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  • Write-error on swap-device, Result: hostbyte=DID_BAD_TARGET driverbyte=DRIVER_OK

    - by Jan
    My root server at 1&1 was unresponsive on HTTP and SSH, so I logged into the serial console . It flooded my connection with endless error messages like quoted below. I initiated a reboot and now everything seems to work properly. After googling, I installed smartctl and ran a short self test, which told me the device was healthy. Is this likely a disk failure soon to happen or could it be just some program going wild? I assume, the swap device could also grow full when huge amounts of memory get consumed by a buggy program? How can I find out for sure? The sever was already unresponsive a week ago when I just restarted it without proper investigation. The server is running on CentOS. Write-error on swap-device (8:16:8351055) Write-error on swap-device (8:16:8351063) Write-error on swap-device (8:16:8351071) Write-error on swap-device (8:16:8351079) Write-error on swap-device (8:16:8351087) Write-error on swap-device (8:16:8351095) Write-error on swap-device (8:16:8351103) Write-error on swap-device (8:16:8351111) Write-error on swap-device (8:16:8351119) Write-error on swap-device (8:16:8351127) Write-error on swap-device (8:16:8351135) Write-error on swap-device (8:16:8351143) Write-error on swap-device (8:16:8351151) Write-error on swap-device (8:16:8351159) Write-error on swap-device (8:16:8351167) Write-error on swap-device (8:16:8351175) Write-error on swap-device (8:16:8351183) Write-error on swap-device (8:16:8351191) sd 1:0:0:0: [sdb] Unhandled error code sd 1:0:0:0: [sdb] Result: hostbyte=DID_BAD_TARGET driverbyte=DRIVER_OK sd 1:0:0:0: [sdb] CDB: Write(10): 2a 00 00 9c 00 ef 00 00 08 00 end_request: I/O error, dev sdb, sector 10223855 Write-error on swap-device (8:16:10223863) sd 1:0:0:0: [sdb] Unhandled error code sd 1:0:0:0: [sdb] Result: hostbyte=DID_BAD_TARGET driverbyte=DRIVER_OK sd 1:0:0:0: [sdb] CDB: Write(10): 2a 00 00 9c 0e 97 00 00 10 00 end_request: I/O error, dev sdb, sector 10227351 Write-error on swap-device (8:16:10227359) Write-error on swap-device (8:16:10227367) sd 1:0:0:0: [sdb] Unhandled error code sd 1:0:0:0: [sdb] Result: hostbyte=DID_BAD_TARGET driverbyte=DRIVER_OK sd 1:0:0:0: [sdb] CDB: Write(10): 2a 00 00 9c b0 1f 00 00 10 00 end_request: I/O error, dev sdb, sector 10268703 Write-error on swap-device (8:16:10268711) Write-error on swap-device (8:16:10268719) sd 1:0:0:0: [sdb] Unhandled error code sd 1:0:0:0: [sdb] Result: hostbyte=DID_BAD_TARGET driverbyte=DRIVER_OK sd 1:0:0:0: [sdb] CDB: Write(10): 2a 00 00 a0 84 7f 00 00 08 00 end_request: I/O error, dev sdb, sector 10519679 Write-error on swap-device (8:16:10519687) sd 1:0:0:0: [sdb] Unhandled error code sd 1:0:0:0: [sdb] Result: hostbyte=DID_BAD_TARGET driverbyte=DRIVER_OK sd 1:0:0:0: [sdb] CDB: Write(10): 2a 00 00 a7 26 af 00 04 00 00 end_request: I/O error, dev sdb, sector 10954415 Write-error on swap-device (8:16:10954423) Write-error on swap-device (8:16:10954431) Write-error on swap-device (8:16:10954439) Write-error on swap-device (8:16:10954447) Write-error on swap-device (8:16:10954455) Write-error on swap-device (8:16:10954463) Write-error on swap-device (8:16:10954471) Write-error on swap-device (8:16:10954479) Write-error on swap-device (8:16:10954487) Write-error on swap-device (8:16:10954495) Write-error on swap-device (8:16:10954503) Write-error on swap-device (8:16:10954511) Write-error on swap-device (8:16:10954519) Write-error on