does overload operator-> a compile time action?

Posted by Brent on Stack Overflow See other posts from Stack Overflow or by Brent
Published on 2010-05-25T14:57:29Z Indexed on 2010/05/25 15:01 UTC
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when I tried to compile the code:

struct S
{
    void func2() {}
};

class O
{
public:
    inline S* operator->() const;
private:
    S* ses;
};

inline S* O::operator->() const
{
    return ses;
}

int main()
{
    O object;
    object->func();
    return 0;
}

there is a compile error reported:

D:\code>g++ operatorp.cpp -S -o operatorp.exe
operatorp.cpp: In function `int main()':
operatorp.cpp:27: error: 'struct S' has no member named 'func'

it seems that invoke the overloaded function of "operator->" is done during compile time? I'd add "-S" option for compile only.

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