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  • Call Webservice using Javascript

    - by ajithperuva
    I am trying to call a webservice using javascript.But it shows an error like selectSingleNode() is not a method.I am trying it in mozilla firefox.Which is perfectly working in explorer when i change XMLHttpRequest to ActiveXObject.here i am adding my source code which i am tried in firefox. // Web Service functionality // Global vars var xmlDoc = null; var _serviceCallback = null; // Calls web service, web service url and parms, and callback function or null must be provided. // Callback function receives a true or false based on success of call to host function callWebService(url, callback) { _serviceCallback = callback; if(xmlDoc == null) { // xmlDoc = new XMLHttpRequest(); xmlDoc = new XMLHttpRequest(); } xmlDoc.onreadystatechange = stateChange; //callback for readystate xmlDoc.async = true; //do background processing //xmlDoc.load(url); xmlDoc.open('GET', url); xmlDoc.send(); //var doc= xmlDoc.responseXML; } // Updates readystate by callback function stateChange() { if (xmlDoc.readyState == 4) { var err = xmlDoc.parseError; var result = false; var nd; if(err.errorCode == 0) { nd = xmlDoc.selectSingleNode("//envelope/date_time"); if(nd.text != "") result = true; } // perform callback if provided if(_serviceCallback != null) _serviceCallback(result, nd == null ? "" : nd.text); } } // Callback supplied to XMLHttpRequest call function callbackTest(result, data) { obj = document.getElementById("txtOuput"); if(result) obj.value = "Success " + data; else obj.value = "Web Service Call Failed"; } Please help me...Already which kill my 8 more hours...

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  • innerHTML yielding undefined, but correct data is visible

    - by Mike Dyer
    var Model,node; document.getElementById('sedans').innerHTML=''; var thismodelabbr,prevmodelabbr; for(var j=0; j<xmlDoc.getElementsByTagName('data').length; j++){ node = xmlDoc.getElementsByTagName('data')[j]; thismodelabbr=node.getAttribute('model'); if(prevmodelabbr!=thismodelabbr){ Model+='<a href="">'+ node.getAttribute('model')+'</a>'; } prevmodelabbr=thismodelabbr; document.getElementById('sedans').innerHTML=Model; } The above javascript snippet is working correctly and as needed, but I'm getting an "Undefined" response before the entry is displayed within its respective page. I'm assuming it has to do with the .innerHTML call. Any insight would be deeply appreciated.

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  • Reading xml document in firefox

    - by Searock
    I am trying to read customers.xml using javascript. My professor has taught us to read xml using `ActiveXObjectand he has given us an assignment to create a sample login page which checks username and password by reading customers.xml. I am trying to use DOMParser so that it works with firefox. But when I click on Login button I get this error. Error: syntax error Source File: file:///C:/Users/Searock/Desktop/home/project/project/login.html Line: 1, Column: 1 Source Code: customers.xml Here's my code. login.js var xmlDoc = 0; function checkUser() { var user = document.login.txtLogin.value; var pass = document.login.txtPass.value; //xmlDoc = new ActiveXObject("Microsoft.XMLDOM"); /* xmlDoc = document.implementation.createDocument("","",null); xmlDoc.async = "false"; xmlDoc.onreadystatechange = redirectUser; xmlDoc.load("customers.xml"); */ var parser = new DOMParser(); xmlDoc = parser.parseFromString("customers.xml", "text/xml"); alert(xmlDoc.documentElement.nodeName); xmlDoc.async = "false"; xmlDoc.onreadystatechange = redirectUser; } function redirectUser() { alert(''); var user = document.login.txtLogin.value; var pass = document.login.txtPass.value; var log = 0; if(xmlDoc.readyState == 4) { xmlObj = xmlDoc.documentElement; var len = xmlObj.childNodes.length; for(i = 0; i < len; i++) { var nodeElement = xmlObj.childNodes[i]; var userXml = nodeElement.childNodes[0].firstChild.nodeValue; var passXml = nodeElement.childNodes[1].firstChild.nodeValue; var idXML = nodeElement.attributes[0].value if(userXml == user && passXml == pass) { log = 1; document.cookie = escape(idXML); document.login.submit(); } } } if(log == 0) { var divErr = document.getElementById('Error'); divErr.innerHTML = "<b>Login Failed</b>"; } } customers.xml <?xml version="1.0" encoding="UTF-8"?> <customers> <customer custid="CU101"> <user>jack</user> <pwd>PW101</pwd> <email>[email protected]</email> </customer> <customer custid="CU102"> <user>jill</user> <pwd>PW102</pwd> <email>[email protected]</email> </customer> <customer custid="CU103"> <user>john</user> <pwd>PW103</pwd> <email>[email protected]</email> </customer> <customer custid="CU104"> <user>jeff</user> <pwd>PW104</pwd> <email>[email protected]</email> </customer> </customers> I get parsererror message on line alert(xmlDoc.documentElement.nodeName); I don't know what's wrong with my code. Can some one point me in a right direction? Edit : Ok, I found a solution. var xmlDoc = 0; var xhttp = 0; function checkUser() { var user = document.login.txtLogin.value; var pass = document.login.txtPass.value; var err = ""; if(user == "" || pass == "") { if(user == "") { alert("Enter user name"); } if(pass == "") { alert("Enter Password"); } return; } if (window.XMLHttpRequest) { xhttp=new XMLHttpRequest(); } else // IE 5/6 { xhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xhttp.onreadystatechange = redirectUser; xhttp.open("GET","customers.xml",true); xhttp.send(); } function redirectUser() { var log = 2; var user = document.login.txtLogin.value; var pass = document.login.txtPass.value; if (xhttp.readyState == 4) { log = 0; xmlDoc = xhttp.responseXML; var xmlUsers = xmlDoc.getElementsByTagName('user'); var xmlPasswords = xmlDoc.getElementsByTagName('pwd'); var userLen = xmlDoc.getElementsByTagName('customer').length; var xmlCustomers = xmlDoc.getElementsByTagName('customer'); for (var i = 0; i < userLen; i++) { var xmlUser = xmlUsers[i].childNodes[0].nodeValue; var xmlPass = xmlPasswords[i].childNodes[0].nodeValue; var xmlId = xmlCustomers.item(i).attributes[0].nodeValue; if(xmlUser == user && xmlPass == pass) { log = 1; document.cookie = xmlId; document.login.submit(); break; } } } if(log == 0) { alert("Login failed"); } } Thanks.

