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  • Use TinyInt to hide/show controls?

    - by grady
    Hi, I have 6 buttons on my GUI. The visibility of the buttons can be configured via checkboxes. Checking the checkbox and saving means the correpsonding button should be shown. I am wondering if it is somehow possible to have one TinyInt column in the database which represents the visibility of all 6 buttons. I created an enum for the buttons, it looks like that: public enum MyButtons { Button1 = 1, Button2 = 2, Button3 = 3, Button4 = 4, Button5 = 5, Button6 = 6 } Now I am wondering how to say that for example only button1, button5 and button6 are checked using this one column. Possible at all? Thanks :-)

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  • SQL Server Max TinyInt Value

    - by Derek Dieter
    The maximum value for a tinyint in SQL Server is: 0 through 255 And the byte size is: 1 byte other maximum values: BigInt: -9223372036854775808 through 9223372036854775807 (8 bytes) Int: -2147483648 through 2147483647 (4 bytes) SmallInt: -32768 through 32767 (2 bytes) Related Posts:»SQL Server Max SmallInt Value»SQL Server Max Int Value»SQL Server Bigint Max Value»Create Date Table»Dynamic Numbers Table

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  • Datatype query on datetime and tinyint

    - by sarah
    Hi , I have Mysql column type has datetime what should be the corresponding datatype in entity bean class for the same column ,as well for tinyint what would be the corresponding datatype in entity bean class for the same column ?

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  • Three boolean values saved in one tinyint

    - by Casper
    Hello, probably a simple question but I seem to be suffering from programmer's block. :) I have three boolean values: A, B, and C. I would like to save the state combination as an unsigned tinyint (max 255) into a database and be able to derive the states from the saved integer. Even though there are only a limited number of combinations, I would like to avoid hard-coding each state combination to a specific value (something like if A=true and B=true has the value 1). I tried to assign values to the variables so (A=1, B=2, C=3) and then adding, but I can't differentiate between A and B being true from i.e. only C being true. I am stumped but pretty sure that it is possible. Thanks

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  • asp.net mvc linq sql problem

    - by user339449
    Hi all, Now I am working on project using asp.net mvc 2 and linq to sql, the problem is occurs when trying to insert data in a table where the table has an identity column type of tinyint. When trying to insert the error following error occurs, The primary key column of type 'TinyInt' cannot be generated by the server. What is the problem, does linq to sql support tinyint datatype? Please help me

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  • Calendar Table - Week number of month

    - by Saif Khan
    I have a calendar table with data from year 2000 to 2012 (2012 wasn't intentional!). I just realize that I don't have the week number of month (e.g In January 1,2,3,4 February 1,2,3,4) How do I go about calculating the week numbers in a month to fill this table? Here is the table schema CREATE TABLE [TCalendar] ( [TimeKey] [int] NOT NULL , [FullDateAlternateKey] [datetime] NOT NULL , [HolidayKey] [tinyint] NULL , [IsWeekDay] [tinyint] NULL , [DayNumberOfWeek] [tinyint] NULL , [EnglishDayNameOfWeek] [nvarchar] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL , [SpanishDayNameOfWeek] [nvarchar] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL , [FrenchDayNameOfWeek] [nvarchar] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL , [DayNumberOfMonth] [tinyint] NULL , [DayNumberOfYear] [smallint] NULL , [WeekNumberOfYear] [tinyint] NULL , [EnglishMonthName] [nvarchar] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL , [SpanishMonthName] [nvarchar] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL , [FrenchMonthName] [nvarchar] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL , [MonthNumberOfYear] [tinyint] NULL , [CalendarQuarter] [tinyint] NULL , [CalendarYear] [char] (4) COLLATE SQL_Latin1_General_CP1_CI_AS NULL , [CalendarSemester] [tinyint] NULL , [FiscalQuarter] [tinyint] NULL , [FiscalYear] [char] (4) COLLATE SQL_Latin1_General_CP1_CI_AS NULL , [FiscalSemester] [tinyint] NULL , [IsLastDayInMonth] [tinyint] NULL , CONSTRAINT [PK_TCalendar] PRIMARY KEY CLUSTERED ( [TimeKey] ) ON [PRIMARY] ) ON [PRIMARY] GO

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  • Html.RadioButton group defaulting to 0

    - by awrigley
    Hi A default value of 0 is creeping into a Surveys app I am developing, for no reason that I can see. The problem is as follows: I have a group of Html.RadioButtons that represent the possible values a user can choose to answer a survey question (1 == Not at all, 2 == A little, 3 == A lot). I have used a tinyint datatype, that does not allow null, to store the answer to each question. The view code looks like this: <ol class="SurveyQuestions"> <% foreach (SurveyQuestion question in Model.Questions) { string col = question.QuestionColumn; %> <li><%=question.QuestionText%> <ul style="float:right;" class="MultiChoice"> <li><%= Html.RadioButton(col, "1")%></li> <li><%= Html.RadioButton(col, "2")%></li> <li><%= Html.RadioButton(col, "3")%></li> </ul> <%= Html.ValidationMessage(col, "*") %> </li> <% } %> </ol> [Note on the above code:] Each survey has about 70 questions, so I have put the questions text in one table, and store the results in a different table. I have put the Questions into my form view model (hence Model.Questions); the questions table has a field called QuestionColumn that allows me to link up the answer table column to the question, as shown above (<%= Html.RadioButton(col, "1")%, etc) [/Note] However, when the user DOESN'T answer the question, the value 0 is getting inserted into the database column. As a result, I don't get what I expect, ie, a validation error. In no place have I stipulated a default value of 0 for the fields in the answers table. So what is happening? Any ideas?

