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  • Use of Shl in assembly

    - by user3097712
    I have the following piece of lines and I do not understand that. Hope that someone can help me: ..... MOV EAX, DWORD PTR SS:[EBP-0x4] SHL EAX, 0x2 ADD EAX, DWORD PTR SS:[EBP-0x8] PUSH EAX .... Normally, it helps me to translate that into C language. But somehow I cant find a way to do it in that case. So, I only know that in the second line with SHL the register is multiplied by 4. And that the DWORD PTR SS:[EBP-0x4] looks like an array representation but i am not sure. I also find the following link x86 Assembler: shl and other instructions But I dont understand the answer there. So my question would be: What it is going on there? Thx...

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