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  • C# xml Class to substitute ini files

    - by Eduardo
    Hi guys, I am learning Windows Forms in C#.NET 2008 and i want to build a class to work with SIMPLE xml files (config file like INI files), but i just need a simple class (open, getvalue, setvalue, creategroup, save and close functions), to substitute of ini files. I already did something and it is working but I am having trouble when I need to create different groups, something like this: <?xml version="1.0" encoding="utf-8"?> <CONFIG> <General> <Field1>192.168.0.2</Field1> </General> <Data> <Field1>Joseph</Field1> <Field2>Locked</Field2> </Data> </CONFIG> how can i specify that i want to read the field1 of [data] group? note that i have same field name in both groups (Field1)! I am using System.Linq, something like this: To open document: XmlDocument xmlDoc = new XmlDocument(); xmlDoc.Load(FilePath); To save document: xmlDoc.Save(FilePath); To get value: public string getValue(string Field) { string result = ""; try { XmlNodeList xmlComum = xmlDoc.GetElementsByTagName(Field); if (xmlComum.Item(0) == null) result = ""; else result = xmlComum.Item(0).InnerText; } catch (Exception ex) { return ""; } return result; } To set value: public void setValue(string Group, string Field, string FieldValue) { try { XmlNodeList xmlComum = xmlDoc.GetElementsByTagName(Field); if (xmlComum.Item(0) == null) { xmlComum = xmlDoc.GetElementsByTagName(Group); if (xmlComum.Item(0) == null) { // create group createGroup(Group); xmlComum = xmlDoc.GetElementsByTagName(Group); } XmlElement xmlE = xmlDoc.CreateElement(Field); XmlText xmlT = xmlDoc.CreateTextNode(FieldValue); xmlE.AppendChild(xmlT); xmlComum.Item(0).AppendChild(xmlE); } else { // item already exists, just change its value xmlComum.Item(0).InnerText = Value; } xmlDoc.Save(FilePath); } catch (Exception ex) { } } The CreateGroup code: public void createGroup(string Group) { try { XmlElement xmlComum = xmlDoc.CreateElement(Group); xmlDoc.DocumentElement.AppendChild(xmlComum); xmlDoc.Save(FilePath); } catch (Exception ex) { } } Thank You!

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  • Problem with XML encoding of database contents with Latin characters

    - by user89691
    I have an ASP Access database that contains strings in various European languages. The database was populated prior by agents in the respective countries. It contains entries with accented etc characters as you would expect. If I open the database with MS Access these characters show up fine. For example the the German equivalent of "Open" shows as "Öffnen" (hopefully you can see an "O" with 2 dots above it!). I have ASP code that reads the database and returns records in XML. The text is passed to XMLEncode to construct the XML, but that only seems to deal with the 5 specials like "<", "&", etc. If I dump the XML the accented characters are unchanged. <English>Open</English> <German>Öffnen</German> If I look at the raw packets with Wireshark I see that the "Ö" byte is hex D6, which appears to be it's decimal Unicode and ISO 8859-1 value. The problem starts when I try to parse the XML in client-side JS. I get: "An invalid character was found in text content" from IE. FF and Chrome happily accept the XML without hiccup but the browser shows the "Ö" character as a diamond with a question mark inside. http://www.validome.org/xml/validate/ reports "encoding error." http://www.w3schools.com/dom/dom_validate.asp thinks it is fine. The XML is UTF-8 encoded. What do I need to do to have IE accept my XML without complaint? What do I need to do to have browsers display the stuff correctly?