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  • converting mysql database to sql server

    - by every_answer_gets_a_point
    i have a mysql database: /* MySQL Data Transfer Source Host: 10.0.0.5 Source Database: jnetdata Target Host: 10.0.0.5 Target Database: jnetdata Date: 5/26/2009 12:27:33 PM */ SET FOREIGN_KEY_CHECKS=0; -- ---------------------------- -- Table structure for chavrusas -- ---------------------------- CREATE TABLE `chavrusas` ( `id` int(11) NOT NULL auto_increment, `date_created` datetime default NULL, `luser_id` int(11) default NULL, `ruser_id` int(11) default NULL, `luser_type` varchar(50) default NULL, `ruser_type` varchar(50) default NULL, `SessionDay` varchar(250) default NULL, `SessionTime` datetime default NULL, `WeeklyReminder` tinyint(1) NOT NULL default '0', `reminder_phone` tinyint(1) NOT NULL default '0', `calling_card` varchar(50) default NULL, `active` tinyint(1) NOT NULL default '0', `notes` mediumtext, `ended` tinyint(1) NOT NULL default '0', `end_date` datetime default NULL, `initiated_by_student` tinyint(1) NOT NULL default '0', `initiated_by_volunteer` tinyint(1) NOT NULL default '0', `student_general_reason` varchar(50) default NULL, `volunteer_general_reason` varchar(50) default NULL, `student_reason` varchar(250) default NULL, `volunteer_reason` varchar(250) default NULL, `student_nli` tinyint(1) NOT NULL default '0', `volunteer_nli` tinyint(1) NOT NULL default '0', `jnet_initiated` tinyint(1) default '0', `belongs_to` varchar(50) default NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM AUTO_INCREMENT=5913 DEFAULT CHARSET=latin1; -- ---------------------------- -- Table structure for tbluseravailability -- ---------------------------- CREATE TABLE `tbluseravailability` ( `availability_id` int(11) NOT NULL auto_increment, `user_id` int(11) NOT NULL, `weekday_id` int(11) NOT NULL, `timeslot_id` int(11) NOT NULL, PRIMARY KEY (`availability_id`) ) ENGINE=MyISAM AUTO_INCREMENT=10865 DEFAULT CHARSET=latin1; -- ---------------------------- -- Table structure for tblusers -- ---------------------------- CREATE TABLE `tblusers` ( `id` int(11) NOT NULL auto_increment, `password` varchar(50) default NULL, `title` varchar(255) default NULL, `first` varchar(255) default NULL, `last` varchar(255) default NULL, `gender` varchar(255) default NULL, `address` varchar(255) default NULL, `address_2` varchar(255) default NULL, `city` varchar(255) default NULL, `state` varchar(255) default NULL, `postcode` varchar(255) default NULL, `country` varchar(255) default NULL, `email` varchar(255) default NULL, `emailnotes` varchar(255) default NULL, `Home_Phone` varchar(255) default NULL, `Office_Phone` varchar(255) default NULL, `Cell_Phone` varchar(255) default NULL, `Contact_Preference` varchar(255) default NULL, `Birthdate` datetime default NULL, `Age` varchar(255 and it goes on for about 10mb i need to convert it to ms sql, how do i do it?

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  • Data Warehouse ETL slow - change primary key in dimension?

    - by Jubbles
    I have a working MySQL data warehouse that is organized as a star schema and I am using Talend Open Studio for Data Integration 5.1 to create the ETL process. I would like this process to run once per day. I have estimated that one of the dimension tables (dimUser) will have approximately 2 million records and 23 columns. I created a small test ETL process in Talend that worked, but given the amount of data that may need to be updated daily, the current performance will not cut it. It takes the ETL process four minutes to UPDATE or INSERT 100 records to dimUser. If I assumed a linear relationship between the count of records and the amount of time to UPDATE or INSERT, then there is no way the ETL can finish in 3-4 hours (my hope), let alone one day. Since I'm unfamiliar with Java, I wrote the ETL as a Python script and ran into the same problem. Although, I did discover that if I did only INSERT, the process went much faster. I am pretty sure that the bottleneck is caused by the UPDATE statements. The primary key in dimUser is an auto-increment integer. My friend suggested that I scrap this primary key and replace it with a multi-field primary key (in my case, 2-3 fields). Before I rip the test data out of my warehouse and change the schema, can anyone provide suggestions or guidelines related to the design of the data warehouse the ETL process how realistic it is to have an ETL process INSERT or UPDATE a few million records each day will my friend's suggestion significantly help If you need any further information, just let me know and I'll post it. UPDATE - additional information: mysql> describe dimUser; Field Type Null Key Default Extra user_key int(10) unsigned NO PRI NULL auto_increment id_A int(10) unsigned NO NULL id_B int(10) unsigned NO NULL field_4 tinyint(4) unsigned NO 0 field_5 varchar(50) YES NULL city varchar(50) YES NULL state varchar(2) YES NULL country varchar(50) YES NULL zip_code varchar(10) NO 99999 field_10 tinyint(1) NO 0 field_11 tinyint(1) NO 0 field_12 tinyint(1) NO 0 field_13 tinyint(1) NO 1 field_14 tinyint(1) NO 0 field_15 tinyint(1) NO 0 field_16 tinyint(1) NO 0 field_17 tinyint(1) NO 1 field_18 tinyint(1) NO 0 field_19 tinyint(1) NO 0 field_20 tinyint(1) NO 0 create_date datetime NO 2012-01-01 00:00:00 last_update datetime NO 2012-01-01 00:00:00 run_id int(10) unsigned NO 999 I used a surrogate key because I had read that it was good practice. Since, from a business perspective, I want to keep aware of potential fraudulent activity (say for 200 days a user is associated with state X and then the next day they are associated with state Y - they could have moved or their account could have been compromised), so that is why geographic data is kept. The field id_B may have a few distinct values of id_A associated with it, but I am interested in knowing distinct (id_A, id_B) tuples. In the context of this information, my friend suggested that something like (id_A, id_B, zip_code) be the primary key. For the large majority of daily ETL processes (80%), I only expect the following fields to be updated for existing records: field_10 - field_14, last_update, and run_id (this field is a foreign key to my etlLog table and is used for ETL auditing purposes).