swap-device (8:16:10954527) Write-error on swap-device (8:16:10954535) Write-error on swap-device (8:16:10954543) Write-error on swap-device (8:16:10954551) Write-error on swap-device (8:16:10954559) Write-error on swap-device (8:16:10954567) Write-error on swap-device (8:16:10954575) Write-error on swap-device (8:16:10954583) Write-error on swap-device (8:16:10954591) Write-error on swap-device (8:16:10954599) Write-error on swap-device (8:16:10954607) Write-error on swap-device (8:16:10954615) Write-error on swap-device (8:16:10954623) Write-error on swap-device (8:16:10954631) Write-error on swap-device (8:16:10954639) Write-error on swap-device (8:16:10954647) Write-error on swap-device (8:16:10954655) Write-error on swap-device (8:16:10954663) Write-error on swap-device (8:16:10954671) Write-error on swap-device (8:16:10954679) Write-error on swap-device (8:16:10954687) Write-error on swap-device (8:16:10954695) Write-error on swap-device (8:16:10954703) Write-error on swap-device (8:16:10954711) Write-error on swap-device (8:16:10954719) Write-error on swap-device (8:16:10954727) Write-error on swap-device (8:16:10954735) Write-error on swap-device (8:16:10954743) Write-error on swap-device (8:16:10954751) Write-error on swap-device (8:16:10954759) Write-error on swap-device (8:16:10954767) Write-error on swap-device (8:16:10954775) Write-error on swap-device (8:16:10954783) Write-error on swap-device (8:16:10954791) Write-error on swap-device (8:16:10954799) Write-error on swap-device (8:16:10954807) Write-error on swap-device (8:16:10954815) Write-error on swap-device (8:16:10954823) Write-error on swap-device (8:16:10954831) Write-error on swap-device (8:16:10954839) Write-error on swap-device (8:16:10954847) Write-error on swap-device (8:16:10954855) Write-error on swap-device (8:16:10954863) Write-error on swap-device (8:16:10954871) Write-error on swap-device (8:16:10954879) Write-error on swap-device (8:16:10954887) Write-error on swap-device (8:16:10954895) Write-error on swap-device (8:16:10954903) Write-error on swap-device (8:16:10954911) Write-error on swap-device (8:16:10954919) Write-error on swap-device (8:16:10954927) Write-error on swap-device (8:16:10954935) Write-error on swap-device (8:16:10954943) Write-error on swap-device (8:16:10954951) Write-error on swap-device (8:16:10954959) Write-error on swap-device (8:16:10954967) Write-error on swap-device (8:16:10954975) Write-error on swap-device (8:16:10954983) Write-error on swap-device (8:16:10954991) Write-error on swap-device (8:16:10954999) Write-error on swap-device (8:16:10955007) Write-error on swap-device (8:16:10955015) Write-error on swap-device (8:16:10955023) Write-error on swap-device (8:16:10955031) Write-error on swap-device (8:16:10955039) Write-error on swap-device (8:16:10955047) Write-error on swap-device (8:16:10955055) Write-error on swap-device (8:16:10955063) Write-error on swap-device (8:16:10955071) Write-error on swap-device (8:16:10955079) Write-error on swap-device (8:16:10955087) Write-error on swap-device (8:16:10955095) Write-error on swap-device (8:16:10955103) Write-error on swap-device (8:16:10955111) Write-error on swap-device (8:16:10955119) Write-error on swap-device (8:16:10955127) Write-error on swap-device (8:16:10955135) Write-error on swap-device (8:16:10955143) Write-error on swap-device (8:16:10955151) Write-error on swap-device (8:16:10955159) Write-error on swap-device (8:16:10955167) Write-error on swap-device (8:16:10955175) Write-error on swap-device (8:16:10955183)

