This question already has an answer here: How do you generate tileable Perlin noise? 9 answers I'm having trouble figuring out the solution to this particular algorithm. I'm using the Perlin Noise implementation from: https://code.google.com/p/mikeralib/source/browse/trunk/Mikera/src/main/java/mikera/math/PerlinNoise.java Here's what I have so far: for (Chunk chunk : chunks) { PerlinNoise noise = new PerlinNoise(); for (int y = 0; y < CHUNK_SIZE_HEIGHT; ++y) { for (int x = 0; x < CHUNK_SIZE_WIDTH; ++x) { int index = get1DIndex(y, CHUNK_SIZE_WIDTH, x); float val = 0; for (int i = 2; i <= 32; i *= i) { double n = noise.tileableNoise2(i * x / (float)CHUNK_SIZE_WIDTH, i * y / (float)CHUNK_SIZE_HEIGHT, CHUNK_SIZE_WIDTH, CHUNK_SIZE_HEIGHT); val += n / i; } // chunk tile at [index] gets set to the colour 'val' } } } Which produces something like this: Each chunk is made up of CHUNK_SIZE number of tiles, and each tile has a TILE_SIZE_WIDTH/HEIGHT. I think it has something to do with the inner-most for loop and the x/y co-ords given to the noise function, but I could be wrong. Solved: PerlinNoise noise = new PerlinNoise(); for (Chunk chunk : chunks) { for (int y = 0; y < CHUNK_SIZE_HEIGHT; ++y) { for (int x = 0; x < CHUNK_SIZE_WIDTH; ++x) { int index = get1DIndex(y, CHUNK_SIZE_WIDTH, x); float val = 0; float xx = x * TILE_SIZE_WIDTH + chunk.x; float yy = y * TILE_SIZE_HEIGHT + chunk.h; int w = CHUNK_SIZE_WIDTH * TILE_SIZE_WIDTH; int h = CHUNK_SIZE_HEIGHT * TILE_SIZE_HEIGHT; for (int i = 2; i <= 32; i *= i) { double n = noise.tileableNoise2(i * xx / (float)w, i * yy / (float)h, w, h); val += n / i; } // chunk tile at [index] gets set to the colour 'val' } } }