Factory Method Pattern clarification
Posted
by nettguy
on Stack Overflow
See other posts from Stack Overflow
or by nettguy
Published on 2010-03-29T18:02:16Z
Indexed on
2010/03/29
18:13 UTC
Read the original article
Hit count: 381
My understanding of Factory Method Pattern is (Correct me if i am wrong)
Factory Method Pattern
"Factory Method allow the client to delegates the product creation (Instance Creation) to the subclass".
There are two situation in which we can go for creating Factory Method pattern.
(i) When the client is restricted to the product (Instance) creation.
(ii) There are multiple products available.But a decision to be made which product instance need to be returned.
If you want to create Abstract Method pattern
- You need to have abstract product
- Concrete Product
- Factory Method to return the appropriate product.
Example :
public enum ORMChoice
{
L2SQL,
EFM,
LS,
Sonic
}
//Abstract Product
public interface IProduct
{
void ProductTaken();
}
//Concrete Product
public class LinqtoSql : IProduct
{
public void ProductTaken()
{
Console.WriteLine("OR Mapping Taken:LinqtoSql");
}
}
//concrete product
public class Subsonic : IProduct
{
public void ProductTaken()
{
Console.WriteLine("OR Mapping Taken:Subsonic");
}
}
//concrete product
public class EntityFramework : IProduct
{
public void ProductTaken()
{
Console.WriteLine("OR Mapping Taken:EntityFramework");
}
}
//concrete product
public class LightSpeed : IProduct
{
public void ProductTaken()
{
Console.WriteLine("OR Mapping Taken :LightSpeed");
}
}
public class Creator
{
//Factory Method
public IProduct ReturnORTool(ORMChoice choice)
{
switch (choice)
{
case ORMChoice.EFM:return new EntityFramework();
break;
case ORMChoice.L2SQL:return new LinqtoSql();
break;
case ORMChoice.LS:return new LightSpeed();
break;
case ORMChoice.Sonic:return new Subsonic();
break;
default: return null;
}
}
}
**Client**
Button_Click()
{
Creator c = new Creator();
IProduct p = c.ReturnORTool(ORMChoice.L2SQL);
p.ProductTaken();
}
Is my understanding of Factory Method is correct?
© Stack Overflow or respective owner