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  • Finding if a Binary Tree is a Binary Search Tree

    - by dharam
    Today I had an interview where I was asked to write a program which takes a Binary Tree and returns true if it is also a Binary Search Tree otherwise false. My Approach1: Perform an inroder traversal and store the elements in O(n) time. Now scan through the array/list of elements and check if element at ith index is greater than element at (i+1)th index. If such a condition is encountered, return false and break out of the loop. (This takes O(n) time). At the end return true. But this gentleman wanted me to provide an efficient solution. I tried but I was unsuccessfult, because to find if it is a BST I have to check each node. Moreover he was pointing me to think over recusrion. My Approach 2: A BT is a BST if for any node N N-left is < N and N-right N , and the INorder successor of left node of N is less than N and the inorder successor of right node of N is greater than N and the left and right subtrees are BSTs. But this is going to be complicated and running time doesn't seem to be good. Please help if you know any optimal solution. Thanks.

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  • Binary to strings as binary? C #/.NET

    - by acidzombie24
    Redis keys are binary safe. I'd like to mess around and put binary into redis using C#. My client of choice doesn't support writing binary keys it uses keys and it make sense. However i am just fooling around so tell me how i can do this. How do i convert a raw byte[] into a string? At first i was thinking about converting a byte[] to a utf8 string however unicode has some checks to see if its valid or not. So raw binary should fail. Actually i tried it out. Instead of failing i got a strange result. My main question is how do i convert a raw byte[] to the equivalent string? My unimportant question is why did i get a 512 byte string instead of an exception saying this is not a valid UTF8 string? code var rainbow = new byte[256]; for (int i = 0; i < 256; i++) { rainbow[i] = (byte)i; } var sz = Encoding.UTF8.GetString(rainbow); var szarr = Encoding.UTF8.GetBytes(sz); Console.WriteLine("{0} {1} {2}", ByteArraysEqual(szarr, rainbow), szarr.Length, rainbow.Length); Output False 512 256

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  • apt-get update error - binary-i386, binary-amd64 [duplicate]

    - by magamig
    This question already has an answer here: How can I fix a 404 Error when updating packages? 5 answers When I run: sudo apt-get update It shows me the following error: W: Failed to fetch http://ppa.launchpad.net/directhex/ppa/ubuntu/dists/trusty/main/binary-amd64/Packages 404 Not Found W: Failed to fetch http://ppa.launchpad.net/directhex/ppa/ubuntu/dists/trusty/main/binary-i386/Packages 404 Not Found E: Some index files failed to download. They have been ignored, or old ones used instead. I have googled for solutions, but none of what I found, have worked for me. Please give me your suggestions

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  • VB6: Slow Binary Write?

    - by Tom the Junglist
    Wondering why a particular binary write operation in VB is so slow. The function reads a Byte array from memory and dumps it into a file like this: Open Destination For Binary Access Write As #1 Dim startP, endP As Long startP = BinaryStart endP = UBound(ReadBuf) - 1 Dim i as Integer For i = startP To endP DoEvents Put #1, (i - BinaryStart) + 1, ReadBuf(i) Next Close #1 For two megabytes on a slower system, this can take up to a minute. Can anyone tell me why this is so slow?

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  • Do dconf use EXI binary XML?

    - by Hibou57
    A question came to my mind reading an answer to the question What are the differences between gconf and dconf?. In an reply to the above question, Oli said: Binary read access is far faster than parsing XML. However, there exist a W3C recommendation for binary XML, since 2010: Efficient XML Interchange (EXI) Format 1.0. Is this what dconf uses? If Yes, where is it confirmed? If No, was there some investigations toward it at some time, and what was the conclusions? Thanks for any tracks, I'm curious to know.

