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  • Google Search API - Only returning 4 results

    - by user353829
    After much experimenting and googling, the following Python code successfully calls Google's Search APi - but only returns 4 results: after reading the Google Search API docs, I thought the 'start=' would return additional results: but this not happen. Can anyone give pointers? Thanks. Python code: /usr/bin/python import urllib import simplejson query = urllib.urlencode({'q' : 'site:example.com'}) url = 'http://ajax.googleapis.com/ajax/services/search/web?v=1.0&%s&start=50' \ % (query) search_results = urllib.urlopen(url) json = simplejson.loads(search_results.read()) results = json['responseData']['results'] for i in results: print i['title'] + ": " + i['url']

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  • Calling Google's Custom Search API via Python

    - by user353829
    I am writing in Python a module that will query Google's Custom Search API and return all listings of domain 'example.com' I Have been reading instructions at https://code.google.com/apis/customsearch/v1/getting_started.html and am a little stumped at the moment. Are my assumptions listed below correct? For example, to search for results that has 'example.com' in the URL, the query is: *'https://www.googleapis.com/customsearch/v1?key=my_key&cx=017576662512468239146:omuauf_lfve&q=site:example.com*' *key=my_key*: value of key given by google cx=017576662512468239146: name of the search engine (google)? *omuauf_lfve*: I have no idea what this is q=site:example.com: This should return all results with 'example.com'; e.g. www.a.example.com, b.example.com, example .com

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