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Search found 3 results on 1 pages for 'xmpppy'.

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• django + xmppy: send a message to two recipients

  - by Agrajag

  I'm trying to use xmpppy for sending jabber-messages from a django-website. This works entirely fine. However, the message only gets sent to the -first- of the recipients in the list. This happens when I run the following function from django, and also if I run it from an interactive python-shell. The weird part though, is that if I extract the -body- of the function and run that interactively, then all the recipients (there's just 2 at the moment) get the message. Also, I do know that the inner for-loop gets run the correct count times (2), because the print-statement does run twice, and return two different message-ids. The function looks like this: def hello_jabber(request, text): jid=xmpp.protocol.JID(settings.JABBER_ID) cl=xmpp.Client(jid.getDomain(),debug=[]) con=cl.connect() auth=cl.auth(jid.getNode(),settings.JABBER_PW,resource=jid.getResource()) for friend in settings.JABBER_FRIENDS: id=cl.send(xmpp.protocol.Message(friend,friend + ' is awesome:' + text)) print 'sent message with id ' + str(id) cl.disconnect() return render_to_response('jabber/sent.htm', locals())

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• python-xmpp and looping through list of recipients to receive and IM message

  - by David

  I can't figure out the problem and want some input as to whether my Python code is incorrect, or if this is an issue or design limitation of Python XMPP library. I'm new to Python by the way. Here's snippets of code in question below. What I'd like to do is read in a text file of IM recipients, one recipient per line, in XMPP/Jabber ID format. This is read into a Python list variable. I then instantiate an XMPP client session and loop through the list of recipients and send a message to each recipient. Then sleep some time and repeat test. This is for load testing the IM client of recipients as well as IM server. There is code to alternately handle case of taking only one recipient from command line input instead of from file. What ends up happening is that Python does iterate/loop through the list but only last recipient in list receives message. Switch order of recipients to verify. Kind of looks like Python XMPP library is not sending it out right, or I'm missing a step with the library calls, because the debug print statements during runtime indicate the looping works correctly. recipient = "" delay = 60 useFile = False recList = [] ... elif (sys.argv[i] == '-t'): recipient = sys.argv[i+1] useFile = False elif (sys.argv[i] == '-tf'): fil = open(sys.argv[i+1], 'r') recList = fil.readlines() fil.close() useFile = True ... # disable debug msgs cnx = xmpp.Client(svr,debug=[]) cnx.connect(server=(svr,5223)) cnx.auth(user,pwd,'imbot') cnx.sendInitPresence() while (True): if useFile: for listUser in recList: cnx.send(xmpp.Message(listUser,msg+str(msgCounter))) print "sending to "+listUser+" msg = "+msg+str(msgCounter) else: cnx.send(xmpp.Message(recipient,msg+str(msgCounter))) msgCounter += 1 time.sleep(delay)

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• How can I transfer a file via XMPP using Python?

  - by Enchantner

  I'm using xmpppy library for my jabber remote administration bot, but I can't find how to send/receive a file and save it inside the directory specified. The documentation is poor and there isn't any examples, but I really want to make it. Can anyone show some examples or some links about it? Or maybe I should use an alternative xmpp bindings?

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