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  • Binary on the Coat of Arms of the Governor General of Canada

    - by user132636
    Can you help me further this investigation? Here is about 10% of the work I have done on it. I present it only to see if there are any truly curious people among you. I made a video a few weeks ago showing some strange things about the Governor General's Coat of Arms and the binary on it. Today, I noticed something kinda cool and thought I would share. Here is the binary as it appears on the COA: 110010111001001010100100111010011 As DEC: 6830770643 (this is easily found on the web) Take a close look at that number. What do you notice about it? It has a few interesting features, but here is the one no one has pointed out... Split it down the middle and you have 68307 70643. The first digit is double the value of the last digit. The second digit is double the second last digit. The third digit is half of the third to last digit. And the middle ones are even or neutral. At first, I thought of it as energy. ++-nnnn+-- But actually you can create something else with it using the values. 221000211. See how that works. You may be asking why that is significant. Bare with me. I know 99% are rolling their eyes. 221000211 as base3 gives you this as binary: 100011101000111 100011101000111 as HEX is 4747, which converts to "GG". Initials of Governor General. GG.ca is his website. When you convert to base 33 (there are 33 digits in the original code) you get "GOV" Interesting? :D There is a lot more to it. I'll continue to show some strange coincidences if anyone is interested. Sorry if I am not explaining this correctly. By now you have probably figured out that I have no background in this. Which is why I am here. Thank you.

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  • Binary Search Tree - Postorder logic

    - by daveb
    I am looking at implementing code to work out binary search tree. Before I do this I was wanting to verify my input data in postorder and preorder. I am having trouble working out what the following numbers would be in postorder and preorder I have the following numbers 4, 3, 14 ,8 ,1, 15, 9, 5, 13, 10, 2, 7, 6, 12, 11, that I am intending to put into an empty binary tree in that order. The order I arrived at for the numbers in POSTORDER is 2, 1, 6, 3, 7, 11, 12, 10, 9, 8, 13, 15, 14, 4. Have I got this right? I was wondering if anyone here would be able to kindly verify if the postorder sequence I came up with is indeed the correct sequence for my input i.e doing left subtree, right subtree and then root. The order I got for pre order (Visit root, do left subtree, do right subtree) is 4, 3, 1, 2, 5, 6, 14 , 8, 7, 9, 10, 12, 11, 15, 13. I can't be certain I got this right. Very grateful for any verification. Many Thanks

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  • C++ find largest BST in a binary tree

    - by fonjibe
    what is your approach to have the largest BST in a binary tree? I refer to this post where a very good implementation for finding if a tree is BST or not is bool isBinarySearchTree(BinaryTree * n, int min=std::numeric_limits<int>::min(), int max=std::numeric_limits<int>::max()) { return !n || (min < n->value && n->value < max && isBinarySearchTree(n->l, min, n->value) && isBinarySearchTree(n->r, n->value, max)); } It is quite easy to implement a solution to find whether a tree contains a binary search tree. i think that the following method makes it: bool includeSomeBST(BinaryTree* n) { if(!isBinarySearchTree(n)) { if(!isBinarySearchTree(n->left)) return isBinarySearchTree(n->right); } else return true; else return true; } but what if i want the largest BST? this is my first idea, BinaryTree largestBST(BinaryTree* n) { if(isBinarySearchTree(n)) return n; if(!isBinarySearchTree(n->left)) { if(!isBinarySearchTree(n->right)) if(includeSomeBST(n->right)) return largestBST(n->right); else if(includeSomeBST(n->left)) return largestBST(n->left); else return NULL; else return n->right; } else return n->left; } but its not telling the largest actually. i struggle to make the comparison. how should it take place? thanks

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  • Find kth smallest element in a binary search tree in Optimum way

    - by Bragaadeesh
    Hi, I need to find the kth smallest element in the binary search tree without using any static/global variable. How to achieve it efficiently? The solution that I have in my mind is doing the operation in O(n), the worst case since I am planning to do an inorder traversal of the entire tree. But deep down I feel that I am not using the BST property here. Is my assumptive solution correct or is there a better one available ?

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  • How to Serialize Binary Tree

    - by Veljko Skarich
    I went to an interview today where I was asked to serialize a binary tree. I implemented an array-based approach where the children of node i (numbering in level-order traversal) were at the 2*i index for the left child and 2*i + 1 for the right child. The interviewer seemed more or less pleased, but I'm wondering what serialize means exactly? Does it specifically pertain to flattening the tree for writing to disk, or would serializing a tree also include just turning the tree into a linked list, say. Also, how would we go about flattening the tree into a (doubly) linked list, and then reconstructing it? Can you recreate the exact structure of the tree from the linked list? Thank you/

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  • Understanding binary numbers in terms of real world objects

    - by Kaushik
    When I represent a number in the decimal system, I have an intuitive knowledge of what it amounts to. For example take the number '10': I understand that it means 10 apples or 10 people... i.e I can count in the real world. But as soon as the number is converted to any other system, this understanding no longer applies. For example 10 when converted to binary will be 1010...now what does this represent? Is there a way to understand this number 1010 in terms of counting objects in the real world?

