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  • C release dynamically allocated memory

    - by user1152463
    I have defined function, which returns multidimensional array. allocation for rows arr = (char **)malloc(size); allocation for columns (in loop) arr[i] = (char *)malloc(v); and returning type is char** Everything works fine, except freeing the memory. If I call free(arr[i]) and/or free(arr) on array returned by function, it crashes. Thanks for help EDIT:: allocating fuction pole = malloc(zaznamov); char ulica[52], t[52], datum[10]; float dan; int i = 0, v; *max = 0; while (!is_eof(f)) { get_record(t, ulica, &dan, datum, f); v = strlen(ulica) - 1; pole[i] = malloc(v); strcpy(pole[i], ulica); pole[i][v] = '\0'; if (v > *max) { *max = v; } i++; } return pole;` part of main where i am calling function pole = function(); releasing memory int i; for (i = 0; i < zaznamov; i++) { free(pole[i]); pole[i] = NULL; } free(pole); pole = NULL;

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