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Search found 38 results on 2 pages for 'user342391'.

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  • Embedding a flash object old SWF markup? Will this work??

    - by user342391
    I am embedding a flash object into my site and when I do I get a message from dreamweaver saying "This page contains some swf objects that may not work correctly in the most recent versions of Internet Explorer. Dreamweaver cannot convert them to the new SWF markups please delete each of them and insert them again" I am not aware of any new SWF markups but here is my code to check maybe I am doing something wrong: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> </head> <body> <object classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" codebase="http://download.macromedia.com/pub/shockwave/cabs/flash/swflash.cab#version=9,0,28,0" width="350" height="140" title="Flash Audio Recorder"> <param name="movie" value="AudioRecorder.swf" /> <param name="allowScriptAccess" value="sameDomain" /> <param name="quality" value="high" /> <param name="FlashVars" value="userid=2&settings=myXML/settings.xml" /> <embed src="AudioRecorder.swf" FlashVars="userid=2&settings=myXML/settings.xml" allowScriptAccess="sameDomain" quality="high" pluginspage="http://www.adobe.com/shockwave/download/download.cgi?P1_Prod_Version=ShockwaveFlash" type="application/x-shockwave-flash" width="350" height="140"></embed> </object> </body> </html>

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  • Jquery onclick change value

    - by user342391
    I have some jquery tabs on my page the code for them is: //tabs options $("#tabs").tabs({ collapsible: true, selected: -1 }); I want to create a button that will toggle the above option 'selected: -1' I need it to change the value of 'selected' to '0' then back to '-1' How would I do this? <a href="#">Toggle View</a>

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  • PHP Get variable to equal value of switch

    - by user342391
    I am trying to get a variable on my page to equal the result of a switch I have. This is the code: $payment_method = switch ($cardtype) { case "visa" : echo "VSA"; break; case "mastercard" : echo "MSC"; break; case "maestro" : echo "MAE"; break; case "amex" : echo "AMX" ; break; default : echo "Please specify a payment method!"; break; }; How can I get $payment_method to equal the result of this???? So far I recieve an error: Parse error: syntax error, unexpected T_SWITCH in /var/www/account/credits/moneybookers/process.php on line 65

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  • PHP echo if post equals, help

    - by user342391
    I am trying to echo the action for my form if a post equals 'paypal' This is what I have: <?php if $_POST['method'] == 'paypal' echo 'action="paypal/process.php"' else echo 'action="moneybookers/process.php" '?> Do i need to print the variable before I do this? what am I doing wrong? I get this error: Parse error: syntax error, unexpected T_VARIABLE, expecting '(' in /var/www/account/credits/credit_amount.php on line 27

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  • How to simplify my country select menu PHP/mysql

    - by user342391
    I have a select menu that displays countries. It looks at the DB and judging by the value in the db shows the option as selected. Is there a simpler way off doing this than: if ($country == 'AG') {echo '<option value="AG" selected="selected">Antigua</option>';} else {echo '<option value="AG">Antigua</option>';}; if ($country == 'AR') {echo '<option value="AR" selected="selected">Argentina</option>';} else {echo '<option value="AR">Argentina</option>';}; if ($country == 'AM') {echo '<option value="AM" selected="selected">Armenia</option>';} else {echo '<option value="AM">Armenia</option>';}; if ($country == 'AW') {echo '<option value="AW" selected="selected">Aruba</option>';} else {echo '<option value="AW">Aruba</option>';}; if ($country == 'AU') {echo '<option value="AU" selected="selected">Australia</option>';} else {echo '<option value="AU">Australia</option >';}; if ($country == 'AT') {echo '<option value="AT" selected="selected">Austria</option>';} else {echo '<option value="AT">Austria</option>';}; if ($country == 'AZ') {echo '<option value="AZ" selected="selected">Azerbaijan</option>';} else {echo '<option value="AZ">Azerbaijan</option>';}; if ($country == 'BS') {echo '<option value="BS" selected="selected">Bahamas</option>';} else {echo '<option value="BS">Bahamas</option>';}; if ($country == 'BH') {echo '<option value="BH" selected="selected">Bahrain</option>';} else {echo '<option value="BH">Bahrain</option>';}; There are a lot of countries and doing this would be madness wouldn't it????

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  • Simplifying Jquery code HELP!

    - by user342391
    I am trying to load two modal dialog boxes with Jquery. Both of them load separate pages using ajax. The only problem is that only one of them works. I think I need to simplify my code but am unsure how. <script type="text/javascript"> $(document).ready(function(){ var dialogOpts = { modal: true, bgiframe: true, autoOpen: false, height: 400, width: 550, draggable: true, resizeable: true, title: "Your campaign rates", }; $("#ratesbox").dialog(dialogOpts); //end dialog $('#ratesbutton').click( function() { $("#ratesbox").load("rate_sheet/index.php", [], function(){ $("#ratesbox").dialog("open"); } ); return false; } ); }); </script> <script type="text/javascript"> $(document).ready(function(){ var dialogOptsPass = { modal: true, bgiframe: true, autoOpen: false, height: 400, width: 550, draggable: true, resizeable: true, title: "Change your pasword", }; $("#passwordbox").dialog(dialogOptsPass); //end dialog $('#passwordbutton').click( function() { $("#passwordbox").load("change_password/index.php", [], function(){ $("#passwordbox").dialog("open"); } ); return false; } ); }); </script> Is it posible to combine the two scripts????