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  • javascript XSL in google chrome

    - by Guy
    Hi, I'm using the following javascript code to display xml/xsl: function loadXMLDoc(fname) { var xmlDoc; // code for IE if (window.ActiveXObject) { xmlDoc=new ActiveXObject("Microsoft.XMLDOM"); } // code for Mozilla, Firefox, Opera, etc. else if (document.implementation && document.implementation.createDocument) { xmlDoc=document.implementation.createDocument("","",null); } else { alert('Your browser cannot handle this script'); } try { xmlDoc.async=false; xmlDoc.load(fname); return(xmlDoc); } catch(e) { try //Google Chrome { var xmlhttp = new window.XMLHttpRequest(); xmlhttp.open("GET",file,false); xmlhttp.send(null); xmlDoc = xmlhttp.responseXML.documentElement; return(xmlDoc); } catch(e) { error=e.message; } } } function displayResult() { xml=loadXMLDoc("report.xml"); xsl=loadXMLDoc("report.xsl"); // code for IE if (window.ActiveXObject) { ex=xml.transformNode(xsl); document.getElementById("example").innerHTML=ex; } // code for Mozilla, Firefox, Opera, etc. else if (document.implementation && document.implementation.createDocument) { xsltProcessor=new XSLTProcessor(); xsltProcessor.importStylesheet(xsl); resultDocument = xsltProcessor.transformToFragment(xml,document); document.getElementById("example").appendChild(resultDocument); } } It works find for IE and Firefox but chrome is fail in the line: document.getElementById("example").appendChild(resultDocument); Thank you for you help

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  • XMLHttpRequest in Ajax and PHP

    - by ajithperuva
    In internet explorer we can create the object of ActiveXObject like follows xmlDoc=new ActiveXObject("Microsoft.XMLDOM"); xmlDoc.async="false"; xmlDoc.load("note_error.xml"); It is possible to use the xmlDoc.load("note_error.xml"); for the object of XMLHttpRequest in other browsers.If no,any other substitute for this method when we use XMLHttpRequest.Please help...am using firefox as my browser

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  • create and modify xml file using javascript (want to save xml file on client side)

    - by user201478
    Hi , How to save xml file on client side using javascript...? if (window.XMLHttpRequest) { xhttp = new XMLHttpRequest(); } else // Internet Explorer 5/6 { xhttp = new ActiveXObject("Microsoft.XMLHTTP"); } xhttp.open("GET", "User.xml", false); xhttp.send(""); xmlDoc = xhttp.responseXML; xmlDoc.getElementsByTagName("Username")[0].childNodes[0].nodeValue = 'asdasf'; xmlDoc.getElementsByTagName("password")[0].childNodes[0].nodeValue = 'asdAS'; xmlDoc.getElementsByTagName("UserId")[0].childNodes[0].nodeValue = '12'; xmlDoc.save("User.xml"); this is not working.. showing error as save is not a function. Thanks Suneetha.

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  • How to Send and Receive XML request to another ASP classic page?

    - by SH
    I want to send an XML to another Asp Classic page on the same domain. i am using following code for sending XMl url = "http://localhost/api/xmlget.asp" information = "ColtTaylor100" Set xmlhttp = server.Createobject("MSXML2.ServerXMLHTTP") xmlhttp.Open "POST", url, false xmlhttp.setRequestHeader "Content-Type", "text/xml" xmlhttp.send information And i have setup xmlget.asp with following code to receive XML: Dim xmlDoc Dim userName set xmlDoc=Server.CreateObject("Microsoft.XMLDOM") xmlDoc.async="false" xmlDoc.load(Request) I run the code but do not see any reflection, how would i know? And if it is successful I want to know the xml and i dont know exact property to load from xmlDoc!

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  • How do I set the encoding statement in the XML declaration when performing an XSL transformation usi

