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• Cannot find FIS partition 'initramfs'......... need help!!!

  - by vikramtheone

  Hi Guys, I have a Ubuntu 9.04 Linux running on Freescale's i.MX515(ARM Cortex based) board with me. There were about 250 updates pending and I did that today, well some of the updates failed because of the infamous errors: E: dpkg was interrupted, you must manually run 'sudo dpkg --configure -a' to correct the problem. E: Couldn't rebuild package cache E: dpkg was interrupted, you must manually run 'sudo dpkg --configure -a' to correct the problem. So, when I do the 'sudo dpkg --configure -a' I get new errors related to FIS partition: Cannot find FIS partition 'initramfs' User postinst hook script [/usr/sbin/flash-kernel] exited with value 1 dpkg: error processing linux-image-2.6.28-18-imx51 (--configure): subprocess post-installation script returned error exit status 1 dpkg: dependency problems prevent configuration of linux-image-imx51: linux-image-imx51 depends on linux-image-2.6.28-18-imx51; however: Package linux-image-2.6.28-18-imx51 is not configured yet. dpkg: error processing linux-image-imx51 (--configure): dependency problems - leaving unconfigured dpkg: dependency problems prevent configuration of linux-imx51: linux-imx51 depends on linux-image-imx51 (= 2.6.28.18.23); however: Package linux-image-imx51 is not configured yet. dpkg: error processing linux-imx51 (--configure): dependency problems - leaving unconfigured Processing triggers for initramfs-tools ... update-initramfs: Generating /boot/initrd.img-2.6.28-18-imx51 Cannot find FIS partition 'initramfs' dpkg: subprocess post-installation script returned error exit status 1 Whats going wrong here, need help!!! I'm a newbie. Regards Vikram

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• Problem in accessing Windows shared folder on Ubuntu using terminal

  - by vikramtheone

  Hi Guys, Description I have 2 systems with me, one running on Windows(Host) and one on Ubuntu, both on a LAN. On the Windows(Host) I develop software intended for the Linux system and because the Linux system has little external memory, my idea to overcome this is by making the project folder on the Host side a Shared Folder with full access and access it on Ubuntu over the network. To achieve this, I have installed Samba on Ubuntu, when I go to Places -> Network I can see the shared project folder and I simply mount it. A link appears on the desktop. Next, using Nautilus I open the link and I can access the contents of the shared folder. Problem Even though I mount the shared project folder, I don't see it appearing in the /media or the /mnt folder, as a result of this I don't know what path to use to access this folder, from the terminal. For example: When, I mounted my USB stick, as expected, a link for the device appears on the Desktop and I also see a folder in the media folder. So, similarly, a mounted shared folder should have appeared on the /mnt folder, too. Can anyone suggest what I should do now? There are many posts around, but no solid solution for this problem. Help!!! :) Vikram

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• VM VirtualBox, Ubuntu 9.10: USB memory stick and SD card not detected...

  - by vikramtheone

  Hello Guys, I have installed Ubuntu9.10 on VM VirtualBox, on my HP laptop. My laptop has several USB ports and also a SD card port. Unfortunately, I'm unable to access both, my pen-drive on the USB port and my 8GB SD card inserted in the SD Card port. Can anyone suggest me what I should do for my Ubuntu to detect both of them? I have installed all latest updates on Ubuntu. I'm able to use my USB mouse. Thank you Vikram

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• Image Processing: What are occlusions?

  - by vikramtheone

  Hi Guys, I'm developing an image processing project and I come across the word occlusion in many scientific papers, what do occlusions mean in the context of image processing? The dictionary is only giving a general definition. Can anyone describe them using an image as a context? Vikram

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• More GCC link time issues: undefined reference to main