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  • Cannot execute binary file

    - by user291727
    I am new to Ubuntu and I'm trying to install Popcorn Time. I downloaded 32 bit version and tried to install it but that's where the problem started showing. I duble clicked the executable file and well, nothing happened. It's a official download from their web-site but it doesn't work. Maybe I'm doing something wrong.....Anyway, I found out that you can insatll it from a script, but people keep talking in ubuntu terms and I don't understand it, so I have a few questions: 1.How to make a script? (witch I'm suppose to run in terminal using bash comand), 2.Is it normal that i cannot run the installer, and if that is an installer or just files for the program. 3.If it is an installer, how do I make it work? 4.What does " Cannot execute binary file" mean? Thank you in advance, hope I'm not asking too many questions(please understand that I'm new to ubuntu) and sorry about my English. xD

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  • Include Binary Files in DEB package

    - by user22611
    I need to build a DEB package from mainly Node.js Javascript files, but it should include some binary files as well. They are listed inside debian/source/include-binaries. Otherwise I get the error message dpkg-source: error: unrepresentable changes to source The command in question is: bzr builddeb -- -us -uc After adding the file include-binaries, when running bzr builddeb -- -us -uc again, now I get a different error: It says dpkg-source: error: aborting due to unexpected upstream changes, see /tmp/mailadmin_0.0-1.diff.n6m5_6 I have no idea how to get rid of this. In the next line of output it tells me dpkg-source: info: you can integrate the local changes with dpkg-source --commit But if I run this command in the build area of my package, it gives me the unrepresentable changes to source error message again, even though debian/source/include-binaries is present in the build area as well. I am missing the way out of this... I tried deleting all files that are produced by the build process, still no success. Further details: The target directory is /opt/mailadmin. Since this directory is unusual, I listed it in the file debian/mailadmin.install (which contains one line:) opt/mailadmin opt/ The bzr builddeb process uses this file as expected.

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  • Binary Search Tree in Java

    - by John R
    I want to make a generic BST, that can be made up of any data type, but i'm not sure how I could add things to the tree, if my BST is generic. All of my needed code is below. I want my BST made up of Locations, and sorted by the x variable. Any help is appreciated. Major thanks for looking. public void add(E element) { if (root == null) root = element; if (element < root) add(element, root.leftChild); if (element > root) add(element, root.rightChild); else System.out.println("Element Already Exists"); } private void add(E element, E currLoc) { if (currLoc == null) currLoc = element; if (element < root) add(element, currLoc.leftChild); if (element > root) add(element, currLoc.rightChild); else System.out.println("Element Already Exists); } Other Code public class BinaryNode<E> { E BinaryNode; BinaryNode nextBinaryNode; BinaryNode prevBinaryNode; public BinaryNode() { BinaryNode = null; nextBinaryNode = null; prevBinaryNode = null; } } public class Location<AnyType> extends BinaryNode { String name; int x,y; public Location() { name = null; x = 0; y = 0; } public Location(String newName, int xCord, int yCord) { name = newName; x = xCord; y = yCord; } public int equals(Location otherScene) { return name.compareToIgnoreCase(otherScene.name); } }

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  • Deletion procedure for a Binary Search Tree

    - by Metz
    Consider the deletion procedure on a BST, when the node to delete has two children. Let's say i always replace it with the node holding the minimum key in its right subtree. The question is: is this procedure commutative? That is, deleting x and then y has the same result than deleting first y and then x? I think the answer is no, but i can't find a counterexample, nor figure out any valid reasoning. EDIT: Maybe i've got to be clearer. Consider the transplant(node x, node y) procedure: it replace x with y (and its subtree). So, if i want to delete a node (say x) which has two children i replace it with the node holding the minimum key in its right subtree: y = minimum(x.right) transplant(y, y.right) // extracts the minimum (it doesn't have left child) y.right = x.right y.left = x.left transplant(x,y) The question was how to prove the procedure above is not commutative.

