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  • Using selection sort in java to sort floats

    - by user334046
    Hey, I need to sort an array list of class house by a float field in a certain range. This is my code for the selection sort: public ArrayList<House> sortPrice(ArrayList<House> x,float y, float z){ ArrayList<House> xcopy = new ArrayList<House>(); for(int i = 0; i<x.size(); i++){ if(x.get(i).myPriceIsLessThanOrEqualTo(z) && x.get(i).myPriceIsGreaterThanOrEqualTo(y)){ xcopy.add(x.get(i)); } } ArrayList<House> price= new ArrayList<House>(); while(xcopy.size()>0){ House min = xcopy.get(0); for(int i = 1; i < xcopy.size();i++){ House current = xcopy.get(i); if (current.myPriceIsGreaterThanOrEqualTo(min.getPrice())){ min = current; } } price.add(min); xcopy.remove(min); } return price; } Here is what the house class looks like: public class House { private int numBedRs; private int sqft; private float numBathRs; private float price; private static int idNumOfMostRecentHouse = 0; private int id; public House(int bed,int ft, float bath, float price){ sqft = ft; numBathRs = bath; numBedRs = bed; this.price = price; idNumOfMostRecentHouse++; id = idNumOfMostRecentHouse; } public boolean myPriceIsLessThanOrEqualTo(float y){ if(Math.abs(price - y)<0.000001){ return true; } return false; } public boolean myPriceIsGreaterThanOrEqualTo(float b){ if(Math.abs(b-price)>0.0000001){ return true; } return false; } When i call looking for houses in range 260000.50 to 300000 I only get houses that are at the top of the range even though I have a lower value at 270000. Can someone help?

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