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  • PHP Session timeout

    - by user342391
    I am creating a session when a user logs in like so: $_SESSION['id'] = $id; How can I specify a timeout on that session of X minutes and then have it perform a function or a page redirect once it has reached X minutes??

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  • Jquery tabs enable tab?

    - by user342391
    I am trying to enable a disabled tab in Jquery but it doesn't work I have my tabs: <!--Jquery AJAX Tabs Start--> <div id="signuptabs"> <ul> <li><a href="type.php"><span>Number type</span></a></li> <li><a href="ber.php"><span>Choose Number</span></a></li> <li><a href="ces.php"><span>Devices</span></a></li> <li><a href="ups.php"><span>Ring Groups</span></a></li> <li><a href="t.php"><span>IVR Text</span></a></li> <li><a href="nu.php"><span>IVR Menu</span></a></li> <li><a href="nfo.php"><span>Billing Information</span></a></li> </ul> </div> <!--Jquery AJAX Tabs End--> Then I have my Javascript: $(document).ready(function() { $("#signuptabs").tabs({ disabled: [1, 2, 3, 4, 5, 6, 7] }); //number type button $('#target').click(function() { $('#signuptabs').enableTab(2); // enables third tab }); }); I have a button with an ID 'target' that when clicked is supposed to enable the (2) tab. The tabs show as disabled but will not enable. what is wrong??

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  • Play wav files on website usign swf

    - by user342391
    How can I play .wav files on my website using flash .swf there are many plugins for mp3s but nothing that does .wav. It is essential that i use .wav not .mp3 and converting it is not an option. I do not want to use the standard embed that uses the quicktime plugin. Can anyone help?

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  • Jquery dialog confirmation, confirm form post

    - by user342391
    I am trying to display jquery's dialog confirmation before submitting a form. But I can't get it to popup up only when the form is submitted this is the code: $(function remove() { $("#dialog-confirm").dialog({ resizable: false, height:200, modal: true, buttons: { 'Delete campaign': function() { return true ; $(this).dialog('close'); }, Cancel: function() { return false; $(this).dialog('close'); } } }); }); Dialog confirmation content <div id="dialog-confirm" title="Delete ?" style="display:none;"> <p><span class="ui-icon ui-icon-alert" style="float:left; margin:0 7px 20px 0;"></span>This will be permanently deleted and cannot be recovered. Are you sure?</p> </div> Form submit content <form style="display: inline;" action="remove.php" method="post"" onsubmit="return remove()">

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  • Jquuery Tabs Cookiess

    - by user342391
    I am trying to use the Jquery cookie plugin to remember the last selected tab. I can't seem to get it to work.Do i need anything else apart from the jquery lib and cookie plugin??? This is the code: <script type="text/javascript"> $(document).ready(function() { $("#tabletabscampaigns > ul").tabs({ remote: true, cache: true }); $("#tabletabscampaigns").tabs({selected: 0, cookie: { expires: 30} }); }); </script> <div id="tabletabscampaigns" style="float:left; width:895px; margin-top:20px;">

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  • Echo items with value of three

    - by user342391
    I need to echo all items in my row that have the value of three. If a field has the value of three I then need to echo the 'name' and 'description' on that row. This is what I have so far $result = mysql_query($query1) or die(mysql_error()); while ($row = mysql_fetch_array($result)) { echo $row['status']; } I need to write 'if $row[`status´ == 3 echo 'description' 'name' else echo 'no current staus' I hope I made some sense because I am seriously confused

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  • Need help simplifying my php table

    - by user342391
    I am relatively new to php and have a feeling that I am going the long way round when displaying data from mysql. I have a table a I want to show a few fields from my database. How would I achieve this without having to echo every bit of the table??? Here is the code: <?php $query1 = mysql_send("SELECT firstname, lastname, email, user, country FROM customers WHERE id='".$_COOKIE['custid']."'"); while ($row = mysql_fetch_array($query1)) { echo ' <table id="account_table" style="width:550px; border:none; "> <tr> <td width="155">Contact Name</td>'; echo '<td width="335">'; echo $row['firstname'] ; echo '&nbsp;'; echo $row['lastname']; echo '</td> </tr> <tr> <td>Email Address</td> <td>'; echo $row['email']; echo ' </td> </tr> <tr> <td>Username</td> <td>' ; echo $row['user']; echo '</td> </tr> <tr> <td>Country</td> <td>'; echo $row['country']; echo '</td> </tr> <tr> <td>Time Zone</td> <td>GMT+1</td> </tr> <tr> <td>Activated</td> <td>16 Dec 2009</td> </tr> </table>'; } ?>