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  • what is called KEY

    - by Bharanikumar
    CREATE TABLE `ost_staff` ( `staff_id` int(11) unsigned NOT NULL auto_increment, `group_id` int(10) unsigned NOT NULL default '0', `dept_id` int(10) unsigned NOT NULL default '0', `username` varchar(32) collate latin1_german2_ci NOT NULL default '', `firstname` varchar(32) collate latin1_german2_ci default NULL, `lastname` varchar(32) collate latin1_german2_ci default NULL, `passwd` varchar(128) collate latin1_german2_ci default NULL, `email` varchar(128) collate latin1_german2_ci default NULL, `phone` varchar(24) collate latin1_german2_ci NOT NULL default '', `phone_ext` varchar(6) collate latin1_german2_ci default NULL, `mobile` varchar(24) collate latin1_german2_ci NOT NULL default '', `signature` varchar(255) collate latin1_german2_ci NOT NULL default '', `isactive` tinyint(1) NOT NULL default '1', `isadmin` tinyint(1) NOT NULL default '0', `isvisible` tinyint(1) unsigned NOT NULL default '1', `onvacation` tinyint(1) unsigned NOT NULL default '0', `daylight_saving` tinyint(1) unsigned NOT NULL default '0', `append_signature` tinyint(1) unsigned NOT NULL default '0', `change_passwd` tinyint(1) unsigned NOT NULL default '0', `timezone_offset` float(3,1) NOT NULL default '0.0', `max_page_size` int(11) NOT NULL default '0', `created` datetime NOT NULL default '0000-00-00 00:00:00', `lastlogin` datetime default NULL, `updated` datetime NOT NULL default '0000-00-00 00:00:00', PRIMARY KEY (`staff_id`), UNIQUE KEY `username` (`username`), KEY `dept_id` (`dept_id`), **KEY `issuperuser` (`isadmin`),** **KEY `group_id` (`group_id`,`staff_id`)** ) ENGINE=MyISAM AUTO_INCREMENT=35 DEFAULT CHARSET=latin1 COLLATE=latin1_german2_ci; Hi the above query is the osticket open source one, i know primary key , foreign key , unique but AM NOT SURE WHAT IS THIS KEY group_id (group_id,staff_id) Please tell me, this constraints name....

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  • ON DELETE RESTRICT Causing Error 150

    - by Levi Hackwith
    CREATE TABLE project ( id INTEGER NOT NULL AUTO_INCREMENT, created_at DATETIME NOT NULL, name VARCHAR(75) NOT NULL, description LONGTEXT NOT NULL, is_active TINYINT NOT NULL DEFAULT '1', PRIMARY KEY (id), INDEX(name, created_at) ) ENGINE = INNODB; CREATE TABLE role ( id INTEGER NOT NULL, name VARCHAR(50) NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE organization ( id INTEGER NOT NULL AUTO_INCREMENT, created_at DATETIME NOT NULL, name VARCHAR(100) NOT NULL, is_active TINYINT NOT NULL DEFAULT '1', PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE user ( id INTEGER NOT NULL AUTO_INCREMENT, created_at DATETIME NOT NULL, role_id INTEGER NOT NULL, organization_id INTEGER NOT NULL, last_login_at DATETIME NOT NULL, last_ip_address VARCHAR(25) NOT NULL, username VARCHAR(45) NOT NULL, password CHAR(32) NOT NULL, email_address VARCHAR(255) NOT NULL, first_name VARCHAR(45) NOT NULL, last_name VARCHAR(45) NOT NULL, address_1 VARCHAR(100) NOT NULL, address_2 VARCHAR(25) NULL, city VARCHAR(25) NOT NULL, state CHAR(2) NOT NULL, zip_code VARCHAR(10) NOT NULL, primary_phone_number VARCHAR(10) NOT NULL, secondary_phone_number VARCHAR(10) NOT NULL, is_primary_organization_contact TINYINT NOT NULL DEFAULT '0', is_active TINYINT NOT NULL DEFAULT '1', PRIMARY KEY (id), CONSTRAINT fk_user_role_id FOREIGN KEY (role_id) REFERENCES role (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_user_organization_id FOREIGN KEY (organization_id) REFERENCES organization (id) ON UPDATE RESTRICT ON DELETE RESTRICT ) ENGINE = INNODB; CREATE TABLE project_user ( user_id INTEGER NOT NULL, project_id INTEGER NOT NULL, PRIMARY KEY (user_id, project_id), CONSTRAINT fk_project_user_user_id FOREIGN KEY (user_id) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE CASCADE, CONSTRAINT fk_project_user_project_id FOREIGN KEY (project_id) REFERENCES project (id) ON UPDATE RESTRICT ON DELETE RESTRICT ) ENGINE = INNODB; CREATE TABLE ticket_category ( id INTEGER NOT NULL AUTO_INCREMENT, name VARCHAR(20) NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE ticket_type ( id INTEGER NOT NULL AUTO_INCREMENT, name VARCHAR(20) NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE ticket_status ( id INTEGER NOT NULL AUTO_INCREMENT, name VARCHAR(20) NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE ticket ( id INTEGER NOT NULL AUTO_INCREMENT, created_at DATETIME NOT NULL, project_id INTEGER NOT NULL, created_by INTEGER NOT NULL, submitted_by INTEGER NOT NULL, assigned_to INTEGER NULL, category_id INTEGER NOT NULL, type_id INTEGER NOT NULL, title VARCHAR(75) NOT NULL, description LONGTEXT NOT NULL, contact_type_id TINYINT NOT NULL, affects_all_clients TINYINT NOT NULL DEFAULT '0', is_billable TINYINT NOT NULL DEFAULT '1', esimated_hours DECIMAL(4, 1) NOT NULL DEFAULT '0', hours_worked DECIMAL (4, 1) NOT NULL DEFAULT '0', status_id TINYINT NOT NULL, PRIMARY KEY (id), CONSTRAINT fk_ticket_project_id FOREIGN KEY (project_id) REFERENCES project (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_created_by FOREIGN KEY (created_by) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_submitted_by FOREIGN KEY (submitted_by) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_assigned_to FOREIGN KEY (assigned_to) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_category_id FOREIGN KEY (category_id) REFERENCES ticket_category (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_type_id FOREIGN KEY (type_id) REFERENCES ticket_type (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_status_id FOREIGN KEY (status_id) REFERENCES ticket_status (id) ON UPDATE RESTRICT ON DELETE RESTRICT ) ENGINE = INNODB; CREATE TABLE ticket_time_entry ( id INTEGER NOT NULL AUTO_INCREMENT, user_id INTEGER NOT NULL, ticket_id INTEGER NOT NULL, started_at DATETIME NOT NULL, ended_at DATETIME NOT NULL, PRIMARY KEY (id), CONSTRAINT fk_ticket_time_entry_user_id FOREIGN KEY (user_id) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_time_entry_ticket_id FOREIGN KEY (ticket_id) REFERENCES ticket (id) ON UPDATE RESTRICT ON DELETE RESTRICT ) ENGINE = INNODB; The ticket table's create statement causes an error 150. I have no clue why. When I remove the ON DELETE RESTRICT statements from the table declaration, it works. Why is that?

