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  • Check if date is allowed weekday in php?

    - by moogeek
    Hello! I'm stuck with a problem how to check if a specific date is within allowed weekdays array in php. For example, function dateIsAllowedWeekday($_date,$_allowed) { if ((isDate($_date)) && (($_allowed!="null") && ($_allowed!=null))){ $allowed_weekdays=json_decode($_allowed); $weekdays=array(); foreach($allowed_weekdays as $wd){ $weekday=date("l",date("w",strtotime($wd))); array_push($weekdays,$weekday); } if(in_array(date("l",strtotime($_date)),$weekdays)){return TRUE;} else {return FALSE;} } else {return FALSE;} } ///////////////////////////// $date="21.05.2010"; $wd="[0,1,2]"; if(dateIsAllowedWeekday($date,$wd)){echo "$date is within $wd weekday values!";} else{echo "$date isn't within $wd weekday values!"} I have input dates formatted as "d.m.Y" and an array returned from database with weekday numbers (formatted as 'Numeric representation of the day of the week') like [0,1,2] - (Sunday,Monday,Tuesday). The returned string from database can be "null", so i check it too. Them, the isDate function checks whether date is a date and it is ok. I want to check if my date, for example 21.05.2010 is an allowed weekday in this array. My function always returns TRUE and somehow weekday is always 'Thursday' and i don't know why... Is there any other ways to check this or what can be my error in the code above? thx

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  • SQL SERVER – Find Weekend and Weekdays from Datetime in SQL Server 2012

    - by pinaldave
    Yesterday we had very first SQL Bangalore User Group meeting and I was asked following question right after the session. “How do we know if today is a weekend or weekday using SQL Server Functions?” Well, I assume most of us are using SQL Server 2012 so I will suggest following solution. I am using SQL Server 2012′s CHOOSE function. It is SELECT GETDATE() Today, DATENAME(dw, GETDATE()) DayofWeek, CHOOSE(DATEPART(dw, GETDATE()), 'WEEKEND','Weekday', 'Weekday','Weekday','Weekday','Weekday','WEEKEND') WorkDay GO You can use the choose function on table as well. Here is the quick example of the same. USE AdventureWorks2012 GO SELECT A.ModifiedDate, DATENAME(dw, A.ModifiedDate) DayofWeek, CHOOSE(DATEPART(dw, A.ModifiedDate), 'WEEKEND','Weekday', 'Weekday','Weekday','Weekday','Weekday','WEEKEND') WorkDay FROM [Person].[Address] A GO If you are using an earlier version of the SQL Server you can use a CASE statement instead of CHOOSE function. Please read my earlier article which discusses CHOOSE function and CASE statements. Logical Function – CHOOSE() – A Quick Introduction Reference:  Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL DateTime, SQL Function, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Ubuntu 13.10 change first weekday to Monday in calendar applet

    - by wonderingapple
    Before the update (I was using 13.04), editing: sudo gedit /etc/default/locale so that LC_TIME="en_GB.UTF-8" does the job. However in 13.10, this does not work anymore. I've tried editing: sudo gedit /usr/share/i18n/locales/en_AU sudo gedit /usr/share/i18n/locales/en_GB sudo gedit /usr/share/i18n/locales/en_US so that first_weekday 2 in each of the files, but this also does not work. As a reference, when I run locale, the output is LANG=en_AU.UTF-8 LANGUAGE=en_AU:en LC_CTYPE="en_AU.UTF-8" LC_NUMERIC=en_AU.UTF-8 LC_TIME=en_AU.UTF-8 LC_COLLATE="en_AU.UTF-8" LC_MONETARY=en_AU.UTF-8 LC_MESSAGES="en_AU.UTF-8" LC_PAPER=en_AU.UTF-8 LC_NAME=en_AU.UTF-8 LC_ADDRESS=en_AU.UTF-8 LC_TELEPHONE=en_AU.UTF-8 LC_MEASUREMENT=en_AU.UTF-8 LC_IDENTIFICATION=en_AU.UTF-8 LC_ALL= Please help.

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  • windows weekday and day of month don't match - calendar fail

    - by steini
    This computer came to my shop for just a simple Windows tuneup, so after doing all my tweaks, I noticed I was getting an error when trying to synchronize with the time server. It wasn't until I was about to give up that I noticed in the calendar that it's one weekday late. Here's a screenshot. As you can see, the day today, Friday - January 7th is a Thursday in the calendar. How is this possible?

