initialising a 2-dim Array in Scala

Posted by Stefan W. on Stack Overflow See other posts from Stack Overflow or by Stefan W.
Published on 2010-05-01T04:38:36Z Indexed on 2010/05/01 4:47 UTC
Read the original article Hit count: 313

(Scala 2.7.7:) I don't get used to 2d-Arrays. Arrays are mutable, but how do I specify a 2d-Array which is - let's say of size 3x4. The dimension (2D) is fixed, but the size per dimension shall be initializable. I tried this:

class Field (val rows: Int, val cols: Int, sc: java.util.Scanner) {
 var field = new Array [Char](rows)(cols)

 for (r <- (1 to rows)) {
  val line = sc.nextLine ()
  val spl = line.split (" ")
  field (r) = spl.map (_.charAt (0))
 }

   def put (val rows: Int, val cols: Int, c: Char) =
       todo ()
}

I get this error: :11: error: value update is not a member of Char field (r) = spl.map (_.charAt (0))

If it would be Java, it would be much more code, but I would know how to do it, so I show what I mean:

public class Field
{
 private char[][] field;

 public Field (int rows, int cols, java.util.Scanner sc) 
 {
  field = new char [rows][cols]; 
  for (int r = 0; r < rows; ++r) 
  {
   String line = sc.nextLine ();
   String[] spl = line.split (" ");
   for (int c = 0; c < cols; ++c)
    field [r][c] = spl[c].charAt (0);
  }
 }

 public static void main (String args[])
 {
  new Field (3, 4, new java.util.Scanner ("fraese.fld"));
 }
}

and fraese.fld would look, for example, like that:

M M M 
M . M 

I get some steps wide with

val field = new Array Array [Char]

but how would I then implement 'put'? Or is there a better way to implement the 2D-Array. Yes, I could use a one-dim-Array, and work with

put (y, x, c) = field (y * width + x) = c

but I would prefer a notation which looks more 2d-ish.

© Stack Overflow or respective owner

Related posts about scala-2.7.7

Related posts about declaration