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  • Getting value of LSB from Hex (C code)

    - by Rjff
    Hi - first post here :) I've got a code like this in C: unsigned char const data[ ] = {0x0a, 0x1d, 0xf0, 0x07}; I need to extract it such that the final value is: 0xa1df7 I have only been able to extract and get it working if the hex values that have at least 1 zero: unsigned char const data[ ] = {0x0a, 0xd0, 0xf0, 0x07}; using the code below: for(int i = 0; i < SIZE; ++i) { tmp = data[i]; if ( (data[i] <= 0x0F) && (((data[i] & 0x0F) == 0) || (data[i] & 0xF0) == 0)) // one of the hex is zero { tmp = ((tmp << 4) >> 4) << N[i]; std::cout << "foo: " << std::hex << tmp << ":" << std::endl; } else if ((data[i] >= 0x0F) && (((data[i] & 0x0F) == 0) || (data[i] & 0xF0) == 0) ) { tmp = (tmp >> 4) << N[i]; std::cout << "bar: " << std::hex << tmp << ":" << std::endl; } else { std::cout << "result: " << std::hex << result << ":" << std::endl; std::cout << "tmp << 8: " << std::hex << (tmp << 8)<< ":" << std::endl; result = result | (tmp << 8); std::cout << "result |= (tmp << 8): " << std::hex << result << ":" << std::endl; } result |= tmp; std::cout << "boo: " << std::hex << result << ":" << std::endl; } It seems the last else {...} block is troublesome for me. Any ideas? Thanks!

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