    - by aspiehler
    I wrote a simple package installer in WinBatch that needs to update an XML file with information about the package contents. My first stab at it involved loading the file with Msxml2.DOMDocument, adding nodes and data as required, then saving the data back to disk. This worked well enough, except that it would not create tab and CR/LF whitespace in the new data. The solution I came up with was writing an XSL stylesheet that would recreate the XML file with whitespace added back in. I'm doing this by: loading the XSL file into an Msxml2.FreeThreadedDOMDocument object setting that object as the stylesheet property of an Msxml2.XSLTemplate object creating an XSL processor via Msxml2.XSLTemplate.createProcessor() setting my original Msxml2.DOMDocument as the input property of the XSL processor Calling transform() method of the XSL processor, and saving the output to a file. This works as for as reformatting the XML file with tabs and carriage returns, but my XML declaration comes out either as <?xml version="1.0"?> or <?xml version="1.0" encoding="UTF-16"?> depending on whether I used Msxml2.*.6.0 or Msxml2.* objects (a fall back if the system doesn't have 6.0). If the encoding is set to UTF-16, Msxml12.DOMDocument complains about trying to convert UTF-16 to 1-byte encoding the next time I run my package installer. I've tried creating and adding an XML declaration using both createProcessingInstruction() to both the XML and XSL DOM objects, but neither one seems to affect the output of the XSLTemplate processor. I've also set encoding to UTF-8 in the <xsl:output/> tag in my XSL file. Here is the relevant code in my Winbatch script: xmlDoc = ObjectCreate("Msxml2.DOMDocument.6.0") if !xmlDoc then xmlDoc = ObjectCreate("Msxml2.DOMDocument") xmlDoc.async = @FALSE xmlDoc.validateOnParse = @TRUE xmlDoc.resolveExternals = @TRUE xmlDoc.preserveWhiteSpace = @TRUE xmlDoc.setProperty("SelectionLanguge", "XPath") xmlDoc.setProperty("SelectionNamespaces", "xmlns:fns='http://www.abc.com/f_namespace'") xmlDoc.load(xml_file_path) xslStyleSheet = ObjectCreate("Msxml2.FreeThreadedDOMDocument.6.0") if !xslStyleSheet then xslStyleSheet = ObjectCreate("Msxml2.FreeThreadedDOMDocument") xslStyleSheet.async = @FALSE xslStyleSheet.validateOnParse = @TRUE xslStyleSheet.load(xsl_style_sheet_path) xslTemplate = ObjectCreate("Msxml2.XSLTemplate.6.0") if !xslTemplate then xslTemplate = ObjectCreate("Msxml2.XSLTemplate") xslTemplate.stylesheet = xslStyleSheet processor = xslTemplate.createProcessor() processor.input = xmlDoc processor.transform() ; create a new file and write the XML processor output to it fh = FileOpen(output_file_path, "WRITE" , @FALSE) FileWrite(fh, processor.output) FileClose(fh) The style sheet, with some slight changes to protect the innocent: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.1"> <xsl:output method="xml" indent="yes" encoding="UTF-8"/> <xsl:template match="/"> <fns:test_station xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:fns="http://www.abc.com/f_namespace"> <xsl:for-each select="/fns:test_station/identification"> <xsl:text>&#x0A; </xsl:text> <identification> <xsl:for-each select="./*"> <xsl:text>&#x0A; </xsl:text> <xsl:copy-of select="."/> </xsl:for-each> <xsl:text>&#x0A; </xsl:text> </identification> </xsl:for-each> <xsl:for-each select="/fns:test_station/software"> <xsl:text>&#x0A; </xsl:text> <software> <xsl:for-each select="./package"> <xsl:text>&#x0A; </xsl:text> <package> <xsl:for-each select="./*"> <xsl:text>&#x0A; </xsl:text> <xsl:copy-of select="."/> </xsl:for-each> <xsl:text>&#x0A; </xsl:text> </package> </xsl:for-each> <xsl:text>&#x0A; </xsl:text> </software> </xsl:for-each> <xsl:for-each select="/fns:test_station/calibration"> <xsl:text>&#x0A; </xsl:text> <calibration> <xsl:for-each select="./item"> <xsl:text>&#x0A; </xsl:text> <item> <xsl:for-each select="./*"> <xsl:text>&#x0A; </xsl:text> <xsl:copy-of select="."/> </xsl:for-each> <xsl:text>&#x0A; </xsl:text> </item> </xsl:for-each> <xsl:text>&#x0A; </xsl:text> </calibration> </xsl:for-each> </fns:test_station> </xsl:template> </xsl:stylesheet> And this is a sample output file: <?xml version="1.0" encoding="UTF-16"?> <fns:test_station xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:fns="http://www.abc.com/f_namespace"> <software> <package> <part_number>123456789</part_number> <version>00</version> <test_category>1</test_category> <description>name of software package</description> <execution_path>c:\program files\test\test.exe</execution_path> <execution_arguments>arguments</execution_arguments> <crc_path>c:\ste_config\crc\123456789.lst</crc_path> <uninstall_path>c:\ste_config\uninstall\uninst_123456789.bat</uninstall_path> <install_timestamp>2009-11-09T14:00:44</install_timestamp> </package> </software> </fns:test_station>

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  • PHP DOMDocument getElementsByTagname??

