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  • how to compare the checksums in a list corresponding to a file path with the file path in the operat

    - by surab
    Hi all, how to compare the checksums in a list corresponding to a file path with the file path in the operating system In Python? import os,sys,libxml2 files=[] sha1s=[] doc = libxml2.parseFile('files.xml') for path in doc.xpathEval('//File/Path'): files.append(path.content) for sha1 in doc.xpathEval('//File/Hash'): sha1s.append(sha1.content) for entry in zip(files,sha1s): print entry the files.xml contains <Files> <File> <Path>usr/share/doc/dialog/samples/form1</Path> <Type>doc</Type> <Size>1222</Size> <Uid>0</Uid> <Gid>0</Gid> <Mode>0755</Mode> <Hash>49744d73e8667d0e353923c0241891d46ebb9032</Hash> </File> <File> <Path>usr/share/doc/dialog/samples/form3</Path> <Type>doc</Type> <Size>1294</Size> <Uid>0</Uid> <Gid>0</Gid> <Mode>0755</Mode> <Hash>f30277f73e468232c59a526baf3a5ce49519b959</Hash> </File> </Files> I need to compare the sha1 checksum in between tags corresponding to the file specified in between the tags, with the same file path in base Operating system.

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