Chaining multiple ShellExecute calls
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by IVlad
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Published on 2010-03-15T16:38:40Z
Indexed on
2010/03/15
18:09 UTC
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Consider the following code and its executable - runner.exe
:
#include <iostream>
#include <string>
#include <windows.h>
using namespace std;
int main(int argc, char *argv[])
{
SHELLEXECUTEINFO shExecInfo;
shExecInfo.cbSize = sizeof(SHELLEXECUTEINFO);
shExecInfo.fMask = NULL;
shExecInfo.hwnd = NULL;
shExecInfo.lpVerb = "open";
shExecInfo.lpFile = argv[1];
string Params = "";
for ( int i = 2; i < argc; ++i )
Params += argv[i] + ' ';
shExecInfo.lpParameters = Params.c_str();
shExecInfo.lpDirectory = NULL;
shExecInfo.nShow = SW_SHOWNORMAL;
shExecInfo.hInstApp = NULL;
ShellExecuteEx(&shExecInfo);
return 0;
}
These two batch files both do what they're supposed to, which is run notepad.exe and run notepad.exe and tell it to try to open test.txt:
1.
runner.exe notepad.exe
2.
runner.exe notepad.exe test.txt
Now, consider this batch file:
3.
runner.exe runner.exe notepad.exe
This one should run runner.exe and send notepad.exe as one of its command line arguments, shouldn't it? Then, that second instance of runner.exe should run notepad.exe - which doesn't happen, I get a "Windows cannot find 'am'. Make sure you typed the name correctly, and then try again" error. If I print the argc
argument, it's 14 for the second instance of runner.exe, and they are all weird stuff like Files\Microsoft, SQL, Files\Common and so on. I can't figure out why this happens. I want to be able to string as many runner.exe calls using command line arguments as possible, or at least 2. How can I do that?
I am using Windows 7 if that makes a difference.
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