    - by FFish
    This is driving me bonkers... I just want to add another img node. $xml = <<<XML <?xml version="1.0" encoding="UTF-8"?> <gallery> <album tnPath="tn/" lgPath="imm/" fsPath="iml/" > <img src="004.jpg" caption="4th caption" /> <img src="005.jpg" caption="5th caption" /> <img src="006.jpg" caption="6th caption" /> </album> </gallery> XML; $xmlDoc = new DOMDocument(); $xmlDoc->loadXML($xml); $album = $xmlDoc->getElementsByTagname('album')[0]; // Parse error: syntax error, unexpected '[' in /Applications/XAMPP/xamppfiles/htdocs/admin/tests/DOMDoc.php on line 17 $album = $xmlDoc->getElementsByTagname('album'); // Fatal error: Call to undefined method DOMNodeList::appendChild() in /Applications/XAMPP/xamppfiles/htdocs/admin/tests/DOMDoc.php on line 19 $newImg = $xmlDoc->createElement("img"); $album->appendChild($newImg); print $xmlDoc->saveXML(); Error:

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  • XML cross-browser support

    - by 1anthony1
    I need help getting the file to run in Firefox: I have tried adapting scripts so that my file runs in both IE and Firefox but so far it still only works in IE. (The file can be tested at http://www.eyle.org/crosstest.html - simply type the word Mike in the text box using IE (doesn't work in Firefox).The HTML document is: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <script type="text/javascript"> var xmlDoc; //loads xml using either IE or firefox function loadXmlDoc() { //test for IE if(window.ActiveXObject) { xmlDoc = new ActiveXObject("Microsoft.XMLDOM"); xmlDoc.async = false; xmlDoc.load("books2.xml"); } //test for Firefox else if(document.implementation && document.implementation.createDocument) { xmlDoc = document.implementation.createDocument("","",null); xmlDoc.load("books2.xml"); } //if neither else {document.write("xml file did not load");} } //window.onload = loadXmlDoc(); var subject; //getDetails adds value of txtField to var subject in outputgroup(subject) function getDetails() { //either this or window.onload = loadXmlDoc is needed loadXmlDoc(); var subject = document.getElementById("txtField1").value; function outputgroup(subject) { var xslt = new ActiveXObject("Msxml2.XSLTemplate"); var xslDoc = new ActiveXObject("Msxml2.FreeThreadedDOMDocument"); var xslProc; xslDoc.async = false; xslDoc.resolveExternals = false; xslDoc.load("contains3books.xsl"); xslt.stylesheet = xslDoc; xslProc = xslt.createProcessor(); xslProc.input = xmlDoc; xslProc.addParameter("subj", subject); xslProc.transform(); document.write(xslProc.output); } outputgroup(subject); } </script> </head> <body> <input type="text" id="txtField1"> <input type="submit" onClick="getDetails(); return false"> </body> </html> The file includes books2.xml and contains3books.xsl (I have put the code for these files at ...ww.eyle.org/books2.xml ...ww.eyle.org/contains3books.xsl) (NB: replace ...ww. with http: // www)

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  • Why does the following Java Script fail to load XML?

    - by Pavitar
    I have taken an example taught to us in class,wherein a javascript is used to retrieve data from the XML,but it doesn't work.Please help I have also added the XML file below. <html> <head> <title>Customer Info</title> <script language="javascript"> var xmlDoc = 0; var xmlObj = 0; function loadCustomers(){ xmlDoc = new ActiveXObject("Microsoft.XMLDOM"); xmlDoc.async = "false"; xmlDoc.onreadystatechange = displayCustomers; xmlDoc.load("customers.xml"); } function displayCustomers(){ if(xmlDoc.readyState == 4){ xmlObj = xmlDoc.documentElement; var len = xmlObj.childNodes.length; for(i = 0; i < len; i++){ var nodeElement = xmlObj.childNodes[i]; document.write(nodeElement.attributes[0].value); for(j = 0; j < nodeElement.childNodes.length; j++){ document.write(" " + nodeElement.childNodes[j].firstChild.nodeValue); } document.write("<br/>"); } } } </script> </head> <body> <form> <input type="button" value="Load XML" onClick="loadCustomers()"> </form> </body> </html> XML(customers.xml) <?xml version="1.0" encoding="UTF-8"?> <customers> <customer custid="CU101"> <pwd>PW101</pwd> <email>[email protected]</email> </customer> <customer custid="CU102"> <pwd>PW102</pwd> <email>[email protected]</email> </customer> <customer custid="CU103"> <pwd>PW103</pwd> <email>[email protected]</email> </customer> <customer custid="CU104"> <pwd>PW104</pwd> <email>[email protected]</email> </customer> </customers>

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  • VBScript Can not Select XML nodes