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  • MySQL Query Error

    - by Nano HE
    I am debug my php forum. Before the error,I modified the DB table name from cdb_sessions to imc_forum_sessions successfully. I tried my best to debug with NetBeans but can't find the reason. Could you please have a look at my post below. Thank you. // It will run to else during debug if($sid) { if($discuz_uid) { $query = $db->query("SELECT s.sid, s.styleid, s.groupid='6' AS ipbanned, s.pageviews AS spageviews, s.lastolupdate, s.seccode, $membertablefields FROM {$tablepre}sessions s, {$tablepre}members m WHERE m.uid=s.uid AND s.sid='$sid' AND CONCAT_WS('.',s.ip1,s.ip2,s.ip3,s.ip4)='$onlineip' AND m.uid='$discuz_uid' AND m.password='$discuz_pw' AND m.secques='$discuz_secques'"); } else { $query = $db->query("SELECT sid, uid AS sessionuid, groupid, groupid='6' AS ipbanned, pageviews AS spageviews, styleid, lastolupdate, seccode FROM {$tablepre}sessions WHERE sid='$sid' AND CONCAT_WS('.',ip1,ip2,ip3,ip4)='$onlineip'"); } } MySQL data table exported as below CREATE TABLE IF NOT EXISTS `imc_forum_sessions` ( `sid` char(6) NOT NULL DEFAULT '', `ip1` tinyint(3) unsigned NOT NULL DEFAULT '0', `ip2` tinyint(3) unsigned NOT NULL DEFAULT '0', `ip3` tinyint(3) unsigned NOT NULL DEFAULT '0', `ip4` tinyint(3) unsigned NOT NULL DEFAULT '0', `uid` mediumint(8) unsigned NOT NULL DEFAULT '0', `username` char(15) NOT NULL DEFAULT '', `groupid` smallint(6) unsigned NOT NULL DEFAULT '0', `styleid` smallint(6) unsigned NOT NULL DEFAULT '0', `invisible` tinyint(1) NOT NULL DEFAULT '0', `action` tinyint(1) unsigned NOT NULL DEFAULT '0', `lastactivity` int(10) unsigned NOT NULL DEFAULT '0', `lastolupdate` int(10) unsigned NOT NULL DEFAULT '0', `pageviews` smallint(6) unsigned NOT NULL DEFAULT '0', `seccode` mediumint(6) unsigned NOT NULL DEFAULT '0', `fid` smallint(6) unsigned NOT NULL DEFAULT '0', `tid` mediumint(8) unsigned NOT NULL DEFAULT '0', `bloguid` mediumint(8) unsigned NOT NULL DEFAULT '0', UNIQUE KEY `sid` (`sid`), KEY `uid` (`uid`), KEY `bloguid` (`bloguid`) ) ENGINE=MEMORY DEFAULT CHARSET=utf8 MAX_ROWS=5000; -- -- Dumping data for table `imc_forum_sessions` -- INSERT INTO `imc_forum_sessions` (`sid`, `ip1`, `ip2`, `ip3`, `ip4`, `uid`, `username`, `groupid`, `styleid`, `invisible`, `action`, `lastactivity`, `lastolupdate`, `pageviews`, `seccode`, `fid`, `tid`, `bloguid`) VALUES ('NYC4r7', 127, 0, 0, 1, 0, '', 6, 5, 0, 3, 1271372018, 0, 0, 939015, 51, 303, 0); And the IE error showed, Time: 2010-4-16 7:12am Script: /forum/index.php SQL: SELECT sid, uid AS sessionuid, groupid, groupid='6' AS ipbanned, pageviews AS spageviews, styleid, lastolupdate, seccode FROM [Table]sessions WHERE sid='NYC4r7' AND CONCAT_WS('.',ip1,ip2,ip3,ip4)='127.0.0.1' Error: Table 'dbbbs.[Table]sessions' doesn't exist Errno.: 1146 Similar error report has beed dispatched to administrator before.

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  • Correlate GROUP BY and LEFT JOIN on multiple criteria to show latest record?

    - by Sunbird
    In a simple stock management database, quantity of new stock is added and shipped until quantity reaches zero. Each stock movement is assigned a reference, only the latest reference is used. In the example provided, the latest references are never shown, the stock ID's 1,4 should have references charlie, foxtrot respectively, but instead show alpha, delta. How can a GROUP BY and LEFT JOIN on multiple criteria be correlated to show the latest record? http://sqlfiddle.com/#!2/6bf37/107 CREATE TABLE stock ( id tinyint PRIMARY KEY, quantity int, parent_id tinyint ); CREATE TABLE stock_reference ( id tinyint PRIMARY KEY, stock_id tinyint, stock_reference_type_id tinyint, reference varchar(50) ); CREATE TABLE stock_reference_type ( id tinyint PRIMARY KEY, name varchar(50) ); INSERT INTO stock VALUES (1, 10, 1), (2, -5, 1), (3, -5, 1), (4, 20, 4), (5, -10, 4), (6, -5, 4); INSERT INTO stock_reference VALUES (1, 1, 1, 'Alpha'), (2, 2, 1, 'Beta'), (3, 3, 1, 'Charlie'), (4, 4, 1, 'Delta'), (5, 5, 1, 'Echo'), (6, 6, 1, 'Foxtrot'); INSERT INTO stock_reference_type VALUES (1, 'Customer Reference'); SELECT stock.id, SUM(stock.quantity) as quantity, customer.reference FROM stock LEFT JOIN stock_reference AS customer ON stock.id = customer.stock_id AND stock_reference_type_id = 1 GROUP BY stock.parent_id

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  • mysql INNODB inserts very slow

