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  • Sorting based on existing elements in xslt

    - by Teelo
    Hi , I want to sort in xslt based on existing set of pattern . Let me explain with the code: <Types> <Type> <Names> <Name>Ryan</Name> </Names> <Address>2344</Address> </Type> <Type> <Names> </Name>Timber</Name> </Names> <Address>1234</Address> </Type> <Type> <Names> </Name>Bryan</Name> </Names> <Address>34</Address> </Type> </Types> Right now I m just calling it and getting it like (all hyperlinks) Ryan Timber Bryan Now I don't want sorting on name but I have existing pattern how I want it to get displayed.Like Timber Bryan Ryan (Also I don't want to lose the url attached to my names earlier while doing this) I was thinking of putting earlier value in some array and sort based on the other array where I will store my existing pattern. But I am not sure how to achieve that.. My xslt looks like this now(there can be duplicate names also) <xsl:for-each select="/Types/Type/Names/Name/text()[generate-id()=generate-id(key('Name',.)[1])]"> <xsl:call-template name="typename"> </xsl:call-template> </xsl:for-each> <xsl:template name="typename"> <li> <a href="somelogicforurl"> <xsl:value-of select="."/> </a> </li> </xsl:template> I am using xsl 1.0

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