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  • Display weekday in textbox or label using date from textbox

    - by Niels Schultz
    I have a textbox with calendar extender and a label <label for="<%= tbxFrom.ClientID %>"> From</label> <asp:Label ID="lblWeekDayFrom" runat="server"></asp:Label> <asp:TextBox ID="tbxFrom" runat="server" CssClass="Calendar"></asp:TextBox> <cc1:CalendarExtender ID="extTbxFrom" runat="server" TargetControlID="tbxStartTag"> </cc1:CalendarExtender> and now I would like to show the weekday of the currently selected date, either using a formatting inside the textbox like Th 05/20/2010 or showing the weekday as string using the label on the left side of the texbox (lblWeekDayFrom). There is a calendarExtender to select the date, but I would also like to be able to have the users enter the date manually. I tried to use JQuery to capture changes, but the label is not showing anything, and it triggers the RequiredFieldValidator on every initial page load. $(document).ready(function() { $('#<%= tbxFrom.ClientID %>').change(updateDate($('#<%= tbxFrom.ClientID %>').val())) } ); function updateDate(date) { $('#<%= lblWeekDayFrom.ClientID %>').val(date); }

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  • MySql Check if NOW() falls within a weekday/time range

    - by Niall
    I have a table as follows: CREATE TABLE `zonetimes` ( `id` int(11) unsigned NOT NULL AUTO_INCREMENT, `zone_id` int(10) unsigned NOT NULL, `active_from_day` tinyint(1) unsigned NOT NULL DEFAULT '2', `active_to_day` tinyint(1) unsigned NOT NULL DEFAULT '2', `active_from` time NOT NULL, `active_to` time NOT NULL PRIMARY KEY (`id`) ) ENGINE=MyISAM ; So, a user could add a time entry starting on a particular day and time and ending on a particular day and time, eg: Between Monday 08:00 and Friday 18:00 or Between Thursday 15:00 and Tuesday 15:00 (Note the crossover at the end of the week). I need to query this data and determine if a zone is currently active (NOW(), DAYOFWEEK() etc)... This is turning out to be quite tricky. If I didn't have overlaps, eg: from 'Wednesday 8pm to Tuesday 4am' or from 'Thursday 4pm to Tuesday 4pm' this would be easy with BETWEEN. Also, need to allow a user to add for the entire week, eg: Monday 8am - Monday 8am (This should be easy enough, eg: where (active_from_day=active_to_day AND active_from=active_to) OR .. Any ideas? Note: I found a similar question here Timespan - Check for weekday and time of day in mysql but it didn't get an answer. One of the suggestions was to store each day as a separate row. I would much rather store one time span for multiple days though.

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  • SFINAE failing with enum template parameter

    - by zeroes00
    Can someone explain the following behaviour (I'm using Visual Studio 2010). header: #pragma once #include <boost\utility\enable_if.hpp> using boost::enable_if_c; enum WeekDay {MONDAY, TUESDAY, WEDNESDAY, THURSDAY, FRIDAY, SATURDAY, SUNDAY}; template<WeekDay DAY> typename enable_if_c< DAY==SUNDAY, bool >::type goToWork() {return false;} template<WeekDay DAY> typename enable_if_c< DAY!=SUNDAY, bool >::type goToWork() {return true;} source: bool b = goToWork<MONDAY>(); compiler this gives error C2770: invalid explicit template argument(s) for 'enable_if_c<DAY!=6,bool>::type goToWork(void)' and error C2770: invalid explicit template argument(s) for 'enable_if_c<DAY==6,bool>::type goToWork(void)' But if I change the function template parameter from the enum type WeekDay to int, it compiles fine: template<int DAY> typename enable_if_c< DAY==SUNDAY, bool >::type goToWork() {return false;} template<int DAY> typename enable_if_c< DAY!=SUNDAY, bool >::type goToWork() {return true;} Also the normal function template specialization works fine, no surprises there: template<WeekDay DAY> bool goToWork() {return true;} template<> bool goToWork<SUNDAY>() {return false;} To make things even weirder, if I change the source file to use any other WeekDay than MONDAY or TUESDAY, i.e. bool b = goToWork<THURSDAY>(); the error changes to this: error C2440: 'specialization' : cannot convert from 'int' to 'const WeekDay' Conversion to enumeration type requires an explicit cast (static_cast, C-style cast or function-style cast)

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  • Jquery Drag-Drop (Getting element being dropped into)

