how to compare the checksums in a list corresponding to a file path with the file path in the operat
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Published on 2010-05-25T20:04:29Z
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2010/05/30
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Hi all,
how to compare the checksums in a list corresponding to a file path with the file path in the operating system In Python?
import os,sys,libxml2
files=[]
sha1s=[]
doc = libxml2.parseFile('files.xml')
for path in doc.xpathEval('//File/Path'):
files.append(path.content)
for sha1 in doc.xpathEval('//File/Hash'):
sha1s.append(sha1.content)
for entry in zip(files,sha1s):
print entry
the files.xml contains
<Files>
<File>
<Path>usr/share/doc/dialog/samples/form1</Path>
<Type>doc</Type>
<Size>1222</Size>
<Uid>0</Uid>
<Gid>0</Gid>
<Mode>0755</Mode>
<Hash>49744d73e8667d0e353923c0241891d46ebb9032</Hash>
</File>
<File>
<Path>usr/share/doc/dialog/samples/form3</Path>
<Type>doc</Type>
<Size>1294</Size>
<Uid>0</Uid>
<Gid>0</Gid>
<Mode>0755</Mode>
<Hash>f30277f73e468232c59a526baf3a5ce49519b959</Hash>
</File>
</Files>
I need to compare the sha1 checksum in between tags corresponding to the file specified in between the tags, with the same file path in base Operating system.
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