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  • Delay the display of image loaded using jquery + ajax

    - by niczoom
    I am using the following code : $.ajax({ url: "pgiproxy.php", data: ({ data : $("#formdata").serialize(), mode : "graph"}), success: function(result){ var temp = $('<div/>').html(result); var val = temp.find('center').html(); $('#BFX').html(val); }, error: function(){ $("#error").html("ERROR !!!"); } }); The 'result' from the ajax call to 'pgiproxy.php' is a whole web page (returned as a string), this is then converted to a jQuery object and stored in 'var'. I then extract the data I need (a .gif image) using .find() which is stored in 'val'. This image is then inserted into a #BFX div for display. My problem is every successive time I click my button to update this image it shows the image loading from top to bottom as it is reading it in from the web. Is there a way to only display this image once it has fully loaded so the user doesnt see the image loading and only sees the image change instantly.

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  • Got a static var which is working, now need to get dynamic var which isnt working

    - by Ritz
    got this variable var zvmlist = { 'Huishoudelijke hulp': 'Huishoudelijke hulp', 'Verpleging thuis': 'Verpleging thuis', 'Verzorging thuis': 'Verzorging thuis', '24 uurs zorg': '24 uurs zorg', 'Ondersteunende begeleiding': 'Ondersteunende begeleiding', }; this var is used in a function to create a dropdownlist. $.each(zvmlist, function(key, value) { var selected=''; if(key==eventdata.title){var selected='selected' } $('<option value="'+key+'" '+selected+'>'+value+'</option>').appendTo($('#calendar_edit_entry_form_title')); }); which works lika a charm. Now i created a function to fetch the list from a mysql table. $.get('get_zorgvormen.php', function(data) { var zvmlist = '{'+data+'}'; //alert(zvmlist); }); when i enable the alert function it shows me the var(array). But i it wont act as a variable. How can i pass this data to my .each function? see it in action here: http://www.zorgzuster-zeeland.nl/site/static/calendar_test.php

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  • Two drop down lists in Ajax and MySQL

    - by Milla
    I'm trying to learn some Ajax and MySQL... Basically, the code that I have right now is similar to: http://www.w3schools.com/PHP/php_ajax_database.asp I was wondering how should I modify those codes (both html, javascript and php) to create two drop down lists. The first drop list would be used for choosing the Lastname (eg. Swanson) and the second drop list would be used for choosing the Hometown (eg. Quahog). Then the user would click "Submit" button and the query would return the matching results (eg. all the Swansons living in Quahog). I'd be very thankful for all the ideas!

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  • Joomla forwarding code to the View...is this the correct way to do it?

    - by jax
    Here are some sample methods from my Controller class. Now when the user clicks the New button $task=add is sent to the Controller and the add() method is called. As you can see it does not really do anything, it just creates a url and forwards it off to the correct view. Is this the correct way of doing things in the MVC pattern? /** * New button was pressed */ function add() { $link = JRoute::_('index.php?option=com_myapp&c=apps&view=editapp&cid[]=', false); $this->setRedirect($link); } /** * Edit button was pressed - just use the first selection for editing */ function edit() { $cid = JRequest::getVar( 'cid', array(0), '', 'array' ); $id = $cid[0]; $link = JRoute::_("index.php?option=com_myapp&c=apps&view=editapp&cid[]=$id", false); $this->setRedirect($link); }

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  • Form with target="_blank" will produce empty POST data in IE6

    - by Seeker
    I have an iframe containing a form. I want the form to point to a new window when the user submits it. Basically, the following code should do the trick: <?php var_dump($_POST); ?> <form method="post" action="test_post_to_blank.php" target="_blank"> <input type="text" name="test" value="test" /> <input type="submit" /> </form> The problem is that in IE6 a new window is opened with empty POST data. Is there any other way I can get the job done? This does not occur in newer versions of IE. Thanks in advance ;).

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  • Passing value in HTML URL link

    - by pradeep
    $.post("/diabetes/ropimages/getcount.php",{pid:$("#patient_id").val()} ,function(data1){ //alert(data1); var count = data1; var pid = $("#patient_id").val(); var rid; for( var i = 1 ; i <= count ; i++) { var link ='<img src="/diabetes/ropimages/thumbpicdisplay.php?pid=+pid+&rid=1" />'; $("#content1").empty().html(link); } }); I am trying to pass pid value in url ..but its taking directly as +pid+ as value ..how do i give it the value of pid. And how do i print 3 images in a div? like the one in code

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  • Redirecting without change of address in browser address bar

    - by Berny Paul
    I have a different but similar question. I have a dynamic dns account where I map my machine's dynamic IP to an address say, www.xxx.yyy.net Now, I have registered another short domain name say www.yyy.com, the hosting is on a linux server. Now, my machine is actually a webserver which runs .net website which can be accessed by www.xxx.yyy.net I need my homepage(index.php) in my www.yyy.com handle the redirection in a way that the pages to be loaded from www.xxx.yyy.net/.... but it should look in the browser as www.yyy.com/... Is there any way to do this using php?