    - by urbanMethod
    I am trying to Select nodes from some webservice response XML to no avail. For some reason I am able to select the root node ("xmldata") however, when I try to drill deeper("xmldata/customers") everything is returned empty! Below is the a sample of the XML that is returned by the webservice. <xmldata> <customers> <customerid>22506</customerid> <firstname>Jim</firstname> <issuperadmin>N</issuperadmin> <lastname>Jones</lastname> </customers> </xmldata> and here is the code I am trying to select customerid, firstname, and lastname; ' Send the Xml oXMLHttp.send Xml_to_Send ' Validate the Xml dim xmlDoc set xmlDoc = Server.CreateObject("Msxml2.DOMDocument") xmlDoc.load (oXMLHttp.ResponseXML.text) if(len(xmlDoc.text) = 0) then Xml_Returned = "<B>ERROR in Response xml:<BR>ERROR DETAILS:</B><BR><HR><BR>" end if dim nodeList Set nodeList = xmlDoc.SelectNodes("xmldata/customers") For Each itemAttrib In nodeList dim custID, custLname, custFname custID =itemAttrib.selectSingleNode("customerid").text custLname =itemAttrib.selectSingleNode("lastname").text custFname =itemAttrib.selectSingleNode("firstname").text response.write("News Subject: " & custID) response.write("<br />News Subject: " & custLname) response.write("<br />News Date: " & custFname) Next The result of the code above is zilch! nothing is written to the page. One strange thing is if I select the root element and get its length as follows; Set nodeList = xmlDoc.SelectNodes("xmldata") Response.Write(nodeList.length) '1 is written to page It correctly determines the length of 1. However when I try the same with the next node down as follows; Set nodeList2 = xmlDoc.SelectNodes("xmldata/customers") Response.Write(nodeList.length) '0 is written to page It returns a length of 0. WHY! Please note that this isn't the only way I have attempted to access the values of these nodes. I just can not work out what I am doing wrong. Could someone please help me out. Cheers.

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  • Jquery Datepicker with XML file

    - by matt
    an extension of my last question, http://stackoverflow.com/questions/2562986/getdate-with-jquery-datepicker , I am trying to use the jquery datepicker to load specific info from xml file dependent on the date selected by the user. Similar code but i am trying to load and parse an xml file to read contents of the file for the particular date. In a perfect world the user would tap a date and below the datepicker html output would give the user specific times for the selected date instead of my last project of an image. my probelm is nothing is loading, so my question is what am i doing wrong? my code is as follows <!DOCTYPE html> <link type="text/css" href="css/ui-darkness/jquery-ui-1.8.custom.css" rel="stylesheet" /> <script type="text/javascript" src="js/jquery-1.4.2.min.js"></script> <script type="text/javascript" src="js/jquery-ui-1.8.custom.min.js"></script> <script type="text/javascript"> $(function(){ // Datepicker $('#datepicker').datepicker({ dateFormat: 'yy-mm-dd', inline: true, minDate: new Date(2010, 1 - 1, 1), maxDate:new Date(2010, 12 - 1, 31), altField: '#datepicker_value', onSelect: function(){ var day1 = $("#datepicker").datepicker('getDate').getDate(); var month1 = $("#datepicker").datepicker('getDate').getMonth() + 1; var year1 = $("#datepicker").datepicker('getDate').getFullYear(); var fullDate = year1 + "" + month1 + "" + day1; //var str_output ="<img src=\"http://69.89.20.27/images/a" + fullDate +".png\" width=\"100%\"/>"; //"<h1>"+fullDate+"</h1>"; //"<img src=\"http://69.*.*.*/images/a" + fullDate +".png\"/>"; //$('#page_output').html(str_output); var doc = loadXMLDoc('date.xml'); // loading the XML file var el = doc.getElementsByTagName('_'+date); // retrieving the elements corrsponding to a date, eg: _20100103 var page_output = document.getElementById('page_output'); if(el.length >= 1) { // matched XML data found for the specified date var dt = el[0].getElementsByTagName('date'); var great_times = el[0].getElementsByTagName('great_times'); var good_times = el[0].getElementsByTagName('good_times'); var str_output = "<h1><center>" + dt[0].childNodes[0].nodeValue + "</center></h1><br/><br>"; str_output += "<b>Excellent Times:</b><br> " + great_times[0].childNodes[0].nodeValue + "<br/><br>"; str_output += "<b>Good Times:</b><br> " + good_times[0].childNodes[0].nodeValue + "<br/><br>"; $('#page_output').html(str_output);// writing the results to the div element (page_out) } else { alert("Sorry","Action not allowed on this page"); page_output.innerHTML = ''; // No XML data found for the selected date reloadmainwDate(); return false; } return true; } }); //hover states on the static widgets $('#dialog_link, ul#icons li').hover( function() { $(this).addClass('ui-state-hover'); }, function() { $(this).removeClass('ui-state-hover'); } ); }); //var img_date = .datepicker('getDate'); //var day1 = $("#datepicker").datepicker('getDate').getDate(); //var month1 = $("#datepicker").datepicker('getDate').getMonth() + 1; //var year1 = $("#datepicker").datepicker('getDate').getFullYear(); //var fullDate = year1 + "-" + month1 + "-" + day1; //var date = $('#datepicker').datepicker({ dateFormat: 'dd-mm-yy' }); //var str_output = "<h1><center><p>"+ date + "</p></center></h1>"; //$('#page_output')[0].innerHTML = str_output; // writing the results to the div element (page_out) </script> <script> function loadXMLDoc(dname) { var xmlDoc; // IE 5 and IE 6 if(typeof ActiveXObject != 'undefined') { xmlDoc=new ActiveXObject("Microsoft.XMLDOM"); xmlDoc.async=false; xmlDoc.load(dname); return xmlDoc; } else if (window.XMLHttpRequest) // firefox { xmlDoc=new window.XMLHttpRequest(); xmlDoc.open("GET",dname,false); xmlDoc.send(""); return xmlDoc.responseXML; } alert("Error loading document"); return null; } <!-- Datepicker --> <div id="datepicker"></div> <!-- Highlight / Error --> <div id="page_output"></div> </body>

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  • XML is case sensitive hence Xml parser (XmlDocument) too...

