Fastest way to find the closest point to a given point in 3D, in Python.
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by Saebin
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Published on 2010-04-14T21:31:14Z
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2010/04/14
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So lets say I have 10,000 points in A and 10,000 points in B and want to find out the closest point in A for every B point.
Currently, I simply loop through every point in B and A to find which one is closest in distance. ie.
B = [(.5, 1, 1), (1, .1, 1), (1, 1, .2)]
A = [(1, 1, .3), (1, 0, 1), (.4, 1, 1)]
C = {}
for bp in B:
closestDist = -1
for ap in A:
dist = sum(((bp[0]-ap[0])**2, (bp[1]-ap[1])**2, (bp[2]-ap[2])**2))
if(closestDist > dist or closestDist == -1):
C[bp] = ap
closestDist = dist
print C
However, I am sure there is a faster way to do this... any ideas?
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