Search Results

Search found 46178 results on 1848 pages for 'java home'.

Page 994/1848 | < Previous Page | 990 991 992 993 994 995 996 997 998 999 1000 1001  | Next Page >

  • Best way to create a Unique ID field for an enum

    - by jax
    What is the best way to get a Unique ID from an ENUM that will stay consistent between repeated execution of the program? Currently I am doing this manually by passing an ID to the enum constructor. I don't really want to do this is I can help it. Another option would be to use a static field that gets incremented for each enum value. The problem is that if later I decide to move the enum fields around or delete some this will cause problems with my program as the ID will be saved into user preferences. The ID can be any basic type or a String.

    Read the article

  • Fastest method to define whether a number is a triangular number

    - by psihodelia
    A triangular number is the sum of the n natural numbers from 1 to n. What is the fastest method to find whether a given positive integer number is a triangular one? I suppose, there must be a hidden pattern in a binary representation of such numbers (like if you need to find whether a number is even/odd you check its least significant bit). Here is a cut of the first 1200th up to 1300th triangular numbers, you can easily see a bit-pattern here (if not, try to zoom out): (720600, '10101111111011011000') (721801, '10110000001110001001') (723003, '10110000100000111011') (724206, '10110000110011101110') (725410, '10110001000110100010') (726615, '10110001011001010111') (727821, '10110001101100001101') (729028, '10110001111111000100') (730236, '10110010010001111100') (731445, '10110010100100110101') (732655, '10110010110111101111') (733866, '10110011001010101010') (735078, '10110011011101100110') (736291, '10110011110000100011') (737505, '10110100000011100001') (738720, '10110100010110100000') (739936, '10110100101001100000') (741153, '10110100111100100001') (742371, '10110101001111100011') (743590, '10110101100010100110') (744810, '10110101110101101010') (746031, '10110110001000101111') (747253, '10110110011011110101') (748476, '10110110101110111100') (749700, '10110111000010000100') (750925, '10110111010101001101') (752151, '10110111101000010111') (753378, '10110111111011100010') (754606, '10111000001110101110') (755835, '10111000100001111011') (757065, '10111000110101001001') (758296, '10111001001000011000') (759528, '10111001011011101000') (760761, '10111001101110111001') (761995, '10111010000010001011') (763230, '10111010010101011110') (764466, '10111010101000110010') (765703, '10111010111100000111') (766941, '10111011001111011101') (768180, '10111011100010110100') (769420, '10111011110110001100') (770661, '10111100001001100101') (771903, '10111100011100111111') (773146, '10111100110000011010') (774390, '10111101000011110110') (775635, '10111101010111010011') (776881, '10111101101010110001') (778128, '10111101111110010000') (779376, '10111110010001110000') (780625, '10111110100101010001') (781875, '10111110111000110011') (783126, '10111111001100010110') (784378, '10111111011111111010') (785631, '10111111110011011111') (786885, '11000000000111000101') (788140, '11000000011010101100') (789396, '11000000101110010100') (790653, '11000001000001111101') (791911, '11000001010101100111') (793170, '11000001101001010010') (794430, '11000001111100111110') (795691, '11000010010000101011') (796953, '11000010100100011001') (798216, '11000010111000001000') (799480, '11000011001011111000') (800745, '11000011011111101001') (802011, '11000011110011011011') (803278, '11000100000111001110') (804546, '11000100011011000010') (805815, '11000100101110110111') (807085, '11000101000010101101') (808356, '11000101010110100100') (809628, '11000101101010011100') (810901, '11000101111110010101') (812175, '11000110010010001111') (813450, '11000110100110001010') (814726, '11000110111010000110') (816003, '11000111001110000011') (817281, '11000111100010000001') (818560, '11000111110110000000') (819840, '11001000001010000000') (821121, '11001000011110000001') (822403, '11001000110010000011') (823686, '11001001000110000110') (824970, '11001001011010001010') (826255, '11001001101110001111') (827541, '11001010000010010101') (828828, '11001010010110011100') (830116, '11001010101010100100') (831405, '11001010111110101101') (832695, '11001011010010110111') (833986, '11001011100111000010') (835278, '11001011111011001110') (836571, '11001100001111011011') (837865, '11001100100011101001') (839160, '11001100110111111000') (840456, '11001101001100001000') (841753, '11001101100000011001') (843051, '11001101110100101011') (844350, '11001110001000111110') For example, can you also see a rotated normal distribution curve, represented by zeros between 807085 and 831405?

