Using AWK find a smallest number in a second column bigger than x

Posted by Andrei on Stack Overflow See other posts from Stack Overflow or by Andrei
Published on 2010-06-04T20:04:23Z Indexed on 2010/06/05 14:22 UTC
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Filed under:

bash

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scripting

|

sed

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awk

I have a file with two columns,

sdfsd 1.3
sdfds 3
sdfsdf 2.1
dsfsdf -1

if x is 2

I want to print sdfsdf 2.1

How to express it in awk (bash or sed is fine too)

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