  - by vikramtheone

  Hi Guys, I'm writing software for a Cortex-A8 processor and I have to write some ARM assembly code to access specific registers. I'm making use of the gnu compilers and related tool chains, these tools are installed on the processor board(Freescale i.MX515) with Ubuntu. I make a connection to it from my host PC(Windows) using WinSCP and the PuTTY terminal. As usual I started with a simple C project having main.c and functions.s. I compile the main.c using GCC, assemble the functions.s using as and link the generated object files using once again GCC, but I get strange errors during this process. An important finding - Meanwhile, I found out that my assembly code may have some issues because when I individually assemble it using the command as -o functions.o functions.s and try running the generated functions.o using ./functions.o command, the bash shell is failing to recognize this file as an executable(on pressing tab functions.o is not getting selected/PuTTY is not highlighting the file). Can anyone suggest whats happening here? Are there any specific options I have to send, to GCC during the linking process? The errors I see are strange and beyond my understanding, I don't understand to what the GCC is referring. I'm pasting here the contents of main.c, functions.s, the Makefile and the list of errors. Help, please!!! Vikram main.c #include <stdio.h> #include <stdlib.h> int main(void) { puts("!!!Hello World!!!"); /* prints !!!Hello World!!! */ return EXIT_SUCCESS; } functions.s * Main program */ .equ STACK_TOP, 0x20000800 .text .global _start .syntax unified _start: .word STACK_TOP, start .type start, function start: movs r0, #10 movs r1, #0 .end Makefile all: hello hello: main.o functions.o gcc -o main.o functions.o main.o: main.c gcc -c -mcpu=cortex-a8 main.c functions.o: functions.s as -mcpu=cortex-a8 -o functions.o functions.s Errors ubuntu@ubuntu-desktop:~/Documents/Project/Others/helloworld$ make gcc -c -mcpu=cortex-a8 main.c as -mcpu=cortex-a8 -o functions.o functions.s gcc -o main.o functions.o functions.o: In function `_start': (.text+0x0): multiple definition of `_start' /usr/lib/gcc/arm-linux-gnueabi/4.3.3/../../../crt1.o:init.c:(.text+0x0): first defined here /usr/lib/gcc/arm-linux-gnueabi/4.3.3/../../../crt1.o: In function `_start': init.c:(.text+0x30): undefined reference to `main' collect2: ld returned 1 exit status make: *** [hello] Error 1

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• How to read pixel values of a video?

  - by vikramtheone

  Hi Guys, I recently wrote C programs for image processing of BMP images, I had to read the pixel values and process them, it was very simple I followed the BMP header contents and I could get most of the information of the BMP image. Now the challenge is to process videos (Frame by Frame), how can I do it? How will I be able to read the headers of continuous streams of image frames in a video clip? Or else, is it like, for example, the mpeg format will also have universal header, upon reading which I can get the information about the entire video and after the header, all the data are only pixels. I hope I could convey. Has anyone got experience with processing videos? Any books or links to tutorials will be very helpful. Vikram

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• bmp image header doubts

  - by vikramtheone

  Hi Guys, I'm doing a project where I have to make use of the pixel information of a bmp image. So, I'm gathering the image information by reading the header information of the input .bmp image. I'm quite successful with everything but one thing bothers me, can any one here clarify it? The header information of my .bmp image is as follows (My test image is very tiny and gray scale)- BMP File header File size 1210 Offset information 1078 BMP Information header Image Header Size 40 Image Size 132 Image width 9 Image height 11 Image bits_p_p 8 So, from the .bmp header I see that the image size is 132 (bytes) but when I multiply the width and height it is only 99, how is such a thing possible? I'm confident with 132 bytes because when I subtract the Offset value with the File Size value, I get 132(1210 - 1078 = 132) and also when I manually count the number of bytes (In a HEX editor) from the point 1078 or 436h (End of the offset field), there are exactly 132 bytes of pixel information. So, why is there a disparity between the size filed and the (width x height)? My future implementations are dependent on the image width and height information and not on Image size information. So, I have to understand thoroughly whats going on here. My understanding of the header should be clearly wrong... I guess!!! Help!!! Regards Vikram My bmp structures are a as follows - typedef struct bmpfile_magic { short magic; }BMP_MAGIC_NUMBER; typedef struct bmpfile_header { uint32_t filesz; uint16_t creator1; uint16_t creator2; uint32_t bmp_offset; }BMP_FILE_HEADER; typedef struct { uint32_t header_sz; uint32_t width; uint32_t height; uint16_t nplanes; uint16_t bitspp; uint32_t compress_type; uint32_t bmp_bytesz; uint32_t hres; uint32_t vres; uint32_t ncolors; uint32_t nimpcolors; } BMP_INFO_HEADER;

