gcc does not resolve extern global variables, with or without -c option
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Published on 2010-05-08T10:07:16Z
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2010/05/08
10:28 UTC
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Hello everyone! So i have this issue : i am declaring some extern global variables in my C program. If I don't use the -c option for gcc, i get undefined references errors. But with that -c option, the linking is not done, which means that i don't have an executable generated.
So how do I solve this?
Here is my makefile. As I am not good with writing makefiles, I took one from another project then I changed a few things. So maybe I'm missing something here.
# Makefile calculPi INCL = -I$(INCL_DIR) DEFS = -D_DEBUG_ CXX_FLAGS =-g -c -lpthread -lm CXX = gcc $(CXX_FLAGS) $(INCL) $(DEFS) LINK_CXX = gcc OBJ = approx.o producteur.o sequentialApproximation.o main.o LINKOBJ = approx.o producteur.o sequentialApproximation.o main.o BIN = calculPi.exe RM = rm -fv all: calculPi.exe clean: ${RM} *\~ \#*\# $(OBJ) clean_all: clean ${RM} $(BIN) cleanall: clean ${RM} $(BIN) $(BIN): $(OBJ) $(CXX) $(LINKOBJ) -o "calculPi.exe" main.o: main.c $(CXX) main.c -o main.o $(CXX_FLAGS) approx.o: approx.c approx.h $(CXX) -c approx.c -o approx.o $(CXX_FLAGS); producteur.o: producteur.c producteur.h $(CXX) -c producteur.c -o producteur.o $(CXX_FLAGS); sequentialApproximation.o : sequentialApproximation.c sequentialApproximation.h $(CXX) -c sequentialApproximation.c -o sequentialApproximation.o $(CXX_FLAGS);
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