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• HTML form -> Flash submit button -> Set a PHP variable in flash button -> Submit form

  - by RobHardgood

  Okay, I'm sorry that this is pretty complicated, but it shouldn't be that hard to solve... Here's what I want to do. I have an HTML form that I want to upload to MySQL with PHP. That part's easy, but the thing is I want the submit button to be a Flash object. Somehow I need the Flash button to submit the form, but I think I can figure that out. The tricky part is that I need it to set another PHP variable before submitting the form. The variable will be determined by a bunch of stuff, but I can code that in actionscript later. I just need to figure out how to pass the variable back to the webpage. A $_POST variable would probably be fine. Thanks!! Let me know if I need to clarify more...

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• Display MySQL BLOB'd image on webpage without separate script (PHP)

  - by robhardgood

  So I've got some images stored in a MySQL database as BLOB's (I know it's better to just store the directory and do it that way, but this is what I need to do for now) and I need to display them on a webpage. Now, I know how to make a script and give it an image header and pull the img src from there, but I have a lot of images from different places for different uses, so I'd have to make a ton of these scripts and I'd rather not clutter up my files like that. Anyway, does anyone know of a function or something I can use to display the image that will run on the same page?

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• PHP getimagesize with ampersand in string creates errors

  - by RobHardgood

  I'm using the getimagesize function in PHP, and the path string contains an ampersand, which otherwise is fine. The page gives me errors where getimagesize() is called. Looking at the source code, though, I see the ampersand is being passed through as & rather than just & I presume this is causing errors because PHP doesn't need to convert it to the html tag in order to find the path, right? Here is the error: Warning: getimagesize(image.php?name=username&pic=picture) [function.getimagesize]: failed to open stream: No such file or directory

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• PHP output of foreach loop into a new array.

  - by RobHardgood

  I know I'm probably missing something easy, but I have a foreach loop and I'm trying to modify the values of the first array, and output a new array with the modifications as the new values. Basically I'm starting with an array: 0 = A:B 1 = B:C 2 = C:D And I'm using explode() to strip out the :'s and second letters, so I want to be left with an array: 0 = A 1 = B 2 = C The explode() part of my function works fine, but I only seem to get single string outputs. A, B, and C.

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• PHP script stops running arbitrarily with no errors.

  - by RobHardgood

  I was working on a fairly long script that seemed to stop running after about 20 minutes. After days of trying to figure out why, I decided to make a very simple script to see how long it would run without any complex code to confuse me. I found that the same thing was happening with this simple infinite loop. At some point between 15 and 25 minutes of running, it simply stopped. There is no error output at all. The bottom of the browser simply says "Done" and nothing else is processed. I've been over every single possible thing I could think of... set_time_limit, session.gc_maxlifetime in the php.ini as well as memory_limit and max_execution_time. The point that the script is stopped is never consistent. Sometimes it will stop at 15 minutes, sometimes 22 minutes, sometimes 17... But it's always long enough to be a PITA to test. Please, any help would be greatly appreciated. It is hosted on a 1and1 server. I contacted them and they couldn't help me... but I have a feeling they just didn't know enough.

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• PHP problem with getimagesize()

  - by RobHardgood

  I'm using the getimagesize() function in PHP and it keeps returning an error: getimagesize(image.php?name=username&pic=picture) [function.getimagesize]: failed to open stream: No such file or directory I'm not doing anything strange with it. The only problem I can imagine is that the path URL is another PHP script that returns a page with an image header, and there is an ampersand in that URL. Here is my code: $location = "image.php?name=username&pic=picture"; $size = getimagesize($location);

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