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  • function which given a point and a value of the area of a square as input parameter returns four squ

    - by osabri
    in this code i don't understand why teacher used sometimes +value, - value; /******************************************/ // function void returnSquares(POINT point, int value) void returnSquares(POINT point, int value) { SQUARE tabSquares[4]; // table of squares that we are creating int i; // getting points of 4 squares // for first square input point is point C tabSquares[0].pointA.dimX = point.dimX - value; tabSquares[0].pointA.dimY = point.dimY + value; tabSquares[0].pointB.dimX = point.dimX; tabSquares[0].pointB.dimY = point.dimY + value; tabSquares[0].pointC.dimX = point.dimX; tabSquares[0].pointC.dimY = point.dimY; tabSquares[0].pointD.dimX = point.dimX - value; tabSquares[0].pointD.dimY = point.dimY; // for 2nd square input point is point D tabSquares[1].pointA.dimX = point.dimX; tabSquares[1].pointA.dimY = point.dimY + value; tabSquares[1].pointB.dimX = point.dimX + value; tabSquares[1].pointB.dimY = point.dimY + value; tabSquares[1].pointC.dimX = point.dimX + value; tabSquares[1].pointC.dimY = point.dimY; tabSquares[1].pointD.dimX = point.dimX; tabSquares[1].pointD.dimY = point.dimY; // for 3rd square input point is point A tabSquares[2].pointA.dimX = point.dimX; tabSquares[2].pointA.dimY = point.dimY; tabSquares[2].pointB.dimX = point.dimX + value; tabSquares[2].pointB.dimY = point.dimY; tabSquares[2].pointC.dimX = point.dimX + value; tabSquares[2].pointC.dimY = point.dimY - value; tabSquares[2].pointD.dimX = point.dimX; tabSquares[2].pointD.dimY = point.dimY - value; // for 4th square input point is point B tabSquares[3].pointA.dimX = point.dimX - value; tabSquares[3].pointA.dimY = point.dimY; tabSquares[3].pointB.dimX = point.dimX; tabSquares[3].pointB.dimY = point.dimY; tabSquares[3].pointC.dimX = point.dimX; tabSquares[3].pointC.dimY = point.dimY - value; tabSquares[3].pointD.dimX = point.dimX - value; tabSquares[3].pointD.dimY = point.dimY - value; for (i=0; i<4; i++) { printf("Square number %d\n",i); // now we print parameters of each point in current Square printf("point A x= %0.2f y= %0.2f\n",tabSquares[i].pointA.dimX,tabSquares[i].pointA.dimY); printf("point B x= %0.2f y= %0.2f\n",tabSquares[i].pointB.dimX,tabSquares[i].pointB.dimY); printf("point C x= %0.2f y= %0.2f\n",tabSquares[i].pointC.dimX,tabSquares[i].pointC.dimY); printf("point D x= %0.2f y= %0.2f\n",tabSquares[i].pointD.dimX,tabSquares[i].pointD.dimY); } }

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  • How is this relation in 4th normal form? Is the dependency trivial?

    - by squ
    I have a question that concerns multi value dependency. The relation looks like this: R(A,B) with A -->> B (A multi value determines B) I've been told that this relation is in 4th normal form, but I don't really se how. I know that if the multi value dependency is trivial, then it doesn't violate the 4th normal form. But is this trivial? It would be trivial if it, for example, looked like this: {A,B} -->> B But the first dependency example shouldn't be trivial. The other rule for 4th NF says that A in this case needs to be a super key of the relation, but it isn't. As far as I can tell, A isn't a super key, since {A,B} is needed to identify a tuple. So the question is, why is this in 4th normal form? It seems to be violating both of the rules.

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