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  • passing javascript value in html url link

    - by pradeep
    $.post("/diabetes/ropimages/getcount.php",{pid:$("#patient_id").val()} ,function(data1){ //alert(data1); var count = data1; var pid = $("#patient_id").val(); var rid; for( var i = 1 ; i <= count ; i++) { var link ='<img src="/diabetes/ropimages/thumbpicdisplay.php?pid=+pid+&rid=1" />'; $("#content1").empty().html(link); } }); i am trying to pass pid value in url ..but its taking directly as +pid+ as value ..how do i give it the value of pid. and how do i print 3 images in a div ? like the one in code

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  • How do i know in the detail view what cell in tableview was selected?

    - by Daniel Rotaru
    how can i know what tableview cell was selected?(being in the detail view) The problem is that. I have an table view controller. Here are parsed from the internet entries to the table. So it's a dynamic tabe view that loads from internet. I will not know how many entries will be in the table so i will not know what details view to call when i click a row. So i have maked one view. This view contains an calendar. On this calendar(wich is the detail iew) i will parse data from internet depending on the selected row. For exemple: i have table: entry 1, entry 2,entry 3,entry 4 When i click entry 2 i need to call a php with the argument entry 2. The php will know what entry on the table i have selected and will generate me the correct xml that i will parse. Here is my tableview didSelectRow function: - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { // Navigation logic -- create and push a new view controller if(bdvController == nil) bdvController = [[BookDetailViewController alloc] initWithNibName:@"BookDetailView" bundle:[NSBundle mainBundle]]; Villa *aVilla = [appDelegate.villas objectAtIndex:indexPath.row]; [self.navigationController pushViewController:bdvController animated:YES] And here is my self view function on detailviewcontroller: -(void)loadView { [super loadView]; self.title=@"Month" UIBarButtonItem *addButtonItem = [[UIBarButtonItem alloc] initWithTitle:@"ListView" style:UIBarButtonItemStyleDone target:self action:@selector(add:)]; self.navigationItem.rightBarButtonItem = addButtonItem; calendarView = [[[KLCalendarView alloc] initWithFrame:CGRectMake(0.0f, 0.0f, 320.0f, 373.0f) delegate:self] autorelease]; appDelegate1 = (XMLAppDelegate *)[[UIApplication sharedApplication] delegate]; myTableView=[[UITableView alloc]initWithFrame:CGRectMake(0, 260, 320, 160)style:UITableViewStylePlain]; myTableView.dataSource=self; myTableView.delegate=self; UIView *myHeaderView=[[UIView alloc]initWithFrame:CGRectMake(0, 0, myTableView.frame.size.width,2)]; myHeaderView.backgroundColor=[UIColor grayColor]; [myTableView setTableHeaderView:myHeaderView]; [self.view addSubview:myTableView]; [self.view addSubview:calendarView]; [self.view bringSubviewToFront:myTableView]; } I think that here in self load i need to make the if procedure.. If indexPath.row=x parse fisier.php?variabila=title_of_rowx but the question is how i know the indexPath variable?

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  • Upload image from local into tinyMCE?

    - by M Sach
    I am using tinymce. It works great. But i want the feature in tinymce where user can upload the images from local box/or from public websites. I am using tomcat ,jsps and core java.I found couple of free third party libraries like ibrowser ,imanager,jbimages etc but all of them using PHP which looks like does not fit in my existing project (i dont know PHP but i tried to integrate one of these in my existing project they don't work and gives some weird error.) Really i am not sure how to have this feature in tinymce(if some other editor support it with jsps i can try that)?

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  • How to insert value to Magento database using module

    - by Kasmin Nicko
    I want to insert value to the database I created. The value would be insert to post column. I have code like this in the IndexController.php class My_Module_IndexController extends Mage_Core_Controller_Front_Action { public function postAction() { $post = Mage::getModel('my/model'); $post->setPost('My Post Here'); $post->save(); } } But after I ran this script, I got the following error Fatal error: Call to a member function setPost() on a non-object in C:\xampp\htdocs\magento\app\code\community\My\Module\controllers\IndexController.php on line 7 What is something I miss?

