Search Results

Search found 9 results on 1 pages for 'seanja'.

Page 1/1 | 1 

  • Can I install Win 7 Pro with a Win 7 Home Premium disc?

    - by SeanJA
    So I got the 64bit Win 7 Pro disc from the Ultimate steal for cheap enough... but I found out that some stuff that I want to run (games mostly... since that is the only reason I keep Windows around...) did not do too well on the 64bit OS. So I have borrowed my friend's install disc, but it turns out that his is only Home Premium rather than Pro which I have a serial for. Can I still just run through the Home Premium install and use my Pro serial number (seems like I should be able to with the whole 'any time upgrade' deal)? Or do I have to go and find a 32bit pro disc to do the install? Are there any hoops that I have to jump through?

    Read the article

  • Smarty html_options

    - by SeanJA
    For smarty's html_options function, is there a way to avoid having to do this (other than not using smarty that is)? {if $smarty.post} {html_options name=option_1 optins=$options selected=$smarty.post.option_1} {else} {html_options name=option_1 optins=$options} {/if} I realize that it won't show up in the template, but it seems like a bad practice to leave something that is not defined in the template (it also fills up my error logs with noise about undefined indexes).

    Read the article

  • Html string replace a span's class doesn't work in IE?

    - by SeanJA
    Someone tried to recreate smarty in js: // actually from a template file, not hardcoded in the javascript html = '<span class="{test}">yay</span>'; html = change(html, 'test', 'foo bar'); function change(html, key, value){ html = html.replace('{'+key+'}',value); html = html.replace('%7B'+key+'%7D',value); return html; } element.innerHTML = html; In FF this works fine (as expected): yay In IE 7/8 and probably 6... it gives me this: <span class="foo" bar="">yay</span> Why does it create the extra attribute instead of doing what I expected it to do?

    Read the article

  • PHP Nested classes work... sort of?

    - by SeanJA
    So, if you try to do a nested class like this: //nestedtest.php class nestedTest{ function test(){ class E extends Exception{} throw new E; } } You will get an error Fatal error: Class declarations may not be nested in [...] but if you have a class in a separate file like so: //nestedtest2.php class nestedTest2{ function test(){ include('e.php'); throw new E; } } //e.php class E Extends Exception{} So, why does the second hacky way of doing it work, but the non-hacky way of doing it does not work?

    Read the article

  • Are there any thead limitations that make it not print on each page in Firefox?

    - by SeanJA
    I have a table that has a <thead>, a <tfoot> and a <tbody>. It is supposed to print the thead and tfoot on each page in theory, but for some reason the thead does not if it contains certain elements together. This works: <thead> <tr> <td colspan="3">This works</td> <tr> <tr> <th colspan="2">column 1</th> <th> column 2 </th> </tr> </thead> This does not seem to work: <thead> <tr> <td colspan="3"> <h2>Header</h2> <address> <strong>address 1</strong> <br /> address 2 <br /> address 3 <br /> </address> <img src="/images/logo.png" alt="Logo" /> <h2>Another header</h2> <hr /> </td> </tr> <tr> <th colspan="2">column 1</th> <th> column 2 </th> </tr> </thead> Is there a reason for this not to work?

    Read the article

  • jQuery :contains(unicode_characters)

    - by SeanJA
    I have an element like this: <span class="tool_tip" title="The full title">The ful&#8230;</span> This seems to work: jQuery('span:contains(…)'); But this does not: jQuery('span:contains(&#8230;)'); I am pretty sure that it would be bad to use the first one because if someone else saves the file, or the browser decides to get the file in a different character set for some reason things will not work. There has to be a way to properly select this span, right?

    Read the article

  • Do ORMs normally allow circular relations? If so, how would they handle it?

    - by SeanJA
    I was hacking around trying to make a basic orm that has support for the one => one and one => many relationships. I think I succeeded somewhat, but I am curious about how to handle circular relationships. Say you had something like this: user::hasOne('car'); car::hasMany('wheels'); car::property('type'); wheel::hasOne('car'); You could then do this (theoretically): $u = new user(); echo $u->car->wheels[0]->car->wheels[1]->car->wheels[2]->car->wheels[3]->type; #=> "monster truck" Now, I am not sure why you would want to do this. It seems like it wastes a whole pile of memory and time just to get to something that could have been done in a much shorter way. In my small ORM, I now have 4 copies of the wheel class, and 4 copies of the car class in memory, which causes a problem if I update one of them and save it back to the database, the rest get out of date, and could overwrite the changes that were already made. How do other ORMs handle circular references? Do they even allow it? Do they go back up the tree and create a pointer to one of the parents? DO they let the coder shoot themselves in the foot if they are silly enough to go around in circles?

    Read the article

  • Defining xml in an xsd where an attribute determines the possible contents

    - by SeanJA
    How would one go about defining something like this in an xsd? <start> <request type="typeA"> <elementOnlyFoundInA /> </request> <request type="typeB"> <elementOnlyFoundInB /> </request> </start> I ran xsd.exe just to get an idea of what it might look like, but it does not appear recognize the relationships between the value of type and the contents of the request. Is it even possible to define contents based on an attribute like this in an xsd file?

    Read the article

  • git: Your branch is Ahead by X commits

    - by SeanJA
    How does this actually come about? I am working in one repo by myself at the moment, so this is my workflow: 1- change files 2- commit 4- repeat until satisfied 4- push to master Then when I do a git status it tells me that my branch is ahead by X commits (presumably the same number of commits that I have made). Is it because when you push the code it doesn't actually update your locally cached files (in the .git folders)? git pull seems to 'fix' this strange message, but I am still curious why it happens, maybe I am using git wrong?

    Read the article

1