    - by Ryan
    I am trying to detect which cell an object is being dropped into. <table> <tr> <td class="weekday">Sun</td> <td class="weekday">Mon</td> <td class="weekday">Tue</td> <td class="weekday">Wed</td> <td class="weekday">Thu</td> <td class="weekday">Fri</td> <td class="weekday">Sat</td> </tr> <tr> <td class="droppable">&nbsp;</td> <td class="droppable">&nbsp;</td> <td class="droppable">&nbsp;</td> <td class="droppable">&nbsp;</td> <td class="droppable">&nbsp;</td> <td class="droppable">&nbsp;</td> <td class="droppable">&nbsp;</td> </tr> </table> <div class="draggable">Drag Me</div> on drop, how do i determine which day the div was dropped into. thanks for any help.

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  • Access: Expression too complex to be evaluated

    - by user2502964
    I'm trying to sort out values from a database by the weekending date. The script I'm using functions on 6 of my 7 databases (they are all constructed identically). The 7th database doesn't function. I get the expression too complex error. any help figuring out why?? Here is my code: SELECT UPC_Test.Type, UPC_Test.[Model No], UPC_Test.[Model Desc], UPC_Test.[Serial No], Format(DateValue([UPC_Test].[Test Date]+7-Weekday([UPC_Test].[Test Date],0)),"m/d/yyyy") AS [Test Date], UPC_Test.Parameter, UPC_Test.[Failure Symptom], UPC_Test.[Repair Action], UPC_Test.[Factory Select], UPC_Test.[Test Station] FROM UPC_Test GROUP BY UPC_Test.Type, UPC_Test.[Model No], UPC_Test.[Model Desc], UPC_Test.[Serial No], Format(DateValue([UPC_Test].[Test Date]+7-Weekday([UPC_Test].[Test Date],0)),"m/d/yyyy"), UPC_Test.Parameter, UPC_Test.[Failure Symptom], UPC_Test.[Repair Action], UPC_Test.[Factory Select], UPC_Test.[Test Station] HAVING (((UPC_Test.Type)="Production") AND ((Format(DateValue([UPC_Test].[Test Date]+7-Weekday([UPC_Test].[Test Date],0)),"m/d/yyyy"))=[Enter]) AND ((UPC_Test.[Failure Symptom])<>"") AND ((UPC_Test.[Repair Action])<>"") AND ((UPC_Test.[Test Station])="UPC RF Test")) ORDER BY Format(DateValue([UPC_Test].[Test Date]+7-Weekday([UPC_Test].[Test Date],0)),"m/d/yyyy");

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  • Group Specific set of data by Day

    - by Jacques444
    Need to get a certian subgroup of data per day (Seperated by weekday) For example Select weekday,bla,blabla,blablabla from dbo.blabla where bla = @StartDate and bla <=@endDate I need the output to be: Monday bla blabla blablabla Tuesday bla blabla blablabla If someone could help me that would be awesome. Thanks & Regards Jacques

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  • least value in count

    - by Nyfer
    i have a table employee(id,dept_id,salary,hire_date,job_id) . the following query i have to execute. Show all the employee who were hired on the day of the week on which least no of employee were hired. i have done the query, but am not able to get the least. please check if am correct. select id, WEEKDAY(hire_date)+1 as days,count(WEEKDAY(hire_date)+1) as count from test.employee group by days

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  • Why are changes to classes ignored after dom changes?

    - by Lg102
    I have a price grid that uses relative positioning to move a field around, beneath a box with: overflow: hidden;. In this is field, there are absolute-positioned boxes containing prices. When this box is hovered, the matching values above and left of the will change color. In order to achieve this, a class is toggled using jQuery. This initially works. However, after the grid is moved, the class change doesn't affect the block above the grid anymore. In the Chrome console, i can see the class being added, but it's css-styling isn't applied. No other styles for the element have changed. I am 100% sure there is no other style-rule influencing the element, it just stops responding to the change in class after the DOM has been altered. Can i 'refresh' the DOM somehow? Edit: I've tried to get the relevant code only: Adding the cell in the first place: $("#price_dates_cells").append("<div id='"+weekday[theBeginDate.getDay()]+"-"+theBeginDate.getDate()+"-"+(theBeginDate.getMonth()-1)+"' class='datecell' style='left: "+( Math.floor( difference / ( 3600 * 24 * 1000) ) * ( cellwidth ) )+"px'>"+weekday[theBeginDate.getDay()]+"<br>"+theBeginDate.getDate()+" "+yearmonth[theBeginDate.getMonth()]+"</div>"); Toggle the class: var str_element = "#"+weekday[Bdate.getDay()]+"-"+Bdate.getDate()+"-"+(Bdate.getMonth()-1); $(str_element).toggleClass("red"); and the movement that seems to cause the problem: $('#price_grid').animate({"top": (( ( horizontalMovement ) * cellheight)) }, 'fast', 'linear');

