How do I cast a void pointer to a struct in C?
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by Rowhawn
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Published on 2010-05-03T23:59:20Z
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2010/05/04
0:08 UTC
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In a project I'm writing code for, I have a void pointer, "implementation", which is a member of a "Hash_map" struct, and points to an "Array_hash_map" struct. The concepts behind this project are not very realistic, but bear with me. The specifications of the project ask that I cast the void pointer "implementation" to an "Array_hash_map" before I can use it in any functions.
My question, specifically is, what do I do in the functions to cast the void pointers to the desired struct? Is there one statement at the top of each function that casts them or do I make the cast every time I use "implementation"?
Here are the typedefs the structs of a Hash_map and Array_hash_map as well as a couple functions making use of them.
typedef struct {
Key_compare_fn key_compare_fn;
Key_delete_fn key_delete_fn;
Data_compare_fn data_compare_fn;
Data_delete_fn data_delete_fn;
void *implementation;
} Hash_map;
typedef struct Array_hash_map{
struct Unit *array;
int size;
int capacity;
} Array_hash_map;
typedef struct Unit{
Key key;
Data data;
} Unit;
functions:
/* Sets the value parameter to the value associated with the
key parameter in the Hash_map. */
int get(Hash_map *map, Key key, Data *value){
int i;
if (map == NULL || value == NULL)
return 0;
for (i = 0; i < map->implementation->size; i++){
if (map->key_compare_fn(map->implementation->array[i].key, key) == 0){
*value = map->implementation->array[i].data;
return 1;
}
}
return 0;
}
/* Returns the number of values that can be stored in the Hash_map, since it is
represented by an array. */
int current_capacity(Hash_map map){
return map.implementation->capacity;
}
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