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  • RPM Spec How to specify in package so that previous RPM is removed

    - by user123819
    Question: What do I put in the foo.spec file so that the rpm's will remove the previous rpm before installing? Description: I have created a spec file that creates rpm's for a few packages that use the same source and provide the same service, each with a slightly different configuration. E.g. they each provide the same "capability" Here's an example of the essentials that my .spec file looks like: %define version 1234 %define name foo %define release 1 %define pkgname %{name}-%{version}-%{release} Name: %{name} Version: %{version} Release: %{release} Provides: %{name} %package one Summary: Summary for foo-one Group: %{group} Obsoletes: %{name} <= %{version} Provides: %{name} = %{version} %description one Blah blah blah %package two Summary: Summary for foo-two Group: %{group} Obsoletes: %{name} <= %{version} Provides: %{name} = %{version} %description two Blah blah blah # %prep, %install, %build and %clean are pretty simple # and omitted here for brevity sake %files one %defattr(-,root,root,-) %{_prefix}/%{pkgname} %files two %defattr(-,root,root,-) %{_prefix}/%{pkgname} When I install the first one, it installs ok. I then remove the first one, and then install the second one, that works fine too. I then install the first one, followed immediately by installing the second one, and they both install, one over the other, but, I was expecting that the second one would be removed before installing the second. Example session: # rpmbuild foo and copy rpms to yum repo $ yum install foo-one ... $ yum list installed|grep foo foo-one.noarch 1234-1 @myrepo $ yum install foo-two ...[Should say that it is removing foo-one, but does not]... $ yum list installed|grep foo foo-one.noarch 1234-1 @myrepo foo-two.noarch 1234-1 @myrepo $ rpm -q --provides foo-one foo = 1234 foo-one = 1234-1 $ rpm -q --provides foo-two foo = 1234 foo-two = 1234-1 What do I put in the foo.spec file so that the rpm's will remove the previous rpm before installing? Thank you, .dave.

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