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  • Finding day of week in batch file? (Windows Server 2008)

    - by Daniel Magliola
    I have a process I run from a batch file, and i only want to run it on a certain day of the week. Is it possible to get the day of week? All the example I found, somehow rely on "date /t" to return "Friday, 12/11/2009", however, in my machine, "date /t" returns "12/11/2009". No weekday there. I've already checked the "regional settings" for my machine, and the long date format does include the weekday. The short date format doesn't, but i'd really rather not change that, since it'll affect a bunch of stuff I do. Any ideas here? Thanks! Daniel

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  • Finding day of week in batch file? (Windows Server 2008)

    - by Daniel Magliola
    I have a process I run from a batch file, and i only want to run it on a certain day of the week. Is it possible to get the day of week? All the example I found, somehow rely on "date /t" to return "Friday, 12/11/2009", however, in my machine, "date /t" returns "12/11/2009". No weekday there. I've already checked the "regional settings" for my machine, and the long date format does include the weekday. The short date format doesn't, but i'd really rather not change that, since it'll affect a bunch of stuff I do. Any ideas here? Thanks! Daniel

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  • iPhone NSCalendar - Incorrect Calendar Drawn for users outside US

    - by xoail
    After trying to work on someone else's code, and so many different iterations, I am unable to understand what am I doing wrong with dates on a calendar month view. I am trying to present a calendar in month view fashion like calendar.app but unfortunately some users in countries like Australia, UK are reporting incorrect alignment of Days to Dates. For instance in Australia it displays 17th March as Friday. Any help is highly appreciated! Here is the code sample I am using: -(void)setCalendar { NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar]; NSDateComponents *comps = [gregorian components:units fromDate:[NSDate date]]; self.currentDate = [gregorian dateFromComponents:comps]; NSInteger weekdayInteger=[comps weekday]; currentMonth=[comps month]; currentYear=[comps year]; NSString *dateString=[[NSString stringWithFormat:@"%@",currentDate] substringToIndex:10]; NSArray *array= [dateString componentsSeparatedByString:@"-"]; NSInteger currentDay=[[array objectAtIndex:2] intValue]; currentMonthConstant=currentMonth; currentYearConstant=currentYear; currentDayConstant=currentDay; currentConstantDate=[NSString stringWithFormat:@"%d/%d/%d",currentDayConstant,currentMonthConstant,currentYearConstant]; currentFirstDay=((8+weekdayInteger-(currentDay%7))%7); if(currentFirstDay==0) currentFirstDay=7; [gregorian release]; } And this is how im populating the calendar: -(void)fillCalender:(NSInteger)month weekStarts:(NSInteger)weekday year:(NSInteger)year { currentMonth=month; currentYear=year; currentFirstDay=weekday; UIButton *temp; NSInteger numberOfDays=[self getNumberofDays:month YearVlue:year]; currentLastDay=(currentFirstDay+numberOfDays-1)%7; if(currentLastDay==0) currentLastDay=7; NSString *monthName=[self getMonth:month]; NSInteger grid=(weekday-1); monthLabel.text=[NSString stringWithFormat:@"%@ %d",monthName,year]; for(int i=1;i<=numberOfDays;i++) { if([frontView isEqualToString:@"view1"]) temp=[arr_View2Buttons objectAtIndex:grid]; else temp= [arr_View1Buttons objectAtIndex:grid]; [temp setBackgroundImage:nil forState:UIControlStateNormal]; [temp setUserInteractionEnabled:TRUE]; UILabel *aLbl = (UILabel *)[temp viewWithTag:123]; [aLbl setText:[NSString stringWithFormat:@"%d",i]]; // check for today if(currentDayConstant == i && currentMonthConstant == currentMonth && currentYearConstant == currentYear) { [aLbl setTextColor:[UIColor blueColor]]; } else { [aLbl setTextColor:[UIColor colorWithRed:69/255.0 green:2/255.0 blue:71/255.0 alpha:1.0]]; } [temp setTag:i]; grid++; if(grid==35) grid=0; } } And finally viewdidload: - (void)viewDidLoad { [super viewDidLoad]; [self setCalendar]; // set views [self.view1 setFrame:CGRectMake(0,45,320,232)]; [self.view2 setFrame:CGRectMake(0,277,320,232)]; [self.view addSubview:self.view1]; [self.view addSubview:self.view2]; frontView = @"view2"; [self fillCalender:currentMonth weekStarts:currentFirstDay year:currentYear]; frontView = @"view1"; }

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  • Error in SQL. Can not find it.