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• C Programming: malloc() for a 2D array (using pointer-to-pointer)

  - by vikramtheone

  Hi Guys, yesterday I had posted a question: How should I pass a pointer to a function and allocate memory for the passed pointer from inside the called function? From the answers I got, I was able to understand what mistake I was doing. I'm facing a new problem now, can anyone help out with this? I want to dynamically allocate a 2D array, so I'm passing a Pointer-to-Pointer from my main() to another function called alloc_2D_pixels(...), where I use malloc(...) and for(...) loop to allocate memory for the 2D array. Well, after returning from the alloc_2D_pixels(...) function, the pointer-to-pointer still remains NULL, so naturally, when I try accessing or try to free(...) the Pointer-to-Pointer, the program hangs. Can anyone suggest me what mistakes I'm doing here? Help!!! Vikram SOURCE: main() { unsigned char **ptr; unsigned int rows, cols; if(alloc_2D_pixels(&ptr, rows, cols)==ERROR) // Satisfies this condition printf("Memory for the 2D array not allocated"); // NO ERROR is returned if(ptr == NULL) // ptr is NULL so no memory was allocated printf("Yes its NULL!"); // Because ptr is NULL, with any of these 3 statements below the program HANGS ptr[0][0] = 10; printf("Element: %d",ptr[0][0]); free_2D_alloc(&ptr); } signed char alloc_2D_pixels(unsigned char ***memory, unsigned int rows, unsigned int cols) { signed char status = NO_ERROR; memory = malloc(rows * sizeof(unsigned char** )); if(memory == NULL) { status = ERROR; printf("ERROR: Memory allocation failed!"); } else { int i; for(i = 0; i< cols; i++) { memory[i] = malloc(cols * sizeof(unsigned char)); if(memory[i]==NULL) { status = ERROR; printf("ERROR: Memory allocation failed!"); } } } // Inserted the statements below for debug purpose only memory[0][0] = (unsigned char)10; // I'm able to access the array from printf("\nElement %d",memory[0][0]); // here with no problems return status; } void free_2D_pixels(unsigned char ***ptr, unsigned int rows) { int i; for(i = 0; i < rows; i++) { free(ptr[i]); } free(ptr); }

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• Problem in accessing Windows shared folder on Ubuntu using terminal

  - by vikramtheone

  Hi Guys, Description I have 2 systems with me, one running on Windows(Host) and one on Ubuntu, both on a LAN. On the Windows(Host) I develop software intended for the Linux system and because the Linux system has little external memory, my idea to overcome this is by making the project folder on the Host side a Shared Folder with full access and access it on Ubuntu over the network. To achieve this, I have installed Samba on Ubuntu, when I go to Places -> Network I can see the shared project folder and I simply mount it. A link appears on the desktop. Next, using Nautilus I open the link and I can access the contents of the shared folder. Problem Even though I mount the shared project folder, I don't see it appearing in the /media or the /mnt folder, as a result of this I don't know what path to use to access this folder, from the terminal. For example: When, I mounted my USB stick, as expected, a link for the device appears on the Desktop and I also see a folder in the media folder. So, similarly, a mounted shared folder should have appeared on the /mnt folder, too. Can anyone suggest what I should do now? There are many posts around, but no solid solution for this problem. Help!!! :) Vikram

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• Webcam video stream processing.

  - by vikramtheone

  Hi Guys, I'm working with an image processing project, my final goal is to detect features on a real time video and finally track those features. I will be working with an Embedded Processor Platform called Freescale's i.MX515, it is a 32-bit media processor running on Ubuntu 9.04. Right now I'm working on the algorithms to locate the features, so, I'm using still images. When I'm satisfied with the results I will have to start using a video stream and I don't want to make use of a video file as a source stream, because then I will have to worry about video decoders then. Instead I would like to plug in a USB Wecam to the embedded platform (It has USB ports on it), directly take the frames as they are captured and send it to my application. I will take care to buy a webcam which will be supported in Linux (Device driver). But my question is will I be able to capture the incoming video stream from the webcam and send it to my application? Will I be able to configure the webcam and DMA to write the incoming frames in a particular memory location whose pointer I can simply pass to my application? (Confused!!!) I hope I could convey my doubts, can anyone guide me with what steps that I have to take to achieve all of these easily? Do you foresee any impossibility here? Help!!! Regards Vikram