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  • Designing binary operations(AND, OR, NOT) in graphs DB's like neo4j

    - by Nicholas
    I'm trying to create a recipe website using a graph database, specifically neo4j using spring-data-neo4j, to try and see what can be done in Graph Databases. My model so far is: (Chef)-[HAS_INGREDIENT]->(Ingredient) (Chef)-[HAS_VALUE]->(Value) (Ingredient)-[HAS_INGREDIENT_VALUE]->(Value) (Recipe)-[REQUIRES_INGREDIENT]->(Ingredient) (Recipe)-[REQUIRES_VALUE]->(Value) I have this set up so I can do things like have the "chef" enter ingredients they have on hand, and suggest recipes, as well as suggest recipes that are close matches, but missing one ingredient. Some recipes can get complex, utilizing AND, OR, and NOT type logic, something like (Milk AND (Butter OR spread OR (vegetable oil OR olive oil))) and I'm wondering if it would be sane to model this in a graph using a tree type representation? An example of what I was thinking is to create three "node" types of AND, OR, and NOT and have each of them connect to the nodes value underneath. How else might this be represented in a Graph Database or is my example above a decent representation?

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  • How important is to be able to write code like you would write prose

    - by benhowdle89
    Recently I heard of a company that, for interviews, asks potential employees to stand up and write out code on a whiteboard. Apparently that freaked alot of interviewees out. This got me thinking and even though I consider myself a reasonable programmer, I would be hard pressed to write lengthy code out without referring to previous code I had written or doing a quick Google search. How many programmers could safely say "Yes I could write all my code out just like I was writing an email"?

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  • Gets Error while i write Response.write() on click event of button

    - by Khilen
    Sys.Webforms.PageRequestManagerParserErrorException: The message received from the server could not be parsed. Common causes for this error are when the response is modified by calls to Response.Write(), response filters, HttpModules, or server trace is enabled. Details: Error parsing near ' Hi i have kept button in updatepanel and i am getting this error

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  • Is it any good to use binary arithmetic in a C++ code like "C style"?

    - by user827992
    I like the fact that the C language lets you use binary arithmetic in an explicit way in your code, sometimes the use of the binary arithmetic can also give you a little edge in terms of performance; but since I started studying C++ i can't really tell how much i have seen the explicit use of something like that in a C++ code, something like a pointer to pointer structure or an instruction for jumping to a specific index value through the binary arithmetic. Is the binary arithmetic still important and relevant in the C++ world? How i can optimize my arithmetic and/or an access to a specific index? What about the C++ and the way in which the bits are arranged according to the standard? ... or i have taken a look at the wrong coding conventions ... ?

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  • Use Extension method to write cleaner code