    - by kmsboy
    Error in SQL. Can not find it. DECLARE @year VARCHAR (4), @month VARCHAR (2), @day VARCHAR (2), @weekday VARCHAR (2), @hour VARCHAR (2), @archivePath VARCHAR (128), @archiveName VARCHAR (128), @archiveFullName VARCHAR (128) SET @year = CAST(DATEPART(yyyy, GETDATE()) AS VARCHAR) SET @month = CAST(DATEPART(mm, GETDATE()) AS VARCHAR) SET @day = CAST(DATEPART(dd, GETDATE()) AS VARCHAR) SET @weekday = CAST(DATEPART (dw, GETDATE()) AS VARCHAR) SET @hour = CAST(DATEPART (hh, GETDATE()) AS VARCHAR) SET @archivePath = 'd:\1c_new\backupdb\' SET @archiveName = 'TransactionLog_' + @year + '_' + @month + '_' + @day + '_' + @hour + '.bak' SET @archiveFullName = @archivePath + @archiveName BACKUP LOG [xxx] TO DISK = @archiveFullName WITH INIT , NOUNLOAD , NAME = N'?????????? ??? ??????????', SKIP , STATS = 10, DESCRIPTION = N'?????????? ??? ??????????', NOFORMAT

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  • Game timings and formats

    - by topright
    There are more or less standardized TV-show/movie formats and recommended timings: 1. By the early 1960s, television companies commonly presented half-hour long "comedy" series, or one hour long "dramas." Half-hour series were mostly restricted to situation comedy or family comedy, and were usually aired with either a live or artificial laugh track. One hour dramas included genre series such as police and detective series, westerns, science fiction, and, later, serialized prime time soap operas. Programs today still overwhelmingly conform to these half-hour and one hour guidelines. Source 2. In the United States, most medical dramas are one hour long. Source 3. Traditionally serials were broadcast as fifteen minute installments each weekday in daytime slots. In 1956 As the World Turns debuted as the first half-hour soap opera. All soap operas broadcast half-hour episodes by the end of the 1960s. With increased popularity in the 1970s most soap operas expanded to an hour (Another World even expanded to ninety minutes for a short time). More than half of the serials had expanded to one hour episodes by 1980. As of 2010, six of the seven US serials air one hour episodes each weekday. Source Interesting. Are there any standards of timing in game development? Well, 5-20 minutes casual games, of course. There is even a "5-minutes-game" site. And 1-hour-gamer site. Are there 1-week, 1-year, 1-eternity game formats? Chess and Go - deep games that you can study all your life; but they are played in hour or several days (pro games). Addictive long-term online role-playing games (without win-condition) are played in monthes and, possibly, years. Replayability is an important factor to consider. It's good when game design document contains a line: "A game is designed for solving in X hours". How can it be measured before there is any prototype or demo? When you know your game format, you know your audience (and vice versa). It is practical question. Are there psychological researches about dynamic of gaming interest and involvement? And is there a correlation between game format and game genre?

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  • Date Time Format in RUBY

    - by Madhan ayyasamy
    The following snippets is very useful when we render views dates in various format in ruby on rails."Format meaning:  %a - The abbreviated weekday name (``Sun'')  %A - The  full  weekday  name (``Sunday'')  %b - The abbreviated month name (``Jan'')  %B - The  full  month  name (``January'')  %c - The preferred local date and time representation  %d - Day of the month (01..31)  %H - Hour of the day, 24-hour clock (00..23)  %I - Hour of the day, 12-hour clock (01..12)  %j - Day of the year (001..366)  %m - Month of the year (01..12)  %M - Minute of the hour (00..59)  %p - Meridian indicator (``AM''  or  ``PM'')  %S - Second of the minute (00..60)  %U - Week  number  of the current year,          starting with the first Sunday as the first          day of the first week (00..53)  %W - Week  number  of the current year,          starting with the first Monday as the first          day of the first week (00..53)  %w - Day of the week (Sunday is 0, 0..6)  %x - Preferred representation for the date alone, no time  %X - Preferred representation for the time alone, no date  %y - Year without a century (00..99)  %Y - Year with century  %Z - Time zone name  %% - Literal ``%'' character   t = Time.now   t.strftime("Printed on %m/%d/%Y")   #=> "Printed on 04/09/2003"   t.strftime("at %I:%M%p")            #=> "at 08:56AM""Have a great day!