    - by Narendra Tiwari
    XML is case sensitive hence Xml parser (XmlDocument) too... In below example I am trying to search the <user> element node with name attibute as 'pupu'.  <user name="PuPu" fullname="Priyanka T" email="[email protected]" /> ::translate() functon esures the case insensitive comparision in Xpath expression.   XmlDocument xmlDoc = new XmlDocument(); xmlDoc.Load("<xml file to load>"); XmlElement userElement = (XmlElement)xmlDoc.DocumentElement.SelectSingleNode("//user[translate(@name,'ABCDEFGHIJKLMNOPQRSTUVWXYZ', 'abcdefghijklmnopqrstuvwxyz') ='pupu']");

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  • How is this "interface"-like structure/pattern called?

    - by Sebastian Negraszus
    Let's assume we have an XmlDoc class that contains basic functionality for dealing with an XML data structure and saving/loading data to/from a file. Now we have several subclasses, A, B and C. They all inherit from XmlDoc and add component-specific methods for setting and getting lots of data. They are like "interfaces" but also add an implementation for the signatures. Finally, we have an ABCDoc class that joins all the "interfaces" via virtual multiple inheritence and adds some ABCDoc-specific stuff, such as using XMLDoc-methods to set an appropriate doc type. We may also have an ADoc class for only saving A data. How is this pattern called? "Interface" is not really the right word since interfaces usually do not contain an implementation. Bonus points for C++ code conventions.

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  • 503 (Server Unavailable) WebException when loading local XHTML file in Visual C# 2008

    - by kcoppock
    Hello! So I'm currently working on an ePub reader application, and I've been reading through a bunch of regular XML files just fine with System.Xml and XmlDocument: XmlDocument xmldoc = new XmlDocument(); xmldoc.Load(Path.Combine(Directory.GetCurrentDirectory(), "META-INF/container.xml")); XmlNodeList xnl = xmldoc.GetElementsByTagName("rootfile"); However, now I'm trying to open the XHTML files that contain the actual book text, and they're XHTML files. Now I don't really know the difference between the two, but I'm getting the following error with this code (in the same document, using the same XmlDocument and XmlNodeList variable) xmldoc.Load(Path.Combine(Directory.GetCurrentDirectory(), "OEBPS/part1.xhtml")); "WebException was unhandled: The remote server returned an error: (503) Server Unavailable" It's a local document, so I'm not understanding why it's giving this error? Any help would be greatly appreciated. :) I've got the full source code here if it helps: http://drop.io/epubtest (I know the ePubConstructor.ParseDocument() method is horribly messy, I'm just trying to get it working at the moment before I split it into classes)

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  • How can I get this dynamic WHERE statement in my LINQ-to-XML to work?

    - by Edward Tanguay
    In this question Jon Skeet offered a very interesting solution to making a LINQ-to-XML statement dynamic, but my knowledge of lambdas and delegates is not yet advanced enough to implement it: I've got it this far, but of course I get the error "smartForm does not exist in the current context": private void LoadWithId(int id) { XDocument xmlDoc = null; try { xmlDoc = XDocument.Load(FullXmlDataStorePathAndFileName); } catch (Exception ex) { throw new Exception(String.Format("Cannot load XML file: {0}", ex.Message)); } Func<XElement, bool> whereClause = (int)smartForm.Element("id") == id"; var smartForms = xmlDoc.Descendants("smartForm") .Where(whereClause) .Select(smartForm => new SmartForm { Id = (int)smartForm.Element("id"), WhenCreated = (DateTime)smartForm.Element("whenCreated"), ItemOwner = smartForm.Element("itemOwner").Value, PublishStatus = smartForm.Element("publishStatus").Value, CorrectionOfId = (int)smartForm.Element("correctionOfId"), IdCode = smartForm.Element("idCode").Value, Title = smartForm.Element("title").Value, Description = smartForm.Element("description").Value, LabelWidth = (int)smartForm.Element("labelWidth") }); foreach (SmartForm smartForm in smartForms) { _collection.Add(smartForm); } } Ideally I want to be able to just say: var smartForms = GetSmartForms(smartForm=> (int) smartForm.Element("DisplayOrder").Value > 50); I've got it this far, but I'm just not grokking the lambda magic, how do I do this? public List<SmartForm> GetSmartForms(XDocument xmlDoc, XElement whereClause) { var smartForms = xmlDoc.Descendants("smartForm") .Where(whereClause) .Select(smartForm => new SmartForm { Id = (int)smartForm.Element("id"), WhenCreated = (DateTime)smartForm.Element("whenCreated"), ItemOwner = smartForm.Element("itemOwner").Value, PublishStatus = smartForm.Element("publishStatus").Value, CorrectionOfId = (int)smartForm.Element("correctionOfId"), IdCode = smartForm.Element("idCode").Value, Title = smartForm.Element("title").Value, Description = smartForm.Element("description").Value, LabelWidth = (int)smartForm.Element("labelWidth") }); }

