    If you know there is a file somewhere on your machine, but you cannot find it with the default Windows Search Tools (that why they tend to call it Windows Search and not Windows Find ) then switch to a tool that really works. Go to http://www.voidtools.com/ to download your copy of Everything. The download is only small (350KB), it indexes fast (within 5 mins) and searches my complete computer even faster then I can type. I only blame David Carpenter for not spreading the word more aggressively and for not developing this earlier.

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  • Supporting Windows Search with MFC

    Windows 7 brings a new level of maturity to Windows Search, and by taking advantage of new MFC functionality first publicly unveiled with the Beta 2 release of Visual Studio 2010, writing a Search filter handler for a MFC application can be easily accomplished.

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  • Search Engine Ranking Competition

    Search engine ranking competition just got tougher. With individuals and businesses pooling a team of SEO experts to update their website, SEO software, working on intensive keyword research, as well as tapping into social media marketing, continuous marketing is necessary to improve and maintain search engine ranking competitiveness.

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  • The ABC's of Search Engine Optimization

    If you're trying to learn more about Search Engine Optimization you're not alone. Many business owners have heard this term, but may not know exactly what it mean. Simply put, SEO is a way to help improve your web site so that it can be found easily by search engines, allowing it to be ranked higher in their results, and ultimately be found by your customers.

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  • Don't Let Someone Else Optimize Your Search Results

    I build websites for a wide variety of clients, and every single client asks me to get their website placed highly within search engine results. However, they don't know that there's more to ranking high in the search engines than just launching a site; this is especially true when the website has just been created.

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  • Designing Search Engine Keyword Optimization Friendly Websites and Blogs

    To generate free targeted traffic, you must know how to go about search engine keyword optimization. This is because optimizing your website or blog for placement on the first page of Google or Yahoo is the best online money making secret. Google, MSN and Yahoo are used by most people to search for information thus if you can optimize your website pages for common keywords you will definitely attract traffic.

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  • Search engine optimization Links

    - by Michael Freidgeim
    Below there are a few links, that I used for my Search engine optimization research:     http://websearch.about.com/od/designforsearch/ss/tendesigntips.htm     Keyword Selection Guidelines   Where To Use Keywords  Google Search Engine Optimization http://websearch.about.com/od/keywordsandphrases/a/sitedesign.htm     http://en.wikipedia.org/wiki/Search_engine_optimization       http://www.google.com/support/webmasters/bin/answer.py?answer=35291

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  • Search Engine Placement Optimization and Link Popularity

    The increased visibility of your website due to high link popularity and search engine placement optimization can mean so much, especially if you are promoting a product or service through your website. If you are new to the business of link building, you might be wondering how to get started with it and how search engine placement optimization can help you. Knowledge of link popularity basics is essential even if you are planning on hiring someone to do link building tasks for you.

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  • Heating Up the Search Results With Local SEO

    With the help of an SEO agencies and local SEO, local businesses are dominating the first page of search results. There are millions of websites in existence today and With so much competition, website owners must have high rankings with the search engines in order to succeed online.

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  • 7 Tips to Avoid Fatal Results in Search Engine Optimization Process

    Most companies whether big or small rely on the search engine marketing techniques for making the site more popular and definitely more search-engine friendly. You have to understand that there will be a lot of companies which will offer their SEO techniques. But you need to be extra cautious when you choose the company. Check out the 7 tips which should be followed if you want to avoid fatal mistakes.

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  • Files and content search outside from opened Visual Studio solution

    - by Suresh Behera
    I have been using Visual studio for decade now and never notice a useful search option on “Find and Replace”  wizard.One of my client still use Windows XP for their development machine.We have set of projects separated to specific group or solutions. So,i always have challenge to find some contents or files other than current opened solutions.On windows 7 it is easier go folder and look for content but not so easy on windows XP.Following “Find and Replace” and content search found very helpful...(read more)

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  • SQL Azure Federations and Semantic Search by the SQL product team in London tonight (Monday)

    - by simonsabin
    Don’t forget that tonight we have Michael Rys from the SQL Server Product Team presenting on the Federation support coming to SQL Azure and the Semantic search coming in SQL Server Denali. This is a must attend evening for anyone that is serious about scaling SQL or doing search in SQL Server. Michael also has a few other hats including Microsoft’s representative on the W3C XML Query Working Group. To register go to http://sqlsocial20110613.eventbrite.com/   Ps Beer and Pizza will be laid on...(read more)

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