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• C Preprocessor: #define in C... advice

  - by vikramtheone

  Hi Guys, I'm making a big C project and I have never come across a situation like this before so, I need your advice. What is your opinion? Is it okay to have the constants defined within conditional preprocessors like I have done below or you advise me to do this some other way? Any drawbacks if I do it this way? Regards Vikram #define NUM_OCTAVES_4 //#define NUM_OCTAVES_5 #ifdef NUM_OCTAVES_4 #define OCTAVES 4 const unsigned char borders [4] = {11, 26, 50, 98}; #elif NUM_OCTAVES_5 #define OCTAVES 5 const unsigned char borders [5] = {11, 26, 50, 98, 194}; #endif

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• C Programming: malloc() inside another function

  - by vikramtheone

  Hi Guys, I need help with malloc() inside another function. I'm passing a pointer and size to the function from my main() and I would like to allocate memory for that pointer dynamically using malloc() from inside that called function, but what I see is that.... the memory which is getting allocated is for the pointer declared withing my called function and not for the pointer which is inside the main(). How should I pass a pointer to a function and allocate memory for the passed pointer from inside the called function? Can anyone throw light on this? Help!!! Vikram I have written the following code and I get the output as shown below SOURCE: main() { unsigned char *input_image; unsigned int bmp_image_size = 262144; if(alloc_pixels(input_image, bmp_image_size)==NULL) printf("\nPoint2: Memory allocated: %d bytes",_msize(input_image)); else printf("\nPoint3: Memory not allocated"); } signed char alloc_pixels(unsigned char *ptr, unsigned int size) { signed char status = NO_ERROR; ptr = NULL; ptr = (unsigned char*)malloc(size); if(ptr== NULL) { status = ERROR; free(ptr); printf("\nERROR: Memory allocation did not complete successfully!"); } printf("\nPoint1: Memory allocated: %d bytes",_msize(ptr)); return status; } PROGRAM OUTPUT: Point1: Memory allocated ptr: 262144 bytes Point2: Memory allocated input_image: 0 bytes

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• How to declare a 2D array of 2D array pointers and access them?

  - by vikramtheone

  Hi Guys, How can I declare an 2D array of 2D Pointers? And later access the individual array elements of the 2D arrays. Is my approach correct? void alloc_2D(int ***memory, unsigned int rows, unsigned int cols); int main() { int i, j; int **ptr; int **array[10][10]; for(i=0;i<10;i++) { for(j=0;j<10;j++) { alloc_2D(&ptr, 10, 10); array[i][j] = ptr; } } //After I do this, how can I access the 10 individual 2D arrays? return 0; } void alloc_2D(int ***memory, unsigned int rows, unsigned int cols) { int **ptr; *memory = NULL; ptr = malloc(rows * sizeof(int*)); if(ptr == NULL) { printf("\nERROR: Memory allocation failed!"); } else { int i; for(i = 0; i< rows; i++) { ptr[i] = malloc(cols * sizeof(float)); if(ptr[i]==NULL) { printf("\nERROR: Memory allocation failed!"); } } } *memory = ptr; }

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• How to declare array of 2D array pointers and access them?

  - by vikramtheone

  Hi Guys, How can I declare an 2D array of 2D Pointers? And later access the individual array elements of the 2D arrays. Is my approach correct? main() { int i, j; int **array[10][10]; int **ptr = NULL; for(i=0;i<10;i++) { for(j=0j<10;j++) { alloc_2D(&ptr, 10, 10); array[i][j] = ptr; } } //After I do this, how can I access the individual 2D array //and then the individual elements of the 2D arrays? } void alloc_2D(float ***memory, unsigned int rows, unsigned int cols) { float **ptr; *memory = NULL; ptr = malloc(rows * sizeof(float*)); if(ptr == NULL) { status = ERROR; printf("\nERROR: Memory allocation failed!"); } else { int i; for(i = 0; i< rows; i++) { ptr[i] = malloc(cols * sizeof(float)); if(ptr[i]==NULL) { status = ERROR; printf("\nERROR: Memory allocation failed!"); } } } *memory = ptr; }

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