How to obtain the root of a tree without parsing the entire file?
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Published on 2011-03-01T22:05:16Z
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I'm making an xml parser to parse xml reports from different tools, and each tool generates different reports with different tags.
For example:
Arachni generates an xml report with <arachni_report></arachni_report>
as tree root tag.
nmap generates an xml report with <nmaprun></nmaprun>
as tree root tag.
I'm trying not to parse the entire file unless it's a valid report from any of the tools I want.
First thing I thought to use was ElementTree, parse the entire xml file (supposing it contains valid xml), and then check based on the tree root if the report belongs to Arachni or nmap.
I'm currently using cElementTree, and as far as I know getroot() is not an option here, but my goal is to make this parser to operate with recognized files only, without parsing unnecessary files.
By the way, I'm Still learning about xml parsing, thanks in advance.
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