    Read the article

  • division problems

    - by David
    This line of code: System.out.println ("aray[j], "+aray[j]+", divided by sum, "+sum+", equals: aray[j]/sum: "+ aray[j]/sum) ; is yeilding this line of text: aray[j], 21, divided by sum, 100, equals: aray[j]/sum: 0 why is it doing this? (everything is right eccept that the answer should be .21)

    Read the article

  • Ordered Data Structure that allows to efficiently remove duplicate items

    - by devoured elysium
    I need a data structure that Must be ordered (adding elements a, b and c to an empty structure, will make them be at positions 0, 1 and 2). Allows to add repeated items. This is, I can have a list with a, b, c, a, b. Allows removing all ocurrences of a given item (if I do something like delete(1), it will delete all ocurrences of 1 in the structure). I can't really pick what the best data structure could be in here. I thought at first about something like a List(the problem is having an O(n) operation when removing items), but maybe I'm missing something? What about trees/heaps? Hashtables/maps? I'll have to assume I'll do as much adding as removing with this data structure. Thanks

    Read the article

  • Abstract class get parameter from implementing subclass?

    - by soren.qvist
    I'm wondering if there is way to do this without breaking encapsulation, I want the abstract class to rely on parameters defined in the implementing subclass. Like so: public abstract class Parent { private int size; private List<String> someList; public Parent() { size = getSize(); someList = new ArrayList<String>(size); } public abstract int getSize(); } public class Child extends Parent { @Override public int getSize() { return 5; } } Is this ugly? Is there a better way? And perhaps more importantly, is this even a good idea?

    Read the article

  • AdMob won't load programmatically

    - by scottbot95
    I'm need to include ads into my app and I have a settings option to disable ads. so I need to load the ad in code. I copied the code from google to handle that and when I set ads:loadAdOnCreate to true, it works just fine. But if I set it to false and add the two lines AdView adView = (AdView)this.findViewById(R.id.ad); adView.loadAd(new AdRequest()); The ads stop displaying. If I look at log cat, it shows that it is receiving an ad and trying to display it. However it won't actually display on screen. Help?

    Read the article

  • Creating Linear Layout with TextViews using a for loop

    - by cad8
    Hi all, I was wondering if there is a way to dynamically create an additional linear layout with a textview within a predefined liner layout. THis is my code so you get the gist of what I am asking: LinearLayout MainLL= (LinearLayout) findViewById(R.id.myLayoutId); for(int i=0; i<5; i++) { LinearLayout childLL= new LinearLayout(this); childLL.setOrientation(LinearLayout.VERTICAL); childLL.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.FILL_PARENT)); childLL.setGravity(Gravity.LEFT); TextView text = new TextView(this); text.setText("The Value of i is :"i); text.setTextSize(12); text.setGravity(Gravity.LEFT); text.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT)); childLL.addView(text); MainLL.addView(childLL); } My problem is that I am only getting "The Value of i is :0" as the output, i.e. the first instance. Any help would be much appreciated

    Read the article

  • Iterating over a String to check for a number and printing out the String value if it doesn't have a number

    - by wheelerlc64
    I have set up my function for checking for a number in a String, and printing out that String if it has no numbers, and putting up an error message if it does. Here is my code: public class NumberFunction { public boolean containsNbr(String str) { boolean containsNbr = false; if(str != null && !str.isEmpty()) { for(char c : str.toCharArray()) { if(containsNbr = Character.isDigit(c)) { System.out.println("Can't contain numbers in the word."); break; } else { System.out.println(str); } } } return containsNbr; } } import com.imports.validationexample.function.NumberFunction; public class Main { public static void main(String[] args) { NumberFunction nf = new NumberFunction(); System.out.println(nf.containsNbr("bill4")); } } I am trying to get it to print out the result to the console, but the result keeps printing multiple times and prints the boolean value, which I do not want, something like this: bill4 bill4 bill4 bill4 Can't contain numbers in the word. true Why is this happening? I've tried casting but that hasn't worked out either. Any help would be much appreciated.