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  • Ajax: Appending list-item at the top

    - by ptamzz
    I'm calling a php processing file using ajax an appending the returned HTML usign the code below $.ajax({ type: "POST", url: "proc/process.php", data: dataString, cache: false, success: function(html){ $("ul#lists").append(html); $("ul#lists li:last").fadeIn("slow"); $("#flash").hide(); } }); It appends a <li></li> item at the end of the ul#lists. I want the returned list-item <li></li> at the top of the lists instead of being appended at the last. How do I do that??

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  • PODS + WP Theme

    - by Sharath
    So I managed to setup pods and create my custom tables. Now I want to revamp my theme so that it pulls data from the POD table. Doesn't seem to be working... This is what I did.. I have a Pod called 'project_type' with a name (string) and a code (string) field. Have also added 3 entries via the admin system. I made a copy of the default wordpress plugin and renamed it to myTheme and activated it. Inside index.php of myTheme, I removed all the default code.. and have just the POD specific code as shown below. <?php echo "Hello World"; $p = new Pod('project_type'); echo $p->getTotalRows(); ?> However, when I reload my page, only Hello World shows up? A bit new to Wordpress so kindly advice.

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  • Facebook email Permission, oath2, doesnt work?

    - by Mathias Eklöf
    since the new Auth Dialog from Facebook (for my App & homepage), I cannot get the dialog to show that my homepage/app needs the users email when connection to my homepage/app. In the Auth-section of my app I've added "email" to the User & Friend Permissions. Also I've added it to the referal when someone clicks the "Login with facebook"-button. When someone clicks the Facebook-button, he/she redirects to a page which has the PHP-code with Facebook SDK PHP (latest). Here's how I generate the send-to-url for the dialog: $login_url = $facebook-getLoginUrl(array('req_perms' = 'email,publish_stream')); header("Location: ".$login_url); But when the Dialog pops up, the only permission request it does is "basic information". I need to request the Email. Am I stupid or is it a bug somehow? I've also recreated the App.

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  • document.forms.gallery_form.submit is not a function

    - by Keene Maverick
    I swear, I have this exact thing working on another page. I'm such a javascript noob it's embarrassing... function delete_gallery() { var gallery = document.getElementById('gallery_id').value; var form = document.getElementById('gallery_form'); form.setAttribute('action', 'index.php?action=delete&section=galleries&id='+gallery); document.forms['gallery_form'].submit(); } Inspecting the element shows that it's updating the action correctly : <form method="post" action="index.php?action=delete&amp;section=galleries&amp;id=12" name="gallery_form" id="gallery_form"><input type="hidden" value="12" id="gallery_id" name="gallery_id"><p>Name: <input type="text" name="name" value="Woo"></p><p>Description:<br><textarea name="description">Dee</textarea><input type="hidden" value="2" name="artist"></p><p><input type="submit" value="Submit" name="submit"> </p></form> Here's the button I use to call the function, it's in a table below the form: <button onclick="delete_gallery()" type="button">Delete Gallery</button>

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  • Projects to learn Python

    - by Andrew
    I know this isn't a question about a specific snippet of code or anything, but here goes - I've been messing around with the idea of learning Python since I'm pretty bored with PHP (and web development in general), but I can't think of any projects to help me learn. I've already worked through some of Project Euler with Python, but it's getting old. I know the basics, and I want to write something more fun that will introduce me to new things in Python. Is there a cliche beginner project for Python? (for example, PHP's would be a blog or something similiar) Are there any common Python projects for newcomers, or any uncommon ones that you'd suggest? Any ideas would help.

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  • problem with application after moving from local to hosting server

    - by marcin_koss
    I have an application developed with CodeIgniter that works perfectly on my local server. After uploading it to the hosting server I've run into few issues that I can't figure out. I removed the index.php from URL by changing $config['index_page'] = "" in config.php file and adding rewriterule in .htaccess file. Everything worked fine on a local server. On hosting server the webstie wouldn't load until I reverted those changes to defaults. Now the strangest thing. I test the website and all pages load fine except of one. When I point to that page the browser responds with "Connection closed by remote server" (That's from Opera, other browser gave similar response). After closing the browser when I try to load the website again, now it won't even load any page showing me CodeIgniter's styled error "404 Page Not Found" What he heck?