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  • C# CreateElement method - how to add an child element with xmlns=""

    - by NealWalters
    How can I get the following code to add the element with "xmlns=''"? using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Xml; namespace ConsoleApplication1 { class Program { static void Main(string[] args) { string strXML = "<myroot>" + " <group3 xmlns='myGroup3SerializerStyle'>" + " <firstname xmlns=''>Neal3</firstname>" + " </group3>" + "</myroot>"; XmlDocument xmlDoc = new XmlDocument(); xmlDoc.LoadXml(strXML); XmlElement elem = xmlDoc.CreateElement(null, "lastname", null); elem.InnerText = "New-Value"; string strXPath = "/myroot/*[local-name()='group3' and namespace-uri()='myGroup3SerializerStyle']/firstname"; XmlNode insertPoint = xmlDoc.SelectSingleNode(strXPath); insertPoint.AppendChild(elem); string resultOuter = xmlDoc.OuterXml; Console.WriteLine("\n resultOuter=" + resultOuter); Console.ReadLine(); } } } My current output: resultOuter=<myroot><group3 xmlns="myGroup3SerializerStyle"><firstname xmlns="" >Neal3<lastname>New-Value</lastname></firstname></group3></myroot> The desired output: resultOuter=<myroot><group3 xmlns="myGroup3SerializerStyle"><firstname xmlns="" >Neal3<lastname xmlns="">New-Value</lastname></firstname></group3></myroot> For background, see related posts: http://www.stylusstudio.com/ssdn/default.asp?fid=23 (today) http://stackoverflow.com/questions/2410620/net-xmlserializer-to-element-formdefaultunqualified-xml (March 9, thought I fixed it, but bit me again today!)

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  • 503 (Server Unavailable) WebException when loading local XHTML file

    - by kcoppock
    Hello! So I'm currently working on an ePub reader application, and I've been reading through a bunch of regular XML files just fine with System.Xml and XmlDocument: XmlDocument xmldoc = new XmlDocument(); xmldoc.Load(Path.Combine(Directory.GetCurrentDirectory(), "META-INF/container.xml")); XmlNodeList xnl = xmldoc.GetElementsByTagName("rootfile"); However, now I'm trying to open the XHTML files that contain the actual book text, and they're XHTML files. Now I don't really know the difference between the two, but I'm getting the following error with this code (in the same document, using the same XmlDocument and XmlNodeList variable) xmldoc.Load(Path.Combine(Directory.GetCurrentDirectory(), "OEBPS/part1.xhtml")); "WebException was unhandled: The remote server returned an error: (503) Server Unavailable" It's a local document, so I'm not understanding why it's giving this error? Any help would be greatly appreciated. :) I've got the full source code here if it helps: http://drop.io/epubtest (I know the ePubConstructor.ParseDocument() method is horribly messy, I'm just trying to get it working at the moment before I split it into classes)

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  • Python modify an xml file

    - by michele
    I have this xml model. link text So I have to add some node (see the text commented) to this file. How I can do it? I have writed this partial code but it doesn't work: xmldoc=minidom.parse(directory) child = xmldoc.createElement("map") for node in xmldoc.getElementsByTagName("Environment"): node.appendChild(child) Thanks in advance.

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  • Syntax Error? When parsing XML value

    - by Ace Munim
    I don't know if I'm having a syntax error but the compiler is giving me TypeError: 'undefined' is not an object (evaluating 'xmlDoc.getElementsByTagName("icon")[i].childNodes') Its me giving me this problem when im parsing the XML from my server, my actual javascript code is like this var xmlDoc = Obj.responseXML; var count = 0; if(xmlDoc){ while(count <= xmlDoc.getElementsByTagName("item").length){ document.getElementById("flow").innerHTML += "<div class='item'><img class='content' src='" + xmlDoc.getElementsByTagName("icon")[i].childNodes[0].nodeValue.replace(/\s+$/g,' ') +"' /></div>"; count++; } }else{ alert("Unable to parse!"); } and my XML goes like this. <feed> <item> <title>Given Title</title> <icon> http://i178.photobucket.com/albums/w255/ace003_album/Logo-ETC-RGB-e1353503652739.jpg </icon> </item> <item>...</item> <item>...</item> <item>...</item> <item>...</item> <item>...</item> <item>...</item> </feed> i just want to parse the image link and to show it.

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