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  • c program output

    - by sandy101
    HELLO , I am trying some program and confused with the output of the program #include #define a(x) (x*x) int main() { int i=3,j; j=a(i+1); printf("%d",j); return 0 ; } i want to know why the program is not giving the output 16(as instead to that i an getting the output 7 for the above program )

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  • #pragma directive and its uses in c

    - by sandy101
    Hello , can anyone tell my what does the #pragma can do in the c language . what are its uses and why the above program is not giving the output 'inside v1'& 'inside v2' in the following program ... include void v1(); void v2(); pragma startup v1 pragma exit v2 int main() { printf("inside main\n"); return 0; } void v1() { printf("inside v1\n"); } void v2() { printf("inside v2\n"); } i also want to know what a are the uses of the #pragma directive .... plz help

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  • function prototype declarations

    - by sandy101
    I am practice the function in c and come across to the program .... #include<stdio.h> int main() { float a=15.5; char ch ='C'; printit(a,ch); return 0; } printit(a,ch) { printf("%f\n%c",a,ch); } I want to know that why the above program compile and not give the error as i understood so for is ... The function in c must be declared with the specific prototype (but this program does not contain the prototype) why the program give the output 'x'for the char variable ? can the function in c are capable of accepting the value without being declared about type in parameters like what has done in the function declaration ?

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  • c program pointer

    - by sandy101
    Hello , I am trying some programs in c face a problem with this program #include<stdio.h> int main() { int a=9,*x; float b=3.6,*y; char c='a',*z; printf("the value is %d\n",a); printf("the value is %f\n",b); printf("the value is %c\n",c); x=&a; y=&b; z=&c; printf("%u\n",a); printf("%u\n",b); printf("%u\n",c); x++; y++; z++; printf("%u\n",a); printf("%u\n",b); printf("%u\n",c); return 0; } can any one tell me what is the problem with this and i also want to know that when in the above case if the pointer value is incremented then will it over write the previous value address as suppose that the value we got in the above program (without the increment in the pointer value )is 65524 65520 65519 and after the increment the value of the pointer is 65526(as 2 increment for the int ) 65524(as 4 increment for the float ) 65520(as 1 increment for the char variable ) then if in that case will the new pointer address overwrite the content of the previous address and what value be contained at the new address ......plz help

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  • pointer in c and the c program

    - by sandy101
    Hello, I am studying the pointer and i come to this program .... #include <stdio.h> void swap(int *,int *); int main() { int a=10; int b=20; swap(&a,&b); printf("the value is %d and %d",a,b); return 0; } void swap(int *a,int*b) { int t; t=*a; *a=*b; *b=t; printf("%d and%d\n",*a,*b); } can any one tell me why this main function return the value reversed . The thing i understood till now is that the function call in c does not affect the main function and it's values . I also want to know how much the space a pointer variable occupied like integer have occupied the 2 bytes and the various application use and advantages of the pointer .... plz.... anyone help

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  • Career Path Choices (Education)

    - by sandy101
    I am in the final year of bca from md university. I am not sure with my career and very confused with the question of should I do MCA or MBA? Can any one help me on this question? I want to know the options available to me, and I also want to know the various colleges which provide MCA and what are the further prospects thereafter!

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  • function in c language

    - by sandy101
    Hello, I am practice the function in c and come across to the program .... include int main() { float a=15.5; char ch ='C'; printit(a,ch); return 0; } printit(a,ch) { printf("%f\n%c",a,ch); } I want to know that why the above program compile and not give the error as i understood so for is ... 1) The function in c must be declared with the specific prototype (but this program does not contain the prototype ) 2)why the program give the output 'x'for the char variable 3)can the function in c are capable of accepting the value without being declared about type in parameters like what has done in the function declaration .... plz.... help

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