    - by 133794m3r
    The database's schema is as follows. CREATE TABLE `items` ( `id` mediumint( 8 ) unsigned NOT NULL AUTO_INCREMENT , `name` varchar( 45 ) NOT NULL , `main_type` tinyint( 4 ) NOT NULL , `rarity` tinyint( 4 ) NOT NULL , `stack_size` smallint( 6 ) NOT NULL , `sub_type` tinyint( 4 ) NOT NULL , `cost` mediumint( 8 ) unsigned NOT NULL , `ilvl` smallint( 6 ) unsigned NOT NULL DEFAULT '0', `flavor_text` varchar( 250 ) NOT NULL , `rlvl` tinyint( 3 ) unsigned NOT NULL , `final` tinyint( 4 ) NOT NULL DEFAULT '0', PRIMARY KEY ( `id` ) ) ENGINE = InnoDB DEFAULT CHARSET = ascii; Now, doing an insert on this table takes 0.22 seconds. I don't know why it's taking so long to do a single row insert. Reads are really really fast something like 0.005 seconds. With using the example configuration from here dev mysql innodb it averages ~0.002 to ~0.005 seconds. Why it takes more than 100x more time to do a single insert makes no sense to me. My computer is as follows. OS:Debian Sid x86-x64, Mysql 5.1, RAM:4GB ddr2, cpu 2.0Ghz dual core, HDD 7200RPM 32MB cache 640GB. Why it's taking almost 100x as much time for a SELECT * FROM items; vs INSERT INTO items ...; will never make any sense to me. It's still a small table at only 70 rows, and took that long even when it had 0 rows.

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  • quick mysql query problem

    - by Haroldo
    sorry, i dont like to ask such instance specific questions but this is driving me MENTAL! there's gotta be something obvious i'm missing: table: |ven_name|varchar(150)|No| |ven_sd|varchar(90)|Yes|NULL |ven_details|varchar(3000)|Yes|NULL |ven_tel|varchar(30)|Yes|NULL |ven_email|varchar(50)|Yes|NULL |ven_address|varchar(300)|Yes|NULL |lat|decimal(9,6)|Yes|NULL |long|decimal(9,6)|Yes|NULL |pub|tinyint(4)|Yes|NULL |bar|tinyint(4)|Yes|NULL |club|tinyint(4)|Yes|NULL |img_added|tinyint(4)|Yes|NULL query: INSERT INTO ven (img_added, ven_name, ven_sd, ven_tel, ven_email, ven_address, lat, long, pub, ven_details) VALUES (1, 'aaa', 'aaa', 'aaa', 'aaa', 'aaa', 100, 156, 1, 'aaa') error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'long, pub, ven_details) VALUES(1, 'aaa', 'aaa', '0117 9246449', 'aaa', 'aaa', 10' at line 1

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  • SQL Server 2008 BULK INSERT causes more reads than writes. Why?

    - by sh1ng
    I've huge a table (a few billion rows) with a clustered index and two non-clustered indices. A BULK INSERT operation produces 112000 reads and only 383 writes (duration 19948ms). It's very confusing to me. Why do reads exceed writes? How can I reduce it? update query insert bulk DenormalizedPrice4 ([DP_ID] BigInt, [DP_CountryID] Int, [DP_OperatorID] SmallInt, [DP_OperatorPriceID] BigInt, [DP_SpoID] Int, [DP_TourTypeID] Int, [DP_CheckinDate] Date, [DP_CurrencyID] SmallInt, [DP_Cost] Decimal(9,2), [DP_FirstCityID] Int, [DP_FirstHotelID] Int, [DP_FirstBuildingID] Int, [DP_FirstHotelGlobalStarID] Int, [DP_FirstHotelGlobalMealID] Int, [DP_FirstHotelAccommodationTypeID] Int, [DP_FirstHotelRoomCategoryID] Int, [DP_FirstHotelRoomTypeID] Int, [DP_Days] TinyInt, [DP_Nights] TinyInt, [DP_ChildrenCount] TinyInt, [DP_AdultsCount] TinyInt, [DP_TariffID] Int, [DP_DepartureCityID] Int, [DP_DateCreated] SmallDateTime, [DP_DateDenormalized] SmallDateTime, [DP_IsHide] Bit, [DP_FirstHotelAccommodationID] Int) with (CHECK_CONSTRAINTS) No triggers & foreign keys Cluster Index by DP_ID and two non-unique indexes(with fillfactor=90%) And one more thing DB stored on RAID50 with stripe size 256K

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  • How much does an InnoDB table benefit from having fixed-length rows?

    - by Philip Eve
    I know that dependent on the database storage engine in use, a performance benefit can be found if all of the rows in the table can be guaranteed to be the same length (by avoiding nullable columns and not using any VARCHAR, TEXT or BLOB columns). I'm not clear on how far this applies to InnoDB, with its funny table arrangements. Let's give an example: I have the following table CREATE TABLE `PlayerGameRcd` ( `User` SMALLINT UNSIGNED NOT NULL, `Game` MEDIUMINT UNSIGNED NOT NULL, `GameResult` ENUM('Quit', 'Kicked by Vote', 'Kicked by Admin', 'Kicked by System', 'Finished 5th', 'Finished 4th', 'Finished 3rd', 'Finished 2nd', 'Finished 1st', 'Game Aborted', 'Playing', 'Hide' ) NOT NULL DEFAULT 'Playing', `Inherited` TINYINT NOT NULL, `GameCounts` TINYINT NOT NULL, `Colour` TINYINT UNSIGNED NOT NULL, `Score` SMALLINT UNSIGNED NOT NULL DEFAULT 0, `NumLongTurns` TINYINT UNSIGNED NOT NULL DEFAULT 0, `Notes` MEDIUMTEXT, `CurrentOccupant` TINYINT UNSIGNED NOT NULL DEFAULT 0, PRIMARY KEY (`Game`, `User`), UNIQUE KEY `PGR_multi_uk` (`Game`, `CurrentOccupant`, `Colour`), INDEX `Stats_ind_PGR` (`GameCounts`, `GameResult`, `Score`, `User`), INDEX `GameList_ind_PGR` (`User`, `CurrentOccupant`, `Game`, `Colour`), CONSTRAINT `Constr_PlayerGameRcd_User_fk` FOREIGN KEY `User_fk` (`User`) REFERENCES `User` (`UserID`) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `Constr_PlayerGameRcd_Game_fk` FOREIGN KEY `Game_fk` (`Game`) REFERENCES `Game` (`GameID`) ON DELETE CASCADE ON UPDATE CASCADE ) ENGINE=INNODB CHARACTER SET utf8 COLLATE utf8_general_ci The only column that is nullable is Notes, which is MEDIUMTEXT. This table presently has 33097 rows (which I appreciate is small as yet). Of these rows, only 61 have values in Notes. How much of an improvement might I see from, say, adding a new table to store the Notes column in and performing LEFT JOINs when necessary?