    Read the article

  • Select SWT Library depending on OS

    - by phineas
    How do I ensure when I distribute a JAR-file that the proper SWT-library (either the windows, the linux or mac version) is loaded an ready to use? It would be very helpful because then you can do one export and your application can run on any platform like Swing apps usually do. Thanks a lot

    Read the article

  • Can anybody explain the working of following code...?

    - by Siddhi
    Can anybody explain the working of following code...? interface myInterface{} public class Main { public static void main(String[] args) { System.out.println(new myInterface(){public String toString(){return "myInterfacetoString";}}); System.out.println(new myInterface(){public String myFunction(){return "myInterfacemyFunction";}}); } } Output is... myInterfacetoString primitivedemo.Main$2@9304b1 All answers saying that myInterface in println() statement is anonymous class. But as I already declared it as an interface, why does it allow me to create anonymous class of same name....? again...if these are anonymous classes then class main should allow me to give any name to these anonymous classes..But if try to do so..I'm getting compilation error

    Read the article

  • Resultset To List

    - by Gnaniyar Zubair
    I want to convert my Resultset to List in my JSP page. and want to display all the values. This is my query: SELECT userId, userName FROM user; I have executed that using preparedstatement and got the Resultset. But how to convert it as a List and want to display the result like this: userID userName ------------------ 1001 user-X 1006 user-Y 1007 user-Z

    Read the article

  • Is this Leftist Tree piece of code from Wikipedia correct?

    - by they changed my name
    Link public Node merge(Node x, Node y) { if(x == null) return y; if(y == null) return x; // if this was a max height biased leftist tree, then the // next line would be: if(x.element < y.element) if(x.element.compareTo(y.element) > 0) { // x.element > y.element Node temp = x; x = y; y = temp; } x.rightChild = merge(x.rightChild, y); if(x.leftChild == null) { // left child doesn't exist, so move right child to the left side x.leftChild = x.rightChild; x.rightChild = null; x.s = 1; } else { // left child does exist, so compare s-values if(x.leftChild.s < x.rightChild.s) { Node temp = x.leftChild; x.leftChild = x.rightChild; x.rightChild = temp; } // since we know the right child has the lower s-value, we can just // add one to its s-value x.s = x.rightChild.s + 1; } return x; } What makes me ask this question is: if(x.element.compareTo(y.element) > 0) { // x.element > y.element Node temp = x; x = y; y = temp; } Isn't that just not gonna work, since the references are only switched inside the method?

    Read the article

  • How to deal with the Hibernate hql multi-join query result in an Object-Oriented Way?

    - by EugeneP
    How to deal with the Hibernate hql multi-join query result in an Object-Oriented Way? As I see it returns a list of Objects. yes, it is tricky and only you who write the query know what should the query return (what objects). But are there ways to simplify things, so that it returned specific objects with no need in casting Object to a specific class according to its position in the query ? Maybe Spring can simplify things here? It has the similar functionality for JDBC, but I don't see if it can help in a similar way with Hibernate.

    Read the article

  • Associate activity with database ID

    - by Mohit Deshpande
    I have a main ListView that is based on an adapter from my database. Each database id is "assigned" to an Activity via the ListView. And in my AndroidManifest, each activity has an intent filter with a custom action. Now with this, I have had to create this class: public final class ActivityLauncher { private ActivityLauncher() { } public static void launch(Context c, int id) { switch(id) { case 1: Intent intent = new Intent(); intent.setAction(SomeActivity.ACTION_SOMEACTIVITY); c.startActivity(intent); break; case 2: ... break; ... } } private static void st(Context context, String action) { Intent intent = new Intent(); intent.setAction(action); context.startActivity(intent); } } So I have to manually create a new case for the switch statement. This would get troublesome if I have to rearrange or delete an id. Is there any way to get around this?

