Actual element tags are not getting captured.

Posted by user323719 on Stack Overflow See other posts from Stack Overflow or by user323719
Published on 2010-04-27T14:56:32Z Indexed on 2010/04/27 17:33 UTC
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I am using the below piece of XSL code to construct a span tag calling a javascript function on mouseover. The input to the javascipt should be a html table. The output from the variable "showContent" gives just the text content but not along with the table tags. How can this be resolved.

XSL:

          <xsl:variable name="aTable" as="element()*">
        <table border="0" cellspacing="0" cellpadding="0">
        <xsl:for-each select="$capturedTags">
        <tr><td><xsl:value-of select="node()" /></td></tr>
        </xsl:for-each>
        </table>
        </xsl:variable>
        <xsl:variable name="start" select='concat("Tip(&#39;", "")'></xsl:variable>
        <xsl:variable name="end" select='concat("&#39;)", "")'></xsl:variable>
        <xsl:variable name="showContent">
                <xsl:value-of select='concat($start,$aTable,$end)'/> 
        </xsl:variable>
        <span xmlns="http://www.w3.org/1999/xhtml" onmouseout="{$hideContent}" 
              onmouseover="{$showContent}" id="{$textNodeId}"><xsl:value-of select="$textNode"></xsl:value-of></span>

Actual Output: <span onmouseout="UnTip()" onmouseover="Tip('content1')" id="d1t14">is my </span>

Expected output:

   <span onmouseout="UnTip()" onmouseover="Tip('<table><tr><td>content1</td></tr>')" id="d1t14">is my </span>

What is the change that needs to done in the above XSL for the table, tr and td tags to get passed?

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