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  • Testing for the presence of a character in an string in C

    - by Prab
    What's wrong with this? #include <stdio.h> void main(){ char *s="some text"; printf("%d",is_in(s,'t')); } int is_in(char *s, char c){ while(*s){ if(*s==c) return 1; s++; } return 0; } I get the following compile time error with GCC: test.c:9: error: conflicting types for ‘is_in’ test.c:9: note: an argument type that has a default promotion can’t match an empty parameter name list declaration test.c:5: note: previous implicit declaration of ‘is_in’ was here

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  • Whats wrong with this C program?

    - by Prab
    It should give me the number of inputs entered by the user. But it gives 100. I compiled with gcc. #include <stdio.h> int arr[100]; int count=0; int max=100; int main(){ int i, input; printf("Enter integer values one by one, q to quit.\n"); for(i=0;i<max;i++){ scanf("%d",&input); arr[i]=input; if(input=='q')break; count++; } printf("You entered %d values.\n",count); return 0; }

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