    Read the article

  • How to set message when I get Exception

    - by user1748932
    public class XMLParser { // constructor public XMLParser() { } public String getXmlFromUrl(String url) { String responseBody = null; getset d1 = new getset(); String d = d1.getData(); // text String y = d1.getYear(); // year String c = d1.getCircular(); String p = d1.getPage(); List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(); nameValuePairs.add(new BasicNameValuePair("YearID", y)); nameValuePairs.add(new BasicNameValuePair("CircularNo", c)); nameValuePairs.add(new BasicNameValuePair("SearchText", d)); nameValuePairs.add(new BasicNameValuePair("pagenumber", p)); try { HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost(url); httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); HttpResponse response = httpclient.execute(httppost); HttpEntity entity = response.getEntity(); responseBody = EntityUtils.toString(entity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } // return XML return responseBody; } public Document getDomElement(String xml) { Document doc = null; DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); try { DocumentBuilder db = dbf.newDocumentBuilder(); InputSource is = new InputSource(); is.setCharacterStream(new StringReader(xml)); doc = db.parse(is); } catch (ParserConfigurationException e) { Log.e("Error: ", e.getMessage()); return null; } catch (SAXException e) { Log.e("Error: ", e.getMessage()); // i m getting Exception here return null; } catch (IOException e) { Log.e("Error: ", e.getMessage()); return null; } return doc; } /** * Getting node value * * @param elem * element */ public final String getElementValue(Node elem) { Node child; if (elem != null) { if (elem.hasChildNodes()) { for (child = elem.getFirstChild(); child != null; child = child .getNextSibling()) { if (child.getNodeType() == Node.TEXT_NODE) { return child.getNodeValue(); } } } } return ""; } /** * Getting node value * * @param Element * node * @param key * string * */ public String getValue(Element item, String str) { NodeList n = item.getElementsByTagName(str); return this.getElementValue(n.item(0)); } } I am getting Exception in this class for parsing data. I want print this message in another class which extends from Activity. Can you please tell me how? I tried much but not able to do.. public class AndroidXMLParsingActivity extends Activity { public int currentPage = 1; public ListView lisView1; static final String KEY_ITEM = "docdetails"; static final String KEY_NAME = "heading"; public Button btnNext; public Button btnPre; public static String url = "http://dev.taxmann.com/TaxmannService/TaxmannService.asmx/GetNotificationList"; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); // listView1 lisView1 = (ListView) findViewById(R.id.listView1); // Next btnNext = (Button) findViewById(R.id.btnNext); // Perform action on click btnNext.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { currentPage = currentPage + 1; ShowData(); } }); // Previous btnPre = (Button) findViewById(R.id.btnPre); // Perform action on click btnPre.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { currentPage = currentPage - 1; ShowData(); } }); ShowData(); } public void ShowData() { XMLParser parser = new XMLParser(); String xml = parser.getXmlFromUrl(url); // getting XML Document doc = parser.getDomElement(xml); // getting DOM element NodeList nl = doc.getElementsByTagName(KEY_ITEM); int displayPerPage = 5; // Per Page int TotalRows = nl.getLength(); int indexRowStart = ((displayPerPage * currentPage) - displayPerPage); int TotalPage = 0; if (TotalRows <= displayPerPage) { TotalPage = 1; } else if ((TotalRows % displayPerPage) == 0) { TotalPage = (TotalRows / displayPerPage); } else { TotalPage = (TotalRows / displayPerPage) + 1; // 7 TotalPage = (int) TotalPage; // 7 } int indexRowEnd = displayPerPage * currentPage; // 5 if (indexRowEnd > TotalRows) { indexRowEnd = TotalRows; } // Disabled Button Next if (currentPage >= TotalPage) { btnNext.setEnabled(false); } else { btnNext.setEnabled(true); } // Disabled Button Previos if (currentPage <= 1) { btnPre.setEnabled(false); } else { btnPre.setEnabled(true); } // Load Data from Index int RowID = 1; ArrayList<HashMap<String, String>> menuItems = new ArrayList<HashMap<String, String>>(); HashMap<String, String> map; // RowID if (currentPage > 1) { RowID = (displayPerPage * (currentPage - 1)) + 1; } for (int i = indexRowStart; i < indexRowEnd; i++) { Element e = (Element) nl.item(i); // adding each child node to HashMap key => value map = new HashMap<String, String>(); map.put("RowID", String.valueOf(RowID)); map.put(KEY_NAME, parser.getValue(e, KEY_NAME)); // adding HashList to ArrayList menuItems.add(map); RowID = RowID + 1; } SimpleAdapter sAdap; sAdap = new SimpleAdapter(AndroidXMLParsingActivity.this, menuItems, R.layout.list_item, new String[] { "RowID", KEY_NAME }, new int[] { R.id.ColRowID, R.id.ColName }); lisView1.setAdapter(sAdap); } } This my class where I want to Print that message