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  • How to calculate next Friday at 3am?

    - by Mark
    How can you calculate the following Friday at 3am as a datetime object? Clarification: i.e., the calculated date should always be greater than 7 days away, and less than or equal to 14. Going with a slightly modified version of Mark's solution: def next_weekday(dt=datetime.datetime.now(), time_of_day=datetime.time(hour=3), day_of_week=4): dt += datetime.timedelta(days=7) if dt.time() < time_of_day: dt = dt.combine(dt.date(), time_of_day) else: dt = dt.combine(dt.date(), time_of_day) + datetime.timedelta(days=1) return dt + datetime.timedelta((day_of_week - dt.weekday()) % 7)

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  • User Mailer Failing

    - by Trevor Nederlof
    I have setup a process in my User model to send a bunch of @users to a mailing script, user_mailer.rb I am using the http://postageapp.com app to send out emails. The users are getting to the User_mailer but I am getting an error from there. Can anyone please point me in the right direction. User Model: class User < ActiveRecord::Base acts_as_authentic def self.mail_out weekday = Date.today.strftime('%A').downcase @users = find(:all, :conditions => {"#{weekday}sub".to_sym => 't'}) UserMailer.deliver_mail_out(@users) end end User_mailer.rb class UserMailer < ActionMailer::Base def mail_out(users) @recipients = { } users.each do |user| @recipients[user.email] = { :zipcode => user.zipcode } end from "[email protected]" subject "Check out the trailer of the day!" body :user => user end end mail_out.html.erb {{zipcode}}, Please check out the trailer of the day at http://www.dailytrailer.net Thank you! -- The DailyTrailer.net Team User db schema create_table "users", :force => true do |t| t.string "email" t.date "birthday" t.string "gender" t.string "zipcode" t.datetime "created_at" t.datetime "updated_at" t.string "crypted_password" t.string "password_salt" t.string "persistence_token" t.string "mondaysub", :default => "f", :null => false t.string "tuesdaysub", :default => "f", :null => false t.string "wednesdaysub", :default => "f", :null => false t.string "thursdaysub", :default => "f", :null => false t.string "fridaysub", :default => "f", :null => false t.string "saturdaysub", :default => "f", :null => false t.string "sundaysub", :default => "f", :null => false end Error: /var/lib/gems/1.8/gems/rails-2.3.5/lib/commands/runner.rb:48: undefined method `name' for #<User:0xb6e8ae48> (NoMethodError) from /home/tnederlof/Dropbox/Ruby/daily_trailer/app/models/user_mailer.rb:5:in `mail_out' from /home/tnederlof/Dropbox/Ruby/daily_trailer/app/models/user_mailer.rb:4:in `each' from /home/tnederlof/Dropbox/Ruby/daily_trailer/app/models/user_mailer.rb:4:in `mail_out' from /home/tnederlof/.gem/ruby/1.8/gems/actionmailer-2.3.5/lib/action_mailer/base.rb:459:in `__send__' from /home/tnederlof/.gem/ruby/1.8/gems/actionmailer-2.3.5/lib/action_mailer/base.rb:459:in `create!' from /home/tnederlof/.gem/ruby/1.8/gems/actionmailer-2.3.5/lib/action_mailer/base.rb:452:in `initialize' from /home/tnederlof/.gem/ruby/1.8/gems/actionmailer-2.3.5/lib/action_mailer/base.rb:395:in `new' from /home/tnederlof/.gem/ruby/1.8/gems/actionmailer-2.3.5/lib/action_mailer/base.rb:395:in `method_missing' from /home/tnederlof/Dropbox/Ruby/daily_trailer/app/models/user.rb:13:in `mail_out' from (eval):1 from /usr/lib/ruby/1.8/rubygems/custom_require.rb:31:in `eval' from /var/lib/gems/1.8/gems/rails-2.3.5/lib/commands/runner.rb:48 from /usr/lib/ruby/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /usr/lib/ruby/1.8/rubygems/custom_require.rb:31:in `require' from script/runner:3

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