Search Results

Search found 3 results on 1 pages for 'telliott99'.

Page 1/1 | 1 

• can't find port 22 traffic under VirtualBox

  - by telliott99

  I'm trying to learn to use tcpdump. I thought I'd eavesdrop on my ssh login. The setup is a bit unusual, I have OS X Lion running VirtualBox, with Ubuntu running in the VM. I have ssh enabled and can login from OS X normally: > ssh -p 22 10.0.1.2 -l telliott Welcome to Ubuntu 11.10 (GNU/Linux 3.0.0-17-generic i686) * Documentation: https://help.ubuntu.com/ 0 packages can be updated. 0 updates are security updates. Last login: Sat Mar 31 19:54:36 2012 from toms-mac-mini.local telliott@U32:~$ logout Connection to 10.0.1.2 closed. > I have not obfuscated the ssh port on Ubuntu. From OS X, stroke gives what I expect: > ./stroke 10.0.1.2 22 22 Port Scanning host: 10.0.1.2 Open TCP Port: 22 ssh So from OS X I do: > sudo tcpdump -i en1 -v port 22 Password: tcpdump: listening on en1, link-type EN10MB (Ethernet), capture size 65535 bytes Then I login from OS X to Ubuntu using ssh, but I see nothing with tcpdump. Here is ifconfig from Ubuntu: telliott@U32:~$ ifconfig eth1 Link encap:Ethernet HWaddr 08:00:27:d7:ba:0e inet addr:10.0.1.2 Bcast:10.0.1.255 Mask:255.255.255.0 inet6 addr: fe80::a00:27ff:fed7:ba0e/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:799 errors:0 dropped:0 overruns:0 frame:0 TX packets:465 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:96863 (96.8 KB) TX bytes:68638 (68.6 KB) Where are the packets I was hoping to see? Thanks for any help.

  Read the article

• Flatten (an irregular) list of lists in Python

  - by telliott99

  Yes, I know this subject has been covered before (here, here, here, here), but AFAIK, all solutions save one choke on a list like this: L = [[[1, 2, 3], [4, 5]], 6] where the desired output is [1, 2, 3, 4, 5, 6] or perhaps even better, an iterator. The only solution I saw that works for an arbitrary nesting is from @Alabaster Codify here: def flatten(x): result = [] for el in x: if hasattr(el, "__iter__") and not isinstance(el, basestring): result.extend(flatten(el)) else: result.append(el) return result flatten(L) So to my question: is this the best model? Did I overlook something? Any problems?

  Read the article

• vectorize is indeterminate

  - by telliott99

  I'm trying to vectorize a simple function in numpy and getting inconsistent behavior. I expect my code to return 0 for values < 0.5 and the unchanged value otherwise. Strangely, different runs of the script from the command line yield varying results: sometimes it works correctly, and sometimes I get all 0's. It doesn't matter which of the three lines I use for the case when d <= T. It does seem to be correlated with whether the first value to be returned is 0. Any ideas? Thanks. import numpy as np def my_func(d, T=0.5): if d > T: return d #if d <= T: return 0 else: return 0 #return 0 N = 4 A = np.random.uniform(size=N**2) A.shape = (N,N) print A f = np.vectorize(my_func) print f(A) $ python x.py [[ 0.86913815 0.96833127 0.54539153 0.46184594] [ 0.46550903 0.24645558 0.26988519 0.0959257 ] [ 0.73356391 0.69363161 0.57222389 0.98214089] [ 0.15789303 0.06803493 0.01601389 0.04735725]] [[ 0.86913815 0.96833127 0.54539153 0. ] [ 0. 0. 0. 0. ] [ 0.73356391 0.69363161 0.57222389 0.98214089] [ 0. 0. 0. 0. ]] $ python x.py [[ 0.37127366 0.77935622 0.74392301 0.92626644] [ 0.61639086 0.32584431 0.12345342 0.17392298] [ 0.03679475 0.00536863 0.60936931 0.12761859] [ 0.49091897 0.21261635 0.37063752 0.23578082]] [[0 0 0 0] [0 0 0 0] [0 0 0 0] [0 0 0 0]]

  Read the article

1