    Read the article

  • i have a arraylist where i am verifying particular object is existing or not but even it exists it always returns false

    - by Raghavender Reddy
    hi i have class called userdata which returns the Userarraylist which is of type User. when ever i try to use contains method to check particular property is existing or not it always returns false why? Actually i want the array list to be generic which should return the objects that are set in array list. String className = data.getUserData().get(0).getClass().getSimpleName(); if(className.equalsIgnoreCase("User")) { ArrayList<User> userdata=new ArrayList(); userdata = data.getUserData(); System.out.println(data.getUserData().contains(u.getUserId())); if(userdata.contains(u.getUserName())) { System.out.println(userdata.get(0).getEmailId()); } }

    Read the article

  • Hibernate OneToMany and ManyToOne confusion! Null List!

    - by squizz
    I have two tables... For example - Company and Employee (let's keep this real simple) Company( id, name ); Employee( id, company_id ); Employee.company_id is a foreign key. My entity model looks like this... Employee @ManyToOne(cascade = CascadeType.PERSIST) @JoinColumn(name = "company_id") Company company; Company @OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER) @JoinColumn(name = "company_id") List<Employee> employeeList = new ArrayList<Employee>(); So, yeah I want a list of employees for a company. When I do the following... Employee e = new Employee(); e.setCompany(c); //c is an Company that is already in the database. DAO.insertEmployee(e); //this works fine! If I then get my Company object it's list is empty! Ive tried endless different ways from the Hibernate documentation! Obviously not tried the correct one yet! I just want the list to be populated for me or find out a sensible alternative. Help would be greatly appreciated, thanks!

    Read the article

  • custom implementation of interface methods

    - by Renuka
    Hello all, I have a doubt in this scenario, I have posted some example code here.... public interface a{ public void m1(); public void m2(); public void m3(); . . . public void m100(); } public class A implements a{ public void m3(){ // implementation code } // Here i need to implement only m3() method but not all 100 methods //basically i have to implement all the other 99 methods // but here i don't want to either implement or provide skeleton declarations for all //remaining.... what should i do for compiling this ???? } Could anyone help this?

    Read the article

  • Spring MVC referencing params variable from RequestMapping

    - by NomNomNom
    Hi guys, I have the method below: @RequestMapping(value = "/path/to/{iconId}", params="size={iconSize}", method = RequestMethod.GET) public void webletIconData(@PathVariable String iconId, @PathVariable String iconSize, HttpServletResponse response) throws IOException { // Implementation here } I know how to pass the variable "webletId" from the RequestMapping using the @PathVariable, but how do I reference the variable "iconSize" from params? The same way? Thanks a lot.

    Read the article

  • Group Objects by Common Key

    - by Marshmellow1328
    I have a list of Customers. Each customer has an address and some customers may actually have the same address. My ultimate goal is to group customers based on their address. I figure I could either put the customers in some sort of list-based structure and sort on the addresses, or I could drop the objects into some sort of map that allows multiple values per key. I will now make a pretty picture: List: A1 - C1, A1 - C2, A2 - C3, A3 - C4, A3 - C5 Map: A1 A2 A3 C1 C3 C4 C2 C5 Which option (or any others) do you see as the best solution? Are there any existing classes that will make development easier?

    Read the article

  • updating a properties file in a web application

    - by AmiraGL
    i have a properties file (under rsources folder) in which i'm stocking a variable (key=value), i need to update it when a user insert a new value or update the older one , so can i do it ? i have doubts because it's a web application so it' simply a war deployed in the server so how it is possible to access the .properties file and change it directly from the code . if it's not possible is there another solution ? Any Help will be apprecited Many thanks

    Read the article

  • What is the security risk of object reflection?

    - by Legend
    So after a few hours of workaround the limitation of Reflection being currently disabled on the Google App Engine, I was wondering if someone could help me understand why object reflection can be a threat. Is it because I can inspect the private variables of a class or are there any other deeper reasons?

    Read the article

< Previous Page | 990 991 992 993 994 995 996 997 998 999 1000 1001  | Next Page >