I have to do a demo of an application, the application has a server.jar and client.jar. Both have command line arguments and are executable. I need to launch two instances of server.jar and two instances of client.jar.
I thought that using a batch file was the way to go, but, the batch file executes the first command (i.e. server.bat [argument1] [argument2]) and does not do anything else unless I close the first instance, in which case it then runs the 2nd command. And also the I do not want a blank console window to open (or be minimized)
What I really need is a batch script that will just launch these apps without any console windows and launch all instances that I need.
Thanks in Advance!
EDIT:
javaw:
works if I type the command
into the console window individually.
If I put the same in the batch file,
it will behave as before. Console
window opens, one instance starts
(whichever was first) and it does not
proceed further unless I close the
application in which case it runs the 2nd command. I want it to run all commands silently
SOLUTION:
Found the solution, below is the contents of my batch file
@echo off
start /B server.jar [arg1] [arg2]
start /B server.jar [arg3] [arg4]
@echo on
this opens, runs all the commands and closes the window, does not wait for the command to finish.
