How to get position of parent element - XSL

Posted by joe on Stack Overflow See other posts from Stack Overflow or by joe
Published on 2010-04-02T16:00:10Z Indexed on 2010/04/02 16:03 UTC
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xsl

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xslt

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Xml

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xsltprocessor

What I wish I could do in xsl is the following, but unfortunatly parent/position() is not valid.

XSL

<xsl:template match="li">
  <bullet>
    <xsl:apply-templates/>
  </bullet>
  <!-- todo: if this is the last bullet AND there are no more "p" tags, output footer -->
  <xsl:if test="count(ancestor::div/*) = parent/position()">
    <footer/>
  </xsl:if>
</xsl:template>

XML

<html>
  <div>
    <p>There is an x number of me</p>
    <p>There is an x number of me</p>
    <p>There is an x number of me</p>
    <ul>
      <li>list item</li>
      <li>list item</li>
      <li>list item</li>
      <li>list item</li>
      <li>list item</li>
    </ul>
  </div>
</html>

Anyone have any ideas how to figure out this problem from WITHIN my template match for li?

Thanks!

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