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  • Problem generating GET url

    - by Bruce
    I am working on Java. I am calling a GET url on my own machine using Java. Here is the url string with the arguments. listen.executeUrl("http://localhost/post_message.php?query_string="+str); I am taking str as user input. BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); System.out.print("Enter query: "); str = br.readLine(); How do I encode str into GET argument. For eg. str -> test query url -> http://localhost/post_message.php?query_string=test%20query

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  • Unbind Events with JQuery: Does it work with events setup in HTML?

    - by Abs
    Hello all, I have a few onclick and on mouseover events in my html generated by PHP, something like this: <div onmouseover="fave('heart_<?php echo $row['id']; ?>';" class="heart"><a href=""></a></div> I wish to make use of unbind on the mouseover but it hasn't worked when I tried this: $('#'+ id).unbind('mouseover'); So I am guessing unbind will only work with events created by JQuery? Is there something else I can try? Btw, I can't move my events to a separate js file as each id is unique and. Thanks all

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  • how to send database data to a MySQL server to update the server database.

    - by haisergeant
    Hi everyone, I am developing Smoking counter and I need to send all the smoking record (about the time user smoking) to database on the server. The server database is MySQL database. I knew that I must have send data to PHP page/script, and this page/script will run on the data to insert record to database. I would like to know: is there another way to update database, because I don't have knowledge about PHP. I used to work on java and c/c++/objective-c. If you know another way to do this task, please let me know. Any help would be appreciated.

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  • Javascript problem when setting src for img element in FireFox - string parsing error?

    - by Kevin
    I'm having problems with image's on the page. I'm using Javascript to create the elements, and in FireFox it seems the string that I'm using to set the innerHTML is not being parsed correctly. I'll see this when the server page is requested with invalid GET variables. They look like this (from the PHP script's error handler): GET[] = Array ( [shrink] => true [file_id] => \' file_id \' [refresh] => \' now.getTime() \' ) This only happens for about 5% of requests, which is making it difficult to solve. I have been able to reproduce this myself in FireFox, and Firebug will show that the URL it is trying to fetch is: https://www.domain.com/secure/%27%20+%20image_src%20+%20%27 I read somewhere that it might be related to FireFox prefetching content (can't find it googling now), since it seems to only happen on FireFox. Disabling prefetching in about:config does prevent the problem from occurring, but I'm looking for another solution or workaround that doesn't involve end users changing their configurations. Here's the specifics and code: I have an empty table cell on an HTML page. In JQuery's $(document).ready() function for the page, I used JQuery's $.ajax() method to get some data from the server about what should be in that cell. It returns the file_id variable, which for simplicity I just set below. It then sets the empty table cell to have an image with src that points to a page that will serve the image file depending on what file_id is passed. This part of the code was JQuery originally, so I changed it to straight Javascript but that didn't help anything. //get data about image from server //this is actually done through JQuery's $.ajax() but you get the idea var file_id = 12; //create the src for the img //the refresh is to prevent the image from being cached ever, since the page's //javascript will be it changes //during the course of the page's life var now = new Date(); var image_src = 'serve_image.php?shrink=true&file_id=' + file_id + '&refresh=' + now.getTime(); //create document.getElementById('image_cell').innerHTML = '<A target="_blank" href="serve_image.php?file_id=' + file_id + '">' + '<IMG id=image_element src="' + image_src + '" alt="Loading...">' + '</A>';` Any help would be greatly appreciated. Thanks!

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  • How do I get the response time from a jQuery ajax call?

    - by Dumpen
    So I am working on tool that can show long a request to a page is taking. I am doing this by using jQuery Ajax (http://api.jquery.com/jQuery.ajax/) and I want to figure out the best way to get the response time. I found a thread (http://forum.jquery.com/topic/jquery-get-time-of-ajax-post) which describes using the "Date" in JavaScript, but is this method really reliable? An example of my code could be this below $.ajax({ type: "POST", url: "some.php", }).done(function () { // Here I want to get the how long it took to load some.php and use it further });

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  • Can jQuery's fadeIn work without AJAX?

    - by Thierry Lam
    I'm submitting a form, sometimes I have some messages that I want to show to the user. I want those messages to jQuery fadeIn after they click on the submit button. Is it possible to achieve that if the submission doesn't involve any AJAX? Here's a sample Django/Python code: # View code message = 'feedback to user' # Template <div id="messages">{{ message }}</div> The equivalent PHP code of the above might be: <?php $message = 'feedback to user'; ?> <div id="messages"><?= $message ?></div> I want #messages above to fade in after a POST. How can I achieve that?

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