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  • SQL Server Max SmallInt Value

    - by Derek Dieter
    The maximum value for a smallint in SQL Server is: -32768 through 32767 And the byte size is: 2 bytes other maximum values: BigInt: -9223372036854775808 through 9223372036854775807 (8 bytes) Int: -2147483648 through 2147483647 (4 bytes) TinyInt: 0 through 255 (1 byte) Related Posts:»SQL Server Max TinyInt Value»SQL Server Max Int Value»SQL Server Bigint Max Value»Dynamic Numbers Table»Troubleshooting SQL Server Slowness

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  • The maximum row size for the used table type, not counting BLOBs, is 65535. You have to change some columns to TEXT or BLOBs

    - by Matthew Chambers
    Hello I am getting the below message on a table i am trying to create The maximum row size for the used table type, not counting BLOBs, is 65535. You have to change some columns to TEXT or BLOBs Anyone know the answer to this please -- Table warrington_central.job -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS warrington_central.job ( id MEDIUMINT(8) UNSIGNED NOT NULL AUTO_INCREMENT , alias_title VARCHAR(255) NOT NULL , reference_number VARCHAR(100) NOT NULL , title VARCHAR(255) NOT NULL , primary_category SMALLINT(5) UNSIGNED NOT NULL , secondary_category SMALLINT(5) UNSIGNED NOT NULL , tertiary_category SMALLINT(5) UNSIGNED NULL , address_id BIGINT(20) UNSIGNED NOT NULL , geolocation_id BIGINT(20) UNSIGNED NULL , company VARCHAR(255) NOT NULL , description VARCHAR(10000) NOT NULL , skills_required VARCHAR(10000) NOT NULL , job_type TINYINT(2) UNSIGNED NOT NULL , experience_months_required TINYINT(2) UNSIGNED NOT NULL , experience_years_required TINYINT(2) UNSIGNED NOT NULL , salary_range VARCHAR(30) NOT NULL , extra_benefits_above_salary VARCHAR(500) NOT NULL , available_from DATE NULL , available_to DATE NULL , extra_location_details VARCHAR(1000) NOT NULL , contact_email VARCHAR(100) NOT NULL , contact_phone_number VARCHAR(20) NOT NULL , contact_mobile_number VARCHAR(20) NOT NULL , terms_conditions_application VARCHAR(5000) NOT NULL , link_to_profile ENUM('0','1') NOT NULL , created_on DATETIME NOT NULL , updated_on DATETIME NOT NULL , updated_by BIGINT(20) UNSIGNED NOT NULL , add_contact_form ENUM('0','1') NOT NULL , admin_package_id TINYINT(1) UNSIGNED NOT NULL , package_start_date DATETIME NOT NULL , package_end_date DATETIME NULL , package_comment VARCHAR(500) NOT NULL , viewable_to_members_only ENUM('0','1') NOT NULL , advertise_to DATETIME NULL , show_comment ENUM('0','1') NOT NULL , hits BIGINT(20) UNSIGNED NOT NULL DEFAULT 0 , visible ENUM('0','1') NOT NULL DEFAULT '0' , approved ENUM('I/* large SQL query (3.9 KB), snipped at 2,000 characters / / SQL Error (1118): Row size too large. The maximum row size for the used table type, not counting BLOBs, is 65535. You have to change some columns to TEXT or BLOBs */ SHOW WARNINGS;

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  • sql-server: Can I update two table with Single Query?

    - by RedsDevils
    How can I write single UPDATE query to change value of COL1 to ‘X’ if COL2 < 10 otherwise change it to ‘Y’, where the following two tables are linked by ID CREATE TABLE TEMP(ID TINYINT, COL1 CHAR(1)) INSERT INTO TEMP(ID,COL1) VALUES (1,'A') INSERT INTO TEMP(ID,COL1) VALUES (2,'B') INSERT INTO TEMP(ID,COL1) VALUES (11,'A') INSERT INTO TEMP(ID,COL1) VALUES (17,'B') CREATE TABLE TEMP2(ID TINYINT, COL2 TINYINT) INSERT INTO TEMP2(ID,COL2) VALUES (1,1) INSERT INTO TEMP2(ID,COL2) VALUES (2,5) INSERT INTO TEMP2(ID,COL2) VALUES (11,10) INSERT INTO TEMP2(ID,COL2) VALUES (17,15) Thanks in advance!

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  • BizTalk 2009 - SQL Server Job Configuration

