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  • VBA Public Function to Excel

    - by Sugih
    Dear sir , I have create below function Option Explicit Public Function fyi(x As Double, f As String) As String Application.Volatile Dim data As Double Dim post(5) post(1) = "Ribu " post(2) = "Juta " post(3) = "Milyar " post(4) = "Trilyun " post(5) = "Ribu Trilyun " Dim part As String Dim text As String Dim cond As Boolean Dim i As Integer If (x < 0) Then fyi = " " Exit Function End If If (x = 0) Then fyi = "Nol" Exit Function End If If (x < 2000) Then cond = True End If text = " " If (x >= 1E+15) Then fyi = "Nilai Terlalu Besar" Exit Function End If For i = 4 To 1 Step -1 data = Int(x / (10 ^ (3 * i))) If (data 0) Then part = fyis(data, cond) text = text & part & post(i) End If x = x - data * (10 ^ (3 * i)) Next text = text & fyis(x, False) fyi = text & f End Function Function fyis(ByVal y As Double, ByVal conds As Boolean) As String Dim datas As Double Dim posts(2) posts(1) = "Puluh" posts(2) = "Ratus" Dim parts As String Dim texts As String 'Dim conds As Boolean Dim j As Integer Dim value(9) value(1) = "Se" value(2) = "Dua " value(3) = "Tiga " value(4) = "Empat " value(5) = "Lima " value(6) = "Enam " value(7) = "Tujuh " value(8) = "Delapan " value(9) = "Sembilan " texts = " " For j = 2 To 1 Step -1 datas = Int(y / 10 ^ j) If (datas 0) Then parts = value(datas) If (j = 1 And datas = 1) Then y = y - datas * 10 ^ j If (y = 1) Then posts(j) = "belas" Else value(y) = "Se" End If texts = texts & value(y) & posts(j) fyis = texts Exit Function Else texts = texts & parts & posts(j) End If End If y = y - datas * 10 ^ j Next If (conds = False) Then value(1) = "Satu " End If texts = texts & value(y) fyis = texts End Function but when I return to Excel and type '=fyi(500,"USD") it return to #name? please do me favor to inform me how to solve Rgds, Sugih

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