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  • Show all data in column

    - by user342391
    I am trying to show all of the data in the 'status' column of my table but am having troubles. What am I doing wrong: <?php $query1 = "SELECT id, status FROM alerts WHERE customerid='".$_SESSION['customerid']."' ORDER BY id LIMIT $start, $limit "; $result = mysql_query($query1); while ($row = mysql_fetch_array($result)) { echo $row['status'] ; } ?>

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  • PHP Show all data in column

    - by user342391
    I am trying to show all of the data in the 'status' column of my table but am having troubles. What am I doing wrong: <?php $query1 = "SELECT id, status FROM alerts WHERE customerid='".$_SESSION['customerid']."' ORDER BY id LIMIT $start, $limit "; $result = mysql_query($query1); while ($row = mysql_fetch_array($result)) { echo $row['status'] ; } ?>

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  • PHP echo text if variable is blank

    - by user342391
    I am trying to echo €00.00 if my variable $amount equals zero I have done something wrong can you help?? Code while ($row9 = mysql_fetch_array($result9)) { $amount = $row9['amount']; } //$amount = $amount / 60; //$amount = round($amount, 2); if $amount == 0 echo "<b>Balance: &#8364;00.00</b>"; else echo "<b>Balance: $$amount</b>";

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  • Jquery click function does not load ajax tabs

    - by user342391
    I have some tabs that load ajax content. When I click on the tabs it loads the ajax content perfectly no issues works exactly like it does in the Jqueryui demos. But when I try and change tab using an onclick function it opens the tab but doesn't do the ajax. Is this a known issue can it be done?? Do ajax tabs rely on the user clicking the href to know what to load. This is the code: $(".step2next").click(function() $('#signuptabs').tabs("select" , 1));

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  • How can I show a div with Jquery hover and then hide?

    - by user342391
    I am trying to show a div when the cursor hovers over and image and hide the div when It is not hovered over the image how is this done?? So far I have a basic show: <script type="text/javascript"> $(document).ready(function(){ $(".plans").hover(function() { $("#planssubnav").show("slow"); } ); }); </script>

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  • php cookies block access to directories

    - by user342391
    I have a mysql database of users that can login to my site and view content. I would like to block a couple of directories from certain users. What is the best way to do this. Currently when a user logs in a cookie is created with their customer id and the customer is is used to display their content. How would I block entire directories from my users???

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  • php mysql timestamp

    - by user342391
    I need to track the date and time a user was created in my mysql database. I have column called 'created' and the data type as TIMESTAMP. The problem is that when a user changes their password or other information the TIMESTAMP value changes. How can I set this to not change????

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  • PHP show image if post result equals

    - by user342391
    I have a form that posts to a page. I want to display an image if the value of the item posted equals "paypal". I need to write something that says; if $_POST['method'] equals "paypal" then show paypal.gif if $_POST['method'] equals "mastercard" then show mastercard.gif I hope I made a bit of sense, new to php trying to learn the best I can

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  • How do I show a hidden DIV with Jquery when a user clicks a radio box?

    - by user342391
    I am having difficulty showing a hidden div when a user selects a radio box. This is my code: The Jquery <script> $(document).ready(function () { $(".paypalmethod").click(function() { $(".paypalinfo").show('slow'); }); </script> The html <input name="method" type="radio" value="paypal" class="paypalmethod"/><img src="/images/paymentlogos/PayPal.png" /> <div class="paypalinfo" style="display:none">Paypal the safe and easy way to pay. Paypal accepts all major credit cards.</div>

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  • php troubles with coding variables

    - by user342391
    I am trying to echo certain values if the variable $cardtype == $paymentmethod = if( $cardtype == 'visa' ) echo 'VSA'; elseif ( $cardtype == 'mastercard' ) echo 'MSC'; elseif ( $cardtype == 'mastercard' ) echo 'MSC'; elseif ( $cardtype == 'maestro' ) echo 'MAE'; elseif ( $cardtype== 'amex' ) echo 'AMX'; How would I do this???

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  • How to open form action in Jquery Dialog

    - by user342391
    I have a form: <form style="display: inline;" action="/player.php" method="post"> <input type="hidden" name="recname" value="'.$row['name'].'"> <input type="hidden" name="recordingdesc" value="'.$row['description'].'"> <input type="hidden" name="reclink" value="$_SESSION['customerid'].'-'.$row['timestamp'].'.wav"> <button type="submit" class="tooltip table-button ui-state-default ui-corner-all" title=" rec"><span class="ui-icon ui-icon-volume-on"></span></button> </form> and i want player.php to open in a modal dialog and be able to display the post information how can this be done.

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