    - by StuartBrierley
    Following the installation of Biztalk Server 2009 on my development laptop I used the BizTalk Server Best Practice Analyser which highlighted the fact that two of the SQL Server Agent jobs that BizTalk relies on were not running successfully.  Upon investigation it turned out that these jobs needed to be configured before they would run successfully. To configure these jobs open SQL Server Management Studio, expand SQL Server Agent > Jobs and double click on the appropriate job.  Select Steps and then edit the appropriate entries. Backup BizTalk Server (BizTalkMgmtDb) This job is comprised of three steps BackupFull, MarkAndBackupLog and ClearBackupHistory. BackupFull exec [dbo].[sp_BackupAllFull_Schedule] ‘d’ /* Frequency */,‘BTS’ /* Name */,‘<destination path>’ /* location of backup files */ The frequency here is set/left as daily The name is left as BTS You must provide a full destination path for the backup files to be stored. There are also two optional parameters: A flag that controls if the job forces a full backup if a partial backup fails A parameter to control the time of day to run the full backup; the default is midnight UTC time For example: exec [dbo].[sp_BackupAllFull_Schedule] ‘d’ /* Frequency */,‘BTS’ /* Name */,‘<destination path>’ /* location of backup files */ , 0, 22 MarkAndBackUpLog exec [dbo].[sp_MarkAll] ‘BTS’ /* Log mark name */,’<destination path>’  /*location of backup files */ You must provide a destination path for the log backups. Optionally you can also add an extra parameter that tells the procedure to use local time: exec [dbo].[sp_MarkAll] ‘BTS’ /* Log mark name */,’<destination path>’  /*location of backup files */ ,1 Clear Backup History exec [dbo].[sp_DeleteBackupHistory] @DaysToKeep=7 This will clear out the instances in the MarkLog table older than 7 days.    DTA Purge and Archive (BizTalkDTADb) This job is comprised of a single step. Archive and Purge exec dtasp_BackupAndPurgeTrackingDatabase 0, --@nLiveHours tinyint, 1, --@nLiveDays tinyint = 0, 30, --@nHardDeleteDays tinyint = 0, null, --@nvcFolder nvarchar(1024) = null, null, --@nvcValidatingServer sysname = null, 0 --@fForceBackup int = 0 Any completed instance that is older than the live days plus live hours will be deleted, as will any associated data. Any data older than the HardDeleteDays will be deleted - this means that those long running orchestration instances that would otherwise never be purged will at some point have their data cleared down while allowing the instance to continue, thus preventing the DTA databse from growing indefinitely.  This should always be greater than the soft purge window. The NVC folder is the path for the backup files, if this is null the job will not run failing with the error : DTA Purge and Archive (BizTalkDTADb) Job failed SQL Server Management Studio, job activity monitor, view history The @nvcFolder parameter cannot be null. Archive and Purge step How long you choose to keep instances in the Tracking Database is really up to you. For development I have set this up as: exec dtasp_BackupAndPurgeTrackingDatabase 0, 1, 30, ’<destination path>’, null, 0 On a live server you may want to adjust these figures: exec dtasp_BackupAndPurgeTrackingDatabase 0, 15, 20, ’<destination path>’, null, 0

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  • STORED PROCEDURE working in my local test machine cannot be created in production environment.

