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  • SELECT Statement without duplicate rows on the multiple join tables

    - by theBo
    I have 4 tables built with JOINS and I would like to SELECT DISTINCT rows on the setsTbl.s_id so they always show regardless if there's relational data against them or not!. This is what I have at present which displays the data but doesn't display all of but not the entire distinct row! SELECT setsTbl.s_id, setsTbl.setName, userProfilesTbl.no + ' ' + userProfilesTbl.surname AS Name, trainingTbl.t_date, userAssessmentTbl.o_id FROM userProfilesTbl LEFT OUTER JOIN userAssessmentTbl ON userProfilesTbl.UserId = userAssessmentTbl.UserId FULL OUTER JOIN trainingTbl ON userAssessmentTbl.tt_id = trainingTbl.tt_id RIGHT OUTER JOIN setsTbl ON trainingTbl.s_id = setsTbl.s_id WHERE (userProfilesTbl.st_id=@st_id AND userProfilesTbl.sh_id=@sh_id) AND (DATEPART(yyyy,t_date) = @y_date ) OR (userAssessmentTbl.o_id IS NULL) ORDER BY setName ASC, t_date ASC With this statement I get some of the rows (the ones with data against them) but as stated the s_id field does not return distinct. This following inner select statement works in part when used in SQL Query analyzer and returns pretty much the data i require s_id setName Name o_id ----- ----- ----- ------ 1 100 Barnes 2 2 100 Beardsley 3 3 101 Aldridge 1 4 102 Molby 2 5 102 Whelan 3 but not when used outside of that environment. select * from ( SELECT userProfilesTbl.serviceNo + ' ' + userProfilesTbl.surname AS Name, userProfilesTbl.st_id, userProfilesTbl.sh_id, userAssessmentTbl.o_id, setsTbl.s_id, setsTbl.setName, row_number() over ( partition by setsTbl.s_id order by setsTbl.s_id ) r FROM userProfilesTbl LEFT OUTER JOIN userAssessmentTbl ON userProfilesTbl.UserId = userAssessmentTbl.UserId FULL OUTER JOIN trainingTbl ON userAssessmentTbl.tt_id = trainingTbl.tt_id RIGHT OUTER JOIN setsTbl ON trainingTbl.s_id = setsTbl.s_id ) x where x.r = 1 Not receiving any errors just not displaying the data?

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