    - by Fredrik N
    This blog post will show you step by step to refactoring some code to be more readable (at least what I think). Patrik Löwnedahl gave me some of the ideas when we where talking about making code much cleaner. The following is an simple application that will have a list of movies (Normal and Transfer). The task of the application is to calculate the total sum of each movie and also display the price of each movie. class Program { enum MovieType { Normal, Transfer } static void Main(string[] args) { var movies = GetMovies(); int totalPriceOfNormalMovie = 0; int totalPriceOfTransferMovie = 0; foreach (var movie in movies) { if (movie == MovieType.Normal) { totalPriceOfNormalMovie += 2; Console.WriteLine("$2"); } else if (movie == MovieType.Transfer) { totalPriceOfTransferMovie += 3; Console.WriteLine("$3"); } } } private static IEnumerable<MovieType> GetMovies() { return new List<MovieType>() { MovieType.Normal, MovieType.Transfer, MovieType.Normal }; } } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } In the code above I’m using an enum, a good way to add types (isn’t it ;)). I also use one foreach loop to calculate the price, the loop has a condition statement to check what kind of movie is added to the list of movies. I want to reuse the foreach only to increase performance and let it do two things (isn’t that smart of me?! ;)). First of all I can admit, I’m not a big fan of enum. Enum often results in ugly condition statements and can be hard to maintain (if a new type is added we need to check all the code in our app to see if we use the enum somewhere else). I don’t often care about pre-optimizations when it comes to write code (of course I have performance in mind). I rather prefer to use two foreach to let them do one things instead of two. So based on what I don’t like and Martin Fowler’s Refactoring catalog, I’m going to refactoring this code to what I will call a more elegant and cleaner code. First of all I’m going to use Split Loop to make sure the foreach will do one thing not two, it will results in two foreach (Don’t care about performance here, if the results will results in bad performance, you can refactoring later, but computers are so fast to day, so iterating through a list is not often so time consuming.) Note: The foreach actually do four things, will come to is later. var movies = GetMovies(); int totalPriceOfNormalMovie = 0; int totalPriceOfTransferMovie = 0; foreach (var movie in movies) { if (movie == MovieType.Normal) { totalPriceOfNormalMovie += 2; Console.WriteLine("$2"); } } foreach (var movie in movies) { if (movie == MovieType.Transfer) { totalPriceOfTransferMovie += 3; Console.WriteLine("$3"); } } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } To remove the condition statement we can use the Where extension method added to the IEnumerable<T> and is located in the System.Linq namespace: foreach (var movie in movies.Where( m => m == MovieType.Normal)) { totalPriceOfNormalMovie += 2; Console.WriteLine("$2"); } foreach (var movie in movies.Where( m => m == MovieType.Transfer)) { totalPriceOfTransferMovie += 3; Console.WriteLine("$3"); } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } The above code will still do two things, calculate the total price, and display the price of the movie. I will not take care of it at the moment, instead I will focus on the enum and try to remove them. One way to remove enum is by using the Replace Conditional with Polymorphism. So I will create two classes, one base class called Movie, and one called MovieTransfer. The Movie class will have a property called Price, the Movie will now hold the price:   public class Movie { public virtual int Price { get { return 2; } } } public class MovieTransfer : Movie { public override int Price { get { return 3; } } } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } The following code has no enum and will use the new Movie classes instead: class Program { static void Main(string[] args) { var movies = GetMovies(); int totalPriceOfNormalMovie = 0; int totalPriceOfTransferMovie = 0; foreach (var movie in movies.Where( m => m is Movie)) { totalPriceOfNormalMovie += movie.Price; Console.WriteLine(movie.Price); } foreach (var movie in movies.Where( m => m is MovieTransfer)) { totalPriceOfTransferMovie += movie.Price; Console.WriteLine(movie.Price); } } private static IEnumerable<Movie> GetMovies() { return new List<Movie>() { new Movie(), new MovieTransfer(), new Movie() }; } } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; }   If you take a look at the foreach now, you can see it still actually do two things, calculate the price and display the price. We can do some more refactoring here by using the Sum extension method to calculate the total price of the movies:   static void Main(string[] args) { var movies = GetMovies(); int totalPriceOfNormalMovie = movies.Where(m => m is Movie) .Sum(m => m.Price); int totalPriceOfTransferMovie = movies.Where(m => m is MovieTransfer) .Sum(m => m.Price); foreach (var movie in movies.Where( m => m is Movie)) Console.WriteLine(movie.Price); foreach (var movie in movies.Where( m => m is MovieTransfer)) Console.WriteLine(movie.Price); } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } Now when the Movie object will hold the price, there is no need to use two separate foreach to display the price of the movies in the list, so we can use only one instead: foreach (var movie in movies) Console.WriteLine(movie.Price); .