    - by Marcos Buarque
    Hi, I have an SQL CREATE PROCEDURE statement that runs perfectly in my local SQL Server, but cannot be recreated in production environment. The error message I get in production is Msg 102, Level 15, State 1, Incorrect syntax near '='. It is a pretty big query and I don't want to annoy StackOverflow users, but I simply can't find a solution. If only you could point me out what settings I could check in the production server in order to enable running the code... I must be using some kind of syntax or something that is conflicting with some setting in production. This PROCEDURE was already registered in production before, but when I ran a DROP - CREATE PROCEDURE today, the server was able to drop the procedure, but not to recreate it. I will paste the code below. Thank you! =============== USE [Enorway] GO /****** Object: StoredProcedure [dbo].[Spel_CM_ChartsUsersTotals] Script Date: 03/17/2010 11:59:57 ******/ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE PROC [dbo].[Spel_CM_ChartsUsersTotals] @IdGroup int, @IdAssessment int, @UserId int AS SET NOCOUNT ON DECLARE @RequiredColor varchar(6) SET @RequiredColor = '3333cc' DECLARE @ManagersColor varchar(6) SET @ManagersColor = '993300' DECLARE @GroupColor varchar(6) SET @GroupColor = 'ff0000' DECLARE @SelfColor varchar(6) SET @SelfColor = '336600' DECLARE @TeamColor varchar(6) SET @TeamColor = '993399' DECLARE @intMyCounter tinyint DECLARE @intManagersPosition tinyint DECLARE @intGroupPosition tinyint DECLARE @intSelfPosition tinyint DECLARE @intTeamPosition tinyint SET @intMyCounter = 1 -- Table that will hold the subtotals... DECLARE @tblTotalsSource table ( IdCompetency int, CompetencyName nvarchar(200), FunctionRequiredLevel float, ManagersAverageAssessment float, SelfAssessment float, GroupAverageAssessment float, TeamAverageAssessment float ) INSERT INTO @tblTotalsSource ( IdCompetency, CompetencyName, FunctionRequiredLevel, ManagersAverageAssessment, SelfAssessment, GroupAverageAssessment, TeamAverageAssessment ) SELECT e.[IdCompetency], dbo.replaceAccentChar(e.[Name]) AS CompetencyName, (i.[LevelNumber]) AS FunctionRequiredLevel, ( SELECT ROUND(avg(CAST(ac.[LevelNumber] AS float)),0) FROM Spel_CM_AssessmentsData aa INNER JOIN Spel_CM_CompetenciesLevels ab ON aa.[IdCompetencyLevel] = ab.[IdCompetencyLevel] INNER JOIN Spel_CM_Levels ac ON ab.[IdLevel] = ac.[IdLevel] INNER JOIN Spel_CM_AssessmentsEvents ad ON aa.[IdAssessmentEvent] = ad.[IdAssessmentEvent] WHERE aa.[EvaluatedUserId] = @UserId AND aa.[AssessmentType] = 't' AND aa.[IdGroup] = @IdGroup AND ab.[IdCompetency] = e.[IdCompetency] AND ad.[IdAssessment] = @IdAssessment ) AS ManagersAverageAssessment, ( SELECT bc.[LevelNumber] FROM Spel_CM_AssessmentsData ba INNER JOIN Spel_CM_CompetenciesLevels bb ON ba.[IdCompetencyLevel] = bb.[IdCompetencyLevel] INNER JOIN Spel_CM_Levels bc ON bb.[IdLevel] = bc.[IdLevel] INNER JOIN Spel_CM_AssessmentsEvents bd ON ba.[IdAssessmentEvent] = bd.[IdAssessmentEvent] WHERE ba.[EvaluatedUserId] = @UserId AND ba.[AssessmentType] = 's' AND ba.[IdGroup] = @IdGroup AND bb.[IdCompetency] = e.[IdCompetency] AND bd.[IdAssessment] = @IdAssessment ) AS SelfAssessment, ( SELECT ROUND(avg(CAST(cc.[LevelNumber] AS float)),0) FROM Spel_CM_AssessmentsData ca INNER JOIN Spel_CM_CompetenciesLevels cb ON ca.[IdCompetencyLevel] = cb.[IdCompetencyLevel] INNER JOIN Spel_CM_Levels cc ON cb.[IdLevel] = cc.[IdLevel] INNER JOIN Spel_CM_AssessmentsEvents cd ON ca.[IdAssessmentEvent] = cd.[IdAssessmentEvent] WHERE ca.[EvaluatedUserId] = @UserId AND ca.[AssessmentType] = 'g' AND ca.[IdGroup] = @IdGroup AND cb.[IdCompetency] = e.[IdCompetency] AND cd.[IdAssessment] = @IdAssessment ) AS GroupAverageAssessment, ( SELECT ROUND(avg(CAST(dc.[LevelNumber] AS float)),0) FROM Spel_CM_AssessmentsData da INNER JOIN Spel_CM_CompetenciesLevels db ON da.[IdCompetencyLevel] = db.[IdCompetencyLevel] INNER JOIN Spel_CM_Levels dc ON db.[IdLevel] = dc.[IdLevel] INNER JOIN Spel_CM_AssessmentsEvents dd ON da.[IdAssessmentEvent] = dd.[IdAssessmentEvent] WHERE da.[EvaluatedUserId] = @UserId AND da.[AssessmentType] = 'm' AND da.[IdGroup] = @IdGroup AND db.[IdCompetency] = e.[IdCompetency] AND dd.[IdAssessment] = @IdAssessment ) AS TeamAverageAssessment FROM Spel_CM_AssessmentsData a INNER JOIN Spel_CM_AssessmentsEvents c ON a.[IdAssessmentEvent] = c.[IdAssessmentEvent] INNER JOIN Spel_CM_CompetenciesLevels d ON a.[IdCompetencyLevel] = d.[IdCompetencyLevel] INNER JOIN Spel_CM_Competencies e ON d.[IdCompetency] = e.[IdCompetency] INNER JOIN Spel_CM_Levels f ON d.[IdLevel] = f.[IdLevel] -- This will link with user's assigned functions INNER JOIN Spel_CM_FunctionsCompetenciesLevels g ON a.[IdFunction] = g.[IdFunction] INNER JOIN Spel_CM_CompetenciesLevels h ON g.[IdCompetencyLevel] = h.[IdCompetencyLevel] AND e.[IdCompetency] = h.[IdCompetency] INNER JOIN Spel_CM_Levels i ON h.[IdLevel] = i.[IdLevel] WHERE (NOT c.[EndDate] IS NULL) AND a.[EvaluatedUserId] = @UserId AND c.[IdAssessment] = @IdAssessment AND a.[IdGroup] = @IdGroup GROUP BY e.[IdCompetency], e.[Name], i.[LevelNumber] ORDER BY e.[Name] ASC -- This will define the position of each element (managers, group, self and team) SELECT @intManagersPosition = @intMyCounter FROM @tblTotalsSource WHERE NOT ManagersAverageAssessment IS NULL IF IsNumeric(@intManagersPosition) = 1 BEGIN SELECT @intMyCounter += 1 END SELECT @intGroupPosition = @intMyCounter FROM @tblTotalsSource WHERE NOT GroupAverageAssessment IS NULL IF IsNumeric(@intGroupPosition) = 1 BEGIN SELECT @intMyCounter += 1 END SELECT @intSelfPosition = @intMyCounter FROM @tblTotalsSource WHERE NOT SelfAssessment IS NULL IF IsNumeric(@intSelfPosition) = 1 BEGIN SELECT @intMyCounter += 1 END SELECT @intTeamPosition = @intMyCounter FROM @tblTotalsSource WHERE NOT TeamAverageAssessment IS NULL -- This will render the final table for the end user. The tabe will flatten some of the numbers to allow them to be prepared for Google Graphics. SELECT SUBSTRING( ( SELECT ( '|' + REPLACE(ma.[CompetencyName],' ','+')) FROM @tblTotalsSource ma ORDER BY ma.[CompetencyName] DESC FOR XML PATH('') ), 2, 1000) AS 'CompetenciesNames', SUBSTRING( ( SELECT ( ',' + REPLACE(ra.[FunctionRequiredLevel]*10,' ','+')) FROM @tblTotalsSource ra FOR XML PATH('') ), 2, 1000) AS 'FunctionRequiredLevel', SUBSTRING( ( SELECT ( ',' + CAST(na.[ManagersAverageAssessment]*10 AS nvarchar(10))) FROM @tblTotalsSource na FOR XML PATH('') ), 2, 1000) AS 'ManagersAverageAssessment', SUBSTRING( ( SELECT ( ',' + CAST(oa.[GroupAverageAssessment]*10 AS nvarchar(10))) FROM @tblTotalsSource oa FOR XML PATH('') ), 2, 1000) AS 'GroupAverageAssessment', SUBSTRING( ( SELECT ( ',' + CAST(pa.[SelfAssessment]*10 AS nvarchar(10))) FROM @tblTotalsSource pa FOR XML PATH('') ), 2, 1000) AS 'SelfAssessment', SUBSTRING( ( SELECT ( ',' + CAST(qa.[TeamAverageAssessment]*10 AS nvarchar(10))) FROM @tblTotalsSource qa FOR XML PATH('') ), 2, 1000) AS 'TeamAverageAssessment', SUBSTRING( ( SELECT ( '|t++' + CAST([FunctionRequiredLevel] AS varchar(10)) + ',' + @RequiredColor + ',0,' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',9') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'FunctionRequiredAverageLabel', SUBSTRING( ( SELECT ( '|t++' + CAST([ManagersAverageAssessment] AS varchar(10)) + ',' + @ManagersColor + ',' + CAST(@intManagersPosition AS varchar(2)) + ',' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',9') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'ManagersLabel', SUBSTRING( ( SELECT ( '|t++' + CAST([GroupAverageAssessment] AS varchar(10)) + ',' + @GroupColor + ',' + CAST(@intGroupPosition AS varchar(2)) + ',' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',9') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'GroupLabel', SUBSTRING( ( SELECT ( '|t++' + CAST([SelfAssessment] AS varchar(10)) + ',' + @SelfColor + ',' + CAST(@intSelfPosition AS varchar(2)) + ',' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',9') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'SelfLabel', SUBSTRING( ( SELECT ( '|t++' + CAST([TeamAverageAssessment] AS varchar(10)) + ',' + @TeamColor + ',' + CAST(@intTeamPosition AS varchar(2)) + ',' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',10') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'TeamLabel', (Count(src.[IdCompetency]) * 30) + 100 AS 'ControlHeight' FROM @tblTotalsSource src SET NOCOUNT OFF GO

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