Pass data to Child Window in Silverlight 4 using MVVM
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by Archie
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Published on 2010-05-21T04:40:26Z
Indexed on
2010/06/15
18:02 UTC
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Hello,
I have a datagrid with master detail implementation as follows:
<data:DataGrid x:Name="dgData" Width="600" ItemsSource="{Binding Path=ItemCollection}"
HorizontalScrollBarVisibility="Hidden" CanUserSortColumns="False" RowDetailsVisibilityChanged="dgData_RowDetailsVisibilityChanged">
<data:DataGrid.Columns>
<data:DataGridTextColumn Header="Item" Width="*" Binding="{Binding Item,Mode=TwoWay}"/>
<data:DataGridTextColumn Header="Company" Width="*" Binding="{Binding Company,Mode=TwoWay}"/>
</data:DataGrid.Columns>
<data:DataGrid.RowDetailsTemplate>
<DataTemplate>
<data:DataGrid x:Name="dgrdRowDetail" Width="400" AutoGenerateColumns="False" HorizontalAlignment="Center"
HorizontalScrollBarVisibility="Hidden" Grid.Row="1">
<data:DataGrid.Columns>
<data:DataGridTextColumn Header="Date" Width="*" Binding="{Binding Date,Mode=TwoWay}"/>
<data:DataGridTextColumn Header="Price" Width="*" Binding="{Binding Price, Mode=TwoWay}"/>
<data:DataGridTemplateColumn>
<data:DataGridTemplateColumn.CellTemplate>
<DataTemplate>
<Button Content="Show More Details" Click="buttonShowDetail_Click"></Button>
</DataTemplate>
</data:DataGridTemplateColumn.CellTemplate>
</data:DataGridTemplateColumn>
</data:DataGrid.Columns>
</data:DataGrid>
</DataTemplate>
</data:DataGrid.RowDetailsTemplate>
</data:DataGrid>
I want to open a Child window in clicking the button which shows more details about the product.
I'm using MVVM pattern. My Model contains a method which takes the Item name as input and retursn the Details data.
My problem is how should I pass the Item to ViewModel which will get the Details data from Model? and where shoukd I open the new Child Window? In View or ViewModel?
Please help.Thanks.
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