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } If we want to increase the Maintainability index we can use the Extract Method to move the Sum of the prices into two separate methods. The name of the method will explain what we are doing: static void Main(string[] args) { var movies = GetMovies(); int totalPriceOfMovie = TotalPriceOfMovie(movies); int totalPriceOfTransferMovie = TotalPriceOfMovieTransfer(movies); foreach (var movie in movies) Console.WriteLine(movie.Price); } private static int TotalPriceOfMovieTransfer(IEnumerable<Movie> movies) { return movies.Where(m => m is MovieTransfer) .Sum(m => m.Price); } private static int TotalPriceOfMovie(IEnumerable<Movie> movies) { return movies.Where(m => m is Movie) .Sum(m => m.Price); } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } Now to the last thing, I love the ForEach method of the List<T>, but the IEnumerable<T> doesn’t have it, so I created my own ForEach extension, here is the code of the ForEach extension method: public static class LoopExtensions { public static void ForEach<T>(this IEnumerable<T> values, Action<T> action) { Contract.Requires(values != null); Contract.Requires(action != null); foreach (var v in values) action(v); } } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } I will now replace the foreach by using this ForEach method: static void Main(string[] args) { var movies = GetMovies(); int totalPriceOfMovie = TotalPriceOfMovie(movies); int totalPriceOfTransferMovie = TotalPriceOfMovieTransfer(movies); movies.ForEach(m => Console.WriteLine(m.Price)); } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } The ForEach on the movies will now display the price of the movie, but maybe we want to display the name of the movie etc, so we can use Extract Method by moving the lamdba expression into a method instead, and let the method explains what we are displaying: movies.ForEach(DisplayMovieInfo); private static void DisplayMovieInfo(Movie movie) { Console.WriteLine(movie.Price); } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } Now the refactoring is done! Here is the complete code:   class Program { static void Main(string[] args) { var movies = GetMovies(); int totalPriceOfMovie = TotalPriceOfMovie(movies); int totalPriceOfTransferMovie = TotalPriceOfMovieTransfer(movies); movies.ForEach(DisplayMovieInfo); } private static void DisplayMovieInfo(Movie movie) { Console.WriteLine(movie.Price); } private static int TotalPriceOfMovieTransfer(IEnumerable<Movie> movies) { return movies.Where(m => m is MovieTransfer) .Sum(m => m.Price); } private static int TotalPriceOfMovie(IEnumerable<Movie> movies) { return movies.Where(m => m is Movie) .Sum(m => m.Price); } private static IEnumerable<Movie> GetMovies() { return new List<Movie>() { new Movie(), new MovieTransfer(), new Movie() }; } } public class Movie { public virtual int Price { get { return 2; } } } public class MovieTransfer : Movie { public override int Price { get { return 3; } } } pulbic static class LoopExtensions { public static void ForEach<T>(this IEnumerable<T> values, Action<T> action) { Contract.Requires(values != null); Contract.Requires(action != null); foreach (var v in values) action(v); } } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } I think the new code is much cleaner than the first one, and I love the ForEach extension on the IEnumerable<T>, I can use it for different kind of things, for example: movies.Where(m => m is Movie) .ForEach(DoSomething); .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } By using the Where and ForEach extension method, some if statements can be removed and will make the code much cleaner. But the beauty is in the eye of the beholder. What would you have done different, what do you think will make the first example in the blog post look much cleaner than my results, comments are welcome! If you want to know when I will publish a new blog post, you can follow me on twitter: http://www.twitter.com/fredrikn

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  • How to convert binary read/write to non-binary read/write in C++

    - by Phenom
    I have some C++ code from somewhere that reads and writes data in binary format. I want to see what it's reading and writing in the file, so I want to convert it's binary read and write to non-binary read and write. Also, when I convert the binary write to non-binary write, I want it to still be able to read in the information correctly. How can this be done? The write function: int btwrite(short rrn, BTPAGE *page_ptr) { // long lseek(), addr; long addr; addr = (long) rrn * (long) PAGESIZE + HEADERSIZE; lseek(btfd, addr, 0); return (write(btfd, page_ptr, PAGESIZE)); } The read function: int btread(short rrn, BTPAGE *page_ptr) { // long lseek(), addr; long addr; addr = (long)rrn * (long)PAGESIZE + HEADERSIZE; lseek(btfd, addr, 0); return ( read(btfd, page_ptr, PAGESIZE) ); }

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