Hello, I have written a simple Hello World program.

   #include <stdio.h>
    int main() {
    printf("Hello World");
    return 0;
    }

I wanted to understand how the relocatable object file and executable file look like. The object file corresponding to the main function is

0000000000000000 <main>:
   0:   55                      push   %rbp
   1:   48 89 e5                mov    %rsp,%rbp
   4:   bf 00 00 00 00          mov    $0x0,%edi
   9:   b8 00 00 00 00          mov    $0x0,%eax
   e:   e8 00 00 00 00          callq  13 <main+0x13>
  13:   b8 00 00 00 00          mov    $0x0,%eax
  18:   c9                      leaveq 
  19:   c3                      retq 

Here the function call for printf is callq 13. One thing i don't understand is why is it 13. That means call the function at adresss 13, right??. 13 has the next instruction, right?? Please explain me what does this mean??

The executable code corresponding to main is

00000000004004cc <main>:
  4004cc:       55                      push   %rbp
  4004cd:       48 89 e5                mov    %rsp,%rbp
  4004d0:       bf dc 05 40 00          mov    $0x4005dc,%edi
  4004d5:       b8 00 00 00 00          mov    $0x0,%eax
  4004da:       e8 e1 fe ff ff          callq  4003c0 <printf@plt>
  4004df:       b8 00 00 00 00          mov    $0x0,%eax
  4004e4:       c9                      leaveq 
  4004e5:       c3                      retq 

Here it is callq 4003c0. But the binary instruction is e8 e1 fe ff ff. There is nothing that corresponds to 4003c0. What is that i am getting wrong?

Thanks. Bala